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JEE Advanced Test- 9 - JEE MCQ


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30 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Advanced Test- 9

JEE Advanced Test- 9 for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2025 preparation. The JEE Advanced Test- 9 questions and answers have been prepared according to the JEE exam syllabus.The JEE Advanced Test- 9 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Advanced Test- 9 below.
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JEE Advanced Test- 9 - Question 1

A particle performs SHM with a time period T and amplitude 'a'. The magnitude of average velocity of the particle over the time interval during which it travels a distance a/T from the extreme position is :

Detailed Solution for JEE Advanced Test- 9 - Question 1

JEE Advanced Test- 9 - Question 2

A simple pendulum 50 cm long is suspended from the roof of a cart accelerating in the horizontal direction with constant acceleration √3 g m/s2. The period of small oscillations of the pendulum about its equilibrium position is (g = π2 m/s2) :    

Detailed Solution for JEE Advanced Test- 9 - Question 2

With respect to the cart, equilibrium position of the pendulum is shown.If displaced by small angle θ from this position, then it will execute SHM about this equilibrium position,
time period of which is given by :

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JEE Advanced Test- 9 - Question 3

A particle is subjected to two simple harmonic motions along x and y directions according to, x = 3 sin 100 πt; y = 4 sin 100 πt :

Detailed Solution for JEE Advanced Test- 9 - Question 3

JEE Advanced Test- 9 - Question 4

When a wave pulse traveling in a string is reflected from a rigid wall to which string is tied as shown in figure. For this situation two statements are given below :                 

   

    (1) The reflected pulse will be in same orientation of incident pulse due to a phase change of p radians
    (2) During reflection the wall exert a force on string in upward direction
    For the above given two statements choose the correct option given below :

Detailed Solution for JEE Advanced Test- 9 - Question 4

Reflected pulse will be inverted as it is reflected by a denser medium. The wall exerts force in downward direction.
 

JEE Advanced Test- 9 - Question 5

The equation of displacement due to a sound wave is s = s0 sin2 (ω t - kx). If the bulk modulus of the medium is B, then the equation of pressure variation due to that sound is :

Detailed Solution for JEE Advanced Test- 9 - Question 5

JEE Advanced Test- 9 - Question 6

A point source of power 50π watts is producing sound waves of frequency 1875Hz. The velocity of sound is 330m/s, atmospheric pressure is 1.0 x 105 Nm-2, density of air is 1.0 kgm-3.  Then pressure amplitude at r =  m from the point source is (using π = 22/7) :      

Detailed Solution for JEE Advanced Test- 9 - Question 6

V are power, pressure amplitude and velocity respectively.

JEE Advanced Test- 9 - Question 7

An organ pipe of length L is open at one end and closed at other end. The wavelengths of the three lowest resonating frequencies that can be produced by this pipe are :

Detailed Solution for JEE Advanced Test- 9 - Question 7

JEE Advanced Test- 9 - Question 8

A wire having a linear mass density 5.0 ´ 10-3 kg/m is stretched between two rigid supports with a tension of 450 N. The wire resonates at a frequency of 420 Hz. The next higher frequency at which the same wire resonates is 480 Hz. The length of the wire is :

Detailed Solution for JEE Advanced Test- 9 - Question 8

Two consecutive frequencies are 420 Hz & 480 Hz. So the fundamental frequency will be 60 Hz.

*Multiple options can be correct
JEE Advanced Test- 9 - Question 9

A particle is executing SHM between points -Xm and Xm, as shown in figure-I. The velocity V(t) of the particle is partially graphed and shown in figure-II. Two points A and B corresponding to time t1 and time t2 respectively are marked on the V(t) curve :

Detailed Solution for JEE Advanced Test- 9 - Question 9

At time t1, velocity of the particle is negative i.e. going towards –Xm. From the graph, at time t1, its speed is decreasing. Therefore particle lies in between –Xm and 0.
At time t2, velocity is positive and its magnitude is less than maximum i.e. it has yet not crossed O.
It lies in between –Xm and 0.
Phase of particle at time t1 is (180 + θ1).
Phase of particle at time t2 is (270 + θ2)
Phase difference is 90 + (θ2 – θ1)
θ2 – θ1 can be negative making  < 90° but can not be more than 90°.

*Multiple options can be correct
JEE Advanced Test- 9 - Question 10

In a standing wave on a string rigidly fixed at both ends.

