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Maths & Logical Reasoning Test - 9 - SSC CGL MCQ


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30 Questions MCQ Test SSC CGL Tier II Mock Test Series 2024 - Maths & Logical Reasoning Test - 9

Maths & Logical Reasoning Test - 9 for SSC CGL 2024 is part of SSC CGL Tier II Mock Test Series 2024 preparation. The Maths & Logical Reasoning Test - 9 questions and answers have been prepared according to the SSC CGL exam syllabus.The Maths & Logical Reasoning Test - 9 MCQs are made for SSC CGL 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Maths & Logical Reasoning Test - 9 below.
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Maths & Logical Reasoning Test - 9 - Question 1

Mr. Shiva invested equal amount of money in two private firms which gives 15% simple interest per annum for 3.5 years and 5 years respectively. If The difference in their interests is Rs. 225. The amount invested by Mr. Shiva is:

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 1

Given:

Mr. Shiva invested equal amount of money in two private firms

And for different times 3.5 and 5 years

And the difference between in their interests = 225

Formula used:

S.I = (P × R × T)/100

Calculation:

Let the amount of money invested by Shiva is Rs. x

So, the simple interest on the principal x for 3.5 years = (x × 15 × 3.5)/100

And the simple interest on the principal x for 5 years = (x × 15 × 5)/100

According to question,

Difference between the interests = 225

So, (x × 15 × 5)/100 - (x × 15 × 3.5)/100 = 225

⇒ (5 – 3.5) 15x/100 = 225

⇒ x = (225 × 100)/(15 × 1.5)

⇒ x = 1000

The amount of money invested by Shiva is Rs. 1000 × 2 = Rs.2000

∴ The amount invested by Mr. Shiva is Rs. 2000.

Maths & Logical Reasoning Test - 9 - Question 2

A, B and C started a business with a pool of capital in the ratio of 9 : 7 : 5. A is the working partner and receives Rs. 1050 per month salary out of the profit. They have also decided to donate 12.5% of the total profit and share the remaining in the ratio of their investment. If A receives Rs. 450 less than B and C together then find the total profit at the end of 11 months?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 2

Let the total profit at the end of 11 months = Rs. X

Since A receives Rs. 1050 per month salary out of the profit

⇒ Total salary taken by A, out of profit = 1050 × 11 = Rs. 11550

⇒ Amount of donation done out of the profit = 12.5% of X = Rs. X/8

⇒ Remaining profit to be shared between all three in the ratio of their investment is

X – 11550 – X/8 = (7X/8 – 11550)

Ratio in which remaining profit will be shared = 9 : 7 : 5

Since A receives Rs. 450 less than B and C together

⇒ (X/8) - 1650 = 12000

⇒ (X/8) = 13650 

⇒ X = 109200

∴ Total profit at the end of 11 months = Rs. 109200

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Maths & Logical Reasoning Test - 9 - Question 3

If the mean of the data 12, 15, 18, 21, x, 27, 30, 33, 36 is 24, then what is the value of x?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 3

Concept use:

Sum of all values = Mean × Number of values

Explanation:

Let's find the sum of the given data values, excluding x:

12 + 15 + 18 + 21 + 27 + 30 + 33 + 36 = 192

We know that the mean is the sum of all values divided by the total number of values.

Given:

Mean = 24

Number of values = 9 (including x)

Sum of all values = Mean × Number of values

Sum of all values = 24 × 9 = 216

Since the sum of the given values (excluding x) is 192, we can find x by subtracting 192 from 216.

x = 216 - 192 = 24
Hence, The Correct Answer is Option 2.

Maths & Logical Reasoning Test - 9 - Question 4
Eight years ago, Maria's age was equal to the sum of the present ages of her only son and her only daughter. Ten years hence, the ratio between the ages of her daughter and her son will be 6 ∶ 5 at that time. If Maria's husband is 8 years older than her and his present age is four times that of her son, then what is the present age of Maria's daughter?
Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 4

Solution:

Let Maria's only son's present age be x years and her daughter's present age be y years.

and Let Maria's present age be z years and her husband's present age be w years.

