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GATE Life Science Mock Test- 4 (Botany & Zoology) - GATE Life Sciences MCQ


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30 Questions MCQ Test GATE Life Sciences 2026 Mock Test Series - GATE Life Science Mock Test- 4 (Botany & Zoology)

GATE Life Science Mock Test- 4 (Botany & Zoology) for GATE Life Sciences 2025 is part of GATE Life Sciences 2026 Mock Test Series preparation. The GATE Life Science Mock Test- 4 (Botany & Zoology) questions and answers have been prepared according to the GATE Life Sciences exam syllabus.The GATE Life Science Mock Test- 4 (Botany & Zoology) MCQs are made for GATE Life Sciences 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Life Science Mock Test- 4 (Botany & Zoology) below.
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GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 1

The excitement generated by the soccer World Cup is ________ in comparison to how cricket _________ the country.

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 1

The word 'compared' conveys that both the fillers should be in contrast to each other. 'Lukewarm ' means 'unenthusiastic', and 'electrify' means 'cause a sudden sense of thrilling excitement'. Option 2 is the correct answer.
'Milder' needs comparative word 'than'. The words in 3 are not contrasting but of different context; hence unfit. 'Unusual' in 4 also does not fit in the context with the other blank word.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 2

Which of the following words is a synonym for the term REPEAL?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 2

'Repeal' means 'revoking or annul (a law or act of parliament)'. So, its synonyms are 'revoke, rescind and invalidate'. Option 4 is correct.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 3

A bacterial population p(t) of 1000, which is introduced into a nutrient medium, exhibits growth described by the equation p(t) = 1000  What is the maximum size of this bacterial population?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 3

Given relation p(t) = 1000 + 1000 t/(100 + t2)
Differentiating with respect to t
p'(t) = 1000[{(100 + t2) × 1 - t(0 + 2t)}/(100 + t2)2]
Put p'(t) = 0
1000[{(100 + t2) × 1 - t(0 + 2t)}/(100 + t2)2] = 0
100 + t2 - 2t2 = 0
t2 = 100
t = 10
As  It means t = 10 is the point of local maxima.
Hence,
Maximum size of this bacterial population = 1000 + (1000 × 10)/(100 + 100) = 1050

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 4

Which among the following possesses the greatest magnetic moment?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 4

Fe3+: 1s2, 2s2, 2p6, 3s2, 3p6, 3d5. As we see 3d orbital is exactly half filled, so all the five electrons in 3d orbital are unpaired. Greater the number of unpaired electrons, greater is the magnetic moment.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 5

Instructions: Examine the following chemical reaction.
CH3CHO HCN → CH3CH(OH)CN  CH3CH(OH)COOH
In this reaction, a chiral center is formed. The resulting acid would be

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 5

The carbonyl carbon being sp2-hybridised has a planar arrangement of three  bonds and the nucleophile (here CN-) can attack from both sides.
Hence, the product formed is a 50% - 50% mixture of both enantiomers i.e., a racemic mixture is obtained.
Therefore, 50% molecules (lactic acid) will have the D-configuration and 50% will have the L-configuration.

*Answer can only contain numeric values
GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 6

The depression of freezing point of water (in K) for 0.1 molal solutions of NaCl and Na2SO4 are ∆T1 and ∆T2, respectively. Assuming the solutions to be ideal, the ratio ∆T1⁄∆T2 is _____________ (rounded off to two decimal places).


GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 7

According to the molecular orbital theory, which of the following statements regarding N2, N2 , O2, and O2 is accurate?

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 8

In alkaline solutions, ammonia creates the complex ion [Cu(NH3)4]2 with copper ions, whereas this does not occur in acidic solutions. What is the underlying reason for this phenomenon?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 8

Ammonia is a base. In acidic medium, it reacts with protons to form ammonium ions. Thus, free ammonia molecules are not present. So they cannot coordinate with Cu(II) ion to form the [Cu(NH3)4]2+ complex ion.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 9

The tundra biome is defined by minimal precipitation; however, during its brief summer period, it becomes notably damp, featuring numerous swampy areas, ponds, and bogs. What accounts for this phenomenon?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 9

Tundra biome becomes little precipitation but at the time of short summer season, it is extremely moist with several swampy regions, ponds and bogs as water cannot absorb into the chilled ground. Tundra's ecology is regulated by cold climate and northern latitude. Long day length which follows short summer is a benefit to plants, which are capable of photosynthesising 24 hours a day in few places. It causes fast plant development.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 10

Which structures are associated with Fernandez-Moran subunits?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 10

Inner membrane of mitochondria possesses characteristic particles on its inner surface. These particles are known as Fernandez moran subunits or oxysomes. Each oxysome has a flat base, a globular head and a small stack (F2-F6 subunit). The base is buried into the inner membrane, while the head and stalk extend into the matrix.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 11

The development of a gametophyte directly from a sporophyte without the meiotic production of spores is referred to as

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 11

Aposporously formed gametophyte is usually diploid. Its diploid gametes bring about polyploidy and hence, development of new species. In seed plants, diploid nuclear cells give rise to diploid female gametophytes aposporously.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 12

Which of the following plant families is characterized by having indefinite stamens?

