KIITEE Mock Test - 7 - JEE MCQ

speed of electron of the hydrogen atom in the ground state,

v₁ = 2.2 x 10⁶ m/s

Since

∴

[for third excited state. n₂ = 4]

⇒

5.5 x 10⁵ m/s

Let us suppose that original length simple pendulum is L and time period is now if the acceleration due to gravity is g.
Now the frequency should be 
Given the ratio of frequencies,it means,

α = I_C/I_E = 0.98 (given)

The ratio of collector current to the base current at constant collector-emitter voltage is given by

β = f_C/f_a

These are related as β = α/1-α

⇒ β = 0.98/1-0.98 = 0.98/0.02 = 49

The coil will orient in a position of torque equilibrium. 
As the torque on the loop is given by  so torque will be zero when area vector  is parallel to magnetic field i.e. when the plane of the coil is perpendicular to the magnetic field. This is so because area vector is perpendicular to the plane of the loop.

For simple cubic cells,

Packing effedency =

∴ Percentage of unoccupied volume in Scc = 100 - 52.4 = 47.6%

Mohr's salt is (NH₄)₂SO₄.FeSO₄.6H₂O.
The equation is 5Fe²⁺ + MnO^-₄ + 8H⁺ 5Fe³⁺ + Mn²⁺ + 4H₂O
Total change in oxidation number of iron = (+3) - (+2)
So, equivalent weight of Mohr's salt
= 
= 
= 392

At constant pressure, q_p = ΔU -W.

q_p = ΔU - pΔV

q_p = U₂ - U₁ - (-p(V₂ - V₁))

q_p = (U₂ + pV₂) - (U₁ + pV₁)

q_p = H₂ - H₁

q_p = ΔH

As we know, ΔH = ΔU + pΔV

ΔH = ΔU + W

Putting the value of ΔH in (1)

q_p = ΔU + W

Other corrected options are as follows:

• For adiabatic process ΔU = W

• For an isochoric process ΔU = q_v

• For an isothermal process q = -W

There are 4-metameric ethers that are represented by the molecular formula C₄H₁₀. Which are as follows

Electrochemical equivalent = Equivalent weight/96500

gm per coulomb. Its unit is kgC^-1.

⇒ 2 moles of sodium metal reacts to give 1 mole of ethane.

Also,

1 mole of Na metal = 23 g

∴ 2 motesol Na metal = 23x 2 = 46g

Thus, 46 g of sodium is required to prepare one mole of ethane from methyl chloride by Wurtz reaction.

p + q = - a, p.q = b
Now, p² q + q² p = pq(p + q)
= b(-a) = - ab
p²q . q²p = (pq)³ = b³
The required equation is
x² - (p²q + q²p) x+ (p²q . q²p) = 0
x² + abx + b³ = 0

Given, pair of lines, x² - 4pxy + 8y² = 0

Which is in the form of ax² + 2hxy + by² = 0

According to the question,

Sum of the slopes = 3 x product of the slopes

⇒ m₁ + m₂ = 3 x (m₁ m₂)

⇒

⇒ 4p = 3 ⇒ p = 3/4

According to the question, we get

Let E₁, E₂ and A be the events defined as follows
E₁ = six occurs
E₂= six does not occurs
A = the man reports that it is a six. We have.

Now, P(A/E₁)= Probability that the man reports that there is a six on the die given then 6 has occured on die
= Probability the man speaks truth

=3/4

P(A/E₂) = Probability that the man reports that there is six is on die given that six has not occured on die
= Probability that the man does not speak truth

We have to find P(E₁/A) i.e. the probability that there is six on the die given that the man has reported that there is six. By Baye's rule, we have

We know that, a_n = S_n - S_n-1

= 5(2ⁿ - 1) - 5(2^n-1 - 1)

= 5(2ⁿ - 2^n-1)

= 5(2^n-1)

On differentiating with respect to x

On substituting the values in equation (i)

Put sin^-1 (0.4) = θ ⇒ sin θ = 0.4

∴ E = sin(3θ) = 3 sinθ - 4sin³θ

= 3(0.4) - 4(0.4)³

= 1.2 -4(0.064)

= 1.2 - 0.256

= 0.944

A =

Therefor, |A| =

= (1 + 2i)(1 - 2i) + i²

= 1 - (2i)² + (-1) = 1 + 4 -1 = 4

∴ A(adj A) = |A| = 4i