IRDAI Assistant Manager Mock Test - 1 - Insurance Exams MCQ

D who was preparing for CGL, was seated at one of the edges and to the immediate right of C.

B who was seated opposite to C, was seated adjacent to the person preparing for BOB.

Case 1: The person preparing for BOB was seated to the immediate left of B

Case 2: The person preparing for BOB was seated to the immediate right of B

Two people were preparing for NIACL and one of them was seated immediate left of H. H was preparing for AXIS.

Case 1a:

Case 1b:

Case 2a:

Case 2b:

A was seated adjacent to F and also was second to the left of G who was preparing for SBI. So, case 1a and 2b are invalid.

Case 1b:

Case 2a:

Now we have the conditions that :

The person preparing for LVB was seated opposite to the one preparing for SBI.

Two persons who were preparing for same exam were not seated adjacent to each other.

So, case 2a is not valid.

Finally, we have:

Case 1b:

H was seated third to the right of the person preparing for LVB.

1^st January is Saturday, so, 3^rd is Monday.

U was held on Tuesday.

T was held on odd numbered date and, after U.
T was not held at the last.
Hence, case 2 is invalid.

G was held on an even numbered date.
Two conferences were held in between L and G, L being before G.
M was held immediately before G.

S was held immediately before C, which was held after G.
Number of conferences held after S is same as that held before M.
Hence, case 1(a), case 1(c)-(i) and case 1(c)-(ii) become invalid.
We get,

A was held before N.
Hence, final arrangement -

S was held on Sunday.

• There are seven chairs between M and F when counted from left of F.
• G sits third to the left of M, who faces towards the centre.

We get,
Case 1: If F faces outwards

Case 2: If F faces inwards

• G sits third to the left of L, who sits immediate right of K.
• No one sits to the immediate left of L. R doesn't sit adjacent to F.
• The number of chairs between F and K, and the number of chairs between R and F is equal but the number is neither a prime number nor a composite number.

We get,
If the no. is neither a prime nor a composite, it means the no. of chair between F & K, and R & F is 1.
Case 1: This case is invalid because there should be 1 chair between the chairs on which F and K sit.

Case 2:

• U sits fourth to the right of R. R and S face the opposite direction.
• S sits second to the left of T, who doesn't face inwards.
• The chair to the immediate right of the one on which S sits is vacant.
• S doesn't sit third to the right of the one who sits fifth to the right of L.

We get,
Case 2: U sits 4^th to the right of R, so R must face outwards. And hence S must face inwards.
T and S must sit adjacent to G. They cannot sit adjacent to U because S cannot sit 3^rd to the right of R, who sits 5^th to the right of L.

Hence, the final arrangement is as follows:

We cannot determine who sits 4^th to the right of U because we don't know which direction U faces.

• There are seven chairs between M and F when counted from left of F.
• G sits third to the left of M, who faces towards the centre.

We get,
Case 1: If F faces outwards

Case 2: If F faces inwards

• G sits third to the left of L, who sits immediate right of K.
• No one sits to the immediate left of L. R doesn't sit adjacent to F.
• The number of chairs between F and K, and the number of chairs between R and F is equal but the number is neither a prime number nor a composite number.

We get,
If the no. is neither a prime nor a composite, it means the no. of chair between F & K, and R & F is 1.
Case 1: This case is invalid because there should be 1 chair between the chairs on which F and K sit.

Case 2:

• U sits fourth to the right of R. R and S face the opposite direction.
• S sits second to the left of T, who doesn't face inwards.
• The chair to the immediate right of the one on which S sits is vacant.
• S doesn't sit third to the right of the one who sits fifth to the right of L.

We get,
Case 2: U sits 4^th to the right of R, so R must face outwards. And hence S must face inwards.
T and S must sit adjacent to G. They cannot sit adjacent to U because S cannot sit 3^rd to the right of R, who sits 5^th to the right of L.

Hence, the final arrangement is as follows:

Total 17 chairs are arranged around the table.

Xena, who was the invigilator of this orientation session, left the departmental training session at 4:30pm due to some personal reason for few minutes.

Thus, Departmental training possible timings are - 3pm to 5pm, 4pm to 6pm

But from 5pm to 6pm there is Tea break. So, the timing of departmental training is from 3pm to 5pm.

None of the same department orientations are consecutive including breaks (for example: If HR orientation is at 12 pm slot then the other HR orientation can't be at 2pm or 11pm slot). None of the HR orientation is after tea. First slot is not of HR.

