HTET TGT Maths Mock Test - 9 - HTET MCQ

The psychologist Robert Sternberg propounded the 'successful intelligence' theory. Intrapersonal intelligence is associated with the ability to understand one's feelings and thoughts.

First generation learners are defined as students whose parent(s)/legal guardian(s) has/have not completed any formal schooling. This means that they are the first in their family to attend school. Generally, there is no one at home to encourage such children for self-studying. So, option 2 is the correct answer.

A lesson can be introduced in the class by using examples related to the lesson so that it is easily understandable by children. Telling stories easily attracts students and students find it easy to understand such lessons by story-telling the children like to listen to the stories. That's why teachers introduce lessons with stories.
Hence, the correct answer is "All of these".

Favour to a particular favourite student in the examination is unfair for other students. This is how children will learn a habit of cheating. Next time, they won't try to learn their lessons and who deserve the best marks will never get a chance. The children will not focus on a study that will make them dull students.
Hence, the correct answer is "Lodge a complaint against him to the principal".

Lev Vygotsky was a Russian teacher who is considered a pioneer in learning in social contexts. As a psychologist, he was also the first to examine how our social interactions influence our cognitive growth. He believed that learning took place through relationships with others in our communities, including peers, adults, teachers, and other mentors. 

मैं आजकल घूमने जाता हूँ।शुद्ध वाक्य है। Key Points

• वाक्य शुद्धि - लिखने एवं बोलने में इस बात का ध्यान रखना कि जो कुछ भी लिखा या कहा जा रहा है वह बिल्कुल सार्थक एवं व्याकरण के नियमानुसार शुद्ध हो।
• उदाहरण - मुझे यह अच्छा नही लगता।

Additional Information

वियोग शब्द 'वि' उपसर्ग से बना है।

• वि + योग = वियोग (वि उपसर्ग)
• 'वि' संस्कृत का उपसर्ग है।
• 'वि' उपसर्ग के उदाहरण - विवाद, विपक्ष, विशुद्ध।

Key Pointsअन्य विकल्प -

• विवाह + इक = वैवाहिक
• वीर मूल शब्द है।
• वीर + त्व = वीरक्त

Additional Informationउपसर्ग -

• उपसर्ग शब्द के शुरूआत में जुड़ते हैं और मूल शब्द का अर्थ बदल देते हैं।
• उदाहरण :- अप + यश = अपयश, अध + पका = अधपका, ना + लायक = नालायक, हाफ + टिकट = हाफटिकट आदि।
• हिन्दी में मुख्यतः चार प्रकार के उपसर्ग होते है :-
  • संस्कृत के उपसर्ग (प्र, परा, अप, सम्, अनु, अव, निस्, निर्, दुस्, दुर्, वि, आङ्, नि, अधि, अपि, अति, सु, उत्, अभि, प्रति, परि तथा उप)
  • हिंदी के उपसर्ग (अन, अध, उन, औ, कु, चौ, पच, पर, बिन, भर, स, सह, चिर, न, बहु, आप, सम, दु)
  • उर्दू के उपसर्ग (ला, बद, बे, कम, ग़ैर, ना, खुश, हम, ऐन, सर, बेश, बा, अल)
  • अंग्रेजी के उपसर्ग (ब, हाफ, को, हैड, वाइस)

(वह - जो) मिश्र वाक्य का योजक चिन्ह है

मारुति - मारुत + ई विकल्प में मूल शब्द एवं प्रत्यय का विभाजन दोषपूर्ण है।

Key Points

• 'मारुति = मारुत + इ'
• मारुति शब्‍द में 'मारुत' मूल शब्‍द और 'इ' प्रत्‍यय है।
• मारुत का अर्थ- पवन, वायु।
• प्रत्यय -वे शब्द जो दूसरे शब्द के अंत में जुड़कर उनका अर्थ बदल दें।
• उदाहरण - लेख+अक =लेखक

Additional Informationअन्य उदाहरण -

सही उत्तर 'अब, एवं, भी' है।

दिए गए विकल्पों में 'अब, एवं, भी' अव्यय की श्रेणी में आते है।

वे शब्द जिनमे लिंग, कारक, वचन, पुरुष आदि के कारण कोई विकार/ परिवर्तन उत्पन्न नहीं होता है, अव्यय शब्द कहलाते है।

जैसे – आज, कब, इधर, किन्तु आदि।

Key Points

अन्य विकल्पों का विश्लेषण:

Additional Information अव्यय के पांच भेद हैं –

Note :- Rule to make active voice of Simple Past Tense
We can say that ,
The above given sentence is given in Passive Voice :-
Use structure “subject + auxiliary + past participle + by + object”
That watch was stolen by him.
Hence , required sentence is option A .

Use structure “subject + auxiliary + not + present participle + to + object”
As per the given above sentence is given in Active Voice.
His whereabouts are not know to me.
Therefore , option A will be correct sentence .

Controversy means prolonged public disagreement or heated discussion

A potential development project in the city of is causing some controversy
When the president gets involved in a controversy, you know it's serious

Hence, Option B is correct.

The correct answer is Trans-Gangetic plain region.

