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MPPGCL JE Electronics Mock Test - 9 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test - MPPGCL JE Electronics Mock Test - 9

MPPGCL JE Electronics Mock Test - 9 for Electronics and Communication Engineering (ECE) 2025 is part of Electronics and Communication Engineering (ECE) preparation. The MPPGCL JE Electronics Mock Test - 9 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The MPPGCL JE Electronics Mock Test - 9 MCQs are made for Electronics and Communication Engineering (ECE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MPPGCL JE Electronics Mock Test - 9 below.
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MPPGCL JE Electronics Mock Test - 9 - Question 1

Which of the following statements is correct about pure resistive AC circuit?

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 1

The correct answer is option 4.

Pure AC resistive circuit

For a purely AC resistive circuit, the voltage and current are in the same phase.

Hence, the power factor (cosϕ) is unity.

The power in an AC circuit is given by:

P = VI cosϕ = positive value

For pure resistive load, cosϕ=0

Hence, P = VI = Power in the DC circuit

Therefore, the expression for power is the same as the DC circuit.

MPPGCL JE Electronics Mock Test - 9 - Question 2

In data communication, jitter refers to ___________

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 2

The effective of a data communications system depends on four fundamental characteristics:

Delivery, Accuracy, Timeliness and Jitter.

Delivery: The system must deliver data to the correct destination; Data must be received by the intended device or user

Accuracy: The system must deliver the data accurately; Data that have been altered in transmission and left uncorrected are unusable

Timeliness: The system must deliver data in a timely manner; Data delivered late are useless

Jitter: Jitter refers to the variation in the packet arrival time; It is the uneven delay in the delivery of audio or video packets
MPPGCL JE Electronics Mock Test - 9 - Question 3

If f(E) is Fermi dirac distribution function, then 1 – f(E) is the probability:

(Where Ef is Fermi level)

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 3

The probability that an electron occupies an energy level E is given by the Fermi-Dirac probability function and It can be expressed by:

The probability that the energy level is not filled with an electron, i.e. empty =1 - f (E)

An energy state being empty is equivalent to the presence of a hole, i.e. positively charged particle.

Important Point

  • At absolute zero, fermions will fill up all available energy states below a level EF called the Fermi energy with one (and only one) particle; They are constrained by the Pauli exclusion principle
  • At higher temperatures, some are elevated to levels above the Fermi level
  • For low temperatures, those energy states below the Fermi energy EF have a probability of essentially 1, and those the Fermi energy essentially zero
MPPGCL JE Electronics Mock Test - 9 - Question 4

A phase modulated signal can be obtained from frequency modulator by passing the modulating signal through a

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 4

The output of FM modulator is of form

After passing the modulating signal through the differentiator we give as the input to the frequency modulator, i.e.

The expression of the output signal will be:

The differentiation of the integral will simply give the original signal.

We get a phase modulated signal which is of the form:

MPPGCL JE Electronics Mock Test - 9 - Question 5

What range of output voltage is developed in the circuit shown in figure?

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 5

Concept:

The gain of non inverting amplifier : AV = 1 + (R/ R1)

       

Calculation:

From the given circuit diagram , the potentiometer can be varied in between 0 Ω to 10 KΩ.

R2 = 200 KΩ ,  R1 = ( 10 + R)

Gain :  AV = 1 + (R2 / R1) = 1 + (200/10 + R)

For , R = 0 Ω ; 

AV = 1 + (200 / 10) = 21

Vo = A× 0.5 = 21 × 0.5 = 10.5 V

For , R = 10 KΩ

AV = 1 + (200 / 10 + 10) = 11

Vo = AV × 0.5 = 11 × 0.5 = 5.5 V

Additional Information
potentiometer is a three-terminal resistor with a sliding or rotating contact that forms an adjustable voltage divider.

As you turn the knob of a potentiometer, the resistance will vary.

MPPGCL JE Electronics Mock Test - 9 - Question 6

PLA consists of _____.

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 6

Programmable logic array (PLA):

It is a kind of PLD (Programmable logic device) used to implement a combinational logic circuit.

1.It has a set of programmable AND gate planes which link a set of programmable OR gate planes.

Hence option (2) is the correct answer.

2.It has 2N AND Gate for N-input variable and form or Gates it has m output.

PLA Design:

The memory IC used in a digital system is selected or enabled only for the range of address assigned to it and this process is called memory decoding.

It denotes the memory to be selected for a specific address.

Important Points

PLD’s (Programmable Logic Devices) are the circuits that contain an array of AND gates and another array of OR gates. There are three kinds of PLD’s depending upon the type of array, i.e.

