All Courses
Get the App Signup / Login
Sign in Open App
JEE Exam  >  JEE Tests  >  Mock Tests for JEE Main and Advanced 2025  >  JEE Main Chemistry Test- 2 - JEE MCQ

JEE Main Chemistry Test- 2 - JEE MCQ


Test Description

25 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Main Chemistry Test- 2

JEE Main Chemistry Test- 2 for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2025 preparation. The JEE Main Chemistry Test- 2 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Chemistry Test- 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Chemistry Test- 2 below.
Solutions of JEE Main Chemistry Test- 2 questions in English are available as part of our Mock Tests for JEE Main and Advanced 2025 for JEE & JEE Main Chemistry Test- 2 solutions in Hindi for Mock Tests for JEE Main and Advanced 2025 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt JEE Main Chemistry Test- 2 | 25 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study Mock Tests for JEE Main and Advanced 2025 for JEE Exam | Download free PDF with solutions
JEE Main Chemistry Test- 2 - Question 1
Save

Which of the following alkenes will react fastest with  under catalytic hydrogenation conditions

JEE Main Chemistry Test- 2 - Question 2
Save

The heat of hydrogenation of 1-hexene is 126 . When a second double bond is introduced in the molecule, the heat of hydrogenation of the resulting compound is 230  . The resulting compound (diene) is

Detailed Solution for JEE Main Chemistry Test- 2 - Question 2
The Diene thus formed is more stable than the initial compound (and rest of the options) due to conjugation (a conjugated diene). Hence the heat of hydrogenation is more as the product will be a thermodynamically controlled one ie a TCP.
1 Crore+ students have signed up on EduRev. Have you? Download the App
JEE Main Chemistry Test- 2 - Question 3
Save

Heat of hydrogenation of benzene is 51 kcal/mol and its resonance energy is 36 kcal/mol. Then the heats of hydrogenation of cyclohexadiene and cyclohexene per mole respectively are

JEE Main Chemistry Test- 2 - Question 4
Save
 is adsorbed on palladium surface.It is a case of
JEE Main Chemistry Test- 2 - Question 5
Save

The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0°C is
JEE Main Chemistry Test- 2 - Question 6
Save
When 0.532 g of benzene (B.P.  C) is burnt in a constant volume system with an excess of oxygen, 22.3 KJ of heat is given out.  for the combustion process is given by :
JEE Main Chemistry Test- 2 - Question 7
Save

The heat released when  & HCl neutralize is :
JEE Main Chemistry Test- 2 - Question 8
Save
The heat of formation of  is 380 kcals/mole and that of  is 195 kcals/mole. The heat (in kcals/mole) of the thermite reaction is
JEE Main Chemistry Test- 2 - Question 9
Save
Enthalpy of Rhombic sulphur of C is
JEE Main Chemistry Test- 2 - Question 10
Save
In the gaseous equilibrium

the formation of  will be favored by
JEE Main Chemistry Test- 2 - Question 11
Save

The  for the decomposition of  (if its degree of dissociation under one atomic pressure is 90%) is
Detailed Solution for JEE Main Chemistry Test- 2 - Question 11
So2cl2---so2+cl2
1. 0. 0
1-.90. .90. .90
total moles at equill. = 1.90
xso2 =.90/1.90 xcl2=.90/1.90 xso2cl2= .10/1.90

kp = pso2 *pcl2 /pso2cl2
kp = .90*.90/1.90*.10 = 4.26
JEE Main Chemistry Test- 2 - Question 12
Save
The pH of  HCl is
JEE Main Chemistry Test- 2 - Question 13
Save
If the maximum concentration of  in water is 0.01M at 298K, its maximum concentration in 0.1M NaCl will be
Detailed Solution for JEE Main Chemistry Test- 2 - Question 13
Pbcl2 = pb +2 + 2 cl - S S 2s 
Ksp = s * (2s)^2 
Ksp = 0.01 * (4 * 10^-4) 
Ksp = 4*10^-6 
Let solubility in Nacl be s’ Pbcl2 = pb + 2cl S’ S’ 2s’ + 0.1 
Neglecting 2s’ Ksp remains same 4*10^-6 = s’ * (0.1) ^2 
By solving this S’ = 4 * 10^-4
JEE Main Chemistry Test- 2 - Question 14
Save

