HTET TGT Maths Mock Test - 2 - HTET MCQ

All exams must be conducted for the backward children. Emphasis must be paid on providing proper education to them so that they can easily face all examinations.

The teacher can deal with the individual differences of the students if she is aware of the abilities, interest and aptitudes of each student. She can then concentrate on each student and help them overcome the difficulties that they have.

The response of a young child on the basis of the past situation is related to the 'Law of Analogy' of learning. 
The 'Law of Analogy' principle was developed by Edward Thorndike. According to him, an individual makes use of old experiences while learning a new situation. The way young child did he identified the similarities between the past situation and the present one.
Hence, the correct answer is, 'Law of Analogy' of learning.

According to Piaget's theory, children actively construct their understanding of the world through their experiences and interactions with the environment.

In psychology, individual differences refer to the extent and kind of variations or similarities among people on some of the important psychological aspects such as intelligence, personality, interest, and aptitude.

Non-discursive communication refers to any form of communication that does not involve the use of words or language.

• Speaking involves the use of words or language to communicate, which is the opposite of non-discursive communication.
• Non-discursive communication includes forms of communication that do not involve the use of words, such as facial expressions, body language, gestures, and silence.
• It is an important aspect of human communication and can play a significant role in how we interact with others and convey meaning and emotion.

Thus, it is concluded that Speaking is NOT a form of non-discursive communication.

सही उत्तर 'सेना' है।

Additional Information

• दिए गए विकल्पों में से 'अनी' का सही पर्यायवाची शब्द 'सेना' होगा।
• अनी के अन्य पर्यायवाची शब्द- कटक, दल, फौज, चमू, अनीकिनी।

अन्य विकल्प:

• स्वादिष्ट के पर्यायवाची - मजेदार, सुस्वादु।
• दुष्ट के पर्यायवाची - पापी, नीच, दुर्जन, अधम, खल, पामर।
• सेतु के पर्यायवाची - गर्डर, धराई, धरण।

Key Points

• एक ही अर्थ में प्रयुक्त होने वाले शब्द जो बनावट में भले ही अलग हों, पर्यायवाची या समानार्थी शब्द कहलाते हैं।

One word substitute is Imposter.

Imposter: a person who pretends to be someone else in order to deceive others, especially for fraudulent gain.
Liar: a person who tells lies.
Rogue: a dishonest or unprincipled man.
Magician: a person with magical powers.

24 → 2 x 4 = 8

32 → 3 x 2 = 6

Prime numbers between 1 and 30 →13, 17, 19, 23 and 29 (5)
Rest are prime numbers.
Total numbers 12 to 29 = 18
Total composite numbers = 13

Hence, Option A is correct.

Time → A : C = 40 : 90 = 4 : 9
Efficiency → A : C = 9 : 4

Hence, Option D is correct.

5³ - 1³ can be solved using the identity ;

(a³ - b³) = (a - b) (a² + b² + ab)

5³ - 1³ = ( 5 - 1 ) ( 5² + 1² + 5*1)

=(4) (25 + 1 + 5)

= (4) (31)

= 124

Closed-ended questions are those that can only be replied by choosing from a restricted set of possibilities, such as multiple-choice questions with a single-word response, such as 'yes' or 'no,' or rating scales (e.g. from strongly agree to strongly disagree).

Key Points

• A multiple-choice question is a form of questionnaire/survey question that allows respondents to choose from a variety of answers. It's also known as an objective response question since it asks people to choose just the proper responses from a list of possibilities.
• Any question for which a researcher offers study participants with alternatives from which to pick an answer is referred to as a closed-ended question.

Additional Information

• Closed-ended inquiries elicit a single response from the respondent. They're set up in such a way that the one-word response doesn't require much thought. "Are you hungry?" is an example of a closed-ended inquiry. People adore talking about themselves.
• An open-ended question is one that cannot be answered with a simple "yes" or "no" or a static answer. Open-ended inquiries are worded in the form of a statement that necessitates a lengthy response. The response can be compared to data that the questioner already has.
• Convergent questions often have just one right answer, but divergent questions, also known as open-ended questions, are designed to encourage many responses and increase student engagement.
• A divergent inquiry is one that doesn't have a clear solution and instead tests one's capacity to think extensively about a topic.