  • Programmable Read-Only Memory
  • Programmable Array Logic
  • Programmable Logic Array (PLA)
  • ROM is a memory device that stores the binary information permanently.

PROM:

  • It is known as programmable read-only memory
  • It includes both AND array & OR array

Out of these two arrays AND array is fixed and OR array is programmable.

​​PAL: 

Programmable AND array followed by fixed OR array

MPPGCL JE Electronics Mock Test - 9 - Question 7

A galvanometer has an internal resistance of 100 ohm and a shunt resistance of 20 ohm. Find the multiplying factor.

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 7

The correct answer is option 2): 6

Concept:

The range of the Galvanometer is extended by keeping a shunt resistance.

Here

Rm = internal resistance of the coil

Rsh = Shunt resistance

Rm and Rsh are in parallel, the voltage drop across the resistance is equal.

m is the multiplying factor

Calculation:

Given

Rm =  100 Ω 

Rsh = 20 Ω 

20 = 

m - 1 = 5

m = 6 

MPPGCL JE Electronics Mock Test - 9 - Question 8
When port 1 of two-port circuit is short-circuited, I1 = 4I2 & V2 = 0.25 I2. Which of the following is true?
Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 8

Concept:

The Y parameter equations are as follows:

I1 = Y11V1 + Y12V2

I2 = Y21V1 + Y22V2

Calculation:

Given, I1 = 4I2  & V2 = 0.25 I2

When port 1 of two-port circuit is short-circuited, then V1 = 0 V

I1 = Y12V2

Y12 = 16

I2 = Y22V2

Y22 = 4

MPPGCL JE Electronics Mock Test - 9 - Question 9

Considering initial value of storage elements as 1, how does the phase of carrier vary for message m(n) = { 1, 0, 1, 1, 0, 1 …} in case of DPSK ?

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 9

In DPSK, the input to the balance modulator is given as:

b(t) = d(t) ⊕ b(t – Tb)

This represents the Ex-OR operation,

Now, sampled version of d(t) is the input m(n)

∴ The sampled version of b(t) is written as:

b(n) = m(n) ⊕ b(n – 1)

m(n) = { 1, 0, 1, 1, 0, 1 ….}

Considering initial storage element = 1

b(1) = m(1) ⊕ b(0)

= 1 ⊕ 1 = 0

b(2) = m(2) ⊕ b(1)

= 0 ⊕ 0 = 0

b(3) = m(3) ⊕ b(2)

= 1 ⊕ 0 = 1

b(n) = {0, 0, 1, 0, 0, 1, …}

The phase of the carrier = {π, π, 0, π, π, 0, …. }

MPPGCL JE Electronics Mock Test - 9 - Question 10
Pulse repetition frequency in radar is:
Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 10

PRF:

The pulse repetition frequency (PRF) is the number of pulses of a repeating signal in a specific time unit, normally measured in pulses per second.

In radar, a radio signal of a carrier frequency is turned on and off; the term "frequency" refers to the carrier, while the PRF refers to the number of switches.

Both are measured in terms of cycle per second, or hertz.

MPPGCL JE Electronics Mock Test - 9 - Question 11

The above circuit can be represented in the frequency domain as:

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 11

Concept:

Inductive impedance is given by:

jXL = jωL

ω = frequency in radian/sec which can be written as:

ω = 2πf

f  = frequency in Hz

L = value of inductor in Henry

Similarly, the capacitive impedance is given by:

Calculation:

Given ω = 50 rad/sec

The capacitive reactance of the capacitor with C = 1000 μF will be:

The capacitance will, therefore be replaced with  -20j

Similarly, the inductor will be replaced with:

jωL = j × 50 × 500 mH

jωL = 25j

The resultant circuit will be, therefore:

MPPGCL JE Electronics Mock Test - 9 - Question 12

The minterm function f(A, B, C, D) = ∑(1, 3, 4, 6, 9, 11, 12, 14) is ________.

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 12

Concept:

A function can be solved using K-map.

A four variable K-map has the following representation.

Observation:

f(A, B, C, D) = ∑(1, 3, 4, 6, 9, 11, 12, 14)

f = B D̅ + D B̅ 

So, Function f depends on only two variable and independent to other two variable.

MPPGCL JE Electronics Mock Test - 9 - Question 13

The unit step response of a closed loop control system is given by c (t) = te-t. The transfer function of the system is

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 13

Concept:

A transfer function is defined as the ratio of Laplace transform of the output to the Laplace transform of the input by assuming initial conditions are zero.