Last slot is of IT orientation.

Admin session is just before one of the breaks.

This is the final arrangement.

Departmental training and HR are between the two breaks.

Ten persons O to X live in a ten-storey building.
Three persons live between R and P, who lives on the topmost floor.
Four persons live between Q and R.

T and U live between W and S. W lives immediately below R.

Thus, either none or seven persons live between P and S.

• A is grandfather of E who is nephew of H.
• No two siblings are of same gender
• I is unmarried sister of E.

• B is son-in-law of D.
• Neither A & D nor B & E are couple.

Since C & F is a couple and A cannot marry B because of same gender.

Therefore only person D can marry B because 4 couples are there

• C who is husband of F is only child of G.
• No two siblings are of same gender

G is married to A because using other possibility that F is daughter of A will lead to a situation in which F only has father & C also has single parent. But, according to condition either both or none parents is alive
C is father of E who is a male.

• Point N is 15m north of P and P is east of Q. Point Q is 25m south-west of point N.

Length of PN = 15m

Length of QN = 25m

Then, PQ = (25² - 15²)^1/2

PQ = 20m

• P is 24m west of R and Q is 18m north of S, which is 12m west of M.

Based on above data we get:

From above data we get:

NP = 15m

QS = 18m

KG = 12m

Then, Pa = (18 - 12) = 6m

Na = (15 + 6) = 21m

TG = Ka = 10m

Then, NK = (21² + 10²)^1/2

Thus, the shortest distance between N and K ≈ 23.2m

Let total persons in queue = N

Rakhi's position from the front = 16

Raina's position from the front = N - 45 + 1 = N - 44

Number of persons standing between Rakhi and Raina = 56

So,

Case I: Rakhi is ahead of Raina.

N - 44 - 16 - 1 = 56

N = 117 (valid case)

Case II: Raina is ahead of Rakhi

16 - (N - 44) - 1 = 56

N = 16 + 44 - 1 - 56

N = 3, which is not possible at all.

Thus,

Total persons in queue = 117

C introduces the topic of the Eiffel Tower. E provides historical context about the tower's completion and purpose. D provides information about the architect, the tower's dimensions, and its significance in terms of height. A further gives details about the tower's composition and its accessibility to visitors. B then highlights the tower's symbolic importance and its popularity among tourists. F, being fixed, lastly elaborates on the tower's broader cultural impact and recognition in various forms of media and art. So, when rearranged in the order CEDABF, the statements create a coherent and logical description of the Eiffel Tower, covering its historical context, design, significance, popularity, and cultural impact.
The third sentence after rearrangement should be D. Hence, (a) is the correct answer.

Refer to the following sentence from the first paragraph. "The robust economic recovery after two waves
of COVID-19 and the unexpected heat wave have brought back power cuts." So, I and III are correct.
II is nowhere discussed in the passage.
Hence, option c) is correct.

Refer to the following sentence from the first paragraph. "The Government is undertaking emergency measures such as cancelling passenger trains so as to be able to get the Indian Railways to transport more coal to power plants and issuing directives to use more imported coal to tide over the supply shortfall". The same is mentioned in option d).
Hence, option d) is correct.

The word 'improve' does not fit in the given sentence. Similarly, the word 'discourage' (means 'prevent or try to prevent (something) by showing disapproval') cannot replace the first highlighted word as it is contextually incorrect. This eliminates option a). The infinitive marker 'to' takes a root verb after it. So, the use of 'revival'(noun) is incorrect in place of the first highlighted word. Similarly, 'revives' [third person present] can also be eliminated. Hence, the answer is option d) where 'revive'(means 'bring back to life; give new strength to') and 'pushed'(which is a part of the idiom 'push to' that means 'to forcibly move someone or something to a particular position') fit in the sentence.

Note:

Infinitive marker: A word or affix attached to the stem of a verb in order to form the full infinitive. In English, to is the infinitive marker.

"Infinitive: The infinitive is the base form of a verb, often preceded by to.

Consider the sentences given below:

· To err is human. [like a noun, the infinitive ‘to err’ is the subject of the verb ‘is’]

· My father likes to cook. [like a noun, the infinitive ‘to cook’ is the object of the verb ‘likes’]

· To vote in elections is our right. [the infinitive ‘to vote’, like a noun, is the subject of the verb ‘is’, but, like a verb, it also takes an object (elections)]

· Radha went to the lake to fetch water. [the infinitive ‘to fetch’, like a noun, is the object of the verb ‘went’, but, like a verb, it also takes an object (water)]

· The above sentences illustrate various ways in which infinitives are used. It can both act as a noun and a verb."

