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HPSC PGT Chemistry Mock Test - 7 - HPSC TGT/PGT MCQ


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30 Questions MCQ Test HPSC PGT Mock Test Series 2025 - HPSC PGT Chemistry Mock Test - 7

HPSC PGT Chemistry Mock Test - 7 for HPSC TGT/PGT 2025 is part of HPSC PGT Mock Test Series 2025 preparation. The HPSC PGT Chemistry Mock Test - 7 questions and answers have been prepared according to the HPSC TGT/PGT exam syllabus.The HPSC PGT Chemistry Mock Test - 7 MCQs are made for HPSC TGT/PGT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPSC PGT Chemistry Mock Test - 7 below.
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HPSC PGT Chemistry Mock Test - 7 - Question 1

Where Pratap Singh revolted against the British?

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 1

The correct answer is Jind.

Important Points

  • Pratap Singh revolted against the British in Jind, Haryana.
  • Raja Bhag Singh suffered a severe paralytic attack in March 1813. Unfit to run the administration of his state, the ailing chief wished to appoint Prince Pratap Singh the ablest and wisest of all his sons as his regent to do his work.
  • But the British government to whom the anti-British bearing of the prince was known stood in his way and got Rani Sobrahi appointed in place of the price in 1814. This was unbearable for Pratap Singh and he raised the standard of revolt on June 23, 1814.
  • Pratap being a popular figure the state forces also revolted and joined him forthwith. With their help, the prince lost no time in occupying the Jind fort and established his government after putting the Rani the puppet of the British government to the sword.

Additional Information

  • Kaithal revolt was started in the year 1843 and its leader was Gulab Singh and Suraj Kaur.
HPSC PGT Chemistry Mock Test - 7 - Question 2

Haryana government has announced to build a huge sports stadium in the village of which famous sportsperson?

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 2

The correct answer is Neeraj Chopra.

Key Points

  • Haryana Chief Minister Manohar Lal Khattar announced that a stadium will be built in Olympic gold-medallist Neeraj Chopra's native village in Panipat.
    • Neeraj Chopra is a Javelin throw player.
    • Javelin thrower Neeraj Chopra's native village Khandra is in Panipat.
    • A stadium would be built in Neeraj Chopra's village for ₹10 crores.

Additional Information

HPSC PGT Chemistry Mock Test - 7 - Question 3

Tvesa Malik is an Indian _____ player.

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 3

The correct answer is golf.

Key Points

  • Tvesa Malik is an Indian golf player.
  • She is from Gurugram, Haryana.
  • She has won the 4th leg of the Hero Women’s Golf Tour.
  • Gursimar Badwal is also an Indian golf player. 

Additional Information

HPSC PGT Chemistry Mock Test - 7 - Question 4
Who among the following will be the chairman of sixth Haryana finance commission?
Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 4

The correct answer is P Raghavendra Rao.

Key Points

  • Haryana State Finance Commission for Panchayats:
    • Articles 243 (I) and 243 (Y) of the Constitution provide for the establishment of a State Finance Commission once every five years.
    • The First Haryana State Finance Commission was established on the 31st of May, 1994.
    • In exercise of the powers conferred by article 243-I of the Constitution of India and section 213 of the Haryana Panchayati Raj Act, 1994. 
    • The Governor of Haryana hereby makes the rules providing for the Constitution of State Finance Commission and regulating the qualifications and appointment of its Chairman and other members. 
    • Former Haryana bureaucrat P Raghavendra Rao will head the Haryana’s sixth State Finance Commission, an institutional mechanism for division of resources between the state government and the Panchayati Raj institutions (PRIs) and the urban local bodies for five years (2021-22 to 2025-26). Hence, Option 4 is correct.
    • The commission would make recommendations on “distribution between state and Zila Parishad, panchayat amenities and gram panchayats of the net proceeds of taxes, duties, tolls, and fees leviable by state”.
HPSC PGT Chemistry Mock Test - 7 - Question 5
The average of 40 numbers is calculated as 25. But later, it is found that 3 numbers 23, 25, and 41 are mistakenly written as 32, 52, and 15 respectively. Find the correct average of numbers.
Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 5

GIVEN:

The average of 40 numbers = 25

CONCEPT:

Basic Average concept.

FORMULA USED:

Average = Sum of all numbers/Total numbers

CALCULATION:

Sum of numbers = 40 × 25 = 1000

23, 25 and 41 are mistakenly written as 32, 52 and 15 respectively.

