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HPCL Civil Engineer Mock Test - 2 - HPSC (Haryana) MCQ


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30 Questions MCQ Test HPCL Civil Engineer Mock Test Series 2024 - HPCL Civil Engineer Mock Test - 2

HPCL Civil Engineer Mock Test - 2 for HPSC (Haryana) 2024 is part of HPCL Civil Engineer Mock Test Series 2024 preparation. The HPCL Civil Engineer Mock Test - 2 questions and answers have been prepared according to the HPSC (Haryana) exam syllabus.The HPCL Civil Engineer Mock Test - 2 MCQs are made for HPSC (Haryana) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPCL Civil Engineer Mock Test - 2 below.
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HPCL Civil Engineer Mock Test - 2 - Question 1

Payal made a bathing vessel for birds by placing a hemisphere on the upper end of a cylinder. The radius of the top of the circular shape is 20 CM and the height of the cylinder is 160 CM. Find the total curved area of the bird bath bowl.

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 1

Given :

Radius of the top of the circular shape (r) = 20 CM.

Height of the cylinder (h) = 160 CM.

Formula used:

The outer surface area of the hemisphere = 2πr2

The curved surface area of the cylinder = 2πrh

where, r = Radius, and h = Height

Calculation:

The total surface area of ​​the bird bath pot equal to

Curved surface area of the cylinder + Inner surface area of the hemisphere

The curved surface area of ​​the bird bath pot

⇒ 2πr2 + 2πrh

⇒ 2 × π × 202 + 2π × 20 × 160

⇒ 6400π + 800π = 7200π cm2

∴ The correct answer is 7200 π cm2.

HPCL Civil Engineer Mock Test - 2 - Question 2

A man lends out an amount of Rs. 25,000 into two parts. The first part of the money is lent out at 8% simple interest and the second part of the money is lent out at 8.5% simple interest. If total annual income of the man is Rs. 2031.25, then find how much money is lent out at the rate of 8.5%?

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 2

Calculation:

Total principal = 25000 and total interest receive = 2031.25

So, all-over interest rate = 2031.25/25000 × 100 = 8.125%

So, the 1st part and 2nd part of the principal were lent out in the ratio 3 : 1

Now, the 2nd part of the money is = 25000 × = Rs. 6250

∴ The correct answer is Rs. 6,250

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HPCL Civil Engineer Mock Test - 2 - Question 3

A bag contains 4 green, 5 blue, 2 red and 3 yellow balls. If eight balls are drawn at random, what is the probability that there are equal number of balls of each colour?

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 3

Given:

A bag contains 4 green, 5 blue, 2 red and 3 yellow balls.

Used Concept:

This problem is related to probability. The probability of an event is calculated as the number of favourable outcomes divided by the total number of possible outcomes.

Calculation:

Total number of balls = 4 green + 5 blue + 2 red + 3 yellow = 14 balls

Total number of ways for selecting 8 balls = 14C8

= 3003

Total no. of ways of selcting 8 balls such that equal no. of balls of each color occur = 4C2 × 5C2 × 2C2 × 3C2

× × ×

⇒ 6 × 10 × 1 × 3 = 180

So, Probablity of picking equal no. of balls of each color = 180/3003

⇒ 60/1001

∴ Probablity of picking equal no. of balls of each color is 60/1001.

HPCL Civil Engineer Mock Test - 2 - Question 4
If 2x + 3y = and xy = then the value of 8x3 + 27y3 is?
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 4

Given:

2x + 3y = and xy =

Formula used:

a3 + b3 = (a + b)3 - 3ab(a + b)

Calculation:

Let, a = 2x and b = 3y.

a3 + b3 = (a + b)3 - 3ab(a + b)

8x3 + 27y3 = (2x)3 + (3y)3

⇒ (2x + 3y)3 – 3 × 2x × 3y(2x + 3y)

⇒ (11/2)3 – 18 × (5/6) × (11/2)

(1331/8) - (660/8) =

8x3 + 27y3 is .

HPCL Civil Engineer Mock Test - 2 - Question 5

A, B, C, D, E, F, and G are 7 friends sitting in a single row facing North.

