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Civil Engineering (CE) Exam  >  Civil Engineering (CE) Tests  >  ESE (CE) Paper II Mock Test - 7 - Civil Engineering (CE) MCQ

ESE (CE) Paper II Mock Test - 7 - Civil Engineering (CE) MCQ


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30 Questions MCQ Test - ESE (CE) Paper II Mock Test - 7

ESE (CE) Paper II Mock Test - 7 for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The ESE (CE) Paper II Mock Test - 7 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The ESE (CE) Paper II Mock Test - 7 MCQs are made for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for ESE (CE) Paper II Mock Test - 7 below.
Solutions of ESE (CE) Paper II Mock Test - 7 questions in English are available as part of our course for Civil Engineering (CE) & ESE (CE) Paper II Mock Test - 7 solutions in Hindi for Civil Engineering (CE) course. Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free. Attempt ESE (CE) Paper II Mock Test - 7 | 150 questions in 180 minutes | Mock test for Civil Engineering (CE) preparation | Free important questions MCQ to study for Civil Engineering (CE) Exam | Download free PDF with solutions
ESE (CE) Paper II Mock Test - 7 - Question 1
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The earliest time of the completion of the last event in the network shown below in weeks is

Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 1


Earliest time of completion = 46 weeks

Hence the option (D) is correct .

ESE (CE) Paper II Mock Test - 7 - Question 2
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The maximum flow occurs in an egg shaped sewer when the ratio of depth of flow to vertical diameter is

Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 2

The maximum velocity occurs in an egg shaped sewer when the ratio of depth of flow to vertical diameter is 0.81

Hence option (A) is Correct.
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ESE (CE) Paper II Mock Test - 7 - Question 3
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A two hour storm hydrograph has 5-unit of direct runoff. The two hour unit hydrograph for this storm can be obtained by dividing the ordinates of the storm hydrograph by

Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 3

A graphical explanation of how a unit hydrograph is used to derive a direct runoff hydrograph is first provided. A unit hydrograph is a hydrograph resulting from one inch or one mm of rainfall falling uniformly over the total watershed area. ... If the rainfall stops after Δt, this is the direct runoff hydrograph.The 2-hour unit hydrograph is obtained by dividing the ordinates of storm hydrograph by the direct runoff depth which is 5 unit.

Hence option (C) is correct.

ESE (CE) Paper II Mock Test - 7 - Question 4
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Consider the following statements:

  1. A soil is at its liquid limit if the consistency index of the soil is equal to zero.
  2. A soil sample having a void ratio of 1.4, water content of 50% and specific gravity of 2.7 is in the state of partial saturation.

Which of the above statements is(are) CORRECT?
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 4

Hence option (C) is correct.

ESE (CE) Paper II Mock Test - 7 - Question 5
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Match List I and List II and select the correct answer using the codes given below the lists.
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 5

Probable maximum flood is the extreme flood that is practically possible in a region as a result of severe most combination.

The standard Project flood results from severe combinations of meteorological and hydrological factors that are reasonably applicable in that region.

According to Gumbel’s distribution, the value of flood with return period of 2.33 years is the mean annual flood.

Hence option (A) is correct

ESE (CE) Paper II Mock Test - 7 - Question 6
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Most economical circular section is designed for
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 6

Most economical section gives maximum discharge for a given amount of excavation and the discharge is maximum velocity is maximum, the area of cross section remaining constant. And for a given slope and roughness coefficient the velocity is maximum when the hydraulic radius (area / perimeter) must be maximum. For it to be maximum the perimeter should be minimum.

But for conduits the condition of the area remaining constant does not hold good since both the wetted perimeter and the wetted area changes with depth of flow, so for most economical section in case of open channel flow in circular conduits is designed for Maximum mean velocity and Maximum flow rate

Hence option (A) is correct 

ESE (CE) Paper II Mock Test - 7 - Question 7
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A velocity field is given by U = 3xy and V = 3/2 (x2 - y2). What is the relevant equation of the stream line?
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 7

U = 3xy
V= 3/2 (x2 - y2)
Equation of streamline is given by
Vdx = Udy

ESE (CE) Paper II Mock Test - 7 - Question 8
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As per ICAO, all markings of the taxiways and runways will be respectively
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 8

Yellow and white

ESE (CE) Paper II Mock Test - 7 - Question 9
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The size of a rectangular column is 300 mm × 400 mm. The effective length about y-axis is equal to 5.0 m. The axial force, Pu on the column is 1200 kN. The additional moment about y-axis due to slenderness will be equal to
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 9

ESE (CE) Paper II Mock Test - 7 - Question 10
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The minimum number of bars required in a rectangular column for earthquake resistant design is
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 10

The minimum reinforcement requirement shall be governed by Cl.26.5.3.1(c) of IS 456:2000 i.e. minimum 4 number of bars are required in rectangular column.

ESE (CE) Paper II Mock Test - 7 - Question 11
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Consider the following steps:

1. Driving sheet pile surrounding a vibration-receiving structure.

2. Digging a trench around a source of vibration.

3. Placing rubber mountings between a machine causing vibration at its base.

Active isolation of vibration can be achieved by
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 11

Isolating the source of vibration is called active isolation while protecting the receiver is passive isolation.

ESE (CE) Paper II Mock Test - 7 - Question 12
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In the following questions two statements are given. Read them carefully and choose from the options given below:

a) Both I and II are true and II is the correct explanation of I.

b) Both I and II are true and II is NOT the correct explanation of I.

c) I is true but II is false.

d) I is false but II is true.

Statement (I): Portal bracing should be used in only through bridges where cross frames cannot be used.