⇒ Change in sum = (23 + 25 + 41) – (32 + 52 + 15)

= 89 – 99

= -10

Actual sum of numbers will be 10 less.

⇒ Sum of numbers = 1000 – 10 = 990

∴ Correct average = 990/40 = 24.75

HPSC PGT Chemistry Mock Test - 7 - Question 6

Choose the odd one out of the given options.

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 6

The pattern followed is, 

Logic: For all the other option sum of place value is 14 except “DJA”


Hence, “DJA” is the correct answer.

HPSC PGT Chemistry Mock Test - 7 - Question 7

According to NEP 2020, what is the role of teachers in the new education system?

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 7

NEP 2020 emphasizes the role of teachers in promoting critical thinking, creativity, and holistic development of students.

HPSC PGT Chemistry Mock Test - 7 - Question 8

The basis of selection of a teaching aid is

  1. age of the learner
  2. objectives of teaching
  3. intellectual level of the learner

Choose from the options given below:

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 8

Age of learner is proportional to the cognitive ability of the learner, thus teaching aids should be selected on the basis of the age. Use of any kind of teaching aid can only be helpful in serving the purpose, if it runs parallel to the cognitive ability of the learner.
The use of teaching aids facilitates the objective of teaching by assisting teachers in differentiating instruction. Hence, they must be chosen keeping in view what the teacher intends to teach the students.
The teaching aids also must be carefully chosen to match the intellectual level of the students. In case of students with intellectual disabilities, different kind of teaching aids are to be used, instead of those used for normal intellectual abilities.

HPSC PGT Chemistry Mock Test - 7 - Question 9

Where would you find the smallest atoms of elements in the periodic table?

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 9

Helium is the smallest atom. The energy level of the electrons determine the atom's volume. Electrons have a negative charge and the nucleus is positive since it is made up of protons and neutrons. Helium and Hydrogen have one and two electrons. This means they are in the the first energy sub level which is 1S (It can hold up to two electrons) So if that's all we were to consider, both atoms would be the same size. However, since Helium has more protons and electrons, the electrons have a greater attraction to the nucleus, thus decreasing its volume. So it is wrong to just look at atomic number. Hydrogen is not the smallest atom, it is the second smallest and Helium is the smallest.

HPSC PGT Chemistry Mock Test - 7 - Question 10

  

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 10

HPSC PGT Chemistry Mock Test - 7 - Question 11

What does hydrogen peroxide liberate from potassium iodide?

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 11

When 2 moles of potassium iodide are reacted with 1 mole of hydrogen peroxide, 2 moles of potassium hydroxide and one mole of iodine is liberated. That means hydrogen peroxide liberates iodine from acidified potassium iodide.

HPSC PGT Chemistry Mock Test - 7 - Question 12

At what temperature white phosphorous changes to red phosphorous?

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 12

White phosphorus when heated to 300° C polymerization occurs and it changes to Red Phosphorus.

HPSC PGT Chemistry Mock Test - 7 - Question 13

What is the major bromination product in the following reaction? 

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 13

The correct answer is option c

Thus, a racemic mixture is obtained. A racemic mixture is one that has an equal amount of left and right handed enantiomers of a chiral molecule.

HPSC PGT Chemistry Mock Test - 7 - Question 14

The substance that gets adsorbed on the surface of the solid is called?

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 14

The substance that gets adsorbed on the surface is known as adsorbate.

HPSC PGT Chemistry Mock Test - 7 - Question 15

Which of the following will have three stereoisomeric form ?

i. [Cr(NO3)3(NH3)3]
ii. K3[Co(C2O4)3]
iii. K3[Co(C2O4)2CI2]
iv. [Co(en)2CIBr]

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 15

The complex [Co(C2O4)2Cl2]3- show both geometrical and optical isomers.

HPSC PGT Chemistry Mock Test - 7 - Question 16

How many structural isomers are possible with molecular formula C4H10O ?

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 16

The formula that these isomers contain no rings or double bonds. The isomers must be alcohols and ethers.
For The alcohols
1. CH3CH2CH2CH2OH, butan 1-ol
2. CH3CH2CH(OH)CH3, butan-2-ol
3. (CH3)2CHCH2OH, 2-methylpropan-1-ol 
4. (CH3)3COH, 2-methylpropan-2-ol.
Now for the ethers.
5. CH3CH2CH2OCH3, 1-methoxypropane
6. CH3CH2OCH2CH3 , ethoxyethane
7. (CH3)2CHOCH3 , 2-methoxypropane.