TF = L[output]/L[input]

For unit impulse input i.e. r(t) = δ(t)

⇒ R(s) = δ(s) = 1

Now transfer function = C(s)

Therefore, transfer function is also known as impulse response of the system.

Transfer function = L[IR]

IR = L-1 [TF]

Calculation:

Given that r(t) = u(t), c(t) = t e-t

Transfer function,

MPPGCL JE Electronics Mock Test - 9 - Question 14

What will be the biasing of D(a) and D(b) in the given circuit?

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 14

Concept:

A diode is in Forward bias if

VD = VP - VN > 0.7 V

A diode is in Reverse bias if

VD = VP - VN < 0.7

Analysis:


Assume both diodes in RB, or OFF or open circuited.


for diode D(a) → VD = VP - VN = 10 V > 0.7 → FB

for diode D(b) → VD = VP - VN = 0 V < 0.7 → RB

MPPGCL JE Electronics Mock Test - 9 - Question 15

For which of the following ROCs, Fourier transforms is not defined?

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 15
  • The Fourier transform of a function is equal to its two-sided Laplace transform evaluated on the imaginary axis of the s-plane.
  • The main drawback of Fourier transform (i.e. continuous F.T.) is that it can be defined only for stable systems, Whereas, Laplace Transform can be defined for both stable and unstable systems.
  • An LTI system is stable if and only if the ROC of its system function H(s) includes the jω-axis [i.e., Re{s} = 0]  
  • Fourier transform is defined only for stable signals. 
  • From the given ROCs, B and C does not include the jω axis thus Fourier transform is not defined for B & C.
MPPGCL JE Electronics Mock Test - 9 - Question 16

The leakage current in an NPN transistor is due to the flow of:

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 16

Leakage current:

  • When the supply at the emitter-base junction is open-circuited, there is only reverse biasing in the base-collector junction.
  • Therefore, this sets up a small amount of current called the leakage current.
  •  It is highly temperature-dependent because it depends upon a number of minority charge carriers that are thermally generated and in turn depend upon temperature.
  • The main source of the leakage current in a transistor is thermally generated minority carrier. consider common emitter configuration.

  • When the switch is open, the emitter-base junction is an open circuit and so the value of input or base current is zero.
  • But a leakage current ICEO flows between collector and emitter. this leakage current ICEO is not only due to the thermally generated minority carriers (ICBO) across the C - B junction but also due to the movement of holes that flow across the base-emitter junction.

Current components of NPN transistor are shown below

MPPGCL JE Electronics Mock Test - 9 - Question 17
For pulse radar with a maximum unambiguous range of 60 km, what is the maximum allowable pulse repetition frequency?
Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 17

Concept:

The maximum unambiguous range of pulse radar is given as:

Where,

c = speed of light

PRT = pulse repetition time

PRF = pulse repetition frequency

Calculation:

Given:

Range = 60 km

PRF = 2.5 × 103 pps

MPPGCL JE Electronics Mock Test - 9 - Question 18
The errors of instruments can be determined by
Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 18
  • The errors of instruments can be determined by a process known as calibration.
  • Calibration is the comparison of measurement values delivered by a device under test with those of a calibration standard of known accuracy.
  • If the difference between the measured value and the pre-defined calibrated value are outside the acceptable range, then the instrument is said to be producing error in its measurement.

Additional Information

  • Slip gauges or gauge blocks are used as standards for precision length measurement.
  • A optical projector is an optical device which is used to enlarge the image.
MPPGCL JE Electronics Mock Test - 9 - Question 19
A 5 H coil is coupled with a 20 H coil. What could be the maximum value of mutual inductance between them considering no flux leakage?
Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 19

The correct answer is option '3'.

Concept:

Mutual inductance:

  • When two coils are brought in proximity with each other the magnetic field in one coil tends to link with the other.
  • It leads to the generation of voltage in the second coil.
  • This property of a coil that affects or changes the current in the second coil is called mutual inductance.
  • Mathematically, mutual inductance (M) between two coils of inductance, L1 and L2 is given by

... (1)

where K is the coefficient of coupling.

K ranges from 0 to 1.

Given:

L1=5 H and L2=20 H.

Here K=1.

From 1, mutual inductance (M) can be given as

  H

  H

= 10 H.

MPPGCL JE Electronics Mock Test - 9 - Question 20

Optical fibre works on the phenomenon of _______

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 20

The correct answer is total internal reflection.

