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Gate Practice Test: Electrical Engineering(EE)- 9 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - Gate Practice Test: Electrical Engineering(EE)- 9

Gate Practice Test: Electrical Engineering(EE)- 9 for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The Gate Practice Test: Electrical Engineering(EE)- 9 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Gate Practice Test: Electrical Engineering(EE)- 9 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Gate Practice Test: Electrical Engineering(EE)- 9 below.
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Gate Practice Test: Electrical Engineering(EE)- 9 - Question 1

Choose the most appropriate word from the options given below to complete the following sentence.
Q. ________ is the key to their happiness; they are satisfied with what they have.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 1

The sentence already mentions a trait that they are satisfied with what they have thus it becomes easy for us to choose the correct word. The meanings of the words are:
Contentment → being satisfied with what one has
Ambition →  a strong desire to do or achieve something.
Perseverance →   persistence in doing something despite difficulty or delay in achieving success.
Hunger →  a feeling of discomfort or weakness caused by lack of food, coupled with the desire to eat.
Thus, contentment is the correct answer.

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 2

Choose the most appropriate words from the options given below to fill in the blanks.
Q. She was ______ to travel abroad and _____ in the field of commerce as per her wishes.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 2

The sentence mentions a person doing something as per her wishes thus the first word must be a positive reaction. 'Restive' which means 'restless' and 'jinxed' which means 'cursed' are incorrect here. Between options 1 and 3,the word 'elated' which means 'too happy' and the word 'venture' which means 'undertake a risky or daring journey or course of action' fit here correctly. The word 'cease' means 'stop' and does not convey a proper meaning. Thus option 3 is the correct answer.

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Gate Practice Test: Electrical Engineering(EE)- 9 - Question 3

The Headmaster ___________ to speak to you.
Which of the following options is correct to complete the above sentence?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 3

The correct tense that fits here is simple present and the subject being singular, the verb should be in the correct form too. Thus 'wants' is the correct answer. The other options are incorrect as:
Is wanting ⇒ it is in present continuous tense which is used to denote an activity which is continuing
Want ⇒ subject is singular thus the verb cannot be in plural form
Was wanting ⇒ it is in past continuous tense which is used to denote an activity which was continuing in the past
Thus option 2 is the correct answer.

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 4

The graph shows cumulative frequency % of research scholars and the number of papers published by them. Which of the following statements is true?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 4

In this problem, cumulative frequency is given, so converting into frequency

From the table, it is clear that option b, i.e.
60% of the scholars published at least 2 papers is correct.

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 5

If |-2X + 9| = 3 then the possible value of |-X| - X2 would be:

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 5


So -30 will be correct as per provided options.

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 6

A growing world population has caused growing concerns about increasing famine. The population in 2000 was 6 billion. Ten years later the population was 7 billion. There were also more people affected by famines in 2010 than in 2000. Furthermore, in each year from 2000 to 2010, when the world's population increased, so did the number of those affected by famine.
Based on the information given, which of the following is true?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 6

The number affected by famine always increases with the population. Therefore, if the population increased in 2005, then the number of those affected by famine also increased.
If there was an increase in 2005, there must have been more people affected in that year than the previous year of 2004.
The available information does not allow us to draw any of the other inferences.
The number of those affected by famine could increase without a corresponding percentage of the population increase.
Neither can we draw inferences about any particular year between 2000 and 2010.
Note:
Option 2 cannot be correct because  consider a case where in 2000 the population is 100 , and people affected are 50
in 2001 the population grew to say 200, and people affected is 100
So in Both cases the percentage of people affected is 50% but the number of people affected grew.

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 7

A tunnel of length 360 m is to be constructed. As per the plan, the team has to complete the tunnelling within a specified period of time. For the first four days, the tunnelling was done according to the plan. However, it was found that the resources were being underutilized. It was then decided that the rate of tunnelling should be increased and then they started tunnelling 15 m more than their everyday plan. Therefore, a day before the planned date they had tunnelled to a length of 380 m. How many meters of tunnelling was planned for each day?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 7