PNB MetLife India Insurance Co. Ltd., a prominent life insurer, announced the appointment of Sameer Bansal as Managing Director and Chief Executive Officer, starting July 1, 2024, subject to the necessary regulatory approvals. He joined PNB MetLife in 2007 and currently serves as Chief Distribution Officer and a member of the leadership team.

The United Nations proclaimed 2025 as the International Year of Quantum Science and Technology (IYQ). According to the proclamation, this year-long, worldwide initiative will "be observed through activities at all levels aimed at increasing public awareness of the importance of quantum science and applications." Led by the nation of Mexico, in May 2023 the Executive Board of the United Nations Educational, Scientific, and Cultural Organization (UNESCO) endorsed a resolution encouraging official UN proclamation, followed by an endorsement of the full UNESCO General Conference in November 2023, which was co-sponsored by nearly 60 countries.

UNDP and Global Environment Facility launched a new $135 million Blue and Green Islands Integrated Programme (BGI-IP) during the Fourth International Conference on Small Island Developing State. The BGI-IP will support 15 SIDS, selected through "Expressions of Interest" process, representing all SIDS sub-regions: the Caribbean, Pacific, Atlantic, Indian Ocean and South China Sea. This initiative aims to emphasize the crucial role of nature and expand nature-based solutions to combat environmental degradation in three key sectors: urban development, food production, and tourism.

TechFini, a Mumbai-based fintech startup, has completed certification from NPCI to facilitate UPI-based payment solutions to Banks, Financial Institutions, and Fintech. The Fintech company has also been approved for UPI Unified Dispute and Issue Resolution (UDIR). The addition of UDIR makes the startup one of the few platforms that supports this capability, which will be a game changer in addressing the intricacies of conflict resolution. The Unified Payments Interface (UPI)-based transactions hit Rs 20070.81 billion in June, up 49% year on year (YoY), according to data provided by the National Payments Corporation of India. The transaction volume in June amounted at Rs. 13885.14 million. In light of this environment, the startup's ability to facilitate the NPCI-led UDIR and give UPI users a platform to easily address their disputes is a significant breakthrough.The NPCI certifications authenticate TechFini's dedication to payment technology innovation and provide authentication to its clients.

Bajaj Housing Finance is venturing into the affordable housing finance sector and has launched Sambhav Home Loans targeting first time home buyers with affordable income criteria. The income norm for first-time homebuyers, under this new product, starts from Rs. 10,000 per month, with loan amounts as low as Rs. 10 lakh. Borrowers will have attractive interest rates with affordable EMIs and the option to choose a repayment tenor of up to 20 years. Earlier last month, the company filed its preliminary papers with SEBI to raise Rs. 7,000 crore via an initial public offering (IPO).

Indian Air Force (IAF) and Indian Army have jointly carried out a first-of-its-kind precise para-drop operation of the Aarogya Maitri Health Cube at a high-altitude area close to 15,000 feet. These critical trauma care cubes have been indigenously developed under Project BHISHM (Bharat Health Initiative for Sahyog Hita and Maitri). The operation was in line with Prime Minister Shri Narendra Modi's vision of providing critical supplies to affected areas affected by Humanitarian Aid and Disaster Relief (HADR). The IAF utilised its advanced tactical transport aircraft C-130J Super Hercules to airlift and precisely para-drop the cube. The Indian Army's Para Brigade, known for its operational acumen and agility, played an major role in the successful deployment of the trauma care cube, utilising its advanced precision drop equipment. The successful para-drop and deployment of the BHISHM trauma care cube exemplified the synergy & jointness of the Armed Forces and underscored the commitment to providing timely assistance as first responder.

Prime Minister Narendra Modi on Friday presented four BHISHM (Bharat Health Initiative for Sahyog Hita and Maitri) Cubes to the Ukrainian government during his visit to the war-torn country where he met President Volodymyr Zelenskyy under the shadow of the raging war with Russia. Each BHISHM Cube consists of medicines and equipment for the first line of care for all kinds of injuries and medical situations. "It also includes surgical equipment for a basic operation room that can manage 10-15 basic surgeries per day. The Cube can handle about 200 cases of diverse nature in emergencies such as trauma, bleeding, burns, fractures, etc. It can also generate power and oxygen in limited amounts. A team of experts from India has been deployed to provide initial training to the Ukrainian side to operate the cube.