Detailed Solution for JEE Advanced Test- 9 - Question 10

*Multiple options can be correct
JEE Advanced Test- 9 - Question 11

For a certain transverse standing wave on a long string, an antinode is formed at x = 0 and next to it, a node is formed at x = 0.10 m. the displacement y(t) of the string particle at x = 0 is shown in figure.

Detailed Solution for JEE Advanced Test- 9 - Question 11

*Multiple options can be correct
JEE Advanced Test- 9 - Question 12

A wave pulse moving in the positive x-direction along the x-axis is represented by the wave function  where x and y are in centimeters and t is in seconds. Then  

Detailed Solution for JEE Advanced Test- 9 - Question 12

JEE Advanced Test- 9 - Question 13

Statement-1 : A particle is moving along x-axis. The resultant force F acting on it is given by F = – ax – b. Where a and b are both positive constants. The motion of this particle is not SHM.

Statement-2 : In SHM resultant force must be proportional to the displacement from mean position.

Detailed Solution for JEE Advanced Test- 9 - Question 13

The mean position of the particle in statement-1 is x = -(b/a). and the force is always proportional to displacement
from this mean position. The particle executes SHM about this mean position. Hence statement-1 is false

JEE Advanced Test- 9 - Question 14

Statement-1 : Two waves moving in a uniform string having uniform tension cannot have different velocities.

Statement-2 : Elastic and inertial properties of string are same for all waves in same string. Moreover speed of wave in a string depends on its elastic and inertial properties only.

Detailed Solution for JEE Advanced Test- 9 - Question 14

Two waves moving in uniform string with uniform tension shall have same speed and may be moving in opposite directions. Hence both waves may have velocities in opposite direction. Hence statement-1 is false.
 

JEE Advanced Test- 9 - Question 15

Statement-1 : In a small segment of string carrying sinusoidal wave, total energy is conserved.

Statement-2 :  Every small part moves in SHM and in SHM total energy is conserved.

Detailed Solution for JEE Advanced Test- 9 - Question 15

Every small segment is acted upon by forces from both sides of it hence energy is not conserved, rather it is transmitted by the element.
 

JEE Advanced Test- 9 - Question 16

Statement-1 : When two vibrating tuning forks having frequencies 256 Hz and 512 Hz  are held near each other, beats cannot be heard.

Statement-2 : The principle of superposition of waves is valid only if the frequencies of both the interfering waves are equal or nearly equal.

Detailed Solution for JEE Advanced Test- 9 - Question 16

The principle of superposition of waves is always valid.
 

JEE Advanced Test- 9 - Question 17

A small block of mass m is fixed at upper end of a massless vertical spring of spring constant K =   and natural length '10L'. The lower end of spring is free and is at a height L from fixed horizontal floor as shown. The spring is initially unstressed and the spring-block system is released from rest in the shown position.

   

Q. At the instant speed of block is maximum, the magnitude of force exerted by spring on the block is :

Detailed Solution for JEE Advanced Test- 9 - Question 17

When speed of block is maximum, net force on block is zero. Hence at that instant spring exerts a force of magnitude 'mg' on block.
 

JEE Advanced Test- 9 - Question 18

A small block of mass m is fixed at upper end of a massless vertical spring of spring constant K =  and natural length '10L'. The lower end of spring is free and is at a height L from fixed horizontal floor as shown. The spring is initially unstressed and the spring-block system is released from rest in the shown position.

Q. As the block is coming down, the maximum speed attained by the block is :

Detailed Solution for JEE Advanced Test- 9 - Question 18

At the instant block is in equilibrium position, its speed is maximum and compression in spring is x given by 

JEE Advanced Test- 9 - Question 19

A small block of mass m is fixed at upper end of a massless vertical spring of spring constant K =   and natural length '10L'. The lower end of spring is free and is at a height L from fixed horizontal floor as shown. The spring is initially unstressed and the spring-block system is released from rest in the shown position.

Q. Till the block reaches its lowest position for the first time, the time duration for which the spring remains compressed is  :

Detailed Solution for JEE Advanced Test- 9 - Question 19

JEE Advanced Test- 9 - Question 20

There is a point source of sound placed at (0, h) as shown in figure. Two detectors D1 and D2 are placed at positions (D,d/2) and (D,– d/2) respectively. Take h < < D. The source emitted a sound pulse at a certain time. Assuming velocity of sound in the surrounding medium is v. 