1. D is to the immediate right of C.

2. E and A are neighbors of F.

3. B is to the immediate left of C and in second place from the leftmost end.

4. A is at the rightmost end.

What is the position of E?

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 5

Given: A, B, C, D, E, F, and G are 7 friends sitting in a single row facing North.

1) B is to the immediate left of C and in second place from the leftmost end.

2) A is at the rightmost end.

3) E and A are neighbors of F.

4) D is to the immediate right of C.

So, G will sit in the remaining place.

Here, the position of E is 5th​ from left.

Hence, the correct answer is "Option 2".

HPCL Civil Engineer Mock Test - 2 - Question 6

Select the most appropriate option that can substitute the underlined words in the given sentence.

The new restaurant is more better than the old one.

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 6
The correct answer is: Better.

Key Points
  • The use of "more" before "better" is incorrect as "better" is already a comparative form of the adjective "good".
  • The correct comparative form of "good" is "better", and the superlative form is "the best".
  • Therefore, the correct sentence should be "The new restaurant is better than the old one."

Hence, option 2 is the correct answer.

Important Points

  • The comparative and superlative forms of adjectives are used to compare and describe different degrees of a particular quality.
  • Comparative Form:

    • Usage: The comparative form is used when you are comparing two things or two groups.

    • Formation: Most adjectives form the comparative by adding "-er" (e.g., faster, taller) or by using "more" before the adjective (e.g., more beautiful, more interesting).

    • Example: The cat is faster than the dog.

  • Superlative Form:

    • Usage: The superlative form is used when you are comparing more than two things or groups, indicating the highest degree of quality.

    • Formation: Most adjectives form the superlative by adding "-est" (e.g., fastest, tallest) or by using "most" before the adjective (e.g., most beautiful, most interesting).

    • Example: The cheetah is the fastest land animal.

HPCL Civil Engineer Mock Test - 2 - Question 7

Select the number that will replace the question mark (?) in the following series.

DZP, SCG, JFV, YIM, PLB, ?

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 7

The pattern here follows is:

Hence, the correct answer is "EOS".

HPCL Civil Engineer Mock Test - 2 - Question 8

The following question consists of a statement followed by two arguments I and II. You have to decide which of the arguments is a STRONG argument:

Statement: Should new big industries be started in Mumbai?

Arguments:

I. Yes. It will create job opportunities.

II. No. it will further add to the pollution of the city.

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 8

Statement: Should new big industries be started in Mumbai?

Now,

Arguments:

I. Yes. It will create job opportunities.True (starting new big industries in Mumbai, citing the potential for job creation as a positive factor. Indeed, the establishment of large industrial units can generate employment opportunities for the local population and contribute to economic growth).

II. No. it will further add to the pollution of the cityFalse (Stringent environmental regulations and effective implementation of pollution control measures can mitigate the negative impacts of industrial activities on the city's environment).

So, Only argument I is strong.

Hence, the correcet answer is "Option 3".

HPCL Civil Engineer Mock Test - 2 - Question 9
A boy bought 50 chocolates for Rs. 1000. If the average price of 30 chocolates is Rs. 25, then what is the average price (in Rs.) of the remaining chocolates?
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 9

Given:

CP of 50 chocolates = 1000

Calculation:

Average Price of remaining chocolates = (Remaining Price)/(Remaining chocolate)

∴ Average Price of remaining chocolates = (1000 - 30 × 25)/(50 - 30) = 250/20 = 12.5
HPCL Civil Engineer Mock Test - 2 - Question 10
The compound interest (compounding half yearly) received on Rs. 10000 for 2 years is Rs. 10736. What is the rate of interest per annum?
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 10

Given:

Compound interest = Rs. 10736

Principal = Rs. 10000

Time = 2 years

Formula used:

Amount when interest is compounded half-yearly = P[1 + (R/200)]2T

P = Principal

R = Rate of interest

T = Time taken

Calculation:

According to the question,

Amount = 10000 + 10736 = 20736

20736 = 10000[1 + (R/200)]4

⇒ 20736/10000 = [1 + (R/200)]4

⇒ (12/10) - 1 = R/200

⇒ R = 40

∴ Rate of interest = 40%

HPCL Civil Engineer Mock Test - 2 - Question 11

The average weight of 6 members of a family is 25 kg, If one family member whose weight is 40 kg leave the group, then find the new average weight of remaining family members.

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 11

The average weight of n members of a family is w kg, If one family member whose weight is W kg leaves the group,

then the new average weight of remaining family members = y

So,

W = {n × (w - y)} + y

According to the question,

⇒ 40 = 6 × (25 - y) + y

⇒ 40 = 150 - 6y + y

⇒ 40 = 150 - 5y

⇒ 5y = 150 - 40

⇒ 5y = 110

⇒ y = 22 kg

Therefore, '22 kg' is the required answer.

HPCL Civil Engineer Mock Test - 2 - Question 12
Radhika borrows Rs. 20000 from a bank at the rate of 8% per annum on simple interest, if she has to pay Rs. 23200 to the bank. What is the time for which Radhika has borrowed money from the bank?
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 12

Given:

Principal = Rs. 20000

Rate = 8% per annum

Amount = Rs. 23200

Formula used:

Interest = (P × R × T)/100

SI = Amount - Principal

Where, P = Principal, R = Rate of interest, T = Time

Calculation:

Let the time be T years

SI = Amount - Principal

⇒ Rs. 23200 - Rs. 20000 = Rs. 3200

According to the question,

3200 = (20000 × 8 × T)/100

⇒ T = (3200 × 100)/160000

⇒ T = 2 years

∴ The time for which Radhika borrowed money is 2 years

HPCL Civil Engineer Mock Test - 2 - Question 13

In this question, three statements are given, followed by two conclusions numbered I and II. Assuming the statements to be true, even if they seem to be at variance with commonly known facts, decide which of the conclusion(s) logically follows/follow from the statements.

Statements:

All cricketers are wealthy.

Some wealthy are Indians.

All Indians are honest.

Conclusions:

I. All Indians are cricketers.

II. Some cricketers are honest.

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 13

Statements:

All cricketers are wealthy.

Some wealthy are Indians.

All Indians are honest.

The Venn diagram as per the given statements:

Conclusions:

I. All Indians are cricketers. → Does not follow (Because there is no definite relation given between Indians and cricketers, so it can be possible only but not definitely true)

II. Some cricketers are honest. → Does not follow (Because there is no definite relation given between cricketers and honest, so it can be possible only but not definitely true)

Hence, the correct answer is "Neither conclusions I nor II follow".

HPCL Civil Engineer Mock Test - 2 - Question 14

In the following figure, triangle represents personal loan, circle represents private bank, hexagon represents government bank, rectangle represents education loan and square represents housing loan.

What does letter ‘L’ represents?

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 14

As per the given information,

The shaded-by part i.e. L represents → Private banks which provide education loan and personal loan but not housing loan

Hence, the correct answer is "option (1)".

HPCL Civil Engineer Mock Test - 2 - Question 15

What will be the value of maximum shear force for the given beam in figure below?

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 15

Maximum shear force for the given beam in the figure below:

Now apply equilibrium condition in the vertical direction

RA + RB = P

RA + RB = 27

So, the Moment equilibrium condition at point A

RB = 18 kN

Hence, RA = 27 - 18 = 9 kN

Shear force diagram for given beam:

The maximum shear force for the given beam is "18 kN".

HPCL Civil Engineer Mock Test - 2 - Question 16

Arrange the stages of construction of highway projects in the correct sequence:

1. Cleaning site of work or construction

2. Construction of drainage work such as culverts etc.

3. Earthwork

4. Construction of road and its shoulders

Select the correct answer using the code given below:

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 16

The stages of construction of highway projects are as follows:

1. Cleaning site of work or construction

  • A good construction practice to follow cutting, removing, and disposing of all unsuitable materials such as trees, bushes, shrubs, stumps, roots, grass, weeds, and top organic soils up to a minimum depth of 150mm from the road construction area known as site clearance-clearing and grubbing.

2. Earthwork

  • Earthwork is, in a few words, the process of moving earth from those areas that are too high, with respect to the road grades, to those areas that are too low, and is a crucial aspect of the overall construction problem.

