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Full Test 3 - EKT CSE - AFCAT MCQ


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30 Questions MCQ Test IAF AFCAT Mock Test Series and EKT for (ME, EEE, CSE) 2025 - Full Test 3 - EKT CSE

Full Test 3 - EKT CSE for AFCAT 2024 is part of IAF AFCAT Mock Test Series and EKT for (ME, EEE, CSE) 2025 preparation. The Full Test 3 - EKT CSE questions and answers have been prepared according to the AFCAT exam syllabus.The Full Test 3 - EKT CSE MCQs are made for AFCAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Full Test 3 - EKT CSE below.
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Full Test 3 - EKT CSE - Question 1

In adiabatic process

Detailed Solution for Full Test 3 - EKT CSE - Question 1

During adiabatic process, there is no exchange of heat takes place between the system and surroundings. i.e. ΔQ = 0. Change in pressure (P), volume (V), temperature (T) takes place.

Full Test 3 - EKT CSE - Question 2

The resistance of a p - n junction in forward bias is –

Detailed Solution for Full Test 3 - EKT CSE - Question 2

A p - n junction diode allows electric current in one direction and blocks electric current in another direction. It allows electric current when it is forward biased and blocks electric current when it is reverse biased. An actual diode offers a very small resistance (ideally zero but actually very low) when forward biased and is called forward resistance. 

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Full Test 3 - EKT CSE - Question 3

A light ray passing through the glass from denser to rarer medium. Which of the following diagram is correct?

Detailed Solution for Full Test 3 - EKT CSE - Question 3

According to Snell’s Law

A light ray passing through glass from denser to rarer medium. The reflected ray in the rarer medium is made obtuse angle with respect to normal.

Full Test 3 - EKT CSE - Question 4

In an x-ray tube, the electron strikes the target with energy E and the characteristic wavelength is λ. If the energy of electron increased then then wavelength of the characteristic x-ray λ is

Detailed Solution for Full Test 3 - EKT CSE - Question 4

The scattering of a photon by an electron is called the Compton effect.

The scattered photon will have less energy (more wavelength) as compare to incident photon (less wavelength).

The energy lost by the photon is taken by an electron as kinetic energy.

There are three essential requirements for the production of X-rays.

(i) A source of the electron
(ii) An arrangement to accelerate the electrons
(iii) A target of a suitable material of high atomic weight and a high melting point on which these high-speed electrons strike.

In X-ray tube, when high speed electrons strikes the target, they penetrate the target. They loses their kinetic energy and comes to rest inside the metal. The electron before finally being stopped makes several collisions with the atoms in the target. At each collision X-rays may get formed.

When the electron loses whole of its energy in a single collision with the atom, an X-ray photon of maximum energy hνmax  is emitted.

If the energy of electron increased then then wavelength of the characteristic x-ray λ is reduced.

Full Test 3 - EKT CSE - Question 5

A ball thrown vertically upward with a speed of 20 m/sec from the top of a tower returns to the earth in 6 sec. The height of the tower (take g = 10 m/sec 2) –

Detailed Solution for Full Test 3 - EKT CSE - Question 5


Let after time t1 the ball reached to the topmost point where the velocity will be zero.

So the falling time of the ball is, t2 = 6 – 2 = 4 sec
Now, difference in distance travelled = height of the tower

⇒ height of tower 
Shortcut: Net displacement, s = - h (negative sign as the direction of motion is opposite to the displacement)

Full Test 3 - EKT CSE - Question 6

The mass of moon is 1% of the mass of earth. The ratio of gravitational pull of earth on moon and that of moon on earth will be

Detailed Solution for Full Test 3 - EKT CSE - Question 6

Gravitational force is an attractive force that acts between any two masses. Gravitational forces are equal in magnitude but opposite in direction.


So the ratio of gravitational pull of earth on moon and that of moon on earth will be 1:1.

Full Test 3 - EKT CSE - Question 7

Entropy change depends on ________.

Detailed Solution for Full Test 3 - EKT CSE - Question 7

Absolute entropy (S) or entropy is a measure of energy dispersion in a system.

Following are basic features of entropy:

  • Entropy transfer is associated with heat transfer (direction of flow of entropy is same as that of heat flow)
  • Entropy is proportional to mass flow in an open system
  • Entropy does not transfer with work

Entropy linked with energy

Full Test 3 - EKT CSE - Question 8

Which of the following statements is NOT correct about HTTP cookies?

Detailed Solution for Full Test 3 - EKT CSE - Question 8

An HTTP cookie is a small piece of data sent from a website and stored on the user's computer by the user's web browser while the user is browsing.
Cookies are just strings, not code.

Full Test 3 - EKT CSE - Question 9

A sorting technique is called stable if 

Full Test 3 - EKT CSE - Question 10

A Boolean function can be expressed

Detailed Solution for Full Test 3 - EKT CSE - Question 10

A Boolean function can be expressed as the product of maxterms (Which is POS form), eg. (A+B)(A'+B') or the sum of minterms (SOP) terms, eg. (AB + A'B')

Full Test 3 - EKT CSE - Question 11

What is dual of A+[B+(AC)]+D

Detailed Solution for Full Test 3 - EKT CSE - Question 11

To get the dual of the given expression change OR to AND operator and AND to OR operator.
A+[B+(AC)]+D = A[B(A+C)]D

Full Test 3 - EKT CSE - Question 12

The greatest negative number which can be stored in a computer that has 8 bit word length and uses 2’complement arithmetic is

Detailed Solution for Full Test 3 - EKT CSE - Question 12

The range of n bit word in 2’s complement representation is,
(−2n−1) to (2n−1−1)
(n-1) is used here because out of n bits 1 bit is used as sign bit 
There is one extra negative number because "0" has only single representation in 2's complement form
For 8 bit word the range will be 127 to -128. 

Full Test 3 - EKT CSE - Question 13

Gray code for number 7 is

Detailed Solution for Full Test 3 - EKT CSE - Question 13

Binary number for 7 is 0111
Gray code for 7 will be 0100

Full Test 3 - EKT CSE - Question 14

The hexadecimal representation of (657)8 is

Detailed Solution for Full Test 3 - EKT CSE - Question 14

(657)8 = (110101111)2 = (1AF)16 = 1AFH

Full Test 3 - EKT CSE - Question 15

If two numbers in excess-3 code are added and the result is less than 9, then to get equivalent binary

Detailed Solution for Full Test 3 - EKT CSE - Question 15

Let two binary numbers 0010 and 0011 equivalent excess-3 numbers are added

0101 + 0110 = (1011)2 = (11)10

To get equivalent binary number 0110 must subtracted from 1011. Hence the result is 0101.

Full Test 3 - EKT CSE - Question 16

Which of the following is error detecting code?

Detailed Solution for Full Test 3 - EKT CSE - Question 16

Hamming code is an error detecting code.

Full Test 3 - EKT CSE - Question 17

The address bus width of a memory of size 1024 × 8 bits is

Detailed Solution for Full Test 3 - EKT CSE - Question 17

There are 1024 memory location 1024 = 210
Hence, address bus width is 10 bits.
The data bus of 8 bits will be required to write/read data at each 8 bit memory location.

Full Test 3 - EKT CSE - Question 18

In 8085 B, C, D, E, H and L are called _______ 8 – bit registers.

Detailed Solution for Full Test 3 - EKT CSE - Question 18

In 8085 microprocessors, B, C, D, E, H and L are 8 bit registers and they are called as general purpose registers.

Full Test 3 - EKT CSE - Question 19

A J – K flip flop can be made from and S – R flip flop by using two additional

Detailed Solution for Full Test 3 - EKT CSE - Question 19

To realize a J-K flip flop from an S-R flip flop, we should have

So, we have to use two additional AND gates.

Full Test 3 - EKT CSE - Question 20

The system of linear equations
(4a – 1)x + y + z = 0
-y + z = 0
(4a – 1) z = 0
has a non-trivial solution, if a equals

Detailed Solution for Full Test 3 - EKT CSE - Question 20

The system of homogeneous linear equations has a non – trivial solution if

Full Test 3 - EKT CSE - Question 21

f ‘X’ is a continuous random variable, then the expected value is given by (where p(x) is the probability function)

Detailed Solution for Full Test 3 - EKT CSE - Question 21

Let X be a continuous random variable with range [a, b] and probability density function f(x). The expected value of X is defined by

The discrete formula says to take a weighted sum of the values xi of X, where the weights are the probabilities p(xi)

Full Test 3 - EKT CSE - Question 22

A car of mass 1000 kg travelling at 32 ms-1 dashes into the rear of a truck of mass 8000 kg moving in the same direction with a velocity of 4 ms-1. After the collision, the car bounces back with a velocity of 8 ms-1. What is the velocity of the truck after the impact?

