JEE Main Chemistry Test- 10 - JEE MCQ

CH3CH2OH−→−HBrCH3CH2Br+H2OCH3CH2OH→HBrCH3CH2Br+H2O
In the given reaction, ethanol i.e. alcohol reacts with hydrogen bromide. The product formed is ethyl hydrogen bromide which is an alkyl halide along with water which is the by-product of the reaction.
In the reaction, an electron rich compound i.e. the bromine atom replaces the hydroxyl leaving group.
The reactions in which an electron rich compound replaces the leaving group is known as nucleophilic substitution reaction.
The mechanism of the reaction is as follows:

In the reaction mechanism, we can see that the simultaneous breaking and making of the bond occurs. The configuration is inverted. Thus, the mechanism of the reaction is SN2SN2 i.e. nucleophilic substitution bimolecular mechanism.

= –2 (3³ – 1³) = – 5² bar.m³ = – 5200 kJ
so, work done by the gas is 5200 kJ

In 1-4-dimethyl cyclohexane, the following indicated bonds can be formed in the given reaction condition

Therefore following dichlorides can be used for this purpose

(I) has two chiral carbons, hence it has four stereoisomers.

(II) Also has two chiral carbons but there are only three stereoismers as one of them is meso.

(1), (2), (3), (5), (6), (8) are soluble in NaHCO₃