3. Construction of drainage work such as culverts

  • The primary purpose of a road drainage system is to remove the water from the road and its surroundings. The road drainage system consists of two parts: dewatering and drainage. “Dewatering” means the removal of rainwater from the surface of the road. “Drainage” on the other hand covers all the different infrastructural elements to keep the road structure dry.

4. Construction of the road and its shoulders

  • The shoulder is a strip of pavement outside an outer lane; it is provided for emergency use by traffic and to protect the pavement edges from traffic damage.
HPCL Civil Engineer Mock Test - 2 - Question 17
A thin-walled spherical shell is subjected to an internal pressure of 10 MPa. The shell has a uniform wall thickness of 25 mm and a diameter of 500 mm. Take E = 20 GPa and μ = 0.3.
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 17

Concept:

Thin spherical walls.

The hoop stress/longitudinal stress of a spherical shell is given by

The hoop strain / longitudinal strain of a spherical shell is given by

The volumetric strain is given by 3 times the hoop strain as the strain is same in all directions because sphere is same about all the axes. (Option 4)

Calculation:

Given:

P = 10 MPa; t = 25 mm; d = 500 mm; E = 20 GPa; μ = 0.3;

Now

ϵV = 3 × ϵH = 3 × 1.75 × 10-4 = 5.25 × 10-4

Due to symmetricity the strain of the sphere in all directions is same.

HPCL Civil Engineer Mock Test - 2 - Question 18
If the atmospheric pressure at sea level is 10.144 N/cm2, what will be the absolute pressure at the height of 3 km from sea level? [Pressure variation may be assumed to follow hydrostatic law, density of air is assumed constant as 1.2 kg/m3]
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 18

Concept:

Pabsolute = Patmospheric + Pgauge

The pressure at any point in a static fluid is obtained by Hydro-static law which is given by-

∴ P = -ρgz

P increases when we go down (z negative) and decreases when we go up (z positive).

where P = pressure above atmospheric pressure and h = height of the point from the free surface.

Calculation:

Given:

Patmospheric = 10.144 N/cm2, h = 3 km ⇒ 3000 m, ρair = 1.2 kg/m3, g = 9.81 m/s 2

Pgauge = -ρgz

Pgauge = -(1.2 × 9.81 × 3000) = - 35316 N/m2 = - 3.53 N/cm2

Pabsolute = Patmospheric + Pgauge

Pabsolute = 10.144 - 3.53 = 6.612 N/cm2

HPCL Civil Engineer Mock Test - 2 - Question 19

In survey work, the Total Station has to be handled properly. From the following options, mark the improper way of handling the total station:

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 19

The following points should be remembered while handling the total station:

  • The instrument should be protected from excessive vibration.
  • It shall be removed from the case by both hands. Generally, the instrument is equipped with a carrying handle; Use one hand to grip the handle and the other to support the base.
  • If it is wet, the total station should be thoroughly wiped before placing it in the carrying case.
  • While traveling from one station to another, the total station should not be taken in a position on the tripod stand.
  • The total station and others should be dismantled and re-cased for transportation of new points. They should be not carried openly to the new point.
  • While traveling, the total station should not be carried on its tripod.
  • The instruments should be protected from moisture as much as possible.
  • The instrument should be turned off prior to removing the battery.
  • Battery must be removed from the instrument before placing it in the carrying case.
  • The instrument should not be used for solar observation unless it has a solar filter, otherwise, it will destroy the EDM instrument and also be harmful to the observer’s eye.
  • After fieldwork, the total station should be placed directly in its carrying case after releasing the locking mechanism.
HPCL Civil Engineer Mock Test - 2 - Question 20

The observed value of N from a standard penetration test conducted on a saturated sandy soil stratum is 33. The corrected value of N for dilatancy can be estimated as:

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 20

Dilatancy correction:

It is to be applied when N’ obtained after overburden correction, exceeds 15 in saturated fine sands and silts. IS: 2131-1981 incorporates the Terzaghi and Peck recommended dilatancy correction (when N’ > 15) using the equation

Given,

N value = 33

Corrected value for dilatancy is

N'' = 15 + 9 = 24

∴ Corrected value N'' = 24

HPCL Civil Engineer Mock Test - 2 - Question 21
The live load for sloping roof with slope 15° where access is not provided to roof is taken as
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 21

Concept:

Live load:

As per IS: 875, Part 2 specifies the following Live loads:

For roof membrane sheets or purlins: 0.75 kN/m2 less 0.02 kN/m2 for every degree increase in slope over 10° subject to a minimum of 0.4 kN/m2.

Calculation:

Given data,

Access is not provided to the roof and the slope = 15°

So, in this case

The live load for the sloping roof is

LL = 0.75 – (15 – 10) × 0.02 = 0.65 kN/m2

HPCL Civil Engineer Mock Test - 2 - Question 22

What is the value of x - coordinate from the left base point 'B' of the center of mass of the given figure below?

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 22

Center of mass:

  • The Centre of mass of a body or system of a particle is defined as, a point at which the whole of the mass of the body or all the masses of a system of particles appeared to be concentrated.

COM for the given fig:

We know that

Where A1 = Area of triangular section (Base = h, height = a - b) = ,

xc1 = Centroid distance from B = ,

A2 = Area of rectangular section (Base = h, height = b) = ,

A2 = Area of rectangular section (Base = h, height = b) = ,

xc2 = Centroid distance from B =

Calculation:

By simplifying the above equation, we can get

HPCL Civil Engineer Mock Test - 2 - Question 23

Identify the WRONG diagram. (G-Centroid, s-shear center)

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 23

Shear centre:

The shear centre is the point through which if the resultant shear force acts then the member is subjected to simple bending without twisting.

Location of shear centre:

(i) Shear centre generally does not coincide with the centroid of section except in special cases when the area is symmetrical bout both axis.

(ii) Shear centre always lies on the axis of symmetry if exists.

(iii) If there are two or more two axis of symmetry exist, then the shear center will coincide with the point of intersection of the axis of symmetry. In this case shear centre of the area will be the same as the centroid of the area.

(iv) If a section is made of two narrow rectangles then the shear center lies on the junction of both rectangles.

HPCL Civil Engineer Mock Test - 2 - Question 24

A 4-hours rainfall in a catchment of 250 km2 produces rainfall depths of 6.2 cm and 5.0 cm in successive 2-hour unit periods. Assuming the φ index of the soil to be 1.2 cm/hour, the runoff volume in ha-m will be

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 24

Concept:

Role of ϕ-index in rainfall

If rainfall is less than ϕ-index then, the infiltration rate is given as

Infiltration rate = Rainfall rate

If rainfall is greater than ϕ-index then, the infiltration rate is given as

Infiltration rate = ϕ-index

That means, above the infiltration rate

Excess rainfall = Runoff

Calculation:

Given,

Catchment area = 250 km2

Rainfall depths are 6.2 cm and 5.0 cm in successive 2 hr periods

∴ Rainfall depths in 1 hr period are 6.2/2 = 3.1 cm/hr and 5/2 = 2.5 cm/hr

ϕ-index = 1.2 cm/hour

Runoff depth = (3.1 - 1.2) × 2 + (2.5 - 1.2) × 2 = 3.8 + 2.6 = 6.4 cm

Runoff volume = Runoff Dept × Area of catchment

Runoff volume = 6.4 × 10-2 × 250 × 106 = 1600 × 104 = 1600 ha.m

Hence the runoff volume in ha-m is 1600 ha.m

HPCL Civil Engineer Mock Test - 2 - Question 25
The depth for which the increase in pressure due to structural loading may cause perceptible settlement is known as ________
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 25

Depth of exploration: Depth up to which the increase in pressure due to structural loading is likely to cause perceptible settlement or shear failure is known as the significant depth.

It depends upon the type of structure, its weight, size, shape and disposition of the loaded areas, and the soil profile and its properties.

It is about the depth up to a level at which the net increase in vertical pressure becomes less than 10% of the initial overburden pressure. Sometimes it is also depth for which a pressure bulb bounded by an isobar of one-fifth or one-tenth of the surface loading intensity.

