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MHT CET Mock Test - 4 - JEE MCQ


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30 Questions MCQ Test MHT CET Mock Test Series - MHT CET Mock Test - 4

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MHT CET Mock Test - 4 - Question 1

Which of the following statements about bar magnets is correct ?

Detailed Solution for MHT CET Mock Test - 4 - Question 1

Explanation:As magnetic monopole does not exist. If we split the bar magnet into two pieces  each part will have its own north and south pole.

MHT CET Mock Test - 4 - Question 2

A metallic rod of 1 m length is rotated with a frequency of 50 rev/s about an axis passing through the centre point O. Other end of the metallic rod slides on a Metallic ring . A constant and uniform magnetic field of 2 T parallel to the axis is present everywhere. What is the emf between the centre and the metallic ring?

Detailed Solution for MHT CET Mock Test - 4 - Question 2

l = 1 m

= 314V

MHT CET Mock Test - 4 - Question 3

In an N-P-N transistor, P-type crystal is

Detailed Solution for MHT CET Mock Test - 4 - Question 3

Explanation:When the p-type crystal is grown between relatively wide sections of n-type crystals then the transistor is called NPN transistor.

 

MHT CET Mock Test - 4 - Question 4

In the given circuit, with steady current, the potential drop across the capacitor must be

Detailed Solution for MHT CET Mock Test - 4 - Question 4

There will be no current flowing in branch BE in steady condition.
Let I be the current flowing in the loop ABCDEFA.
Applying Kirchoff's law in the loop moving in anticlockwise direction starting from C. + 2V – I (2R) – I (R) – V = 0
∴V = 3IR
⇒ I = V/3R ... (1)

Applying Kirchoff's law in the circuit ABEFA we get on moving  in anticlockwise direction starting from B

+ V + Vcap – IR – V = 0 (where Vcap is the p.d. across capacitor).

MHT CET Mock Test - 4 - Question 5

In the case of metals the valence and conduction bands have

Detailed Solution for MHT CET Mock Test - 4 - Question 5

Explanation:The materials can be classified by the energy gap between their valence band and the conduction band. The valence band is the band consisting of the valence electron, and the conduction band remains empty. Conduction takes place when an electron jumps from valence band to conduction band and the gap between these two bands is forbidden energy gap. Wider the gap between the valence and conduction bands, higher the energy it requires for shifting an electron from valence band to the conduction band.In the case of conductors, this energy gap is absent or in other words conduction band, and valence band overlaps each other. Thus, electron requires minimum energy to jump from valence band. The typical examples of conductors are Silver, Copper, and Aluminium.In insulators, this gap is vast. Therefore, it requires a significant amount of energy to shift an electron from valence to conduction band. Thus, insulators are poor conductors of electricity. Mica and Ceramic are the well-known examples of insulation material.Semiconductors, on the other hand, have an energy gap which is in between that of conductors and insulators. This gap is typically more or less 1 eV, and thus, one electron requires energy more than conductors but less than insulators for shifting valence band to conduction band.

MHT CET Mock Test - 4 - Question 6

A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane, it follows that:   

[AIEEE 2004]

Detailed Solution for MHT CET Mock Test - 4 - Question 6

When a force of constant magnitude acts on the velocity of a particle perpendicularly, then there is no change in the kinetic energy of the particle. Hence, kinetic energy remains constant.

MHT CET Mock Test - 4 - Question 7

The earth takes 24 h to rotate once about its axis. How much time does the sun take to shift by 1º when viewed from the earth?​

Detailed Solution for MHT CET Mock Test - 4 - Question 7

Time taken for 360° shift = 24 h
Time taken for 1° shift = 24/360 h = 4 min.
 

MHT CET Mock Test - 4 - Question 8

What pulls a ball back to earth?

Detailed Solution for MHT CET Mock Test - 4 - Question 8

The gravitational force of the earth acts on every object having mass. When a ball is thrown upwards the gravitational force of the earth acts against the velocity of the object and pulls the ball downwards, i.e, towards itself.

Thus, gravity pulls a ball back to earth.