Number of candidates who learn German language and Italian language together from institute S = 1320
Number of candidates who learn German language from institute S = 880
Number of candidates who learn Italian language from institute S = 1320 - 880 = 440
Similarly, calculating the remaining data:

Required average = (440 + 600)/2 = 520

The pattern is as follows:

2 x 4 + 8 = 16

3 x 5 + 9 = 24

4 x 6 + 10 = 34

5 x 7 + 11 = 46

6 x 8 + 12 = 60

7 x 9 + 13 = 76

From equation I:
10x² + 7x - 12 = (2x + 3)(5x - 4) = 0
=> x = -3/2, 4/5
From equation II:
y² + 23y + 132 = (y + 12)(y + 11) = 0
=> y = -12, -11

So, x > y

From equation I:
x² + 5x - 66 = (x - 6)(x + 11) = 0
=> x = 6, -11
From equation II:
y² + 31y + 210 = (y + 21)(y + 10) = 0
=> y = -21, -10

So, relationship cannot be established between x and y

Let speeds of A and B be 'a' km/h and 'b' km/h, respectively.

Relative speeds of A and B when travelling towards each other = (a + b)

According to the question:

54/(a + b) = 48/60 = 4/5

(a + b) = (54 * 5)/4

(a + b) = 67.5 ........ (1)

[a * (48/60)] - [b * (48/60)] = 2

(a - b) = 2 * (5/4)

(a - b) = 2.5 ......... (2)

From (1) and (2):

a = (67.5 + 2.5)/2 = 35

Speed of A = a

= 35 km/h

Total number of coins of both the denominations in bag A = 25 * 2 = 50

Let number of coins of ₹5 denomination and that of ₹10 denomination in bag A be 'a' and '50 - a' respectively.

Now,

[(50 - a) * 10] - [a * 5] = 20

500 - 10a - 5a = 20

15a = 480

a = 32

Total number of coins of both the denominations in bag B = 30 * 2 = 60

Let number of coins of ₹5 denomination and that of ₹10 denomination in bag B be 'b' and '60 - b' respectively.

Now,

[(60 - b) * 10] - [b * 5] = 30

600 - 10b - 5b = 30

15b = 570

b = 38

Total number of coins of both the denominations in bag C = 20 * 2 = 40

Let number of coins of ₹5 denomination and that of ₹10 denomination in bag C be 'c' and '40 - c' respectively.

Now,

[(40 - c) * 10] - [c * 5] = 10

400 - 10c - 5c = 10

15c = 390

c = 26

Total number of coins of both the denominations in bag D = 35 * 2 = 70

Let number of coins of ₹5 denomination and that of ₹10 denomination in bag D be 'd' and '70 - d' respectively.

Now,

[(70 - d) * 10] - [d * 5] = 40

700 - 10d - 5d = 40

15d = 660

d = 44

Total number of coins of both the denominations in bag E = 15 * 2 = 30

Let number of coins of ₹5 denomination and ₹10 denomination in bag E be 'e' and '30 - e' respectively.

Now,

[(30 - e) * 10] - [e * 5] = 30

300 - 10e - 5e = 30

15e = 270

e = 18

Total worth of both the denominations coins in bag C = 26 * 5 + 14 * 10 = 130 + 140 = ₹270

Total worth of both the denominations coins in bag E = 18 * 5 + 12 * 10 = 90 + 120 = ₹210

Required ratio = 270: 210

= 9: 7

Number of students who attempted the exam on Friday in shift I, II, and III = 244

Number of students who attempted the exam on Friday in shift III, and IV = 106

Number of students who attempted the exam on Friday in shift I = 90

And number of students who attempted the exam on Friday in shift IV = 36

So, number of students who attempted the exam on Friday in shift III = 106 - 36 = 70

Thus, number of students who attempted the exam on Friday in shift II = 244 - 90 - 70 = 84

Similarly, calculating the remaining data:

The number of students who attempted the exam on Monday in shift I = 80

The number of students who attempted the exam on Thursday in shift II = 54 - 6 = 48

The number of students who attempted the exam on Thursday in shift I = 116 - 48 = 68

So, required difference = 80 - 68 = 12

In University A:

Let number of students who play Hokey, Baseball and Cricket are H, B and C respectively.

H + B = 276 ---(1)

B + C = 252 ---(2)

C + H = 312 ---(3)

Adding equation (1), (2) and (3), we get

2(H + B + C) = 276 + 252 + 312

=> H + B + C = 420 ---(4)

So, from (1) and (4) equations, we get

C = 420 - 276 = 144

And, from (2) and (4), we get

H = 420 - 252 = 168

And, from (3) and (4), we get

B = 420 - 312 = 108

Calculating the remaining data:

Required ratio = (136 + 140): (136 + 134) = 276: 270 = 46: 45

Unit price of all Red coloured tickets = Rs.8

Unit price of all Blue coloured tickets = Rs.15

Monday:

Total tickets sold = 50

Let Red coloured tickets sold = x

Blue coloured tickets sold = (50 - x)

According to question-

(8 * x): [15 * (50 - x)] = 56: 45

x: (50 - x) = 7: 3

3x = 350 - 7x

10x = 350

x = 35

Red coloured tickets sold = x = 35

Total amount collected after selling all the Red coloured tickets = 35 * 8 = Rs.280

Blue coloured tickets sold = (50 - x) = 15

Total amount collected after selling all the Blue coloured tickets = 15 * 15 = Rs.225

Total amount collected after selling both type of tickets = 280 + 225 = 505

Tuesday:

Total amount collected after selling both type of tickets = 835

Total amount collected after selling all the Red coloured tickets = Rs.160

Total amount collected after selling all the Blue coloured tickets = 835 - 160 = Rs.675

Red coloured tickets sold = x = 160/8 = 20

Blue coloured tickets sold = 675/15 = 45

Wednesday:

Let Red coloured and Blue coloured tickets sold is (y + 10) and 'y' respectively.

Total amount collected after selling all the Red coloured tickets = (y + 10) * 8 = (8y + 80)

Total amount collected after selling all the Blue coloured tickets = y * 15 = 15y

According to question-

15y - (8y + 80) = 130

7y = 210

y = 30

Red coloured tickets sold = (y + 10) = 40

Blue coloured tickets sold = y = 30

Total amount collected after selling all the Red coloured tickets = (8y + 80) = Rs.320

Total amount collected after selling all the Blue coloured tickets = 15y = Rs.450

Total amount collected after selling both type of tickets = 320 + 450 = Rs.770

Total amount collected after selling all the Red coloured tickets on all the three days together = 280 + 160 + 320 = 760

Total amount collected after selling all the Blue coloured tickets on all the three days together = 225 + 675 + 450 = 1350

Required ratio = 760: 1350 = 76: 135

Unit price of all Red coloured tickets = Rs.8

Unit price of all Blue coloured tickets = Rs.15

Monday:

Total tickets sold = 50

Let Red coloured tickets sold = x

Blue coloured tickets sold = (50 - x)

According to question-

(8 * x): [15 * (50 - x)] = 56: 45

x: (50 - x) = 7: 3

3x = 350 - 7x

10x = 350

x = 35

Red coloured tickets sold = x = 35

Total amount collected after selling all the Red coloured tickets = 35 * 8 = Rs.280

Blue coloured tickets sold = (50 - x) = 15

Total amount collected after selling all the Blue coloured tickets = 15 * 15 = Rs.225

Total amount collected after selling both type of tickets = 280 + 225 = 505

Tuesday:

Total amount collected after selling both type of tickets = 835

Total amount collected after selling all the Red coloured tickets = Rs.160

Total amount collected after selling all the Blue coloured tickets = 835 - 160 = Rs.675

Red coloured tickets sold = x = 160/8 = 20

Blue coloured tickets sold = 675/15 = 45

Wednesday:

Let Red coloured and Blue coloured tickets sold is (y + 10) and 'y' respectively.

Total amount collected after selling all the Red coloured tickets = (y + 10) * 8 = (8y + 80)

Total amount collected after selling all the Blue coloured tickets = y * 15 = 15y

According to question-

15y - (8y + 80) = 130

7y = 210

y = 30

Red coloured tickets sold = (y + 10) = 40

Blue coloured tickets sold = y = 30

Total amount collected after selling all the Red coloured tickets = (8y + 80) = Rs.320

Total amount collected after selling all the Blue coloured tickets = 15y = Rs.450

Total amount collected after selling both type of tickets = 320 + 450 = Rs.770

Total Red coloured tickets sold on Wednesday = 40% of (35 + 20 + 40) = 38

Total Blue coloured tickets sold on Wednesday = 30% of (15 + 45 + 30) = 27

Total amount collected after selling both type of tickets = (38 * 8) + (27 * 15) = Rs.709