Let, the per day tunnelling plan was ‘x’ meter and the tunnelling of 360 m was to be completed in ‘y’ day.
Therefore, xy = 360----(i)
Now, as per plan tunneling was done for four days and then rate of tunnelling was increased to
(x + 15) for (y - 4) days. One day before the planned date they have tunnelled 380 m.
∴ Number of days when the tunnelling was done at increased rate is
= (y – 4 - 1) = (y - 5) days
According to the statement given the following situations can be inferred
∴ 4x + (y - 5) (x + 15) = 380
⇒ 4x + xy + 15y – 5x – 75 = 380
⇒ 4x + 15y – 5x = 380 + 75 – xy
⇒ 15y – x = 380 + 75 – 360
⇒ 15y – x = 95     ----(ii)
Putting y value from eq (i) in eq (ii) we get

⇒ x2 + 95x – 5400 = 0
On solving the above quadratic equation, we get
⇒ x = 40 m

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 8

Consider a random walk on an infinite two-dimensional triangular lattice, a part of which is shown in the figure below.

If the probabilities of moving to any of the nearest neighbour sites are equal. What is the probability that the walker returns to the starting position at the end of exactly three steps?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 8


A person can take 1st step in any direction independently
Suppose he moves to A
Now to return to O ( initial point) in 2 steps he can move in 2 directions. Either B or f
Thus probability he will move to either B or F will be 
Suppose he moves to B
Now to return back to O
he has only 1 option
⇒ to move in BO
Probability he will move in BO direction 
Total probability he will return

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 9

A paper sheet is in the shape of a right angle triangle and cut along a line parallel to hypotenuse leaving a smaller triangle. There was 25% reduction in the length of the hypotenuse of the triangle. If area of triangle initially was 28 cm2 then area of smaller triangle will be ______ cm2.


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 9


Let PQR is the initial triangle and SQT is the final triangle.
ΔPQR is similar to ΔSQT
∵ ST = 0.75 PR
∴ SQ = 0.75 PQ
And QT = 0.75 QR
Initial Area = 
Final Area = 


= (0.75)2 × 28 = 15.75 cm2

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 10

If x+ x − 1 = 0 what is the value of 

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 10

x2 + x – 1 = 0
x2 + x = 1
x(x + 1) = 1

Again squaring 

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 11

Which of the following Boolean expression represents the given logic circuit?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 11


 

Y = AB + A(B + C) + B(B + C)
= AB + AB + AC + BB + BC
= AB + AC + B + BC
= AB + AC + B(1 + C)
= AB + AC + B
= B(A + 1) + AC
= B + AC

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 12

When a 2300/230 V, 50 kVA, 50 Hz transformer is connected as an auto transformer to supply a 2300 V circuit form 2530 V source, the kVA rating of the auto – transformer will be _______(in kVA)


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 12

kVA rating of transformer = 50 kVA
Auto transformer rating = 2300 / 2530

kVA rating of auto transformer 

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 13

Transformer connections of two three phase transformers are given in the options. Which of the pair is not suitable for the parallel operation.

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 13

For the parallel operation, phase displacement angle between secondaries of both transformers must be zero. That means both the transformers must belong to same phase group.

In the given options,
Y/Zig Zag Y and Y/Y belongs to different phasor groups. Hence this pair is not suitable for parallel operation.

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 14

An 8 pole 3ϕ induction motor has an equivalent rotor resistance of 0.07 Ω/Phase. If its stalling speed is 630 RMP, how much resistance must be added per phase to obtain maximum torque at starting? Ignore magnetizing current.


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 14


X2 = 0.4375 Ω
Sstarting 
Rext = 0.3675 Ω

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 15

For a system to be minimum phase

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 15

The Basic difinition of minimum phase system in Z-domain is it should have all poles and zerores inside the unit circle.
H(z) stable and causal:
All poles of H(z) are inside the unit circle.

All poles of  i.e. zeroes of H(z) are inside unit circle.

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 16

Let x[n] = e-2n u[n] be the input to a system. Which of the following impulse responses gives the bounded output for this input?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 16

A system is said to be BIBO stable if it’s impulse response is absolutely summable,

Out of all the responses only  is absolutely summable.

Is not absolutely summable it is divergent.

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 17

In a 12 phase full wave rectifier if source frequency is 30 Hz, then the ripple frequency will be_____Hz


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 17

We know that 
Ripple frequency = 2nf = 2 × 12 × 30 = 720 Hz 

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 18

A 3 phase bridge inverter delivers power to a resistive load 400 V DC source. For a start connected load of 10 Ω/phase. Determine load power (in watt) 1200 conduction mode.


