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EmSAT Physics Mock Test- 3 - EmSAT Achieve MCQ


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30 Questions MCQ Test Mock Tests for EmSAT Achieve 2024 - EmSAT Physics Mock Test- 3

EmSAT Physics Mock Test- 3 for EmSAT Achieve 2024 is part of Mock Tests for EmSAT Achieve 2024 preparation. The EmSAT Physics Mock Test- 3 questions and answers have been prepared according to the EmSAT Achieve exam syllabus.The EmSAT Physics Mock Test- 3 MCQs are made for EmSAT Achieve 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for EmSAT Physics Mock Test- 3 below.
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EmSAT Physics Mock Test- 3 - Question 1

A projectile is projected with an initial velocity of  The equation of the trajectory followed by the projectile will be

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 1

Equation of projectile is given as:


This is the required solution.

EmSAT Physics Mock Test- 3 - Question 2

Two springs with spring constant K1 and K2 are stretched by the same force. If the potential energy stored in the two springs respectively is U1 and U2 and the ratio U1: U2 is given to be 1 : 2, find the ratio of the spring constants K1 : K2.

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 2

We know,
Potential energy stored in the spring, 
Therefore,

This is the required solution.

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EmSAT Physics Mock Test- 3 - Question 3

In a situation it is observed that the coefficient of restitution of a collision is greater than 1. This condition implies to the possibility that

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 3

The coefficient of restitution is almost every time less than 1. It is the ratio of the relative velocity after collision to that before collision. As some part of the energy is dissipated during the collision, the relative velocity after collision decreases, giving e < 1.
For e > 1, it is possible that there is some amount of energy produced via chemical reaction or explosion during the collision.
Therefore, it is the correct option.

EmSAT Physics Mock Test- 3 - Question 4

A particle of mass 2 kg is at the point P of a circular track as shown in the figure. It is released from the rest. At point Q, the velocity of the body is 10 m/s. If the radius of the track is 40 m, what is the work done by the body against friction between points P and Q? (Take g = 10 N/m2)

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 4


Energy of the body at point P
= mgh = 2 × 10 × 40 = 800 J
Energy of the particle at point Q

Work done against friction = Change in the mechanical energy of the body
= 800 - 500
= 300 J
This is the required solution.

EmSAT Physics Mock Test- 3 - Question 5

What will be the angular velocity of the rotation of the Earth, so that the acceleration due to gravity at the equator becomes zero? Mass of the Earth = 6400 × 103 kg and g = 9.8 m/s2

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 5

EmSAT Physics Mock Test- 3 - Question 6

A force F(x) = -2kx is acting on a body of mass 1 kg, moving along the positive x-direction. The velocity of the particle at time t = 0 is zero and the displacement at t = 0 is 2 m. If k = 1 Nm-2, what is the velocity of the body when the displacement is 1 m?

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 6

Given: F(x) = -2kx, k = 1 Nm-2
At time t = 0, v = 0 m/s and x = 2 m
At time t = t, x = 1 m and velocity is v.
Therefore, change in kinetic energy in moving from x = 2 to x = 1 m,

This is the required solution.

EmSAT Physics Mock Test- 3 - Question 7

A time dependent force F is acting on a block of mass 10 kg. The plot of the magnitude of force versus time is given below. The momentum gained by the body at the end of 20 seconds will be

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 7

Change in momentum = Area under F-t curve

Therefore,

Therefore, it is the correct option.

EmSAT Physics Mock Test- 3 - Question 8

A ball of mass m, moving with a constant velocity, collides with another identical ball at rest. After the collision, the first ball acquires velocity v1 and the second ball that was at rest before collision acquires velocity v2. If the coefficient of restitution is given to be 5/7, what will be the ratio v1 : v2?

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 8

Let the velocity of the ball before the collision be u.
Velocity of the bodies after the collision is given by:
Using conservation of momentum
mu = mv1 + mv2
u = v1 + v2
Coefficient of restitution,

Hence,

Therefore, the ratio of velocities is given by:

Therefore, it is the correct option.

