MCQ: Coded Inequality- 1 - SSC CGL MCQ

Checking C1:  A < G

We can clearly see that the signs between A and G get reversed therefore the relation between A and G cannot be formed.

Therefore, C1 does not follow.

Checking C2: B ≥ H

We can clearly see that the signs between B and H get reversed therefore the relation between B and H cannot be formed.

Therefore, C2 does not follow.

Hence, Option D is correct.

Checking C1: E > M

Given Statements:  E > L > V > M = N < T < H

The common sign between E and M is >.

Therefore, C1 follows.

Checking C2: M < H

Given Statements:  E > L > V > M = N < T < H

The common sign between M and H is <.

Therefore, C2 follows.

Hence, Option D is correct.

Checking C1: N > Z

Given Statements:  N < T ≤ K = Y = Z < L < S

The common sign between N and Z is <.

Therefore, C1 doesn’t follow.

Checking C2: N < Z

Given Statements:  N < T ≤ K = Y = Z < L < S

The common sign between N and Z is <.

Therefore, C2 follows.

Hence, Option B is correct.

Combining statements: I = V > A > F = B ≥ H, E > A > F = B ≥ H

Checking C1: E > B

Here, E > A > F = B so, E > B follows.

Therefore, C1 follows.

Checking C2: H < I

Here, H ≤ B = F < A < V = I so, H < I follows.

Therefore, C2 follows.

Hence, Option C is correct.

Combining statements: 1 > 2 < 4; 3 = 5 ≥ 7 > 2

Checking C1: 1 > 4

Here, 1 > 2 < 4

We can clearly see that the signs between 1 and 4 get reversed therefore the relation between 1 and 4 cannot be formed.

Therefore, C1 doesn’t follow.

Checking C2: 4 > 3

Here, 3 = 5 ≥ 7 > 2 < 4

We can clearly see that the signs between 4 and 3 get reversed therefore the relation between 4 and 3 cannot be formed.

Therefore, C2 doesn’t follow.

Hence, Option D is correct.

Combining statements: M ≤ N; M > P ≥ O = H ≤ L ≤ Z

Checking C1: L ≥ M

Here, M > P ≥ O = H ≤ L

We can clearly see that the signs between L and M get reversed therefore the relation between L and M cannot be formed.

Therefore, C1 doesn’t follow.

Checking C2: O ≤ Z

Here, M > P ≥ O = H ≤ L ≤ Z

The common sign between O and Z is =, ≤.

So, O ≤ Z follows.

Therefore, C2 follows.

Hence, Option B is correct.

Combining statements: B ≤ Y; D ≥ E = B; Y ≤ S ≤ L
Checking C1: E < Y
Here, E = B ≤ Y, so E < Y is a doubtful case.
Checking C2: E = Y
Here, E = B ≤ Y, so E = Y is a doubtful case.
Thus, either conclusion I or II follows.
Hence, Option D is correct.

Check options one by one
Checking Option A: B = Y > T = H > E > F ≤ A, so T > Y is definitely false.
Checking Option B: A = H > Y = T > B > L ≤ F, so T > Y is definitely false.
Checking Option C: T = Y > K = L > H > P ≤ O, so T > Y is definitely false.
Hence, Option D is correct.

Given statement: U = L ? I ≤ D ? Q = E ≤ F
Check options one by one
Checking Option A: U = L < I ≤ D ≥ Q = E ≤ F, it doesn’t satisfy the given conditions.
Checking Option B: U = L < I ≤ D < Q = E ≤ F, it satisfies the given conditions.
Checking Option C: U = L > I ≤ D ≤ Q = E ≤ F, it doesn’t satisfy the given conditions.
Checking Option D: U = L ≤ I ≤ D ≥ Q = E ≤ F, it doesn’t satisfy the given conditions.
Hence, Option B is correct.

Check options one by one
Checking Option A: 4 < 7 > 8 > 9, 9 < 4 is not definately true.
Checking Option B: 7 < 4 > 8 > 9, 9 < 4 is true.
Checking Option C: 9 < 8 > 4 > 7, 9 < 4 is not definately true.
Checking Option D: 4 < 7 > 9 > 8, 9 < 4 is not definately true.
Hence, Option B is correct.

By combining all the statements we get:
E = H > A ≥ W < C = Y; A > J
Checking C1: H > J
Here, H > A > J, so H > J is true.
Therefore, C1 follows.
Checking C2: W < E
Here, E = H > A ≥ W, so W < E is true.
Therefore, C2 follows.
Checking C3: E < C
Here, E = H > A ≥ W < C, so no relation is possible because of opposite sign between them.
Therefore, C3 doesn’t follow.
Hence, Option D is correct.

By combining all the statements we get:
X ≤ F > M = Y ≤ R ≤ P, J ≥ F
Checking C1: J = X
Here, J ≥ F ≥ X, so J = X is not true.
Therefore, C1 doesn’t follow.
Checking C2: J > X
Here, J ≥ F ≥ X, so J > X is not true.
Therefore, C2 doesn’t follow.
Checking C3: X > R
Here, X ≤ F > M = Y ≤ R, so no relation is possible because of opposite sign between them.
Therefore, C3 doesn't follow.
But evaluating the options either I or II can be true.
Hence, Option D is correct.

By combining all the statements we get:
I ≤ H < F < E ≤ C > G; G < C < B ≤ D
Checking C1: D > G
Here, G < C < B ≤ D, so D > G is true.
Therefore, C1 follows
Checking C2: B > F
Here, B > C ≥ E > F, so, B > F is true.
Therefore, C2 follows.
Checking C3: I < C
Here, I ≤ H < F < E ≤ C, so I < C is true.
Therefore, C3 follows.
Hence, Option E is correct.

By combining all the statements we get:
K < Y ≤ X ≤ W > L; S < W ≤ T < U
Checking C1: K < W
Here, K < Y ≤ X ≤ W, so K < W is true.
Therefore, C1 follows.
Checking C2: U > Y
Here, Y ≤ X ≤ W ≤ T < U, so U > Y is true.
Therefore, C2 follows.
Checking C3: S < L
Here, S < W > L, so S < L is not true.
Therefore, C3 doesn’t follow.
Hence, Option D is correct.

By combining all the statements we get:
K < E ≤ X ? I ≤ W
Check options one by one
Checking Option A:
K < E ≤ X > I ≤ W; it doesn’t satisfy the given condition.
Checking Option B:
K < E ≤ X ≤ I ≤ W; it satisfies the given condition.
Checking Option C:
K < E ≤ X < I ≤ W; it doesn’t satisfy the given condition.
Checking Option D:
K < E ≤ X ≥ I ≤ W; it doesn’t satisfy the given condition.
Hence, Option B is correct.