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JEE Main Physics Test- 3 - JEE MCQ


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25 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Main Physics Test- 3

JEE Main Physics Test- 3 for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2025 preparation. The JEE Main Physics Test- 3 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Physics Test- 3 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Physics Test- 3 below.
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JEE Main Physics Test- 3 - Question 1

Given that y = a cos,  where t represents time in second and x represents distance in metre. Which of the following statements is true ? 

JEE Main Physics Test- 3 - Question 2

The length of a rod is (11.050.05) cm. What is the length of the two rods ?

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JEE Main Physics Test- 3 - Question 3

The angle between vectors   and   is 

JEE Main Physics Test- 3 - Question 4

A ball is thrown vertically upward with a speed v from a height h meters above the ground. The time taken for the ball to hit ground is

Detailed Solution for JEE Main Physics Test- 3 - Question 4



Now retain only the positive sign.

JEE Main Physics Test- 3 - Question 5
A ball rolls from the top of a stair way with a horizontal velocity u m/s. If the steps are h metre high and b metre wide, the ball will hit edge of the nth step, if
Detailed Solution for JEE Main Physics Test- 3 - Question 5
Horizontal dist. travelled=nb Vertical dist. travelled=nh nb=ut nh=0+(1/2)gt^2 => n=(2hu^2)/(gb^2)
JEE Main Physics Test- 3 - Question 6
Which of the following is the altitude-time graph for a projectile thrown horizontally from the top of the tower?
Detailed Solution for JEE Main Physics Test- 3 - Question 6
When the time is 0 the object will be at a certain height and when we throw the object as the time increases the object will come down ie the altitude decreases.
JEE Main Physics Test- 3 - Question 7

A long spring is stretched by 2 cm. Its potential energy is U. If the spring is streched by 10 cm, its potential energy would be

Detailed Solution for JEE Main Physics Test- 3 - Question 7

We know, potential energy of spring is given by (1/2)kx^2 where k is spring constant and x is stretched distance.
Here , x=2cm so, U=(1/2)k*2^2=2k
For, x=10cm :-
E=(1/2)k*10^2=50k=25(2k)=25U.
Final potential energy will be 25U.

JEE Main Physics Test- 3 - Question 8

A uniform flexible chain of mass m and length 2 l hangs in equilibrium over a smooth horizontal pin of negligible diameter. One end of the chain is given a small vertical displacement so that the chain slips over the pin.The speed of chain when it leaves pin is

Detailed Solution for JEE Main Physics Test- 3 - Question 8

Key Concept:

If work done by non-conservative and external force acting on the system is zero, then mechanical energy of the system is conserved.

Initially centre of mass of chain was at distance 2l/4 below the pin and in final position it is at distance l/2 below the pin.

Here, non- conservative force and external force are absent , so we can apply conservation of mechanical energy.

∴U1+K1=U2+K2

Taking pin as a reference point,

JEE Main Physics Test- 3 - Question 9
A stone is tied with a string and is rotated in a circle horizontally. When the string suddenly breaks, the stone will move 
JEE Main Physics Test- 3 - Question 10

A sphere A of mass m moving with constant velocity u hits another stationary sphere B of the same mass in a head on collision. if e is the coefficient of restitution, what is the ratio of velocities of sphere A to the sphere B after collision?

JEE Main Physics Test- 3 - Question 11
A boy of mass m is standing on a block of mass M kept on a rough surface. When the boy walks from left to right on the block, the centre of mass (boy block) of system
JEE Main Physics Test- 3 - Question 12

The radius of gyration of a uniform rod of length L about on axis passing through its centre of mass is 

JEE Main Physics Test- 3 - Question 13

In case of an orbiting satellite if the radius of orbit is decreased 

Detailed Solution for JEE Main Physics Test- 3 - Question 13

KE=I w²=Iv²/r² ( since omega =v/r)
This implies that KE is inversely proportional to r²
So when radius is decreased , KE will increase due to which PE will decrease
Hence option D is correct.