As a result, closed-ended questions, which can only be answered by choosing from a restricted number of answers, are commonly known as multiple-choice questions.

a+2d=600
a+6d=700
4d=100
d=25
so a+2x25=600
a+50=600
a=550

Let the angle be x. Its complement will be 90 - x. Therefore,

x = 90 - x 

=> 2x = 90 

=> x = 45 degree

The answer is 45 degree.

The point D(3, -6) lies in the IV Quadrant.
Explanation: In the Cartesian plane, the X-axis and Y-axis divide the plane into four quadrants. The I Quadrant is where both x and y are positive. The II Quadrant is where x is negative and y is positive. The III Quadrant is where both x and y are negative. The IV Quadrant is where x is positive and y is negative.
The point D(3, -6) has a positive x-coordinate and a negative y-coordinate. Therefore, it lies in the IV Quadrant.

We have the sequence 5n²+2n+3
It will be in AP if it satisfies an-an-1=d where d is a constant.
Here, a_n=5n²+2n+3
And, a_n-1=5(n-1)²+2(n-1)+3=5(n²+1-2n)+2n-2+3
=5n²+5-10n+2n+1=5n²-8n+6
a_n-a_n-1=5n²+2n+3-(5n²-8n+6)
=5n²+2n+3-5n²+8n-6
=10n-3, which depends on a variable , so its not constant.

use factor theorem as x+2 is factor of

x³-2ax²+16 so put x = -2 and equate the equation to 0

so putting x = -2

(-2)³-2a(-2)²+16 =0

-8-8a+16=0

-8a = -8

a = 8/8= 1

So,

a = 1

Given,
ABC is a triangle.
D is midpoint of BC and DQ is drawn parallel to BA.
Then, Q is midpoint of AC.
∴ AQ = DC
∴ FA parallel to DQ||PC.
AQC, is a transversal so, AQ = QC and FDP also a transveral on them.
∴ FD = DP .......(1) [ intercept theorem]
EC = 1/2 AC = QC
Now, triangle EQD, here C is midpoint of EQ and CP which is parallel to DQ.
And, P is midpoint of DE.
DP = PE..........(2)
Therefore, From (1) and (2)
FD = DP = PE
∴ FD = 1/3 FE

Greatest 5-Digit number = 99999

LCM of 8 and 9,

8 = 2 × 2 × 2

9 = 3 × 3

LCM = 2 × 2 × 2 × 3 × 3 = 72

Now, dividing 99999 by 72, we get

Quotient = 1388

Remainder = 63

So, the greatest 5-digit number divisible by 8 and 9 = 99999 - 63 = 99936

Required number = 99936 + 5 = 99941

The solution of the linear equation is represented by the ordered pair (x,y)

Hence if x>0 , y>0 , then the solution will always lie in the first quadrant.

Median is the middle value of the observations. So Median cannot be obtained when the observations are not in order. So first we have to arrange in ascending order. 
59, 46, 30, 23, 27, 44, 52, 40 and 29
Gives- 23,27,29,30,40,44,46,52,59
Since the no. of observations is odd 

To find the weight of the iron beam, we need to calculate its volume and then multiply it by the weight of 1 cubic meter of iron, which is given as 50 kg.Given:
Length of beam (l) = 9 m
Breadth (b) = 40 cm = 0.4 m
Height (h) = 20 cm = 0.2 m
Weight of 1 cubic meter of iron = 50 kgVolume of the beam = l × b × h = 9 m × 0.4 m × 0.2 m = 0.72 cubic metersWeight of the beam = Volume × Weight of 1 cubic meter of iron = 0.72 cubic meters × 50 kg/cubic meter = 36 kg

Therefore, the weight of the iron beam is 36 kg, which corresponds to option B.

sum=n/2x(2a+(n-1)d )
       =50/2(2x3+ (50-1)3 )
       = 25 ( 6+49x3 )
       = 25x 153
       = 3825

Time duration between 4.00 om and 4.25 pm = 25 minutes
∵ Angle described by minute hand in 60 minutes = 360°
∴ Angle described by minute hand in 25 minutes  

11th term is 35 so a+10d = 35 => equation 1

13th term is 41 so a+12d = 41 => equation 2

solve both equations by elimination method

we get common difference as 3.

If a, b and c are in A.P., then 

The maximum number of zeroes that a polynomial of degree 3 can have is three because the number of zeroes of a polynomical is equals to the degree of that polynomial.