In a reversible chemical reaction at equilibrium, if the concentration of any one of the reactants is doubled, then the equilibrium constant will
JEE Main Chemistry Test- 2 - Question 15
Save
Ammonium hydrogen sulphide is contained in a closed vessel at 313 K when total pressure at equilibrium is found to be 0.8 atm. The value of Kp for the reaction
    
Detailed Solution for JEE Main Chemistry Test- 2 - Question 15
If dissociation of NH4HS is x then at equilibrium,

2x=0.8 ( Using PV= nRT you can equate partial pressure to total pressure.)
so, x= 0.4 atm.
Then Kp= [P]²= (0.4)²=0.16
JEE Main Chemistry Test- 2 - Question 16
Save
Reactivity of hydrogen atoms attached to different carbon atoms in alkanes has the order
JEE Main Chemistry Test- 2 - Question 17
Save
Reaction of ethene with  in  gives
JEE Main Chemistry Test- 2 - Question 18
Save
The major product obtained when isobutane is treated with chlorine in the presence of light is
JEE Main Chemistry Test- 2 - Question 19
Save
The compound contains atoms X,Y,Z. The oxidation number of X is 2, Y is 5 and Z is –2, a possible formula of the compound is
JEE Main Chemistry Test- 2 - Question 20
Save

 acts as
*Answer can only contain numeric values
JEE Main Chemistry Test- 2 - Question 21
Save

Enthalpy of neutralization of H3PO3 acid is –106.68 KJ/mole using NaOH. If enthalpy of neutralization of HCl by NaOH is –55.84 KJ/mole. Calculate ΔHionisation of H3PO3 into its ions. (in KJ)

Detailed Solution for JEE Main Chemistry Test- 2 - Question 21

H3PO3 → 2H+ + HPO3–2

2H+ + 2OH– → 2H2O
ΔH = –55.84 × 2 = –116.68
Now
–106.68 = ΔHion – 55.84 × 2
ΔHion = 5KJ/mol

*Answer can only contain numeric values
JEE Main Chemistry Test- 2 - Question 22
Save

An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :

Detailed Solution for JEE Main Chemistry Test- 2 - Question 22

*Answer can only contain numeric values
JEE Main Chemistry Test- 2 - Question 23
Save

100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon.

Detailed Solution for JEE Main Chemistry Test- 2 - Question 23

*Answer can only contain numeric values
JEE Main Chemistry Test- 2 - Question 24
Save

What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH (pH = 12.0)?

Detailed Solution for JEE Main Chemistry Test- 2 - Question 24

*Answer can only contain numeric values
JEE Main Chemistry Test- 2 - Question 25
Save

How many grams of NH4Cl should be dissolved per litre of solution to have a pH of 5.13 ? Kb for NH3 is 1.8 × 10–5.

Detailed Solution for JEE Main Chemistry Test- 2 - Question 25

NH4Cl  is a salt of strong acid and weak base for solutions of such salts.
pH = 1/2 [pKW – log C – pKb]
⇒ 10.26 = 14 – log C – 4.74
⇒ log C = 9.26 – 10.26 = –1.0
∴ C = 10–1 M
[NH4Cl] = 10–1 M
= 10–1 × 53.5 gL–1
= 5.35 gL–1

357 docs|148 tests
Join Course
Information about JEE Main Chemistry Test- 2 Page
In this test you can find the Exam questions for JEE Main Chemistry Test- 2 solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Main Chemistry Test- 2, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE

Important Questions for JEE Main Chemistry Test- 2

Find all the important questions for JEE Main Chemistry Test- 2 at EduRev.Get fully prepared for JEE Main Chemistry Test- 2 with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the JEE Main Chemistry Test- 2 syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of JEE Main Chemistry Test- 2 resources.

JEE Main Chemistry Test- 2 MCQs with Answers

Prepare for the JEE Main Chemistry Test- 2 within the JEE exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for JEE Main Chemistry Test- 2 Mock Tests for JEE Main and Advanced 2025

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace JEE Main Chemistry Test- 2 with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup