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KEAM Paper 1 Mock Test - 8 - JEE MCQ


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30 Questions MCQ Test KEAM Mock Test Series 2024 - KEAM Paper 1 Mock Test - 8

KEAM Paper 1 Mock Test - 8 for JEE 2024 is part of KEAM Mock Test Series 2024 preparation. The KEAM Paper 1 Mock Test - 8 questions and answers have been prepared according to the JEE exam syllabus.The KEAM Paper 1 Mock Test - 8 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for KEAM Paper 1 Mock Test - 8 below.
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KEAM Paper 1 Mock Test - 8 - Question 1

The frequency for which a 5 μF capacitor has a reactance of 1/1000 ohm is given by

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 1
Given:C=5uf Xc=1/1000. Xc=1/wc=1/1000 ,, wc=10002πf=1000/5u =200*10^6= F=100/π M Hz
KEAM Paper 1 Mock Test - 8 - Question 2

If the instantaneous current in a circuit is given by: I = 2cos(ω t + φ)A, then r.m.s. value of the current is

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KEAM Paper 1 Mock Test - 8 - Question 3

When the speed of electrons increases, then the value of its specific charge

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 3
Because these electrons are losing energy.
KEAM Paper 1 Mock Test - 8 - Question 4
To see first 20 lines of Balmer series distinctly, minimum resolving power of instrument should be
KEAM Paper 1 Mock Test - 8 - Question 5

In which of the following systems will the radius of the first orbit (n = 1) be minimum

KEAM Paper 1 Mock Test - 8 - Question 6

A ball weighing 10 g hits a hard surface vertically with a speed of 5 ms⁻1 and rebounds with the same speed. The ball remains in contact with the surface for 0.01 s. The average force exerted by the surface on the ball is

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 6
Since, F=P/T

where, P= change in momentum and T = total time

F= ( mv1 - mv2 )/T

F= { 0.01[5-(-5)]}/0.01

F=10 N
KEAM Paper 1 Mock Test - 8 - Question 7

A dipole of dipole moment p̅ is placed in uniform electric field E̅, then torque acting on it is given by

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 7
Torque=p×E.

It is due to the reason that torque is a vector quantity .therefore we use a cross product to measure the torque acting on the body
KEAM Paper 1 Mock Test - 8 - Question 8

In a certain 0.1m3 of space, electric potential is found to be 5V throughout. The electric field in this region is

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 8
Consider there is sphere of volume 0.1m3 now since it is in space it is a hollow sphere so electric field inside it will be zero now this was the easy method u can also do it by taking a sphere and deriving values. 
KEAM Paper 1 Mock Test - 8 - Question 9

A ball of mass 0.25 kg attached to the end of a string of length 1.96 m is moving in a horizontal circle. The string will break if the tension is more than 25 N. What is the maximum speed with which the ball can be moved?

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 9

Given,
Length of String, l = 1.96m
Mass of Ball, m = 0.25 Kg
Maximum Tension of String, Tmax = 25 N
Let the speed of the balls is v m/s
In the horizontal circular motion of the ball tension in the string is balanced by the centrifugal force (mv2/l) and hence the maximum tension in the string will be for the maximum speed of the ball (since m and l are fixed)
Therefore,

Therefore, maximum speed of the ball will be 14 m/s

KEAM Paper 1 Mock Test - 8 - Question 10

A ball of mass m strikes elastically a wall at an angle of 30º with velocity ν. The change in momentum is

KEAM Paper 1 Mock Test - 8 - Question 11

A current passing through a circular coil of two produces a magnetic field of 8 T at its centre. The coil is then rewound, so as to have four turns and current is passed through it is doubled. Now magnetic field at the centre of the coil will be

KEAM Paper 1 Mock Test - 8 - Question 12

The following figure shows a logic gate circuit with two inputs A and B and the output C. The voltage waveforms of A, B and C are as shown below.

The logic circuit gate is

KEAM Paper 1 Mock Test - 8 - Question 13

Sixty four spherical rain drops of equal size are falling vertically through air with a terminal velocity 1.5 m-s⁻1 If these drops coalesce to form a big spherical drop, then terminal velocity of big drop is

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 13

There is a general formula for calculating the velocity of big drop which is formed by the number of smaller drops The terminal velocity of bigger drop be v' The terminal velocity of smaller drop be v The total no.of smaller drop is 64(n) v'=v×n^2/3 v'=1.5×(64)^2/3 v'=24m/s

KEAM Paper 1 Mock Test - 8 - Question 14

An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 14
First resolve the motion is 2 components 1st horizontal and 2nd vertical .
1st vertical component :-

As there is no velocity in the vertical direction so in Italy velocity there will be zero but the gravitational force is acting in that direction so the accleration in the vertical direction will be g(10)m/s^2
Apply equation of motion here and u will get the time i.e about 19.79sec .
Then we have no acceleration in the horizontal direction so simply 
Velocity[horizontal] =distance /time 
Hence distance will be 3.3km approx 
KEAM Paper 1 Mock Test - 8 - Question 15

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A): When charges are shared between two bodies, there occurs loss of energy.
Reason(R): In case of sharing of charges, conservation of energy fails.

KEAM Paper 1 Mock Test - 8 - Question 16


Number of particles emitted in the reaction is

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 16
The mass number differs by 4 so 1 Alpha, and atomic number differs by 1 so one electron.
KEAM Paper 1 Mock Test - 8 - Question 17

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A): For refraction in a plane surface v can be used for the light moving from μ1 to μ2.
Reason(R): for light getting into a medium of index μ2 from μ1.

KEAM Paper 1 Mock Test - 8 - Question 18

The moment of inertia of a uniform disc about an axis passing through its centre and perpendicular to its plane is 1kg - m2. It is rotating with an angular velocity 100 radians/second. Another identical disc is gently placed on it so that their centres coincide. Now these two discs together continue to rotate about the same axis. Then the loss in kinetic energy in kilo joules is

KEAM Paper 1 Mock Test - 8 - Question 19
For a gas, if the ratio of specific heats at constant pressure and volume is γ, then the value of degree of freedom is
KEAM Paper 1 Mock Test - 8 - Question 20
Faraday is the unit of
KEAM Paper 1 Mock Test - 8 - Question 21
The penetration of light into the region of geometrical shadow is called
KEAM Paper 1 Mock Test - 8 - Question 22

Huygen's wave theory of light can not explain

KEAM Paper 1 Mock Test - 8 - Question 23
When a star moves away from earth, the spectrum of the star shifts towards higher wavelength side. This is due to
KEAM Paper 1 Mock Test - 8 - Question 24
A metal wire of linear mass density 9.8 g/m is stretched with a tension of 10 kg wt between two rigid supports 1 metre apart. The wire passes at its middle point between the poles of a permanent magnet and it vibrates in resonance when carrying an alternating current of frequency n. The frequency n of alternating source is
Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 24
The wire vibrates because of the magnetic force on it. When the alternating current completes one cycle, the wire completes one oscillation and hence the frequency of oscillation of the wir is the same as the frequency of the alternating current (n). Therefore we have

n = (1/2L)√(T/m) where L is the length of the segment of the wire betweenetween the supports, T is the tension and ‘m’ is the linear density (mass per unit length) of the wire. Substituting for L, T and m we have

n = (1/2)√[(10X9.8)/(9.8X10–3 )] = 50 Hz.
KEAM Paper 1 Mock Test - 8 - Question 25
Which of the following will give maximum ions in solution ?
Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 25
A) has 2 ions :- K+& (I3)- , b) & d) have 3 ions , While FeCl3 has 4 ions :- 1Fe+³ and 3 Cl- So (c) has maximum number of ions
KEAM Paper 1 Mock Test - 8 - Question 26

According to the Bohr model, electrons of quantum number n = 4 in excited hydrogen atoms can undergo transitions to lower energy states in different ways and give rise to photons of discrete frequencies. How many discrete frequencies are possible in this case?

KEAM Paper 1 Mock Test - 8 - Question 27

A parallel plate capacitor with air between the plates has a capacitance of 9 pF. The separation between its plates is 'd' . The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant K1 = 3 and thickness d 3 while the other one has dielectric constant K2 = 6 and thickness. 2d 3 Capacitance of the capacitor is now

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 27

KEAM Paper 1 Mock Test - 8 - Question 28

The angular speed of an engine wheel making 90 revolutions per minute is

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 28
Angular speed=2π × n =2π×(1.5rps)=3 rad/s
KEAM Paper 1 Mock Test - 8 - Question 29

The resistivity of a wire depends on its

KEAM Paper 1 Mock Test - 8 - Question 30

An electron moves in a circular orbit with a uniform velocity v. It produces a magentic field B at the centre of the circle. The radius of the circle is proportional to

Detailed Solution for KEAM Paper 1 Mock Test - 8 - Question 30

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