It is usually assumed to be equal to one-and a half to two times the width (smaller lateral dimension) of the loaded area.
HPCL Civil Engineer Mock Test - 2 - Question 26
In a certain soil sample, there are little or no fines. In this soil sample, more than half of the coarse fraction retain on 4.75 mm sieve and is well graded. Soil can be classified as:
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 26

Concept:

Soil classification:

Here,

Cu - Coefficient of uniformity

Cc - Coefficient of curvature

Explanation:

Given,

More than half of the coarse fraction > 4.75 mm IS sieveGW

HPCL Civil Engineer Mock Test - 2 - Question 27
Normally what should be the height of building for which fire lifts must be provided ?
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 27

Solution:

Following are guidelines and provisions for regulating and preventing fire in Indian buildings by NBC

  • A building 15 meters above the ground level or exceeding three storeys is considered a high-rise structure and must obtain a certificate of approval from the Director of Fire Force or an officer authorized by him before commencing the construction of any such structure.
  • Each floor of the building should have two staircase exits for faster evacuation during a fire.
  • Massive static water storage in the form of underground water should be made available in the buildings at the rate of 1,000 liters per minute. Automatic sprinklers should also be installed in the basements used for car parking or storage occupancy exceeding 200 meters.
  • Every building with a height of more than 25 meters should have diesel generators which can be used for controlling fire in the case of power failure.

Provision of lifts:

  • Provision of the lifts shall be made for all multi-storeyed buildings having a height of 15.0 m. and above.
  • All the floors shall be accessible for 24 hrs. by lift.
  • The lift provided in the buildings shall not be considered as a means of escape in case of emergency.
  • A grounding switch at ground floor level to enable the fire service to ground the
  • lift car in case of emergency shall also be provided.
  • The lifts machine room shall be separate and no other machinery be installed in it
HPCL Civil Engineer Mock Test - 2 - Question 28

The bending moment diagram of a simply supported beam AC is shown in figure. The load acting on the beam is:

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 28

The bending moment diagram shows the variation of bending moment along the length of the beam.

The point of contra flexure is defined as a point where the bending moment changes its sign from positive to negative and vice-versa.

There is a sudden change in the bending moment diagram i.e. from positive to negative when there is a concentrated moment acting on a point.

Similarly, if the uniformly distributed load is acting on the beam, the BMD becomes parabolic (2°)

If equal and opposite moments are acting on supports the BMD becomes a rectangle.

HPCL Civil Engineer Mock Test - 2 - Question 29

The ratio of the flexural strengths of two beams of square cross section, the first beam being placed with its top and bottom sides horizontal and second beam being placed with one diagonal horizontally, is:

Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 29

Bending Stress:

It is a more specific type of Normal Stress. It is the ratio of the Bending moment at a cross-section to the section modulus.

σ =

where, σ = Bending Stress, M = Bending Moment,

y = vertical distance away from the Neutral Axis, I = Moment of Inertia about the Neutral Axis, Z = Section Modulus it is given by,

Flexural strength is proportional to the sectional modulus of beams.

ZNA =

1.) Bending Stress for square cross-section simply supported beam with sides horizontal is given by,

σ =

And Section Modulus is given by,

(ZNA)1 =

2.) Bending Stress for the square cross-section with one diagonal placed horizontally is given by,

σ1 =

And the Section Modulus for a simply supported beam with the diagonal horizontal is given by,

(ZNA)2 =

Therefore the ratio of their section modulus is given by

HPCL Civil Engineer Mock Test - 2 - Question 30
If 400 mm is the perimeter of a closed traverse and 20 mm is the closing error in departure, the correction for departure of a traverse side of length 80mm, according to Bowditch rule is:
Detailed Solution for HPCL Civil Engineer Mock Test - 2 - Question 30

Concept

Balancing of errors: The process of adjusting the latitudes and departures to make the algebraic sum of latitudes or departures to zero is called the balancing of errors.

Bowditch rule (Compass rule)/Compass rule:

It is most commonly adopted when angular measurement and linear measurement both are nearly of same precision.

The correction is considered directly proportional to the length of the side.

By Bowditch rule Correction to a particular line is given by

Where CL, CD is corrections in latitude and longitude for a line.

Correction for Latitude/Departure = Total error in Latitude/Departure ×

Calculation:

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