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MAHATRANSCO AE Electrical Mock Test - 5 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test MAHATRANSCO AE Electrical Mock Test Series 2024 - MAHATRANSCO AE Electrical Mock Test - 5

MAHATRANSCO AE Electrical Mock Test - 5 for Electrical Engineering (EE) 2024 is part of MAHATRANSCO AE Electrical Mock Test Series 2024 preparation. The MAHATRANSCO AE Electrical Mock Test - 5 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The MAHATRANSCO AE Electrical Mock Test - 5 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MAHATRANSCO AE Electrical Mock Test - 5 below.
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MAHATRANSCO AE Electrical Mock Test - 5 - Question 1

In the circuit below, the operational amplifier is ideal. If V1 = 10 mV and V2 = 50 mV, the output voltage (Vout) is

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 1




 

MAHATRANSCO AE Electrical Mock Test - 5 - Question 2

Let  f(x) =  . Then f(x) decreases in the interval, 

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 2

By Leibnitz rule :

f'(x) = [ex(x - 1)(x - 2)] - 0 < 0 

= (x - 1)(x - 2) < 0

= x > 1 and x < 2

= x ∈ (1, 2)

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MAHATRANSCO AE Electrical Mock Test - 5 - Question 3

In the circuit shown below, X and Y are digital inputs, and Z is a digital output. The equivalent circuit is a

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 3



The above expression is for XOR gate 

MAHATRANSCO AE Electrical Mock Test - 5 - Question 4

The maximum value of “a” such that the matrix  has three linearly independent real eigenvectors is

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 4

Case (a) repeated roots (α,α,β)

Note that the graph of f(x) cannot be like the one given below

3real rootsnot possible

 

MAHATRANSCO AE Electrical Mock Test - 5 - Question 5

IQ of a person is given by the formula where MA is mental age and CA is the chronological age. If   for a group of 12 years old children, find the range of their mental age.

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 5
  • IQ = (MA*100)/CA
  • and 80 ≤ IQ ≤ 140
  • 80 ≤ (MA*100)/CA ≤ 140
  • 80 ≤ (MA*100)/12 ≤ 140
  • 960 ≤ (MA*100) ≤ 1680
  • 9.6 ≤ MA ≤ 16.8
MAHATRANSCO AE Electrical Mock Test - 5 - Question 6

The graphical representation of x ≤ -3 and x ≥ 3 on number line is

MAHATRANSCO AE Electrical Mock Test - 5 - Question 7

Point W is 7m towards the West of point X. Point X is 3m towards the North of point Y. Point Z is 4m towards West of point Y…………… 

Q. What is the position of X with respect to P

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 7

X is towards the east wrt to P

MAHATRANSCO AE Electrical Mock Test - 5 - Question 8

Vivek travelled 12kms West, then he turned left and travelled 8kms. Then he turned left and travelled 12kms. How far was Vivek from starting point ?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 8

MAHATRANSCO AE Electrical Mock Test - 5 - Question 9

Which one will replace the question mark ?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 9

(2)2 + (4)2 = 20

and (3)2 + (9)2 = 90

Therefore (1)2 + (5)2 = 26.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 10

Which one will replace the question mark ?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 10

(7 x 3) = 21 and (9 x 3) = 27

and (4 x 9) = 36 and (2 x 9) = 18

Therefore (9 x 6) = 54 and (4 x 6) = 24.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 11

Which one will replace the question mark ?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 11

(16 + 13) = (14 + 15)

and (28 + 12) = (10 + 30)

Therefore (29 + 16) = (15 + 30).

MAHATRANSCO AE Electrical Mock Test - 5 - Question 12

Which one will replace the question mark ?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 12

(15 - 12) + (10 - 9) = 4

(28 - 12) + (16 - 20) = 12

Similarly, (23 -11) + (15- 16) = 11.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 13

How many days will there be from 23rd January, 2011 to 31st July, 2013 (both days included)?  

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 13

As 2012 was a leap year, so the number of days in each month from 23rd January, 2011 to 31st July, 2013 is given as follows.
Since 2011 is not a leap year = 365 - 22 = 343 days
Number of days in 2012 = 366 days (leap year)
Number of days in 2013:
January = 31 days
February = 28 days
March = 31 days
April = 30 days
May = 31 days
June = 30 days
July = 31 days
Total number of days in 2013 = 212
Therefore, total number of days from 23rd January, 2011 to 31st July, 2013 = 343 + 366 + 212 = 921

MAHATRANSCO AE Electrical Mock Test - 5 - Question 14

A man went outside between 7 o'clock and 9 o'clock at such a time that the minute hand and the hour hand were found to be coinciding before 8 o'clock; and when he returned, again he found both the hands to be coinciding, but after 8 o'clock. What was the time when he returned to the house?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 14

He returned after 8 o'clock but before 9 o'clock, at such a time when both the minute hand and the hour hand were found to be coinciding.
In a simple way, we need to calculate the time when the angle between the minute hand and the hour hand is zero.
Angle between the minute hand and the hour hand at 8 o'clock = 8 × 30 = 240°
We can reduce the difference of 5.5 degree in 1 min,
Required time = 8 hrs + 240 × 2 ÷ 11

MAHATRANSCO AE Electrical Mock Test - 5 - Question 15

Directions: This question consists of three statements followed by four conclusions marked I, II, III and IV. Consider the statements to be true, even if they seem to be at variance from commonly known facts, and decide which of the given conclusions logically follow(s) from the statements, disregarding commonly known facts. Mark your answer accordingly.