MHT CET Mock Test - 4 - Question 9

A proton, a deuteron and an α - particle having the same kinetic energy are moving in circular trajectories in a constant magnetic field. If rp, rd, and ra denote respectively the radii of the trajectories of these particles, then

Detailed Solution for MHT CET Mock Test - 4 - Question 9

KEY CONCEPT :

 

MHT CET Mock Test - 4 - Question 10

Consider the following reaction,

 

Q. 

The correct statement concerning I and II is

Detailed Solution for MHT CET Mock Test - 4 - Question 10

This is an example of E1 reaction and more substituted alkene (I) is formed as the major product.

MHT CET Mock Test - 4 - Question 11

How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of Pbo and 3.2 g of HCl?

Detailed Solution for MHT CET Mock Test - 4 - Question 11

PbO + 2HCl 
6.5\223
= 2.9 x 10-2
= 2.9x10-2 - x 
nx = 9a
PbCl2 + H2O
3.2/36.5
= 8.76 x 10-2 
8.76 x 10-2 - x
x = 2.9 x 10-2

MHT CET Mock Test - 4 - Question 12

Which is the correct statem ent about  structure?

Detailed Solution for MHT CET Mock Test - 4 - Question 12

The correct answer is Option A.
In a dichromate dianion structure, the negative charge can be on any O attached to Cr, therefore all Cr - O are equivalent. Also have Cr - O - Cr bond.

MHT CET Mock Test - 4 - Question 13

Comprehension Type

Direction (Q. Nos. 16 and 17) This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

Oxides are generally formed by the reaction of metals with oxygen at high temperatures. All the metals except scandium form MO oxides which are ionic. The highest oxidation number in the oxides, coincides with the group number and is attained in Sc2O3 to Mn2O7. Beyond 7th group, higher oxides coinciding with the group number do not form. As the oxidation number of metal increases covalent character and acidity increases. Mn2O7, CrO3 are acidic and their lower oxides are basic and amphoteric. Stability of higher oxides increases down the group.

Q. 

Which of the following reacts with both acids and bases?

Detailed Solution for MHT CET Mock Test - 4 - Question 13

ZnO and V2O5 are am photeric oxides.

MHT CET Mock Test - 4 - Question 14

The physical adsorption is due to

Detailed Solution for MHT CET Mock Test - 4 - Question 14

Vander waal forces are weak force of attractions, responsible for physisorption, as no chemical reaction taking place here.

MHT CET Mock Test - 4 - Question 15

Structure of a disaccharide formed by glucose and fructose is given below. Identify anomeric carbon atoms in monosaccharide units.

Detailed Solution for MHT CET Mock Test - 4 - Question 15

The correct answer is option C
'a' carbon of glucose and 'b' carbon of fructose
Carbon adjacent to the oxygen atom in the cyclic structure of glucose or fructose is known as anomeric carbon. As shown in the structure above ‘a’ and ‘b’ are present adjacent to an oxygen atom. Both carbons differ in configurations of the hydroxyl group.

MHT CET Mock Test - 4 - Question 16

Which one of the following is a water soluble vitamin?

Detailed Solution for MHT CET Mock Test - 4 - Question 16

The correct answer is Option C
Fat soluble vitamin - A, D, E, K
Water soluble vitamin - Vitamin B complex and C
So, vitamin B is water soluble.
Vitamins which can dissolve in water are called water-soluble vitamins. Water-soluble vitamins include vitamin-C and vitamin-B because they remove the toxins from our body through urine. Therefore, they are not stored in our body and should be taken on a daily basis through the food we eat.

MHT CET Mock Test - 4 - Question 17

Buna-S is a copolymer of:

Detailed Solution for MHT CET Mock Test - 4 - Question 17

Styrene-butadiene or styrene-butadiene rubber (SBR) describe families of synthetic rubbers derived from styrene and butadiene (the version developed by Goodyear is called Neolite). These materials have good abrasion resistance and good aging stability when protected by additives.

MHT CET Mock Test - 4 - Question 18

A transition Metal M can exist in two oxidation states +2 and +3.It forms an oxide whose experimental formula is given by MxO where x < 1. Then the ratio of metal ions in +3 state to those in +2 state in oxide is given by :

Detailed Solution for MHT CET Mock Test - 4 - Question 18

In 1 mole of MxO,
mole of M2+ ion = y
∴ mole of M3+ ion = x - y.
Applying charge balance, 2y + 3(x-y)-2 = 0
⇒ y = 3x - 2


 

MHT CET Mock Test - 4 - Question 19

Whta is the major organic product formed in the follwing reaction ?

