JEE Main Chemistry Test- 1 - JEE MCQ

Given,
Mass of gas = 20 g
Pressure of gas = 1 atm
Volume of gas = 5.6 L
Temperature of gas = 273 K
Using ideal gas law,

where,
P = pressure of the gas
V = volume of the gas
T = temperature of the gas
n = number of moles of the gas
R = gas constant = 0.0821
Latm/moleK
M = molar mass of gas
w = mass of gas
Now put all the given values in the formula, we get
Therefore, the molar mass of the gas is, 80.0475 g/mole

Therefore 2 moles will have 1.204*10²⁴ molecules of NH₃.

There are 3 atoms in each molecule, so 2 moles will have 3*(1.204*10²⁴) atoms

which is 3.61 * 10²⁴ atoms.

The spectrum of an atom depends on the number of electrons present in it. Here, helium has two electrons, so the spectrum of Li⁺ (Z = 3) is similar to that of helium because both He and Li⁺ have two electrons.

If the value of l=0, then electron lies in s-subshell which has spherical shape. So electron distribution is spherical.

Shape of orbital is given by azimuthal quantum number as it describes the subshell.

Magnetic quantum number determines the shift of atomic orbital due to external magnetic field i.e., zeeman effect.

Spin quantum number describes the spin of electron in particular orbital. Orientations of electron cloud is specified of a magnetic quantum number.

So B option is incorrect.

Because of intramolecular hydrogen bonding in (B), i.e., ortho nitrophenol, the vapour pressure of ortho nitrophenol is expected to be higher than paranitrophenol.

Therefore, the correct option is A.

In the given options, BeF3−​, Be forms three sigma bonds with three flourines.

So, hybridisation of Be becomes sp2. 

Hence, the correct answer is option A.

BF3​is trigonal planar which makes the angle as 120 degree.PF3​ is trigonal bipyramidal making the angle slightly less than 109 degrees ClF3​ is T-shaped making the least angle.

Li+ ion being smallest in size is heavily hydrated and thus Li+(aq) is largest in size.

Energy is released when an electron is added to the atom. Hence 1st electron affinity (EA1​) is always taken as negative. The addition of second electron to the negativity charged ions is opposed by Coulombic repulsion, hence energy has to be supplied for the addition of second electron. Hence (EA2​) is taken as positive. 

Addition of an electron to F− and O− ions will involve repulsions, hence their (EA2​) will be positive.
Due to stable fully filled configuration of Na+ (1s2 2s2 2p6) it has lower value of electron affinity than O. Hence O has highest electron affinity.

mol of C₂H₂ = 1/2 × mol of CHI₃
= 1/2 × 0.01 = 0.005
volume at N.T.P. = 0.005 × 22400 = 112 ml

Single bond is σ bond and double bond contains 1σ and 1 π bond. Therefore, it contains 7 σ and 1 π bond. Hence, total is 8

Maximum number of electron in a shell
= 2n²
= 2(7)²
= 98