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 18

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 19

The admittance locus of the circuit shown in figure is

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 19


Gate Practice Test: Electrical Engineering(EE)- 9 - Question 20

While testing a coil having a resistance of 1 Ω, resonance occurred when the oscillator frequency was 10 MHz and the variable capacitor was set at  pF. What is effective value of the coil?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 20

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 21

The Bode plot of a system is shown in figure below the magnitude (in dB) at ω = 10 rad/sec is___________ (Assume initial low frequency is 0.5 rad/sec)


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 21

Magnitude at 10 rad/sec is same as magnitude at 2 rad/sec

6 dB/octave = 20 dB/decade
y = 24.04 dB

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 22

The frequency at which polar plot of   intersects the -1800 phase line is ______ radian/sec


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 22

For intersection with -1800 axis
∠GH = -1800

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 23

Power in a three-phase star connected balanced inductive load is measure by two wattmeter method. The phase voltage and phase current are 200 V and 10 A, respectively. The power-factor of load is 0.5. The readings P1 and P2 of the two wattmeter’s are

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 23

Given that,
Phase voltage (Vph) = 200 V
Phase current (Iph) = 10 A
Power factor = cos ϕ = 0.5
⇒ ϕ = cos-1 (0.5) = 600
In two wattmeter method,
W1 = VLIL cos (30 + ϕ)
And
W2 = VLIL cos (30 – ϕ)

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 24

A galvanometer with a full scale current of 2 A has internal resistance of 500 Ω. The multiplying power of 20 Ω shunt with this galvanometer is –


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 24

Given that, I = 2 A
Rm = 500 Ω
Rsh = 20 Ω
We know that,

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 25

A certain 8-bit DAC has a full scale output of 2mA and full scale error of ± 0.5 % full scale reading. The maximum possible output current for an input of 10000000 is__________ μA.


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 25

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 26

What is the output voltage Vo of the given circuit.


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 26


Voltage at A point

By using virtual short circuit condition
VA = VB = 8V
Apply KCL at node B

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 27

Frequency compensation is used in op-amp to increase its

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 27

Frequency compensation is used in operational amplifiers to improve the stability of the op-amp over the input signal frequency range.

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 28

In a short transmission line, if the impedance of the line is (0.01 + j0.15) per unit when the load current is 1.0 p.u. at 0.8 lag power factor and the receiving end voltage Vr = 1.0 p.u, what is the regulation of the line?

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 28

Given that, impedance = (0.01 + j 0.15) p.u.
Resistance (R) = 0.01 p.u.
Reactance (X) = 0.15 p.u.
Voltage regulation
% V.R = [R cos ϕr + X sin ϕr] × 100
= [0.01 × 0.8 + 0.15 × 0.06] × 100
= 0.098 × 100 = 9.8%

*Answer can only contain numeric values
Gate Practice Test: Electrical Engineering(EE)- 9 - Question 29

A three phase transmission line has a self-reactance of 0.2 pu and mutual reactance of 0.05 pu. The sum of positive sequence reactance, negative sequence reactance and zero sequence reactance is __ (in pu)


Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 29

Given that, Xs = 0.2 pu
Xm = 0.05 pu
X1eq = Xs - Xm = 0.2 – 0.05 = 0.15 pu
X2eq = Xs - Xm = 0.2 – 0.05 = 0.15 pu
X0eq = Xs + 2X m = 0.2 + 2 (0.05) = 0.3 pu
X1eq + X0eq + X2eq = 0.6 pu

Gate Practice Test: Electrical Engineering(EE)- 9 - Question 30

In a 30 bus lower system networks, there are 3 voltage controlled buses. The size of Jacobian matrix useful for power system analysis will be

Detailed Solution for Gate Practice Test: Electrical Engineering(EE)- 9 - Question 30

The size of Jacobian matrix = (2n - 2 - m) × (2n - 2 - m)
Where n is number of buses
M is number of voltage controlled buses
Size of Jacobian matrix = (2 (30) - 2 - 3) × (2 (30) - 2 - 3)
= 55 × 55

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