HPSC PGT Chemistry Mock Test - 2 - HPSC TGT/PGT MCQ

The correct answer is The Supreme Court.

Key Points 

• The Supreme Court of India is called the custodian of the Constitution in India.
• The highest court in India, the Supreme Court is considered as the guardian of the Constitution.
• The conflicts or quarrels of jurisdiction between the central government and the state governments or between the legislature and the executive are decided by the court.
• It upholds and uplifts the rule of law and also ensures and protects citizens’ rights and liberties as given in the Constitution.
• Therefore, the Supreme Court is also known as the Guardian of the Constitution.​

Additional Information 

• The Indian constitution provides for a provision of the Supreme Court under Part V (The Union) and Chapter 6 (The Union Judiciary).
• The Supreme Court of India is the highest judicial court and the final court of appeal under the Constitution of India, the highest constitutional court, with the power of judicial review.
• India is a federal state and has a single and unified judicial system with a three-tier structure, i.e. Supreme Court, High Courts, and Subordinate Courts.

The correct answer is Wrestling.

Key Points

• Satyawart Kadian is associated with wrestling sports.
  • He was born on 9th November 1993, in Rohtak, Haryana, India.  
• The Achievements of Satyawart Kadian:
  • A bronze medal in the 100 kg category at the 2010 Youth Olympic Games, held in Singapore.
  • Earned a bronze medal in the 96 kg category at the World Junior Championships in 2013 that took place in Sofia.
  • Bagged silver and a bronze medal in the 97 kg category at the Commonwealth Games and Asian Championships of 2014.
  • Won the title at the 1st Rustam-e-International tournament which was held at Jammu in 2015.
  • Clinched a gold medal in the 97 kg category at the Commonwealth Championships of 2016, held in Singapore.
  • Claimed a bronze medal in the 97 kg category at the 2019 Asian Championships.

Additional Information

The correct answer is Rakesh Singh.

Key Points

• Rakesh Koch -
  • He is a resident of Bahadurgarh, Haryana
  • He has been elected General Secretary of the Wrestling Association of Haryana.
  • He has been associated with sports for a long time and is also the director of the Model School located in Bahadurgarh.

Additional Information

• ​Santosh Sharma -
  • This is the head constable of Panipat Police.
  • He has recently brought laurels to the state of Haryana by winning the gold medal in the World Police Sports Competition.
• Preetpal Sangwan -
  • ​He is the Haryana police officer who has been awarded the Police Medal.

The correct option is A increases by 1
He² (4 electrons) : (σ1s²)(σ∗1s)²
Bond order = (2−2)/2 = 0
Electron is taken to next excited state that is (σ2s), then the electronic configuration is:
(σ1s²)(σ∗1s)²(σ2s)¹
number of electrons in bonding molecular orbital = 3
and in anti-bonding molecular orbital = 1
Bond order =(3−1)/2=1
Thus, the bond order increases by 1 .

Non metallic oxides are acidic.

In the given figure if line 'E' is in visible region then line belonging to ultraviolet region will have more energy than 'E' i.e. line A

Bond length and (EN) oppose each other, with the larger halogens having longer bonds but weaker (EN). Thus CH₃CI > CH₃F > CH₃Br.

Pure phoshine is not inflammable but due to contamination of P₂H₄ and P₄ vapours, it becomes inflammabl.

The potential energy of an electron in the first Bohr’s orbit in the H-atom is

This energy is defined as an atomic unit of energy called HARTREE.

The correct answer is option C
CH_3​CH₂​CONH₂​ (A)⟶ CH₃​ − CH₂ ​− NH₂​ (B)⟶ ​CH_3​ − CH₂ ​− OH
In the above sequence A & B respectively are Br₂​/KOH and HNO₂​
The first step is Hoffmann bromamide degradation reaction in which an amide (propanamide) is converted to an amine  (ethylamine) containing one carbon atom less. The reagent A is bromine in presence of KOH. In the second step, aliphatic primary amine (ethyl amine) reacts with nitrous acid (reagent B) to form aliphatic primary alcohol (ethyl alcohol).
 

X is a primary, chiral alcohol.

Enthalpy is a state function; which means change in enthalpy depends only on final and initial state. So, the change in enthalpy for a cyclic process is zero.

On addition of H₂/Pd/CaCO₃
we get H-CH=C-CH₂-CH₂-CH₃ 
H-CH=C-CH₂-CH₂-CH₃ + NBS/CCl₄   →   H-CH=C-CHCl-CH₂-CH₃  (NBS adds Br to carbon at next alternate to double bond)
H-CH=C-CHCl-CH₂-CH₃ + KOH/EtOH  →  H₂C=C-CH=CH-CH₃
(by E₂ elimination)

On substituting the values of conc. of NO, O₂ and NO₂ in given rate equation, we get a +ve (positive) value indicating that the reaction takes place in forward direction.

A small and highly electronegativity elements form a stronger hydrogen bond. The order of size of N , O and F is F < O < N .and so the order of strength of hydrogen bond is F > O > N.

Hence, electronegativity of F is the highest, therefore magnitude of positive charge on hydrogen and negative charge on F is the highest in HF and Hence, electrostatic attraction of H bonding is the strongest in HF.

• Autoxidation is any oxidation that occurs in presence of oxygen.
• The term is usually used to describe the degradation of organic compounds in air (as a source of oxygen).
• Autoxidation produces hydroperoxides and cyclic organic peroxides.

Catalyst only increases or decreases the activation energy of a reaction, It doesnot get used up in reaction.

The correct answer is option C
The order of reaction with respect to A = 1
The order of reaction with respect to B =1
Total order of reaction = 1+1 = 2

When sodium is dissolved in liquid ammonia, it donates electrons to the ammonia solvent, forming ammoniated electrons. These solvated electrons are responsible for the deep blue colour of the solution.

There are several ways to tell metals and nonmetals apart. Nonmetalsdon't have a metallic appearance. Unlike metals, they typically have lower melting and boiling points and tend not to conduct heat or electricity very well.

The electronic configuration of Be is 1s²2s². We can see that there are only 4 orbitals in its valence shell( they are s and p). In other words, d orbital is absent. So, Be shows ccoordination no 4 and not 6 as like other members of its group.

Due to intermolecular H-bonding at two terminals boiling point of glycol is maximum.

Octahedral complexes of formula [Ma₄b₂] in which the two ligands b may be oriented cis or trans to each other, e.g.

Geometrical isomers (cis and trans) of [Co(NH₃)₄CI₂]⁺.

54 gram of water is formed or three moles of water is formed.
C₂H₆ + (7/2)O2 → 2CO₂ + 3H₂O
So it indicates that only one mole of C₂H₆ is used in the combustion so the heat released is itself the value of heat of combustion of Ethane.

Hydration energy ∞ polarising power
Na⁺ < Mg²⁺ < Mg³⁺ < Be³⁺ < Al³⁺

∆S= 2.303nR × log(V₂/V₁)Here n=2, R=8.314, V2= 10, V₁= 1

In this question l=3 means the sub shell is f & n=4 means it is present in 4^th orbit.
Finally it is a 4f sub shell.
The no of orbital in f sub shell =2l+1
                                                = 2*3+1
                                                =7
Each orbital can accommodate 2 electrons.
  7*2 = 14 electrons.

Maximum number of electrons in a sub shell with l=3& n=4 (4f) is 14electrons.

The correct answer is option D
For Na₂​SO₄ ​: −i = n
Na₂​SO₄ ​⟶ 2Na⁺ + SO₄²⁻​​
                         n=2
i=1−α+nα
i=1−α+2α
i=1+2α