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Gate Practice Test: Electrical Engineering(EE)- 3 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - Gate Practice Test: Electrical Engineering(EE)- 3

Gate Practice Test: Electrical Engineering(EE)- 3 for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The Gate Practice Test: Electrical Engineering(EE)- 3 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Gate Practice Test: Electrical Engineering(EE)- 3 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Gate Practice Test: Electrical Engineering(EE)- 3 below.
Solutions of Gate Practice Test: Electrical Engineering(EE)- 3 questions in English are available as part of our GATE Electrical Engineering (EE) Mock Test Series 2025 for Electrical Engineering (EE) & Gate Practice Test: Electrical Engineering(EE)- 3 solutions in Hindi for GATE Electrical Engineering (EE) Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Gate Practice Test: Electrical Engineering(EE)- 3 | 65 questions in 180 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study GATE Electrical Engineering (EE) Mock Test Series 2025 for Electrical Engineering (EE) Exam | Download free PDF with solutions
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 1

“Wanted a two bedroom flat in the court area for immediate possession” - An Advertisement.
Assumptions:
I. Flats are available in the court area
II. Some people will respond to the advertisement
III. It is a practice to give such an advertisement

Gate Practice Test: Electrical Engineering(EE)- 3 - Question 2

Which of the following is most similar in meaning to the given word
DIRE

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Gate Practice Test: Electrical Engineering(EE)- 3 - Question 3

In the question given below, the sentence has a part printed in bold. That part may contain a grammatical error. Replace that part with four choices given below:
The famous playwright has been in the sick bed from the last one week.

Gate Practice Test: Electrical Engineering(EE)- 3 - Question 4
He always _________ you in his letters
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 5
His health ____________ under the pressure of work.
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 6
A, B and C shoots to hit a target. If A hits the target 4 times in 5 trials, B hits in 3 times in 4 trials and C hits it 2 times in 3 trials. What is the probability that the target is hit by at least 2 persons?
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 6
Probability that A hits the target = 4/5
Probability that B hits the target = 3/4
Probability that C hits the target = 2/3
P (at least 2) = P(2) + P(3)
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 7
Two liquids are mixed in the ratio 4:3 and the mixture is sold at Rs 20 with a profit of % .If the first liquid is costlier than the second by Rs 7. Find the sum of costs of both the liquids.
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 7
Profit = %

Cost of 1 unit of liquid 1 = x+7
Cost of 1 unit of liquid 2 = x
(x+7)×4+3x = 15(4+3)
x = 11
x+7 = 18
Total value of the prices = 11+18 = 29
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 8
Henry and Ford worked together to complete a task in 10 days. Had Henry worked with half of his efficiency and Ford at 5 times of his efficiency it would have taken them to finish the job in 50% of the scheduled time. In how many days can Ford complete the job working alone?
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 8
Let henry’s one day work be x
Let ford’s one day work be y

Solving 2 equations we get, y = 1/30
Hence, Ford can complete the job working alone in 30 days
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 9
A new flag is to be designed with six vertical stripes using some or all of the colours- yellow, green, blue and red. Then the number of ways this can be done such that no two adjacent stripes have the same colour out is:
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 9
There are 6 stripes. The stripe can be coloured in 4ways, in 3, in 3 and so on.
Thus, total number of ways = 4×3×3×3×3×3=12×81
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 10
Find the value of
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 10

y(y-3) = 0
y = 3
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 11
In the given circuit determine the value of current source
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 11
V = 4i
Here, 
2i = 4–v
2i = 4 – 4i
6i = 4
i = 2/3
So, v = 8/3
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 12
If power of a signal x (t) is 6 units, then determine the power of g(t), where g (t) is given as,
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 12
Power of g(t),

= 48 + 108
= 156 units
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 13
Which one of the following is non-periodic?
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 13
For a signal to be periodic, the signal must be define from
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 14

The ROC of z-transform of the discrete time sequence x(n) =

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 14

One part of the equation is the right sided signal and other part is the left sided signal hence the ROC of the system will be 1/3>|z|<1/2.

Gate Practice Test: Electrical Engineering(EE)- 3 - Question 15
A 3 phase voltage source-inverter is operated in mode of conduction. Which of the following statement is true?
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 16
A dc shut generator has full load voltage regulation of 10% at rated speed of 1000 rpm. If it is now driven at 1250 rpm, then its voltage regulation at full load is
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 16

Gate Practice Test: Electrical Engineering(EE)- 3 - Question 17
The signal flow graph of a closed loop system is shown in the figure, where represents the disturbance in the forward path. The effect of the disturbance can be reduced by
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 17
With feedback, the output due to disturbance

Without feedback output due to disturbance is

By comparing above two equations, feedback decreases the effect of noise.If Increases, disturbance decreases, But gain also decreases. This is not desirable.
If increases, disturbance increases, since noise links with 
if increases, disturbance decreases, and gain also decreases. This is desirable.
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 18
The system having characteristic equation is to be used as an oscillator. What is the value of frequency of oscillation?
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 18
Characteristic equation

Gate Practice Test: Electrical Engineering(EE)- 3 - Question 19
Piecewise linear model of a diode shown in the figure

Determine the value of in the given circuit
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 19
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 20
The transfer function of a system is The output of the system for the input x (t) = 4u(t) is y (t). The value of y(t) is
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 20

Since one root is lies on the right half of s-plane, so output is unbounded. Therefore y(t) =
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 21
If an energy meter disc makes 10 resolutions in 100 sec when load of 450W is connected to it. Meter constant in revolution per kwH is?
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 21
10 revolution --> 100 sec
P = 450 w = 4.5 kW
Energy consumed in time
T = 100 sec =1/36 hr

Number of revolution = 10

1 kwH = 800 revolution
Meter constant = 800 revolution /kwH
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 22
For the circuit shown in the figure assume ideal diodes with forward resistance and forward voltage drop are zero. The current through diode
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 22
In the given circuit both the diodes cannot be ON simultaneously.
In the above circuit only is ON.
So current through diode is zero.
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 23
Determine the value of in the given circuit given = 100
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 23

Gate Practice Test: Electrical Engineering(EE)- 3 - Question 24
Determine the value of in the circuit, assume op-amp is ideal.
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 24

= 11–10
= 1 volt
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 25
Assume the op-amp is ideal the transfer characteristics of the circuit is
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 25
In the given circuit for positive half cycle of input voltage is at i.e.
–10V and diode is off,and during negative half cycle is at i.e. +10V, so diode is ON and,virtual short-cirucit exist.

So transfer characteristic

Gate Practice Test: Electrical Engineering(EE)- 3 - Question 26
If cross-sectional area of base-emitter junction of transistor is 2 times of transistor then determine the value of Assume of both the transistors are very large
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 26


Gate Practice Test: Electrical Engineering(EE)- 3 - Question 27
A 90 MVA, 11 KV water wheel generator has an inertia constant H = 3, the stored energy in the rotor at synchronous speed is
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 27
Rating of the machine = 90 MVA, Inertia constant (H) = 3 MJ/MVA

K.E. = 270 MJ
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 28
The minimal some of products form of is
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 28

The K-map of the above function

So, the required minimal SoP of f is
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 29
A single phase load of 100 KVA is connected across line B & C of a 3 phase supply of 3.3kV. Determine positive sequence symmetrical component of line current
Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 3 - Question 29
Gate Practice Test: Electrical Engineering(EE)- 3 - Question 30

 

 

If two induction motors A and B are identical except that the airgap of motor 'A' is 50% greater than that of motor 'B' then

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