• India has been broadly divided into fifteen agricultural regions.
• It is based on agroclimatic features particularly soil type, climate including temperature and rainfall and its variation and water resources availability.
• Haryana falls in the Agro Climatic Zone-VI, which is called Trans-Gangetic Plains Region.
• The four main geographical features of the state are:
  • Shivalik Hills, Ghaggar Yamuna Plain, Semi-desert sandy plain and Aravali hills.
• All the regions are given below:
  • Western Himalayan division
  • Eastern Himalayan division
  • Lower Gangetic plain region
  • Middle Gangetic plain region
  • Upper Gangetic plain region
  • Trans-Gangetic plain region
  • Eastern plateau and hill region
  • Central plateau and hill region
  • Western plateau and hill region
  • Southern plateau and hill region
  • East coast plain and hill region
  • West coast plain and hill region
  • Gujarat plain and hill region
  • Western plain and hill region
  • Island region

80% of B = 125% of C
Efficiency → B : C = 125 : 80 = 25 : 16
Time → B : C = 16 : 25

Hence, Option C is correct.

Exterior angle = sum of two interior opposite angle so, exterior angle =1/2×80 = 40^°

Given : A die is thrown once .

A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.

If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6

Number of possible outcomes are = 6

Let E = Event of getting a getting a multiple of 3

Multiples of 3 are = 3, 6

Number of outcome favourable to E = 2

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 2/6  = 1/3

Hence, the probability of getting a  multiple of 3, P(E) = 1/3

To find the zeroes of the polynomial y=x³−4x, we can follow these steps:

Step 1: Set the polynomial equal to zero
To find the zeroes of the polynomial, we need to solve the equation:
x³−4x=0

Step 2: Factor the polynomial
We can factor out x from the equation:
x(x²−4)=0

Step 3: Further factor the quadratic
The expression x²−4 is a difference of squares, which can be factored as:
x(x−2)(x+2)=0

Step 4: Solve for the zeroes
Now, we can set each factor equal to zero:
1. x=0
2. x−2=0 → x=2
3. x+2=0 → x=−2

Conclusion
The zeroes of the polynomial x³−4x are:
x=−2,x=0,x=2

we have to  find the largest number which divide 615 and 963 leaving remainder 6 in each case.

so let us subtract 6 from 615 and 963

⇒ 615 − 6 = 609

⇒ 963 − 6 = 957

now lets find the HCF

⇒ prime factorisation of 609=29×3×7

prime factorisation of 957=29×3×11

now lets take out the common factors from both the cases

⇒ 29 and 3

x = 29 × 3 = 87

∴ 87 is the number which will divide 615 and 963 leaving remainder 6 in each case.

Modal class is the interval which has the highest frequency ie, which occur most of the times.Here highest frequency is 13 in the class interval 20-30. So lower limit of the class interval is 20.

The teaching and learning of mathematics have always been a major concern in education. The National Policy of Education (1986) lays down the importance of "Mathematics" as a vehicle for developing creativity.

• In primary classes, the teaching of mathematics should be done through fun and playful activities that include real-life situations to provide students the concrete experiences.
• The effective teaching of geometry at the primary level lays the foundation for the understanding of basic geometrical shapes that will further help the students in conceptual understanding of geometry at higher levels of classes.
• The teaching of geometry can be done informally by using a range of activities like paper folding, exploring ideas of symmetry, and transformation.

Key Points

• The teaching of geometry can be done informally by using a range of activities like paper folding, exploring ideas of symmetry, and transformation.
• In Geometry teaching, the teacher starts from what is required (that is unknown or conclusion) and arrived at what is given (that is known rule or hypothesis).

Analysis method:

• In this method, the teacher usually separates the things that are together to start from what is required and then traces the connection between it and the given data.
• This method helps to analyze the difficult parts of the given problem to find out its solution. It is based upon the heuristic approach and inductive reasoning.
• In this method, we start from "what is to be determined" or "what is to be proved" to reach the conclusion.

Hence, the teacher uses the analysis method when starts from what is required to arrive at what is given.

Additional Information

To find the maximum length of a pencil that can be kept in a rectangular box of dimensions 8 cm × 6 cm × 2 cm, we need to find the length of the diagonal of the box, which will be the maximum length of the pencil that can fit inside the box.Using the Pythagorean theorem, the length of the diagonal of the box can be found as:Diagonal = √(length² + breadth² + height²)
Diagonal = √(8² + 6² + 2²)
Diagonal = √(64 + 36 + 4)
Diagonal = √104
Diagonal = 2√26Therefore, the maximum length of a pencil that can be kept in the rectangular box is 2√26 cm, which corresponds to option C.

Two coins are tossed simultaneously, so there are four possible outcomes ie, HH,HT,TT,TH
Total number of outcomes=4
Probability of getting no head=no. of favourable outcomes/ total no. of outcomes
=1/4

Roots of the equation means a value of x such that the equation becomes zero when that value is substituted. If the equation can be represented into product of two linear equations then the roots can be found by keeping each of the equation equal to zero.We know two numbers in multiplication is equal to zero only when either of the number is zero.So we get zeros of the equation putting the two linear equations equal to 0

tan 1 . tan 2 . tan 3 ... tan 87 . tan 88 . tan 89 = LHS 
tan 1 . tan 2 . tan 3 ... tan (90 - 3 ) . tan ( 90 - 2 ) . tan ( 90 - 1)
tan 1 . tan 2  . tan 3 ... cot 3 . cot 2 . cot 1 

tan 1 . cot 1 . tan 2 . cot 2 . tan 3 . cot 3 ... tan 89 . cot 89 
1 x 1 x 1 x 1 x ... x 1 
As 1ⁿ = 1  = RHS