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Civil Engineering (CE) Exam  >  Civil Engineering (CE) Test  >  Mock Test Series for IES/ESE (CE)  >  ESE (CE) Paper II Mock Test - 7 - Civil Engineering (CE) MCQ

ESE (CE) Paper II Mock Test - 7 Free Online Test 2026


Full Mock Test & Solutions: ESE (CE) Paper II Mock Test - 7 (150 Questions)

You can boost your Civil Engineering (CE) 2026 exam preparation with this ESE (CE) Paper II Mock Test - 7 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of Civil Engineering (CE) 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 180 minutes
  • - Total Questions: 150
  • - Analysis: Detailed Solutions & Performance Insights

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ESE (CE) Paper II Mock Test - 7 - Question 1
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In case of transmission of hydraulic power by a pipe line to a turbine in a hydroelectric power station, the maximum power transmission efficiency through the pipe line is

Detailed Solution: Question 1

Maximum power transmission efficiency occurs when

∴ 

Hence option (B) is correct.

ESE (CE) Paper II Mock Test - 7 - Question 2
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The influence line diagram for reaction at D in the frame shown below is
 

Detailed Solution: Question 2

Let the unit load be at a distance x from A. Taking moments about B,

This represents a straight line equation
At x = 0; 
​​​​​​​Hence option (A) is correct.

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ESE (CE) Paper II Mock Test - 7 - Question 3
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The earliest time of the completion of the last event in the network shown below in weeks is

Detailed Solution: Question 3


Earliest time of completion = 46 weeks

Hence the option (D) is correct .

ESE (CE) Paper II Mock Test - 7 - Question 4
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The maximum flow occurs in an egg shaped sewer when the ratio of depth of flow to vertical diameter is

Detailed Solution: Question 4

The maximum velocity occurs in an egg shaped sewer when the ratio of depth of flow to vertical diameter is 0.81

Hence option (A) is Correct.

ESE (CE) Paper II Mock Test - 7 - Question 5
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A two hour storm hydrograph has 5-unit of direct runoff. The two hour unit hydrograph for this storm can be obtained by dividing the ordinates of the storm hydrograph by

Detailed Solution: Question 5

A graphical explanation of how a unit hydrograph is used to derive a direct runoff hydrograph is first provided. A unit hydrograph is a hydrograph resulting from one inch or one mm of rainfall falling uniformly over the total watershed area. ... If the rainfall stops after Δt, this is the direct runoff hydrograph.The 2-hour unit hydrograph is obtained by dividing the ordinates of storm hydrograph by the direct runoff depth which is 5 unit.

Hence option (C) is correct.

ESE (CE) Paper II Mock Test - 7 - Question 6
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Consider the following statements:

  1. A soil is at its liquid limit if the consistency index of the soil is equal to zero.
  2. A soil sample having a void ratio of 1.4, water content of 50% and specific gravity of 2.7 is in the state of partial saturation.

Which of the above statements is(are) CORRECT?

Detailed Solution: Question 6

Hence option (C) is correct.

ESE (CE) Paper II Mock Test - 7 - Question 7
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Match List I and List II and select the correct answer using the codes given below the lists.

Detailed Solution: Question 7

Probable maximum flood is the extreme flood that is practically possible in a region as a result of severe most combination.

The standard Project flood results from severe combinations of meteorological and hydrological factors that are reasonably applicable in that region.

According to Gumbel’s distribution, the value of flood with return period of 2.33 years is the mean annual flood.

Hence option (A) is correct

ESE (CE) Paper II Mock Test - 7 - Question 8
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Most economical circular section is designed for

Detailed Solution: Question 8

Most economical section gives maximum discharge for a given amount of excavation and the discharge is maximum velocity is maximum, the area of cross section remaining constant. And for a given slope and roughness coefficient the velocity is maximum when the hydraulic radius (area / perimeter) must be maximum. For it to be maximum the perimeter should be minimum.

But for conduits the condition of the area remaining constant does not hold good since both the wetted perimeter and the wetted area changes with depth of flow, so for most economical section in case of open channel flow in circular conduits is designed for Maximum mean velocity and Maximum flow rate

Hence option (A) is correct 

ESE (CE) Paper II Mock Test - 7 - Question 9
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A velocity field is given by U = 3xy and V = 3/2 (x2 - y2). What is the relevant equation of the stream line?

Detailed Solution: Question 9

U = 3xy
V= 3/2 (x2 - y2)
Equation of streamline is given by
Vdx = Udy

ESE (CE) Paper II Mock Test - 7 - Question 10
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As per ICAO, all markings of the taxiways and runways will be respectively

Detailed Solution: Question 10

Yellow and white

ESE (CE) Paper II Mock Test - 7 - Question 11
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The size of a rectangular column is 300 mm × 400 mm. The effective length about y-axis is equal to 5.0 m. The axial force, Pu on the column is 1200 kN. The additional moment about y-axis due to slenderness will be equal to

Detailed Solution: Question 11

ESE (CE) Paper II Mock Test - 7 - Question 12
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The minimum number of bars required in a rectangular column for earthquake resistant design is

Detailed Solution: Question 12

The minimum reinforcement requirement shall be governed by Cl.26.5.3.1(c) of IS 456:2000 i.e. minimum 4 number of bars are required in rectangular column.

ESE (CE) Paper II Mock Test - 7 - Question 13
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Consider the following steps:

1. Driving sheet pile surrounding a vibration-receiving structure.

2. Digging a trench around a source of vibration.

3. Placing rubber mountings between a machine causing vibration at its base.

Active isolation of vibration can be achieved by

Detailed Solution: Question 13

Isolating the source of vibration is called active isolation while protecting the receiver is passive isolation.

ESE (CE) Paper II Mock Test - 7 - Question 14
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In the following questions two statements are given. Read them carefully and choose from the options given below:

a) Both I and II are true and II is the correct explanation of I.

b) Both I and II are true and II is NOT the correct explanation of I.

c) I is true but II is false.

d) I is false but II is true.

Statement (I): Portal bracing should be used in only through bridges where cross frames cannot be used.

Statement (II): Portal bracing causes bending moment in end frames.

ESE (CE) Paper II Mock Test - 7 - Question 15
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In a Newmark’s chart for stress distribution, there are 10 concentric circles and 20 radial lines. The influence factor for the chart will be

Detailed Solution: Question 15

ESE (CE) Paper II Mock Test - 7 - Question 16
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Match List-I with List-II and select the correct answer using the codes given below the lists:

ESE (CE) Paper II Mock Test - 7 - Question 17
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Pick up the incorrect statement:

Detailed Solution: Question 17

Sewer pipes can be carried up and down the hills.

ESE (CE) Paper II Mock Test - 7 - Question 18
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The carbonate and non-carbonate hardness of water respectively (in mg/l as CaCO3) having a total alkalinity of 200 mg/l as CaCO3 and 140mg/l of Ca2+ and 80mg/l of Mg2+ as ions can be the following:

Detailed Solution: Question 18

= 350 + 333.33
= 683.33 mg/l as CaCO₃
Carbonate hardness = Lesser of total hardness or alkalinity
= Lesser of (200 mg/l, 683.33 mg/l)
= 200 mg/l
So, non-carbonate hardness = 683.33 - 200
= 483.33 mg/l

ESE (CE) Paper II Mock Test - 7 - Question 19
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A recently reclaimed alkaline soil should preferably be sown with a salt resistent crop like

ESE (CE) Paper II Mock Test - 7 - Question 20
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Consider the following statements regarding aqua privy:

  1. It stores and decomposes the excreta anaerobically.
  2. It can be located above the ground level.

Which of the above statements is(are) CORRECT?

Detailed Solution: Question 20

In an aqua pit priry, urine and feaces are dropped into a water tight tank which stores and decomposes excreta in absence of oxygen. The aqua privy may be located above ground level or privy above ground and privy below ground.

ESE (CE) Paper II Mock Test - 7 - Question 21
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What is the modular ratio to be used in WSM if grade of concrete is M30?

Detailed Solution: Question 21

ESE (CE) Paper II Mock Test - 7 - Question 22
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What is the net downward load to be considered for the analysis of the prestressed concrete beam provided with parabolic cable as shown in figure?

Detailed Solution: Question 22

w1 = 16 kN/m = Balancing load
∴ Net downward load = 40 - 16 = 24 kN/m

ESE (CE) Paper II Mock Test - 7 - Question 23
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The Poisson’s ratio for a circular bar of diameter 25 mm, whose bulk modulus is 6.93 × 104 N/mm2 and modulus of rigidity is 2.65 × 104 N/mm2 will be

Detailed Solution: Question 23

ESE (CE) Paper II Mock Test - 7 - Question 24
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A lap joint is designed using bolted connections. The bolts used are of 20 mm diameter and 4.6 grade. The plate in connection is of thickness 20 mm and of grade Fe410 with  The pitch is 60 mm, gauge is 50 mm and end distance is 40 mm. The bearing strength of bolt is

Detailed Solution: Question 24

ESE (CE) Paper II Mock Test - 7 - Question 25
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The number of possible independent mechanisms for the frame shown below is

Detailed Solution: Question 25

n = N - r
where, N = Number of possible hinge locations available
r= Redundancy
n= Number of independent mechanisms
N  =4 
r  =1 
n  =4-1=3

ESE (CE) Paper II Mock Test - 7 - Question 26
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The degree of kinematic indeterminacy of the frame shown below is

[Assume the members to be inextensible]

Detailed Solution: Question 26

Total number of joints, j = 14
Total number of external reactions, Re = 4
Total number of members, m = 19
∴ Degree of kinematic indeterminacy,

Dk = 3j - Re - m = 3 x 14 - 4 - 19 = 19

ESE (CE) Paper II Mock Test - 7 - Question 27
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What is the design load for collapse condition for given loads: Dead load = 120 kN/m, Live load = 200 kN/m, Wind load = 25 kN/m ?

Detailed Solution: Question 27

Design load for collapse :

(i) 1.5 DL + 1.5 LL = 1.5 × 120 + 1.5 × 200 = 480 kN/m

(ii) 1.5 DL + 1.5 WL = 1.5 × 120 + 1.5 × 25 = 217.5 kN/m

(iii) 1.20 DL + 1.2 LL + 1.2 EL = 1.2 × 120 + 1.2 × 200 + 1.2 × 25 = 414 kN/m

So maximum of these three values will be the design load for collapse condition i.e. 480 kN/m.

ESE (CE) Paper II Mock Test - 7 - Question 28
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Consider the following statements based on response spectra of structure with low value of natural period:

  1. Short natural period or high natural frequency indicates a very stiff structure.
  2. The maximum relative displacement is nearly zero.

Which of the above statements (is)are CORRECT?

ESE (CE) Paper II Mock Test - 7 - Question 29
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The soil sample with specific gravity of solids as 2.7 has a mass specific gravity of 1.84. If the soil is perfectly dry then void ratio of soil will be

Detailed Solution: Question 29

ESE (CE) Paper II Mock Test - 7 - Question 30
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In a damped freely vibrating SDOF system, the damping ratio is 0.012 and critical damping coefficient is 1600 Ns/m then damped coefficient is

Detailed Solution: Question 30

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About this Civil Engineering (CE) Mock Test

This mock test contains 150 questions designed to replicate the pattern, difficulty level and time pressure of the actual Civil Engineering (CE) exam. It is part of Mock Test Series for IES/ESE (CE) on EduRev, covering all the topics that are being asked as per the current Civil Engineering (CE) syllabus. Attempting this test under timed conditions will help you assess your exam readiness, identify subject-wise weak areas, and improve your speed and accuracy before the actual exam.

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