KIITEE Mock Test - 7 - JEE MCQ

Time period of simple pendulum inside a stationary lift

..(i)

where, l = length of string and

g = gravitational acceleration

Acceleration of lift in upward direction,

a = g/3

∴ Time period of the pendulum

Given,
velocity of the particle is 
time instance is 1 sec.
The acceleration of the particle is the rate of change of velocity with respect to time thus, acceleration is given by,

Acceleration of the particle remains constant at all times.

The magnetic susceptibility of a substance shows how easily a substance am be magnetised and given by x_m = I/H

where, I = intensity of magnetisation,

and H = magnetic intensity of the field

From the given relation, F = y/√d

⇒ y = F√d

Substituting the above dimensions, we get [y] = [F][d]^½ = [MLT^-2][ML^-3T⁰]^½=[M^3/2L^-1/2T^-2]

As the block is released from rest, it means the initial velocity, (u) = 0

and let block cover a distance d at a time (t₁),

a = gsinθ.

We know,

Substituting values, we get,

When the block slides from a rough surface, then,

The coefficient of kinetic friction is applicable here as the block moves over the inclined plane.

P₄O₁₀ is not used to dehydrate ammonia because it reacts with ammonia forming ammonium phosphate.

CO(g) + (1/2)O₂(g) → CO₂(g), ΔH₂ = -Y, ….(ii)

For the formation of CO subtract Eqs. (ii) from (i), i.e,

∴ Δ_rH for formation of CO = ΔH₁ - ΔH₂

= -x+y or y-x

The hydroboration oxidation of an alkene will give the alcohol as the product and the OH group will attach to the carbon which is less hindered. Thus this reaction follows Anti-Markownikoff's rule.

Hence isobutylene on hydroboration oxidation will isobutyl alcohol.

For simple cubic cells,

Packing effedency =

∴ Percentage of unoccupied volume in Scc = 100 - 52.4 = 47.6%

For reaction can be written as:

Decarboxylation is the loss of carbon dioxide from carbonyl group of a molecule. Most carboxylic acids are quite resistant to moderate heat and melt or even boil without decarboxylation. Exceptions are carboxylic acids that have a carbonyl group  to the carboxyl group. This type of carboxylic group undergoes decarboxylation quite readily on mild heating. For example, phenoxyacetic acid brings its decarboxylation upon warming, more readily.

At Boyle's temperature, T = T_B and z = 1

E.g.

⇒ 2 moles of sodium metal reacts to give 1 mole of ethane.

Also,

1 mole of Na metal = 23 g

∴ 2 motesol Na metal = 23x 2 = 46g

Thus, 46 g of sodium is required to prepare one mole of ethane from methyl chloride by Wurtz reaction.

At constant pressure, heat given by one mole gas (qp) = nCpΔT

Reduction in the concentration of ozone in the ozone layer of the stratosphere is known as ozone depletion.
Various chemical pollutants like NO, CFC's etc., are responsible for ozone depletion.
In Antarctica, polar stratospheric clouds(PSCs) are observed during winters. This is due to the hydrolysis of chlorine nitrate resulting in hypochlorous acid. 

Hypochlorous acid further breaks down into chlorine free radicals in the presence of sunlight, causing the depletion of ozone.

p + q = - a, p.q = b
Now, p² q + q² p = pq(p + q)
= b(-a) = - ab
p²q . q²p = (pq)³ = b³
The required equation is
x² - (p²q + q²p) x+ (p²q . q²p) = 0
x² + abx + b³ = 0

According to the question, we get

∴ Required equation is

We know that, a_n = S_n - S_n-1

= 5(2ⁿ - 1) - 5(2^n-1 - 1)

= 5(2ⁿ - 2^n-1)

= 5(2^n-1)

= 2/17

Total number of ways of selecting a pair of numbers which are different from set (0,1,2,3,...,9)

Now, correct pair is only one. Hence, probability that the number dialed is correct = 1/90

sin^-1(1 - x) - 2 sin^-1 x = π/2
Option (1)
x = 0
sin^-1(1 - 0) - 2 sin^-1 0

Hence, 0 is a solution.



Now,  does not exist.
Option (2)


Hence, option (2) does not satisfy.
Option (3)
sin^-1(1 - 0) - 2 sin^-1 0

We have already checked that 0 is a solution.
Hence, option (3) is the solution.