*Multiple options can be correct
GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 13

Which of the processes mentioned below does NOT produce carbon dioxide during fermentation?

*Answer can only contain numeric values
GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 14

The effectiveness of aerobic respiration is _____________. (Provide the answer in percentage.)


Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 14

One ATP yields about 34 KJ energy. The total energy obtained from 38 ATP molecule is 1292 KJ. The glucose molecules store energy of about 2870 KJ.
Efficiency: 1292/2870 × 100 = 45%

*Answer can only contain numeric values
GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 15

An mRNA transcript of a plant gene encoded by the nucleus, known as DSH20, contains an open reading frame (ORF) consisting of 1353 nucleotides. Given that the average molecular weight of an amino acid is 110 Dalton (Da), what is the calculated molecular weight of the DSH20 protein in kilodaltons (kDa), rounded to one decimal place? ____


GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 16

Which of the following assertions is accurate regarding autogenic succession?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 16

Community itself modifies its own environment and thus, causing its own replacement by new community.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 17

Which of the following assertions is accurate?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 17

During carbon dioxide fixation in C3 plants, only granal type of chloroplasts are involved.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 18

Which plant's leaves and flowers are the origin of the drug 'Stramonium', utilized in the management of asthma and parkinsonism?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 18

Datura stramonium is the plant of solanaceae family. It has medicinal importance here the leaves are exstipulate, alternate, entire, lobed and reticulate venetion.
The flowers are ebracteate, bisexual, pentamerous, actinomorphic and hypogynous.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 19

Groups I, II, and III denote enzyme, product resulting from the enzymatic reaction, and metabolic process, respectively.

The accurate pairing for Groups I, II, and III is

*Answer can only contain numeric values
GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 20

In garden pea plants, two distinct traits that influence pod characteristics are governed by genes located on chromosome 5. The trait for narrow pods is recessive compared to that for normal pods, while the trait for yellow pods is recessive to that for green pods. A true-breeding plant exhibiting narrow green pods was mated with a true-breeding plant that has normal yellow pods. The offspring from the F1 generation were subsequently test crossed with plants that possess narrow yellow pods. The results recorded were as follows:

144 narrow green pods, 150 normal yellow pods, 11 narrow yellow pods, 9 normal green pods

What is the distance between these two genes?


Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 20

Narrow green and yellow normal pods are parental type. After crossing these two, all F1 progenies are normal green pod type. Then, F1 is test crossed with homozygous recessive parent. This cross results in 11 narrow yellow and 9 normal green pods.
These are recombinant type. So, recombination frequency will be
= (number of recombinants / total number of offsprings) × 100
=[(11+9)/(144+150+11+9)] ×100
=(20/314) ×100=0.064×100=6.4%
We know that map distance between two genes = recombination frequency between those two genes
Therefore, distance between 2 genes = 6.4 mu.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 21

Which type of worm is responsible for causing enterobiasis?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 21

It is found in human caecum, colon or vermiform appendix

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 22

Which animals exhibit the presence of “Bottle cells” during the gastrulation phase of their development?

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 23

Organisms that derive energy from inorganic substances are referred to as what?

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 24

An mRNA encoding a secretory protein, when translated using free ribosomes in an in vitro environment, produced a 40 kDa protein. Conversely, the same mRNA translated via the rough endoplasmic reticulum yielded a 36 kDa protein. The difference in molecular weight between the two polypeptides can be attributed to the loss of a

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 24

The variation in molecular weight of 2 polypeptides is because of loss of a 4 kDa peptide from N-terminus.

*Multiple options can be correct
GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 25

Which of the following is/are the agents responsible for causing Filariasis?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 25

Lymphatic filariasis is caused by infection with parasites classified as nematodes (roundworms) of the family Filariodidea. There are 3 types of these thread-like filarial worms: Wuchereria bancrofti, which is responsible for 90% of the cases. Brugia malayi, which causes most of the remainder of the cases.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 26

If a person has been consuming a diet high in butter, red meat, and eggs for extended periods, which of the following health issues might he experience?

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 26

Hypercholesterolemia is a condition whereby an increased cholesterol in blood is caused due to high amount of fat in diet for a prolonged period. It leads to thickening and hardening of arterial wall, which in turn causes narrowing of arteries and thereby blood pressure is increased.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 27

Pair the immunological statements listed in Column I with their corresponding explanations in Column II.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 28

Identify the statement that is incorrect.

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 28

For precipitation to take place, both antigen and antibody should be multivalent. It is a false statement.

GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 29

Toll-like receptors (TLRs) are crucial in immune defense as they recognize

Detailed Solution for GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 29

Toll-like-receptors (TLRs) play the essential role in the immune defense by identifying Microbial components. TLRs are the group of proteins which play the key role in innate immune system and also the digestive system.

*Answer can only contain numeric values
GATE Life Science Mock Test- 4 (Botany & Zoology) - Question 30

The molecular weight of a double-stranded DNA segment found in mitochondria is 7.92 × 108 g mol-1. Each pair of nucleotides adds 0.34 nm to the DNA's length, and the average molecular weight of a nucleotide is 330 g mol-1. How many protein molecules, each composed of 200 amino acids, are encoded by this mitochondrial DNA?


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