Statements:
Some right are left.
No left is west.
All west are south.
Conclusions:
I. No right is west.
II. Some left are west.
III. Some south are not left.
IV. All south are left.

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 15

MAHATRANSCO AE Electrical Mock Test - 5 - Question 16

In the following question, Few statements are given which are followed by some conclusions. According to the given statements, which conclusion is/are definitely true?

Statements:

M ≤ N = O ; M ≤ P ; O < Q

Conclusions:

I. Q > N

II. M ≥ O

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 16

According to given information:

Statements: M ≤ N = O ; M ≤ P ; O < Q

Combining the statement:> M ≤ N = O < Q

Here, P is greater than or equal to M which is less than or equal to N equal to O which is less than Q.

Conclusions:

I.  Q > N → True (In the given statement, P > M ≤ N = O < Q ,It clearly mentioned Q is greater than O which is equal to N .So, Q is greater than N too. Thus, the conclusion I is true).

II. M ≥ O → False (In the given statement, M ≤ N = O, It is clearly mentioned that M is less than or equal to N which is equal to O. So, M can never be greater than O. Thus, conclusion II is a false).

Hence, "Option b" is the correct answer.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 17

In the following question, a statement is being followed by two conclusions. Find which of the two conclusion is/are true according to the given statement.

Statement:

J = K ≥ L > X ≥ Y ;  J ≥ P ; P ≥ Z 

Conclusions:

I: J < L

II: P ≤ Y

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 17

The given statement is: J = K ≥ L > X ≥ Y ;  J ≥ P ; P ≥ Z 

Combining the statement: < P J = K ≥ L > X ≥ Y 

Here, Z is smaller than or equal to P which is Smaller than or equal to J which is equal to K which is greater than or equal to L which is greater than X and X is greater than or equal to Y.

Conclusions:

I: J < L → False (as J = K ≥ L gives as J = K and K ≥ L which implies that J ≥ L and J cannot be less than L . Thus, Conclusion I is false.).

II:  P ≤ Y → False (as Z < P J = K ≥ L > X ≥ Y  → clear relationship between P and Y cannot be determined. Thus, Conclusion II is false.)

Hence, the "Option c" is the correct answer.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 18

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Race : Fatigue :: Fast : ?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 18

As the result of Race is Fatigue similarly the result of Fast is Hunger.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 19

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Peace : Chaos :: Creation : ?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 19

As opposite meaning of peace is chaos similarly opposite meaning of creation is destruction.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 20

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Poles : Magnet :: ? : Battery

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 20

As magnet has poles similarly battery has terminals.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 21

Pointing to a photograph Lata says, "He is the daughter of the only son of my grandfather." How is the man in the photograph related to Lata?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 21

The man in the photograph is the daughter of the only son of Lata's grandfather i.e., the girl is the daughter of Lata's father. Hence, the girl is the sister of Lata.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 22

If D is the brother of B, how B is related to C? To answer this question which of the statements is/are necessary?

  1. The son of D is the grandson of C.
  2. B is the sister of D.

 

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 22

Given: D is the brother of B.

From statement 1, we can detect that D is son of C (son of D is the grandson of C).

From statement 2, we can detect that B is 'Female' (sister of D).

Therefore, B is daughter of C.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 23

If A + B means A is the father of B; A - B means A is the brother B; A % B means A is the wife of B and A x B means A is the mother of B, which of the following shows that M is the maternal grandmother of T?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 23

M x N → M is the mother of N

N % S → N is the wife of S

and S + T → is the father of T.

Hence, M is the maternal grandmother of T.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 24

Look at this series: 53, 53, 40, 40, 27, 27,...so on. What number should come next?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 24

A number is repeated. Then it is reduced by 13 and the result is repeated.

► The next number is 27-13=14.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 25

Three friends, Sam, Michael and Puma went to a restaurant for lunch. Sam had $100 with him, Michael had $60 and Puma had $40. They got a bill for $104 and paid $16 as tip. They shared the total expenses in the ratio of the amounts of money each carried. If A is the difference between amount of money paid by Sam and Michael, and B is the difference between amount of money paid by Michael and Puma, then find the value of A : B.