Eight years ago,

Maria's age = z - 8 = x + y . . .(i)

10 years from now,

son's age = x + 10 and daughter's age = y + 10

ATQ: (y + 10)/(x + 10) = 6/5

⇒ 5y + 50 = 6x + 60

⇒ 5y - 6x = 10 . . .(ii)

Since, Maria's husband is 8 years older than her.

⇒ w = z + 8 . . .(iii)

Husband's present age is four times that of her son

⇒ w = 4x . . .(iv)

From (iii) and (iv),

z = 4x - 8 . . .(v)

From (v) and (i),

4x - 8 - 8 = x + y

⇒ 3x - y = 16 . . .(vi)

2 × (vi) + (ii), we get

5y - 2y = 10 + 32 ⇒ 3y = 42

⇒ y = 14

Hence, present age of Maria's daughter is 14 years.

Maths & Logical Reasoning Test - 9 - Question 5

At 7 : 30 P.M. the owner of a Cycle noticed that a thief is taking away his cycle from his home and is cycling in a particular direction at an estimated speed of 10 km per hour. He informed the police about the theft and the policeman started from the same point, half an hour later than the time of the theft but with a speed of 12 km per hour. At what time will Policeman catch the thief?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 5

Given:

The thief started cycling at 7:30 pm
The policeman started half an hour later at 8:00 pm
The thief's speed is 10 km/h.
The policeman's speed is 12 km/h.

Formula used:

Distance = Speed × Time

Calculation:

Let t be the time it takes for the policeman to catch the thief.

In the half-hour interval between the thief's departure and the policeman's departure

The thief travels, Distance = Speed × Time

D = 10 × (1/2) km = 5km

So, when the policeman starts at 8:00 P.M., the thief is already 5 km away

Now,

Distance covered by the policeman = Relative speed × t

Relative speed = (12 - 10) = 2 km/h

Now,

⇒ 2km/h × t = 5 km

⇒ t = (5/2) = 2.5 hours 
Since the policeman started at 8:00 P.M., he will catch the thief 2.5 hours later:

8:00 pm + 2:30 hours = 10:30 pm

∴ The policeman will catch the thief at 10:30 pm

Maths & Logical Reasoning Test - 9 - Question 6

A deposited ₹8,000 in a bank at 8% per annum simple interest. B deposited ₹6,000 at 10% compound interest per annum. After 3 years the difference between their interest will be:

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 6

GIVEN:

A's principle = 8,000

Rate = 8% at S.I.

B's principle = 6,000

Rate = 10%at C.I.

FORMULA USED:

S.I. = ( P × R × T )/100

A = P × (1 + (R/100))t

C.I. = Amount - Principle

Where, A = Amount , S.I. = Simple Interest, C.I.= Compound Interest

P = Principle, R = Rate , t = time in years

CALCULATION:

As, we have, A's Principle = Rs8,000 , Rate = 8% , Time = 3 years

⇒ S.I. = ( P × R × T)/100 = ( 8000 × 8 × 3)/100 = Rs1,920.

Now, we have B's Principle = Rs6,000, Rate = 10% , Time = 3 years

⇒ A = P × (1 + (R/100)t

⇒ A = 6000 × ((1 + (10/100)3)  = 6000 × 11/10 × 11/10 × 11/10 = Rs7,986.

Now, the Compound Interest = (Amount - Principle) = (7986 - 6000) = Rs1,986

After 3 years, Difference = (1,986 - 1,920) = Rs66.

Hence, the required difference after 3 years is Rs 66.

Maths & Logical Reasoning Test - 9 - Question 7
The angles of the quadrilateral are in the ratio 4 : 5 : 10 : 11. The angles are given below:
Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 7

Concept use:

The Sum of Angles of Quadrilateral = 360°

Calculation:

The angles of the quadrilateral are in the ratio 4 : 5 : 10 : 11.