EmSAT Physics Mock Test- 3 - Question 9

A circular ring of mass m is rolling without slipping along an inclined plane. The angle of inclination of the plane is given to be θ and the linear velocity of the ring at the bottom of the inclined plane is v. If a body of the same mass is slipping on the same inclined plane, what will be the velocity at the bottom of the inclined plane? Consider the plane to be smooth and frictionless.

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 9

Let the velocity of the object sliding down the plane be v'.
Therefore,  where h is the height of the inclined plane.
If l is the length of the plane, then
h = I sin θ
For pure rolling without slipping of the ring,
v2 = 2al; where a = linear acceleration of the ring

Therefore,

Therefore,

EmSAT Physics Mock Test- 3 - Question 10


In the graph, the stress-strain curve for two different materials P and Q are plotted. Which of the following statements are correct?
I. Tensile strength of P is more than that of Q.
II. Young's modulus of P is more than that of Q.
III. Tensile strength of P is less than that of Q.
IV. Young's modulus of P is less than that of Q.

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 10

From the graph,


For same stress,

Therefore, Young's modulus of P > Young's modulus of Q
Also, the breaking stress in P is more than breaking stress in Q. Therefore, tensile stress of P is greater than that of Q. Therefore, it is the correct option.

EmSAT Physics Mock Test- 3 - Question 11

Refer to the system shown in figure. The acceleration of the masses is

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 11

5g − T2 = 5a        ....(i)
T2 − T1 − 3g = 3a      ...(ii)
T1 − g = a    ...(iii)
Adding Eqs (i) and (iii),
−T2 + T1 + 4g = 6a
Adding this to Eq. (ii), we get
g = 9a or a = g/9

EmSAT Physics Mock Test- 3 - Question 12

Two blocks of masses m and 2m are connected by a light string passing over a frictionless pulley. As shown in the figure, the mass m is placed on a smooth inclined plane of inclination 30° and 2m hangs vertically. If the system is released, the blocks move with an acceleration equal to

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 12

As 2m > m
The acceleration of the two block system will be as shown in figure.

The equation for block of mass 2m is
2mg − T = 2ma  ...(i)
Similarly, for block of mass m
T − mg sin30° = ma ...(ii)
From Eqs. (i) and (ii), we have

⟹ a = g/2

EmSAT Physics Mock Test- 3 - Question 13

A wooden box of mass 8 kg slides down an inclined plane of inclination 30° to the horizontal with a constant acceleration of 0.4 ms−2. What is the force of friction between the box and the inclined plane? [g = 10 ms−2]

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 13

ma = mg sin θ − f
or f = mg sinθ − ma

EmSAT Physics Mock Test- 3 - Question 14

A Gardner waters the plants by a pipe of diameter 1 mm. The water comes out at the rate of 10 cm3s−1. The reactionary force exerted on the hand of the Gardner is

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 14


So, we get 

EmSAT Physics Mock Test- 3 - Question 15

Which of the following statements is absolutely correct about mass?

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 15

Consider the situation in gravity free space.
From Newton's second law of motion,
F = ma
Here, F = Force on mass m
m = Mass of the object 
a = Acceleration of the object
Now, for a constant force,

From the above relation, we can say that, if the mass of a body increases, its acceleration decreases.

EmSAT Physics Mock Test- 3 - Question 16

Assertion: Tension in massless string may be different at different points.
Reason: Net force on a massless object is zero.

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 16


A: Friction exists in the pulley and the pulley rotates.
R: F = 0 × a = 0

EmSAT Physics Mock Test- 3 - Question 17

A block of mass 2 kg rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 17

The force which is trying to accelerate the block on the inclined plane in the downward direction is mg sinθ, while the force opposing this is the force of friction f. The force of friction f⁡ can take any value for 0 to μmg cosθ. Here



As the dragging force is 9.8 N, the force of friction will grow up to this value to stop the block from sliding.

EmSAT Physics Mock Test- 3 - Question 18

A pendulum consisting of a small heavy bob suspended from a rigid rod oscillates in a vertical plane as shown in the figure. When the bob passes through the position of equilibrium, the rod is subjected to a tension equal to twice the weight of the bob. Through what maximum angle α from the vertical will the pendulum be deflected? Disregard the weight of the rod and the resistance of the air.