Key Points

  • Optical fiber:
    • The working of an optical fiber is based on total internal reflection. Hence, option 2 is correct. 
    • Optical fibers consist of many long high-quality composite glass/quartz fibers. Each fiber consists of a core and cladding.
    • The refractive index of the core (μ1) material is higher than that of the cladding (μ2).
    • When the light is incident on one end of the fiber at a small angle, the light passes inside, undergoes repeated total internal reflections along with the fiber, and finally comes out.
    • The angle of incidence is always larger than the critical angle of the core material concerning its cladding.
    • Even if the fiber is bent, the light can easily travel through along the fiber.
MPPGCL JE Electronics Mock Test - 9 - Question 21

Output data ratio of a 8-bit PCM-TDM system sampling 24 voice channels, comparing these using μ-law at the rate of 8 kHz with a 1 frame alignment word, is:

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 21

Pulse-code modulation(PCM):

  • Pulse-code modulation (PCM) is a process used to digitally represent sampled analog or continuous-time signals.
  • It is the reference form of digital in computers, CDs, digital telephony, and other digital audio applications. 
  • The amplitude of the continuous-time signal is sampled at uniform intervals and each sample is quantized to its nearest value within a predetermined range of digital levels.

Time-division multiplexing(TDM):

Time-division multiplexing (TDM) is a process of transmitting and receiving independent signals over a common signal path by means of synchronized switches at each end of the transmission line so that each signal appears on the line only a fraction of time in an alternating pattern.

PCM-TDM system:

  • PCM with time-division multiplexing, transmissions from multiple sources occur in the same facility but not at the same time.
  • The multiplexer is simply an electrically controlled digital switch with two inputs and one output.
  • One 8-bit PCM code from each channel (16-bits total) is called a TDM frame, and the time it takes to transmit one TDM frame is called frame time.
  • The frame time is reciprocal of the sample rate.
  • The PCM code for each channel occupies a fixed time slot within the total TDM frame.
  • Output data ratio(Rb) = 1 / Tb . Where Tb is time for each bit.

Calculation:

Given that 

Each frame consists of 24 8-bit words, plus a single synchronizing bit.

Total number of pulses sent over sampling period = 24 × 8 + 1 = 193

Sampling frequency (fs) = 8 kHz

Sampling Time(Ts) = 1 / fs = 1 / 8 kHz = 0.125 ms

Time for each bit(Tb) = Ts / 193 = 0.648 μs

Output data ratio(Rb) = 1 / Tb = 1 / 0.648 μs = 1.544 mbps ≈ 1.6 × 106 bits/sec.

Alternative method:

Rb = sampling frequency × total number of pulses over Ts 

= 8 × 103 × 193 

= 1.544 mbps ≈ 1.6 × 106 bits/sec

MPPGCL JE Electronics Mock Test - 9 - Question 22

Consider a signal v(t) with Fourier transform V(f). If V '(f) represents the Fourier transform of v(2t), what is the relation between V '(f) to V(f) 

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 22

Concept:

Time Scaling property

Consider the signal x(t) then the Fourier Transform will be X(ω)

Consider the signal which is scaled by ‘α’ as x(αt). Then the Fourier Transform will be

Consider the signal as shown:

The compressed signal is:

The expanded signal is:

Analysis:

 If x(t) ↔ X(ω) then Fourier transform of x(αt) is;

Case 1: For a positive real constant α

Change of variable is performed τ = αt, which yields dτ = α dt

τ → - ∞ as t → - ∞ and τ →  ∞ as t →  ∞

Case 2: For a negative real constant α

Change of variable is performed τ = - αt, which yields dτ = - α dt

τ → - ∞ as t → ∞ and τ →  ∞ as t → - ∞

Combining two cases, we have

 NOTE:

Time compression of signal results in spectral expansion.

Time expansion of signal results in spectral compression.

Answer:

Given signal is v(t) having the F.T as V(f).

The signal scaled by a factor 2 then F.T is given as v’(f).

By using property we get v’(f) as:

Conclusion: From the above transformation we can conclude that magnitude scaled by 0.5 and bandwidth increased by 2 times.

MPPGCL JE Electronics Mock Test - 9 - Question 23
File Transfer Protocol (FTP) uses _______ for control connection and _______ for data connection
Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 23

The correct answer is Persistent TCP connection, non-persistent TCP connection.

Key Points

  • File Transfer Protocol or FTP is an application layer protocol and is used to communicate and transfer files between different systems on a TCP/IP protocol over the internet. It is a standard protocol for transmitting files from one host to another.
  • It is also used for downloading files from servers to computers. Two computers can have different file conventions and different ways to represent data. This creates a problem while transferring.
  • FTP overcomes these issues by establishing two connections between hosts. One is used for data transfer and the other connection is used for the control connection.
  • For sending the actual file, the data connection is used. This connection is made between the data transfer process. For this non-persistent connection is used.
  • Through control connection, we can send control information like user credentials, commands to change the remote directory, commands to retrieve and store files etc. For this FTP uses a persistent connection. Hence Option 2 is correct.