JEE Main Physics Test- 3 - Question 14
For a satellite orbiting very close to earth’s surface total energy is
JEE Main Physics Test- 3 - Question 15
A point P (R ,0,0) lies on the axis of a ring of mass M and radius R. The ring is located in y-z plane with its centre at origin O. A small particle of mass m starts from P and reaches O under gravitational attraction only. Its speed of O will be
JEE Main Physics Test- 3 - Question 16
The number of molecules per unit volume of a gas is given by 
JEE Main Physics Test- 3 - Question 17

Pressure versus temperature graph of an ideal gas of equal number of moles of different volumes are plotted as shown in figure. Choose the correct alternative

JEE Main Physics Test- 3 - Question 18

A system undergoes a cyclic process in which it absorbs Q1 heat and gives out Q2 heat. The efficiency of the process is η and work done is W. Select the correct statement

Detailed Solution for JEE Main Physics Test- 3 - Question 18

Concept: Carnot engine. Explanation: Heat is transferred to the working material (Q1) and heat is rejected during (Q2). The thermal efficiency is  ηth = W/Q1. Applying first law, we have,  W = Q1 − Q2.  ηth = 1 − Q2/Q1. Hence, correct answer is (b).

JEE Main Physics Test- 3 - Question 19

A cylinder of radius R, made of a material of thermal conductivity k1,  is surrounded by a cylindrical shell of inner radius R and outer radius 2R. The shell is made of a material of thermal conductivity k2.  The two different temperatures. There is no loss of heat across the cylindrical surface and the system is in steady state. The effective thermal conductivity of the system is

Detailed Solution for JEE Main Physics Test- 3 - Question 19

R1 = Initial radius = R & R2 = final radius = 2R

  The two conductors are thermally in parallel. Therefore, equivalent thermal resistance R is given by:-

JEE Main Physics Test- 3 - Question 20
If you set up the seventh harmonic on a string fixed at both ends,how many nodes & anti nodes are set up in it
*Answer can only contain numeric values
JEE Main Physics Test- 3 - Question 21

In the arrangement shown coefficient of friction between the two blocks A and B is 0.6 and ground is frictionless. Force constant of spring is 900 N/m. Find the maximum elongation of spring (in cm) such that the blocks do not slip over each other when released.


*Answer can only contain numeric values
JEE Main Physics Test- 3 - Question 22

Two particles A & B are projected from top of two towers of height 300 m and 600 m with velocity 50 m/s and 250 m/s respectively. The angular velocity of B wrt A is α rad/min. Fill the value of 10a in OMR sheet


Detailed Solution for JEE Main Physics Test- 3 - Question 22

*Answer can only contain numeric values
JEE Main Physics Test- 3 - Question 23

A sphere of radius r is projected up an inclined plane for which  with a velocity v0 and initial angular velocity . The total time of rise is found to be Find k.


*Answer can only contain numeric values
JEE Main Physics Test- 3 - Question 24

A hemispherical bowl of radius R = 0.1m is rotating about its own axis (which is vertical) with an angular velocity ω. A particle of mass 10–2 kg on the frictionless inner surface of the bowl is also rotating with the same ω. The particle is at a height h from the bottom of the bowl. It is desired to measure 'g' using this set up, by measuring h accurately. Assuming that R and ω are known precisely and that the least-count in the measurement of h is 10–4 m, the numerical value of minimum possible error Δg in the measured value of g is given by α x 10–2 m/s2. Fill the value of α in OMR sheet.


Detailed Solution for JEE Main Physics Test- 3 - Question 24

*Answer can only contain numeric values
JEE Main Physics Test- 3 - Question 25

A bimetallic strip consisting of a brass strip and a steel strip, each of length 1 m and each of thickness 0.5 cm is clamped at one end  as shown in figure. Calculate the depression to the nearest integer (in cm) of the free end when it is heated by 100ºC. 
[Take : αiron = 11 × 10–6 K–1; αbrass = 19 × 10–6 K–1]


Detailed Solution for JEE Main Physics Test- 3 - Question 25


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