Statement (II): Portal bracing causes bending moment in end frames.
ESE (CE) Paper II Mock Test - 7 - Question 13
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In a Newmark’s chart for stress distribution, there are 10 concentric circles and 20 radial lines. The influence factor for the chart will be
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 13
ESE (CE) Paper II Mock Test - 7 - Question 14
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Match List-I with List-II and select the correct answer using the codes given below the lists:
ESE (CE) Paper II Mock Test - 7 - Question 15
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Pick up the incorrect statement:
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 15

Sewer pipes can be carried up and down the hills.

ESE (CE) Paper II Mock Test - 7 - Question 16
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The carbonate and non-carbonate hardness of water respectively (in mg/l as CaCO3) having a total alkalinity of 200 mg/l as CaCO3 and 140mg/l of Ca2+ and 80mg/l of Mg2+ as ions can be the following:
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 16

= 350 + 333.33
= 683.33 mg/l as CaCO₃
Carbonate hardness = Lesser of total hardness or alkalinity
= Lesser of (200 mg/l, 683.33 mg/l)
= 200 mg/l
So, non-carbonate hardness = 683.33 - 200
= 483.33 mg/l

ESE (CE) Paper II Mock Test - 7 - Question 17
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A recently reclaimed alkaline soil should preferably be sown with a salt resistent crop like
ESE (CE) Paper II Mock Test - 7 - Question 18
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Consider the following statements regarding aqua privy:

  1. It stores and decomposes the excreta anaerobically.
  2. It can be located above the ground level.

Which of the above statements is(are) CORRECT?
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 18

In an aqua pit priry, urine and feaces are dropped into a water tight tank which stores and decomposes excreta in absence of oxygen. The aqua privy may be located above ground level or privy above ground and privy below ground.

ESE (CE) Paper II Mock Test - 7 - Question 19
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What is the modular ratio to be used in WSM if grade of concrete is M30?
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 19

ESE (CE) Paper II Mock Test - 7 - Question 20
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What is the net downward load to be considered for the analysis of the prestressed concrete beam provided with parabolic cable as shown in figure?
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 20

w1 = 16 kN/m = Balancing load
∴ Net downward load = 40 - 16 = 24 kN/m

ESE (CE) Paper II Mock Test - 7 - Question 21
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The Poisson’s ratio for a circular bar of diameter 25 mm, whose bulk modulus is 6.93 × 104 N/mm2 and modulus of rigidity is 2.65 × 104 N/mm2 will be
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 21

ESE (CE) Paper II Mock Test - 7 - Question 22
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The degree of kinematic indeterminacy of the frame shown below is

[Assume the members to be inextensible]
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 22

Total number of joints, j = 14
Total number of external reactions, Re = 4
Total number of members, m = 19
∴ Degree of kinematic indeterminacy,

Dk = 3j - Re - m = 3 x 14 - 4 - 19 = 19

ESE (CE) Paper II Mock Test - 7 - Question 23
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Lap length of reinforcement in compression be equal to development length but shall not be less than
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 23

Lap length in compression shall not be less than 24 Φ.

ESE (CE) Paper II Mock Test - 7 - Question 24
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Consider the following assumption used for the designing limit state of collapse in flexure:

(A) Plane sections normal to the axis of bending remain plane after bending.

(B) The maximum strain in concrete at the outermost compression edge is taken as 0.0035 in bending.

(C) The relationship between the compressive stress distribution and the corresponding compressive

strain in concrete is assumed to be rectangular only.

Which of the above assumptions are correct according to code IS 456 : 2000?
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 24

The 3rd assumption is wrong.

The relationship between the compressive stress distribution and the compressive strain in concrete may be assumed to be rectangular, trapezoid, parabola or any other shape.

ESE (CE) Paper II Mock Test - 7 - Question 25
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What is the design load for collapse condition for given loads: Dead load = 120 kN/m, Live load = 200 kN/m, Wind load = 25 kN/m ?
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 25

Design load for collapse :

(i) 1.5 DL + 1.5 LL = 1.5 × 120 + 1.5 × 200 = 480 kN/m

(ii) 1.5 DL + 1.5 WL = 1.5 × 120 + 1.5 × 25 = 217.5 kN/m

(iii) 1.20 DL + 1.2 LL + 1.2 EL = 1.2 × 120 + 1.2 × 200 + 1.2 × 25 = 414 kN/m

So maximum of these three values will be the design load for collapse condition i.e. 480 kN/m.

ESE (CE) Paper II Mock Test - 7 - Question 26
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Consider the following statements regarding role of internal hinge :

  1. It introduces a moment release in a beam.
  2. It can render an originally ‘over rigid’ structure to ‘just rigid’ structure.
  3. It effectively divides a beam into two sub elements that are now connected by a pin joint.

Which of the above statements are CORRECT?
ESE (CE) Paper II Mock Test - 7 - Question 27
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Consider the following statements based on response spectra of structure with low value of natural period:

  1. Short natural period or high natural frequency indicates a very stiff structure.
  2. The maximum relative displacement is nearly zero.

Which of the above statements (is)are CORRECT?
ESE (CE) Paper II Mock Test - 7 - Question 28
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The soil sample with specific gravity of solids as 2.7 has a mass specific gravity of 1.84. If the soil is perfectly dry then void ratio of soil will be
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 28

ESE (CE) Paper II Mock Test - 7 - Question 29
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In a damped freely vibrating SDOF system, the damping ratio is 0.012 and critical damping coefficient is 1600 Ns/m then damped coefficient is
Detailed Solution for ESE (CE) Paper II Mock Test - 7 - Question 29
ESE (CE) Paper II Mock Test - 7 - Question 30
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Consider the following statements:

  1. Bernoulli’s equation is applicable for inviscid and incompressible fluid flow
  2. The necessary and sufficient condition for a surface to be called as free surface is that shear stress acting on it must be zero.

Which of the above statements is(are) CORRECT?
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