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MPPGCL JE Electrical Mock Test - 5 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - MPPGCL JE Electrical Mock Test - 5

MPPGCL JE Electrical Mock Test - 5 for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The MPPGCL JE Electrical Mock Test - 5 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The MPPGCL JE Electrical Mock Test - 5 MCQs are made for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MPPGCL JE Electrical Mock Test - 5 below.
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MPPGCL JE Electrical Mock Test - 5 - Question 1

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

REASON : SFBTPO :: THINK : ?

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 1

MPPGCL JE Electrical Mock Test - 5 - Question 2

617 + 6.017 + 0.617 + 6.0017 = ?

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 2

MPPGCL JE Electrical Mock Test - 5 - Question 3

A man is standing facing the sun during sunset. Where will his shadow fall?

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 3
While standing towards the sun during sunset, that is, standing towards west, his shadow will fall behind him, that is to his back.
MPPGCL JE Electrical Mock Test - 5 - Question 4

The average weight of A, B and C is 55 kg. If the average weight of A and B be 50 kg and that of B and C be 53 kg, then the weight of B is

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 4

MPPGCL JE Electrical Mock Test - 5 - Question 5

WHO was formed in the year

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 5

The WHO was established by constitution on 7 April 1948, which is celebrated as World Health Day.

MPPGCL JE Electrical Mock Test - 5 - Question 6

What is the average of all the composite numbers between 11 and 30?

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 6

Prime numbers between 1 and 30 →13, 17, 19, 23 and 29 (5)
Rest are prime numbers.
Total numbers 12 to 29 = 18
Total composite numbers = 13

Hence, Option A is correct.

MPPGCL JE Electrical Mock Test - 5 - Question 7

How many squares in the figure?

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 7

The total squares is in the give figure is 1+ 2+ 3+ 4= 30

MPPGCL JE Electrical Mock Test - 5 - Question 8

Which figure from the answer figures will replace the question mark (?) in the problem figures?

Problem Figures:

Answer Figures:

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 8

The logic followed here is:

The figure in image 2 is water image of the figure in image 1. The figure in image C of answer figure will be the water image of the figure in image 3.

Hence, image C of answer figure is the correct answer.

MPPGCL JE Electrical Mock Test - 5 - Question 9

Four Iron metal rods of lengths 78 cm, 104 cm, 117 cm, and 169 cm are to be cut into parts of equal length. Each part must be as long as possible. What is the maximum number of pieces that can be cut? 

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 9

Since each Iron rod must be cut into parts of equal length and 
each part must be as long as possible, so HCF should be 
taken. 
HCF of 78, 104, 117 and 169 = 13. 
No. of parts from 78cm. rod = 78 /13=6 
No. of parts from 104 cm. rod =104/13=8 
No. of parts from 117 cm. rod =117/ 13=9 
No. of parts from 169 cm. rod =169 /13=13 
Maximum no. of pieces = 6 + 8 + 9 + 13 = 36 

MPPGCL JE Electrical Mock Test - 5 - Question 10

A circuit with a resistor, inductor, and capacitor in series in resonant of (f0) Hz. If all the component values are now doubled, the new resonant frequency is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 10

MPPGCL JE Electrical Mock Test - 5 - Question 11

A real inductor has resistance because it is composed of a coil of wire with nonzero resistivity. To measure the inductance of a coil, a student places it across a 12.0-V battery and measures a current of 0.72 A. The student then connects the coil to a 30.0-V (rms) 60 Hz generator and measures an rms current of 0.86 A. What is the inductance of the coil?

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 11

The coil has an inductance and resistance. We can visualize the coil therefore as an inductor and resistor in series. When we connect the DC battery across the coil, we have therefore and LR circuit. The steady state current is just i0 = V/R – same as above. So

MPPGCL JE Electrical Mock Test - 5 - Question 12

Hydrogen is used in large alternators mainly to-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 12
To cool the machine
MPPGCL JE Electrical Mock Test - 5 - Question 13

The active and reactive power of an inductive circuit are 60 W and 80 VAR, respectively. The power factor of the circuit is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 13

Power factor,

MPPGCL JE Electrical Mock Test - 5 - Question 14

The yoke of a DC. Machine is made of-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 14
To provide low reluctance path, it must be made up of some magnetic material. It is prepared by using cast iron because it is cheapest. For large machines rolled steel, cast steel, silicon steel is used which provides high permeability i.e. low reluctance and gives good mechanical strength.
MPPGCL JE Electrical Mock Test - 5 - Question 15

Which of the following is not an advantage of semiconductor gauges as compared to conventional strain gauges?

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 15
Hence, the correct option is (B)
MPPGCL JE Electrical Mock Test - 5 - Question 16

Diversity factor is the ratio of_____

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 16
Hence, the correct option is (A)
MPPGCL JE Electrical Mock Test - 5 - Question 17

A photocell is illuminated by a small bright source placed 1m away. When the same source of light is placed two meters away, the electrons emitted by the photocathode_____.