∴ 4x + 5x + 10x + 11x = 360°

30x = 360° ⇒ x = 12°

Hence, The Angles of Quadrilaterals are 48°, 60°, 120°, 132°

Hence, The Correct Answer is 48°, 60°, 120°, 132°.

Maths & Logical Reasoning Test - 9 - Question 8
Sachin lent Rs. 20000 to Ankit at simple interest at the rate of 10% per annum for 2 years and Ankit lent half of the money to Gaurav at simple interest at the rate of 5% per annum for 2 years and lent rest half of the money to Amar at compound interest at the rate of 10% per annum for 2 years. Find the profit or loss of Ankit after 2 years in the whole transaction.
Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 8

Given:

Sachin lent Rs. 20000 to Ankit at simple interest at the rate of 10% per annum for 2 years.

Ankit lent half of the money to Gaurav at simple interest at the rate of 5% per annum for 2 years.

And lent rest half of the money to Amar at compound interest at the rate of 10% per annum.

Formula used:

S.I = P × R × T/100

C.I = P [(1 + R/100) n – 1], n = number of years

Calculation:

Simple interest paid by Ankit to Sachin = Rs. 20000 × 10 × 2/100 = Rs. 4000

Simple interest paid by Gaurav to Ankit = Rs. 10000 × 5 × 2/100 = Rs. 1000

Compound interest paid by Amar to Ankit = 10000 [(1+ 10/100)2 – 1] = Rs. 2100

So, total amount received by Ankit = 1000 + 2100 = Rs. 3100

Hence, loss incurred by Ankit = 4000 – 3100 = Rs. 900
Maths & Logical Reasoning Test - 9 - Question 9
In a hostel, there was provision for 15 days of food for 60 boys. If after 5 days, 15 more boys come, for how many days will the remaining food last?
Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 9

Given:

There is a provision for 15 days of food for 60 boys

After 5 days, 15 more boys joined the hostel

Concept Used:

Total Food = No. of Days × No. of Boys

Calculation:

Total Food = 15 × 60 = 900 units

According to the question

Total Food for 5 days = 5 × 60 = 300 units

Remaining Food = 900 - 300 = 600 units

New number of boys = 60 + 15 = 75

So the remaining food will last for (600 ÷ 75) = 8 days

∴ After 5 days if 15 more boys are joined, food will last for 8 more days.

Maths & Logical Reasoning Test - 9 - Question 10

What is the least common multiple (LCM) of 2 and 4?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 10

Given:

First number = 2

Second number = 4

Formula Used:

LCM of two numbers = (Product of the numbers) / GCD (Greatest Common Divisor) of the numbers

Calculation

First, find the GCD of 2 and 4.

⇒ GCD of 2 and 4 = 2

Then, use the formula to find the LCM.

⇒ LCM = (2 × 4) / 2

⇒ LCM = 8 / 2

⇒ LCM = 4

Hence, the LCM of 2 and 4 is 4.

Maths & Logical Reasoning Test - 9 - Question 11

In quadrilateral ABCD, bisectors of ∠C and ∠D meet at E. If ∠CED = 52° and ∠A = 35°, what is the value of ∠B?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 11


In ∆CDE
∠ECD + ∠EDC = 180° – 52° = 128°
As CE and DE are angle bisectors of ∠C and ∠D
∠C + ∠D = 2 × 128° = 256°
∠B = 360° – 35° – 256° = 69°
Hence, option C is correct.

Maths & Logical Reasoning Test - 9 - Question 12

In a quadrilateral ABCD, ∠A = 116° and ∠B = 86°. The bisectors of ∠C and ∠D meet at point O. What is the measure of ∠COD?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 12


∠A + ∠B + ∠C + ∠D = 360
∠C + ∠D = 360° – (∠A + ∠B)
In ∆ COD


∠COD = 180° – ∠ODC – ∠OCD
= 180° – (∠ODC + ∠OCD)


Hence, option C is correct.