Additional Information

  • FTP is one of the fastest and most efficient ways to transfer files from one computer to the other. The size limit of the file to be transferred is 2GB.
  • Persistent connection or HTTP persistent connection is a communication channel that remains open for further HTTP requests and responses.
  • Non-persistent connection is a channel that maintains no information about the previous requests.
MPPGCL JE Electronics Mock Test - 9 - Question 24

It is easier

P :to venture into space

Q :for men

R :beneath their feet

S :than to explore

The Proper sequence should be:

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 24

From the options given, it can be guessed that the parts labelled P, Q, R, S can be ordered to form a meaningful sentence as
It is easier → for men→ to venture into space → than to explore→beneath their feet.
so order is QPSR.

MPPGCL JE Electronics Mock Test - 9 - Question 25

In the following question, assuming the given statements to be true, find which of the conclusion among given conclusions is/are definitely true and then give your answer accordingly.

Statement: P < Q < R < S = T

Conclusion:

I. Q < T

II. P > S

III. R = T

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 25

Given Statement: P < Q < R < S = T

Conclusion:

I. Q < T → True (As, Q < R < S = T → Thus, it is clear that Q < T. So, the conclusion is true)

II. P > S → False (As, P < Q < R < S → Thus, it is clear that P < S. So, the conclusion is false)

III. R = T → False (As, R < S = T → Thus, it is clear that R < T. So, the conclusion is false)

Hence, the correct answer is "Only conclusion I follows".

MPPGCL JE Electronics Mock Test - 9 - Question 26

Directions: In each of the following questions, a sentence has been given in Active (or Passive) Voice. Out of the four alternatives suggested, select the one that best expresses the same sentence in Passive/ Active Voice.

Shut the door.

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 26

The passive voice of imperative sentences which suggest order, suggestion or request can be made in two ways:

Active: Verb + object

Passive:

Let + object + be + past participle
You are requested/ ordered/ suggested + to + verb (Ist form) + object
Going by first way of passive voice, the passive voice of the given sentence would be: Let the door be shut.

MPPGCL JE Electronics Mock Test - 9 - Question 27

Direction: In the following question, the sentences have been given in Active/ Passive Voice. From the given alternatives, choose the one that best expresses the given sentence in Passive/ Active Voice.

She took the dog for a walk.

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 27

The sentence is in active voice and to convert it in passive voice the predicate of the sentence becomes the subject.
Use structure “auxiliary + past participle”
As per the given above sentence is given in Passive Voice.
The dog was taken for a walk by her.
Hence , required answer will be option C .

MPPGCL JE Electronics Mock Test - 9 - Question 28

Mr. X walks 10 km towards the North. From there it is 6 km towards south then moves 3 km to the east. In which direction is he now standing from his starting point?

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 28

i) Mr. X walks 10 km towards the North.

ii) From there it is 6 km towards the south then moves 3 km to the east.

According to the information given in the question, we can draw the following diagram.

Thus we can see he is standing in a North-East direction from his starting point.

Hence, the correct answer is "North-East".

MPPGCL JE Electronics Mock Test - 9 - Question 29

Directions to Solve

Each of the following questions has a group. Find out which one of the given alternatives will be another member of the group or of that class.

Question -

Pathology, Cardiology, Radiology, Ophthalmology

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 29

As all terms given in the question are medical terms and Hematology is also medical term.

MPPGCL JE Electronics Mock Test - 9 - Question 30

Which of the following freedoms is not available to an Indian citizen?

Detailed Solution for MPPGCL JE Electronics Mock Test - 9 - Question 30

Freedom available to Indian citizens:
- Freedom to criticise the government
- Freedom to reside in any part of the country
Freedom not available to Indian citizens:
- Freedom to participate in armed rebellion
Explanation:
- Indian citizens have the freedom to criticise the government. This means they have the right to express their opinions, voice their concerns, and hold the government accountable for its actions and policies.
- Indian citizens also have the freedom to reside in any part of the country. They can choose to live and work in any state or union territory without any restrictions.
- However, the freedom to participate in armed rebellion is not available to Indian citizens. Engaging in armed rebellion or taking up arms against the government is considered a criminal act and is punishable under the law.
Conclusion:
In summary, Indian citizens have the freedom to criticise the government and the freedom to reside in any part of the country. However, they do not have the freedom to participate in armed rebellion.
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