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 17
Hence, the correct option is (D)
MPPGCL JE Electrical Mock Test - 5 - Question 18

A capacitor used on 230 V AC Supply should have a peak voltage rating of-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 18
First, there is the voltage rating. The voltage rating on a capacitor is of course a maximum DC (i.e. a peak) rating. For 50/60Hz mains we're talking about a sinusoidal voltage waveform with an RMS value of for instance 230V, so the DC peak value of such a supply is Vrms⋅√2 or about 1.4 times this quoted value. If you're already dealing with a DC system, there is no math involved. The peak rating of your cap should be more than the peak DC voltage you expect over the device.

For longevity and nonlinear effects at high stresses, it is recommended to keep ample margin on these ratings, especially on the voltage rating. For 230VAC applications, even though typically you wouldn't expect more than about 325V peak over your lines, choose at least a 400V or better even a 450V capacitor. And yes, even when the manufacturer specifies survivability of the part at higher voltages. Survivability does not mean proper operation. It just means that it doesn't blow up and cause a mess.

Hence, the correct option is (A)

MPPGCL JE Electrical Mock Test - 5 - Question 19

dielectric is introduced between the plates of a capacitor kept at a constant potential difference. The capacitance of the capacitor-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 19
Suppose +Q is the charge on one plate and –Q is charge on the second plate. Bring a rectangular slab made up of conducting material between the plates of the capacitor. The thickness of the slab must be less than the distance between the plates of the capacitor. When the electric field will be applied then polarization of molecules will be started. The polarization will take place in the same direction as that of the electric field. Consider a vector that must be polarized, name it as P. The polarization vector must be in the direction of the electric field Eo. Then this vector will start its functioning and will produce an electric field Ep in the opposite direction to that of Eo. The net electric field in the circuit is shown by the figure.

Hence, the correct option is (A)

MPPGCL JE Electrical Mock Test - 5 - Question 20

Transformer oil is used as-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 20
Transformer Oil or insulating oil is an oil that is stable at high temperatures and has excellent electrical insulating properties. It is used in oil-filled transformers, some types of high-voltage capacitors, fluorescent lamp ballasts, and some types of high-voltage switches and circuit breakers.

Hence, the correct option is (C)

MPPGCL JE Electrical Mock Test - 5 - Question 21

A load the connected to an active Network. At the Terminal to which load is connected in 10 Ω and Vth = 60 V, then the maximum Power supplied to the load is

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 21

Rn = 10Ω
Vth  = 60V

MPPGCL JE Electrical Mock Test - 5 - Question 22

A moving coil instrument has a resistance of 10 and gives full-scale deflection at 0.5 V potential difference across it. How can it be adapted to measure a current upto 100 A ?

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 22

 

MPPGCL JE Electrical Mock Test - 5 - Question 23

In a 50 kVA  transformer, the iron loss is 500 W and full-load Cu loss in 800 W.  The efficiency of the transformer at full-load at 0.8 p.f. lagging is

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 23

Full-load output
=kVA×cosϕ=50×0.8=40 kW
Total F.L. losses
=500+800=1300 W=1.3 kW
Full-load input=40+1.3=41.3 kW
Full-load 

MPPGCL JE Electrical Mock Test - 5 - Question 24

To avoid the effect of the stray magnetic field in AC bridges, we can use-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 24
Magnetic screening/shielding is a phenomenon of protection of a region against any external magnetic effects. For example, when a soft iron ring is placed in a magnetic field, most of the lines are found to pass through the ring, and no lines pass through the space inside the ring.

Hence, the correct option is (A)

MPPGCL JE Electrical Mock Test - 5 - Question 25

From a uniform light source of 500 CP, a surface 15 meter below, find the value of illumination when rays are inclined at an angle to (60°) to the surface.

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 25
The value of illumination is 4.44 lumen

Hence, the correct option is (A)

MPPGCL JE Electrical Mock Test - 5 - Question 26

In reference to the figure, the voltage waveform v (t) is measured by a PMMC, a PMMC combined with a bridge rectifier and a moving iron (MI) instrument. Two lists are prepared thereafter.

List-I (Instrument List) List-II (List of instrument reading)

a. PMMC i. 5V

b. PMMC rectifier ii. 2.75

c. M.I iii. 2.5 V

The correct option relation the instruments and their reading is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 26

PMMC reads Average values = 10/4 = 2.5V

PMMC rectifier = 2.75V

M.I. reads = 10/2 = 5

MPPGCL JE Electrical Mock Test - 5 - Question 27

If the supply polarity to the armature terminals of a separately excited DC motor is reversed, the motor will run under-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 27
If the supply polarity to be armature terminals of a separately excited dc motor is reversed, the motor will run under plugging conditions.
MPPGCL JE Electrical Mock Test - 5 - Question 28

A Zener diode has a Zener resistance of 4Ω if the current through it changes from 15 mA to 20 mA, the change of voltage across the Zener diode will be

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 28

MPPGCL JE Electrical Mock Test - 5 - Question 29

When the current through the coil of an electromagnet reverses, the-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 29
The direction of the magnetic field gets reversed by the coil of the electromagnet.
MPPGCL JE Electrical Mock Test - 5 - Question 30

When a series RL circuit is connected to a voltage source V at t =, the current passing through the inductor L at t = is-

Detailed Solution for MPPGCL JE Electrical Mock Test - 5 - Question 30

Inductors become open, and then the current becomes zero.

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