HPSC PGT Chemistry Mock Test - 7 - Question 17

In the following compounds, select the points of interm olecular H-bonding (linear),

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 17


1. Enoiic H, acidic and polar takes part in H-bonding.
2. 3° alcohol least acidic maximum basic.
3. Carbonyl oxygen is not involved.
4. Acidic and polar H, takes part in H-bonding.

HPSC PGT Chemistry Mock Test - 7 - Question 18

One of the following rubbers is used in making oil seals, tank lining, etc.

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 18

Buna N is used in making oil seals , tank linings.

HPSC PGT Chemistry Mock Test - 7 - Question 19

The reagent which can best bring about the following transformation is

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 19

With aluminium isopropoxide (MPV reduction), carbonyls are selectively reduced to alcohols leaving other groups intact.

HPSC PGT Chemistry Mock Test - 7 - Question 20

Direction (Q. Nos. 7 - 10) This section contains 4 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q. Predict product(s) in the following reaction.

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 20

In Benzene ring, the meta position is more stable than ortho and para.
At high temperature meta position will exist 
i.e option B is correct
 

HPSC PGT Chemistry Mock Test - 7 - Question 21

Study of rate of chemical reaction is known as

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 21

Chemical Kinetics deals with rate of a Chemical reactions.

HPSC PGT Chemistry Mock Test - 7 - Question 22

(Yellow ppt) T  X  Y. (Yellow ppt) + Z­ (pungent smellinggas)

If X gives green flame test. Then, X is :

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 22

Green flame is given by Ba2+

BaS2O3+K2CrO4 → BaCrO4+K2S2O3   yellow ppt

HPSC PGT Chemistry Mock Test - 7 - Question 23

The standard enthalpies of formation of CO2(g), H2O (l) and glucose (s) at 25°C are - 400 kJ mol-1, - 300 kJ mol-1 and - 1300 kJ mol-1 respectively. The standard enthalpy of combustion per gram of glucose at 25°C is

[JEE Advanced 2013]

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 23

HPSC PGT Chemistry Mock Test - 7 - Question 24

The oxygen family is also known as:

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 24

Oxygen family is also known as chalcogen family when the 17 th family is known as halogen family.

HPSC PGT Chemistry Mock Test - 7 - Question 25

In the propanoate ion

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 25

This is because of Resonance.

HPSC PGT Chemistry Mock Test - 7 - Question 26

The primary difference between the modern periodic table and Mendeleev's periodic table is:

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 26

The modern periodic table orders elements by increasing atomic number, which is the number of protons in the atom of the element. Mendeleev did not know about the parts of the atom, so he used the next best thing -- atomic weight.

HPSC PGT Chemistry Mock Test - 7 - Question 27

How many assymmetric carbon atoms are present in
(i) 2-Dimethyl cyclohexane
(ii) 3-Methyl cyclopentene
(iii) 3-Methylcyclohexene

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 27

The correct answer is Option A.
No of asymmetric carbon atoms in 
2 - dimethylcyclohexane  = 2
3-methylcyclopentene = 1
3-methylcyclohexene = 1

HPSC PGT Chemistry Mock Test - 7 - Question 28

Atmosphere traps the sun’s heat near the earth’s surface. This is called:

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 28

The greenhouse effect is a natural process that warms the Earth's surface. When the Sun's energy reaches the Earth's atmosphere, some of it is reflected back to space and the rest is absorbed and re-radiated by greenhouse gases. The absorbed energy warms the atmosphere and the surface of the Earth.

HPSC PGT Chemistry Mock Test - 7 - Question 29

In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3 . Taking kƒ for water as 1.85, the freezing point of the solution will be nearest to _

[AIEEE-2003]

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 29

The correct answer is option C
ΔT = Kf​ × molality × (1+α)(HX ⇌ H+   + X−)
Given molality = 0.2;  degree of ionization is 0.3
=1.85×0.2×(1+0.3)
=0.481K
The freezing point of the solution will be 0.81 K.

HPSC PGT Chemistry Mock Test - 7 - Question 30

When an electron is added to neutral gaseous atom to convert it into a negative ion, the enthalpy change accompanying the process is called:

Detailed Solution for HPSC PGT Chemistry Mock Test - 7 - Question 30

Electron affinity is defined as the change in energy (in kJ/mole) of a neutral atom (in the gaseous phase) when an electron is added to the atom to form a negative ion.

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