Detailed Solution for Full Test 3 - EKT CSE - Question 22

for the car,

mcar = 1000 kg, ucar = 32 ms-1, vcar = -8 ms-1

for truck,

mtruck = 8000 kg, utruck = 4 ms-1, vtruck = ?

By conservation of linear momentum,

mcar.ucar + mtruck.utruck = mcar vcar + mtruck.vtruck

⇒ 1000 × 32 + 8000 × 4 = 1000 × (-8) + 8000 × vtruck

⇒ vtruck = 9 ms-1

Full Test 3 - EKT CSE - Question 23

If ω is a cube root of unity then the value of (1−ω8)(1−ω4)(1−ω2)(1−ω) is ___

Detailed Solution for Full Test 3 - EKT CSE - Question 23

We know that 1+ω+ω2=0 and ω3 =1 then
(1−ω8)(1−ω4)(1−ω2)(1−ω) = (1−ω2)(1−ω)(1−ω2)(1−ω)
= (1−ω2−ω+ω3)(1−ω2−ω+ω3)
= (2−(ω+ω2))(2−(ω+ω2))
= (2−(−1))(2−(−1)) = 9

Full Test 3 - EKT CSE - Question 24

A zener diode works on the principle of

Detailed Solution for Full Test 3 - EKT CSE - Question 24

A zener diode works based on the tunneling of charge carriers across the junction. A zener diode is a normal diode in the forward biased. It is in the reverse biased condition that the heavy doping causes a zener to behave differently than a normal diode.

Full Test 3 - EKT CSE - Question 25

Poisson’s ratio is defined as the ratio of:

Detailed Solution for Full Test 3 - EKT CSE - Question 25

The ratio of lateral strain to the longitudinal strain is a constant for a given material, when the material is stressed within the elastic limit. This ratio is known as Poisson’s ratio (μ).

Full Test 3 - EKT CSE - Question 26

Force of buoyancy on a floating body equals ________.

Detailed Solution for Full Test 3 - EKT CSE - Question 26

When a body is immersed in a fluid, an upward force is exerted by the fluid on the body.
This upward force is equal to the weight of the fluid displaced by the body and is called the force of buoyancy.

Full Test 3 - EKT CSE - Question 27

then the sum of matrix A and its Transpose is equal to unity matrix then the value of β is

Detailed Solution for Full Test 3 - EKT CSE - Question 27



Full Test 3 - EKT CSE - Question 28

The widely employed computer architecture for CAD/CAM application

Detailed Solution for Full Test 3 - EKT CSE - Question 28

Mainframe is a very large in size and expensive computer capable of supporting thousands of users simultaneously. Mainframe executes many programs concurrently.

Minicomputer is a midsize computer. A minicomputer is a multi-processing system capable of supporting up to 250 users simultaneously. A minicomputer is a computer of a size intermediate between a microcomputer and a mainframe.

microcomputer is a complete computer on a smaller scale and is generally a synonym for, personal computer or PC, a computer designed for an individual.

Workstation is a computer used for engineering applications such as Computer Aided Design/Computer Aided Manufacturing (CAD/CAM), desktop publishing, software development, and other types of applications, which require a moderate amount of computing power and relatively high quality graphics capabilities.

CAD is the use of computer technology for design and design documentation. CAD/CAM applications are used to both design a product and program manufacturing processes, specifically, CNC machining. CAM software uses the models and assemblies created in CAD software to generate tool paths that drive the machines that turn the designs into physical parts.

Full Test 3 - EKT CSE - Question 29

Hamming distance between 001111 and 010011 is

Detailed Solution for Full Test 3 - EKT CSE - Question 29

There is change at 3rd, 4th and 5th bit from LSB.

Full Test 3 - EKT CSE - Question 30

Which of the following is not a class A host address

Detailed Solution for Full Test 3 - EKT CSE - Question 30

Class A addresses range from 0.0.0.0 to 127.255.255.255. Class B addresses range from 128.0.0.0 to 191.255.255.255. Class C addresses range from 192.0.0.0 to 223.255.255.255.

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