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 18

Newton's second law to find the velocity when the bob passes through the position of equilibrium

From the equation of the law of conservation of energy,  it is possible to find the height from which the bob dropped ;

EmSAT Physics Mock Test- 3 - Question 19

A solid disc of mass M is just held in air horizontal by throwing 40 stones per sec vertically upwards to strike the disc each with a velocity 6 ms−1. If the mass of each stone is 0.05 kg 0.05 kg . What is the mass of the disc (g = 10 ms−2 )

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 19

Weight of the disc will be balanced by the force applied by the bullet on the disc in vertically upward direction
F = n m v

EmSAT Physics Mock Test- 3 - Question 20

A L shaped rod whose one end is horizontal and the other is vertical is rotating about a vertical axis as shown with the angular speed ω. The sleeve has mass m and friction coefficient between rod and sleeve is μ. The minimum angular speed ω for which sleeve cannot slip on rod -

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 20


EmSAT Physics Mock Test- 3 - Question 21

One quarter of the disc of mass mis removed. If r be the radius of the disc, the new moment of inertia is

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 21

Moment of inertia of whole disc about an axis through centre of disc and perpendicular to its plane is 
As one quarter of disc is removed, new mass,

EmSAT Physics Mock Test- 3 - Question 22

A spool is pulled horizontally by two equal and opposite forces as shown in Figure. Which of the following statements are correct?

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 22


net torque about bottommost point

then for accelaration of com ,
Friction force will act towards right.

EmSAT Physics Mock Test- 3 - Question 23

The moment of inertia about an axis of a body which is rotating with angular velocity 1 rads−1 is numerically equal to

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 23

Rotational kinetic energy,

ie, moment of inertia about an axis of a body is twice the rotational kinetic energy.

EmSAT Physics Mock Test- 3 - Question 24

A particle at rest is to reach an angular velocity of 36 rad s−1 in 6 s, with a constant angular acceleration. The total angle turned during this interval is

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 24

The angular displacement in a given time is,

EmSAT Physics Mock Test- 3 - Question 25

A fly wheel of radius R and of moment of inertia I can be rotated in vertical plane without friction about its natural axis. A light string is wound over the wheel and a body of weight W is suspended at the other end of string. The angular acceleration of wheel when suspended body is released is

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 25


If the angular acceleration of the wheel is α, acceleration of the body a = Rα.
Using torque equation
TR = Iα
And for the block,

By solving the above equations,

Therefore, the angular acceleration is less than 

EmSAT Physics Mock Test- 3 - Question 26

Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that 

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 26

At point A and C, electric field lines are dense and equally spaced, so EA = EC
While at B they are far apart.
∴ EA = E> EB

EmSAT Physics Mock Test- 3 - Question 27

When the separation between two charges is increased, the electric potential energy of the charges 

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 27

Potential  energy between two charges 
Now if r increases and q1 and q2 are of same sign then
 decrases. if q1 and q2 are of opposite  increases.
Therefore depending on signs of q1 and q may increase or decrease.

EmSAT Physics Mock Test- 3 - Question 28

An electric dipole is placed in a uniform electric field. The net electric force on the dipole 

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 28
As dipole is combination of equal positive and negative charges, when an electric field is generated in the region of the dipole, torque can act on the dipole, but there will be no force on the dipole.
EmSAT Physics Mock Test- 3 - Question 29
Electric charge are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10cm surrounding the total charge is 25V-m The flux over a concentric sphere of radius 20cm will be
EmSAT Physics Mock Test- 3 - Question 30

A charge q is placed at the centre of the open end of a cylindrical vessel in figure. The flux of the electric field through the surface of the vessel is 

Detailed Solution for EmSAT Physics Mock Test- 3 - Question 30

when a charge Q is placed at the centre of the open end of a cylindrical vessel then only half of the charge will contribute to the flux,because half will lie inside the surface and half will outside the surface so flux=Q/2ε0

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