Mathematics Practice Test - 3 - Class 5 MCQ

To find the measure of ∠A in triangle ABC:

180 - (120 + 40)
= 20.

So, (C) is the right option.

To find the ratio P:Q, we start with the provided equations:

• P + Q = 105
• P − Q = 45

Next, we can solve for P and Q:

• Add the two equations:
  • (P + Q) + (P − Q) = 105 + 45
  • 2P = 150
  • P = 75
• Now substitute P back into one of the original equations:
  • P + Q = 105
  • 75 + Q = 105
  • Q = 30

Now we have:

• P = 75
• Q = 30

Finally, we calculate the ratio P:Q:

• P:Q = 75:30
• Simplifying this gives:
  • 75 ÷ 15 = 5
  • 30 ÷ 15 = 2

Thus, the ratio P:Q is: 5:2

To find the missing number, we can set up a proportion based on the given fraction.

• We have the ratio: 5/20 = 9/x.
• Cross-multiply to solve for x:
• 5 * x = 20 * 9
• This simplifies to:
• 5x = 180
• Now, divide both sides by 5:
• x = 180 / 5
• x = 36

The missing number is 36.

The surface area of a cube is given as 54 m². Since a cube has six equal faces, each face has an area of:

• Divide the total surface area by 6: 54 m² ÷ 6 = 9 m² per face.

The area of one face is the square of the side length (s) of the cube:

• The equation is: s² = 9 m².

Solving for s:

• The side length s = 3 m (since 3² = 9).

To find the volume of the cube, use the formula for volume:

• Volume = s³.
• Thus, Volume = 3³ = 27 m³.

Therefore, the volume of the cube is 27 m³.

The product of 255 and 37 is 255×37=9435
The place value of9 in 9435 is 9000 =90×100
Thus, 9 stands for 90 hundreds.

To find the highest common factor (H.C.F.) of 120, 144, and 216, follow these steps:

• Prime factorisation: Break down each number into its prime factors.
• 120 = 2³ × 3 × 5
• 144 = 2⁴ × 3²
• 216 = 2³ × 3³

Identify common factors: Look for the lowest power of common prime factors.

• For 2: The lowest power is 2³.
• For 3: The lowest power is 3¹.

Calculate the H.C.F.: Multiply the common factors together.

• H.C.F. = 2³ × 3¹ = 8 × 3 = 24

The highest common factor of 120, 144, and 216 is 24.

The number represented by point Q on the number line can be identified by considering its position relative to the other marked points.

• Point Q appears to be between 3.4 and 3.6.
• It is closer to 3.6 than to 3.4.
• Based on its position, the best representation of point Q is 3.6.

To find the number of primary school students who are 10 years old and above:

5/5 - 1/5 = 4/5
4/5 * 350 = 280

To determine how many times the two toy trains stop together in 1 minute:

• The first train stops every 5 seconds.
• The second train stops every 4 seconds.
• In 1 minute (60 seconds), the first train stops:
• 60 seconds ÷ 5 seconds = 12 times.
• Similarly, the second train stops:
• 60 seconds ÷ 4 seconds = 15 times.
• To find when they stop together, calculate the least common multiple (LCM) of 5 and 4:
• LCM of 5 and 4 is 20 seconds.
• In 60 seconds, they stop together:
• 60 seconds ÷ 20 seconds = 3 times.

Thus, the trains stop together 3 times in 1 minute.

To find the total mass of spinach Mrs. Gupta bought:

• She cooked 520g of spinach.
• She had 0.48 kg of spinach left, which is 480g (since 1 kg = 1000g).
• Add the cooked spinach and the remaining spinach to get the total mass:
  • 520g + 480g = 1000g

Therefore, Mrs. Gupta bought 1000g of spinach.

What percent of the squares on a chess board are black?

A standard chess board consists of 64 squares arranged in an 8x8 grid.

• Each row alternates between black and white squares.
• There are 32 black squares and 32 white squares on the board.

To find the percentage of black squares:

• Divide the number of black squares (32) by the total number of squares (64).
• Multiply the result by 100 to convert it to a percentage.

The calculation shows that 50% of the squares are black.

To find the missing number in the box:

5/6 * 15 = 75/6
75/6 = 150/12
= 5*30/12

The solution involves solving for the values of X and Y using given information.

• Inspect the options to find a match for X and Y.
• Based on calculations, the correct values are X = 5 and Y = 7.

Thus, option A is correct.

The scale is balanced, indicating that the weights on both sides are equal.

To determine the weight of one cube, follow these steps:

• Count the number of cubes on the left side.
• Identify the total weight on the right side.
• Divide the total weight on the right by the number of cubes on the left.

For example:

• If there are 4 cubes on the left and the total weight on the right is 20 grams, then:
• Weight of one cube = Total weight / Number of cubes
• Weight of one cube = 20 grams / 4 = 5 grams.

Thus, one cube weighs 5 grams.

To find the quotient of 280.5 ÷ 25.5, we can simplify the problem by using the information given about 2805 ÷ 2.55.

• We know that 2805 ÷ 2.55 = 1100.
• To relate this to our target division, we can express 2805 and 2.55 in terms of 280.5 and 25.5:
• Notice that 2805 = 280.5 × 10 and 2.55 = 25.5 ÷ 10.
• Thus, we can rewrite the equation:
• 2805 ÷ 2.55 = (280.5 × 10) ÷ (25.5 ÷ 10).
• This simplifies to:
• 2805 ÷ 2.55 = (280.5 ÷ 25.5) × 100.
• Setting this equal to 1100 gives:
• (280.5 ÷ 25.5) × 100 = 1100.
• To isolate (280.5 ÷ 25.5), divide both sides by 100:
• 280.5 ÷ 25.5 = 1100 ÷ 100.
• This leads to:
• 280.5 ÷ 25.5 = 11.

To find the cost price of the radio:

• The radio was sold for Rs. 572.
• The profit made on the sale was Rs. 24.
• To calculate the cost price, use the formula:
• Cost Price = Selling Price - Profit
• Plugging in the values:
• Cost Price = Rs. 572 - Rs. 24
• This simplifies to:
• Cost Price = Rs. 548

Analyse the blocks closely and try to form a figure. Option (A) turns out to be right solution, given that the bottom surface of the cube is also shaded.

When two rays emerge from a common endpoint, they form an angle.

Here’s a brief explanation:

• Rays are straight lines that start at a point and extend infinitely in one direction.
• When two rays share the same starting point, they create an angle between them.
• The measure of this angle is determined by the separation of the two rays.

To determine the distance between the third and the last plant:

• The distance between the second and fifth plants is given as 6 m.
• This means there are three plants (2nd, 3rd, and 4th) in between.
• Assuming equal spacing, the distance between each consecutive plant can be calculated:
• Distance between each plant = 6 m / 3 = 2 m.

Now, we can find the distance between the third and the last (eighth) plant:

• The distance from the third to the fourth plant is 2 m.
• The distance from the fourth to the fifth plant is also 2 m.
• The distance from the fifth to the sixth plant is 2 m.
• The distance from the sixth to the seventh plant is 2 m.
• The distance from the seventh to the eighth plant is 2 m.

Adding these distances together:

• Total distance = 2 m + 2 m + 2 m + 2 m + 2 m = 10 m.

Thus, the distance between the third and the last plant is 10 m.

To find Ravi's total marks:

• Calculate the average mark: 50.
• Multiply the average by the number of tests: 5.
• Thus, total marks = 50 x 5 = 250.

Ravi's total marks in the tests are 250.