Q. The time gap between the recordings made by the detectors will approximately be :  

Detailed Solution for JEE Advanced Test- 9 - Question 20

JEE Advanced Test- 9 - Question 21

There is a point source of sound placed at (0, h) as shown in figure. Two detectors D1 and D2 are placed at positions (D,d/2) and (D,– d/2) respectively. Take h < < D. The source emitted a sound pulse at a certain time. Assuming velocity of sound in the surrounding medium is v. 

Q. If the source emits continuous waves, and the pressures recorded by the two detectors are superposed at every instant in detector D0 (which is equidistant from D1 & D2), the resultant pressure amplitude will be maximum if the minimum frequency of the source is :  

Detailed Solution for JEE Advanced Test- 9 - Question 21

JEE Advanced Test- 9 - Question 22

There is a point source of sound placed at (0, h) as shown in figure. Two detectors D1 and D2 are placed at positions (D,d/2) and (D,– d/2) respectively. Take h < < D. The source emitted a sound pulse at a certain time. Assuming velocity of sound in the surrounding medium is v. 

Q. If the source is shifted slightly towards positive X direction. The minimum frequency required for the super posed pressure amplitude (detected at D0) to be maximum will (as compared to the answer in above question) :  

Detailed Solution for JEE Advanced Test- 9 - Question 22

JEE Advanced Test- 9 - Question 23

Detailed Solution for JEE Advanced Test- 9 - Question 23

JEE Advanced Test- 9 - Question 24

Match the statements in column-I with the statements in column-II.
            Column-I                                                            Column-II 
  (A)  A tight string is fixed at both ends and         (p)   At the middle, antinode is formed 
        sustaining standing wave                                       in odd harmonic
  (B)  A tight string is fixed at one end and           (q)   At the middle, node is formed 
        free at the other end                                              in even harmonic
  (C)  Standing wave is formed in an open organ   (r)    At the middle, neither node nor 
        pipe. End correction is not negligible.                     antinode is formed
  (D)  Standing wave is formed in a closed           (s)    Phase difference between SHMs of any
        organ pipe. End correction is not negligible.            two particles will be either p or zero.  

                                                                        (t)    The displacement of the particle in the                                                                                                                                                        middle is always non zero.

Detailed Solution for JEE Advanced Test- 9 - Question 24

(A) Number of loops (of length λ/2) will be even or odd and node or antinode will respectively be formed at the
middle.
Phase of difference between two particle in same loop will be zero and that between two particles in adjacent
loops will be π.
(B) and (D) Number of loops will not be integral. Hence neither a node nor an antinode will be formed in in the
middle.
Phase of difference between two particle in same loop will be zero and that between two particles in adjacent
loops will be π.
(C) Number of loops (of length λ/2) will be even or odd and antinode or node will respectively be formed at the
middle.
Phase of difference between two particle in same loop will be zero and that between two particles in adjacent loops will be π ..

JEE Advanced Test- 9 - Question 25

Acidic strength of marked hydrogen of following compound in decreasing order is

Detailed Solution for JEE Advanced Test- 9 - Question 25

JEE Advanced Test- 9 - Question 26

The correct IUPAC name of following compound is

Detailed Solution for JEE Advanced Test- 9 - Question 26

JEE Advanced Test- 9 - Question 27

A hydrocarbon (P) on ozonolysis in presence of zinc gives only one dicarbonyl compound, which gives both Tollen’s and iodoform test. Identify the structure of (P).

Detailed Solution for JEE Advanced Test- 9 - Question 27

JEE Advanced Test- 9 - Question 28

Consider the true/false of the following statements:
    S1: The most stable resonating structure of p-nitrophenol (not having aromatic ring) is .
    S2 : In  all C–O bonds are of equal length.
    S3 : CH3COONa is more resonance stabilised than the protonated acid CH3COOH.
    S4 : Benzene ring is more electron dense in phenol than phenoxide.

Detailed Solution for JEE Advanced Test- 9 - Question 28

S1: Most stable resonating structure is 

S4 : In  group has greater +m effect, so it makes phenoxide ion more electron dense.

JEE Advanced Test- 9 - Question 29

Choose the strongest base among the following :

Detailed Solution for JEE Advanced Test- 9 - Question 29

Only in (D) the l.p of N atom is not involved in resonance with benzene ring.
 

JEE Advanced Test- 9 - Question 30

A hydrocarbon ‘X’ C7H10 is catalytically hydrogenated to C7H14 ‘Y’. 'Y' gives six monochloro products after photochemical chlorination. The structure of 'X'  is -

Detailed Solution for JEE Advanced Test- 9 - Question 30

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