Detailed Solution for MHT CET Mock Test - 4 - Question 19


MHT CET Mock Test - 4 - Question 20

Considering x-axis as the internuclear axis, which out of the following will not form sigma bond.

Detailed Solution for MHT CET Mock Test - 4 - Question 20




*Multiple options can be correct
MHT CET Mock Test - 4 - Question 21

In a 0.2 molal aqueous solution of a weak acid (HX), depression in freezing point is 0.383° Kf is 1.86° mol-1 kg. Assum e molarity equal to molality.
Match the parameters in Column I with their values in Column II and select the answer from the codes given below.

Detailed Solution for MHT CET Mock Test - 4 - Question 21

(d) Depression in freezing poin t is a colligative property.

Thus, (i) -> (r) (ii) -+ (p) (iii) -4 (s) (iv) -> (q)

MHT CET Mock Test - 4 - Question 22

For k = 1, 2, 3, the box Bk contains k red balls and (k + 1) white balls. Let P(B1) = 1/2, P(B2) = 1/3, P(B3) = 1/6. A box is selected at random and a ball is drawn from it. If a red ball is drawn, then probability that it has come from box B2 is

Detailed Solution for MHT CET Mock Test - 4 - Question 22

Use Baye’s Theorem formula


A : Red ball is drawn






= 14/39

MHT CET Mock Test - 4 - Question 23

Vector equation of a plane that passes through the intersection of planes  expressed in terms of a non – zero constant λ is

Detailed Solution for MHT CET Mock Test - 4 - Question 23

In vector form:
Vector equation of a plane that passes through the intersection of planes
 expressed in terms of a non – zero constant λ is given by :

MHT CET Mock Test - 4 - Question 24

If z is a complex number such that  is purely imaginary, then what is |z| equal to ? 

Detailed Solution for MHT CET Mock Test - 4 - Question 24

Concept:
If a number ω = a + ib is purely imaginary, then

  • a = 0 
  • and ω =

Calculation:
Given, z is a complex number such that is purely imaginary,
Let = a + ib, then a = 0
And


MHT CET Mock Test - 4 - Question 25

The function f (x) = x + cos x

Detailed Solution for MHT CET Mock Test - 4 - Question 25

f(x) = x
g(x) = cosx 
D(f) = R
D(g) = R
D(f+g) = D(f) ⋂ D(g)
So , D(f+g) = R
Therefore, given function is defined for real numbers.

MHT CET Mock Test - 4 - Question 26

The number of ways in which 6 “ + “ and 4 “ – “ signs can be arranged in a line such that no two “ – “ signs occur together is

Detailed Solution for MHT CET Mock Test - 4 - Question 26

′+′ signs can be put in a row in one way creating seven gaps shown as arrows:
Now 4′−′ signs must be kept in these gaps. So, no tow ′−′ signs should be together.
Out of these 7 gaps 4 can be chosen in 7C4 ways.

MHT CET Mock Test - 4 - Question 27

Detailed Solution for MHT CET Mock Test - 4 - Question 27

MHT CET Mock Test - 4 - Question 28

Detailed Solution for MHT CET Mock Test - 4 - Question 28




MHT CET Mock Test - 4 - Question 29

Let x be any real, then [x + y] = [x] + [y] holds for

Detailed Solution for MHT CET Mock Test - 4 - Question 29

Let y has some fractional part
x = 6.5
y = 0.9
[x] = 6, [y] = 0, [x]+[y] = 6
[x + y] = [7.4] = 7
[x + y] ≠ [x]+[y]
Let x, y be integers
x = 6.5
y = 1
[x] = 6, [y] = 1, [x]+[y] = 7
[x + y] = [7.5] = 7
[x + y] = [x]+[y]
So, [x + y] = [x]+[y] holds for y ϵ I

MHT CET Mock Test - 4 - Question 30

 ∫ log(log x) + (log x)-1) dx is equal to 

Detailed Solution for MHT CET Mock Test - 4 - Question 30


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