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 25

Ratio of amounts with Sam : Michael : Puma = 100 : 60 : 40 = 5 : 3 : 2
Let us assume that amounts spent are 5x, 3x and 2x, respectively.
A = 5x - 3x = 2x
B = 3x - 2x = x
Hence, A : B = 2 : 1 (Total expense is the redundant data in the question)

MAHATRANSCO AE Electrical Mock Test - 5 - Question 26

The price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay ?

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 26

Let the price of a saree and a shirt be Rs. x and Rs. y respectively.

Then, 2x + 4y = 1600 .... (i)

    and x + 6y = 1600 .... (ii)

Divide equation (i) by 2, we get the below equation. => x + 2y = 800. --- (iii)

Therefore, y = 200. Now apply value of y in (iii) => x + 2 x 200 = 800 => x + 400 = 800 Therefore x = 400

Solving (i) and (ii) we get x = 400, y = 200.

∴ Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.

MAHATRANSCO AE Electrical Mock Test - 5 - Question 27

x+(1/x) = 2, then find the value of x + (-1/x)

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 27

X+(1/X) = 2 ;

(X^2+ 1)/ X = 2 ;

X^2+1 = 2X ;

X^2 - 2X + 1= 0 ;

By factorisation method ,

X = 1 ;

Now substitute X= 1 in X +(-1/X) ;

we get , 1 - 1/1 = 0 ;

Therefore , X = 0 ;

MAHATRANSCO AE Electrical Mock Test - 5 - Question 28

The ratio of the number of boys and girls in a school is 3:2. If 20% of the boys and 25% of the girls are scholarship holders, the percentage of the students who are not scholarship holders is

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 28

D. 78%
Explanation: Consider Total no of students = 100 Ratio is 3:2 i.e Boys=60 and Girls=40 20% of boys who get scholarship = 60*20/100=12% 25% of girls who get scholarship = 40*25/100 =10% Therefore % of students who do not get scholarship =100-(12+10) = 78%

MAHATRANSCO AE Electrical Mock Test - 5 - Question 29

If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 29

Let
P's capital = p,
Q's capital = q and
R's capital = r.
Then

MAHATRANSCO AE Electrical Mock Test - 5 - Question 30

मन्वंतर या शब्दाची संधी कोणती ? 

Detailed Solution for MAHATRANSCO AE Electrical Mock Test - 5 - Question 30

मन्वंतर या शब्दाची संधी मनु + अंतर ही होईल.

मन्वंतर या शब्दाची संधी उ किंवा ऊ पुढे विजातीय स्वर आल्यास उ किंवा ऊ बद्दल व याप्रमाणे होईल.

मन्वंतर हे यणादेश स्वरसंधीचे उदाहरण आहे.

मन्वंतर = मनु + अंतर = उ + अ = व् + अ = व

यणादेश स्वरसंधी - इ, उ, ऋ (ह्रस्व किंवा दीर्घ) यांच्या पुढे विजातीय स्वर आल्यास इ/ई बद्दल य्, उ/ऊ बद्दल व् तर ऋ बद्दल र् वर्ण येतात आणि त्यात पुढील स्वर मिसळून संधी तयार होते. अशाप्रकारे य्, व्, र् असे बदल होतात त्याला यणादेश असे म्हणतात.

Important Points

संधी - जोडशब्द तयार करताना पहिल्या शब्दातील शेवटचा वर्ण व दुसऱ्या शब्दातील पहिला वर्ण हे एकमेकांमध्ये मिसळतात व त्या दोन्हीबद्दल एक वर्ण तयार होतो. वर्णाच्या अशा एकत्र होण्याच्या प्रकाराला संधी असे म्हणतात.

संधीचे तीन प्रकार आहेत.

  1. स्वरसंधी
  2. व्यंजनसंधी
  3. विसर्गसंधी

स्वरसंधी - एकमेकांच्या शेजारी येणारे वर्ण हे जर स्वरांनी जोडले असतील तर त्यांना स्वरसंधी असे म्हणतात.

स्वर + स्वर असे याचे स्वरूप असते.​ उदा. विद्या + अर्थी = विद्यार्थी  (आ + अ = आ)

व्यंजनसंधी - जवळ जवळ येणाऱ्या या दोन वर्णांपैकी दोन्ही वर्ण व्यंजने असतील किंवा पहिला वर्ण व्यंजन व दुसरा वर्ण स्वर असेल तर त्याला व्यंजनसंधी असे म्हणतात.

व्यंजन + व्यंजन किंवा स्वर असे त्याचे स्वरूप असते. उदा. सत् + आचार = सदाचार (त् + आ)

विसर्गसंधी - एकत्र येणाऱ्या वर्णातील पहिला विसर्ग व दुसरा वर्ण व्यंजन किंवा स्वर असेल तर तेव्हा त्यास विसर्ग संधी असे म्हणतात. 

विसर्ग + व्यंजन किंवा विसर्ग + स्वर असे त्याचे स्वरूप असते. उदा. नि: + अंतर = निरंतर

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