Maths & Logical Reasoning Test - 9 - Question 13

If A = (x4 ‒ 9)/(x2 ‒ 1) and B = (y8 + 4)/(3y2 + 1), where x = 3 and y = 2, what is the value of A2 + AB+ B2?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 13

x = 3 and y = 2



= A2 + AB + B2
= 92 + 9 × 20 + 202
= 661
Hence, option A is correct.

Maths & Logical Reasoning Test - 9 - Question 14

In the given figure, ABC is a right-angled triangle with ∠ABC = 90° and ∠ACB = 60°. If the radius of the smaller circle is 5cm, what is the radius (in cm) of the larger circle?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 14





CO = 10 cm
In ∆CPE,


R = 15 cm
Hence, option C is correct.

Maths & Logical Reasoning Test - 9 - Question 15

If a + b = 40, where a and b are natural numbers, then the value of (a × b) will be maximum, when:

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 15

Using the relation AM > GM

Given, a + b = 40
∴ 20 > √ab
⇒ ab < 400
Thus, maximum value of ab = 400
Solving, a + b = 40 and ab = 400
We get a = b = 20
Thus, ab is maximum when a = b.
Hence, option (D) is correct.

Maths & Logical Reasoning Test - 9 - Question 16

If 5sin A + 2cosA = 3 and 5cosA – 2sinA = y, find the value of ‘29cosA’.

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 16

5sin A + 2cosA = 3 ---- (1)
25sin2A + 4cos2A + 20 sin A cos A = 9 ---- (2)
5cosA – 2sinA = y
25cos2A + 4sin2A – 20sinAcosA = y2 ---- (3)
Add eq (2) and (3)
29 = y2 + 9
±2√5 = y = 5cosA – 2sinA ---- (4)
On solving (1) and (4)
29cosA = 6 ± 10√5
Hence, Option C is correct.

Maths & Logical Reasoning Test - 9 - Question 17

Select the option in which the numbers share the same relationship as that shared by the numbers in the given set.

(850, 645, 410)

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 17

Given: (850, 645, 410)

The logic followed here is:

(850, 645, 410) → 850 - 645 = 205 → 205 × 2 = 410

By checking options,

(1) (751, 396, 544) → 751 - 396 = 355 → 355 × 2 = 710

(2) (558, 256, 356) → 558 - 256 = 302 → 302 × 2 = 604

(3) (440, 229, 422) → 440 - 229 = 211 → 211 × 2 = 422

(4) (550, 402, 135) → 550 - 402 = 148 → 148 × 2 = 296

Hence, (440, 229, 422) is the correct answer.

Maths & Logical Reasoning Test - 9 - Question 18

If a mirror is placed on the line AB, then which of the answer figure is the right image of the given figure?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 18

Hence, mirror image of the given figure will be option 1.

Maths & Logical Reasoning Test - 9 - Question 19

A paper is folded and cut as shown in the following figures. How will it appear when unfolded?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 19
  • The image obtained when the paper is unfolded is as shown below:

  • Hence, the correct answer is "Option (3)".
Maths & Logical Reasoning Test - 9 - Question 20

Select the option that is related to the fourth figure in the same way as the first figure is related to the second figure.

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 20

The logic followed here is:

From figure B to A:

  • All shapes shifted in an anticlockwise direction.
  • Arrow Shifted in the center and it is rotating 90 degrees in a clockwise direction.

Similarly,

From figure D to C:

  • All shapes shifted in an anticlockwise direction.
  • Arrow Shifted in the center and it is rotating 90 degrees in a clockwise direction.

Hence, the correct answer is "Option 2".

Maths & Logical Reasoning Test - 9 - Question 21

In the following question, find the missing number from the given series.

2, 3, 6, 15, 45, ?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 21

Given: 2, 3, 6, 15, 45, ?

The logic follows here is:

Hence, the correct answer is "157.5".

Maths & Logical Reasoning Test - 9 - Question 22

Read the given statements and conclusions carefully. Assuming that the information given in the statements is true, even if it appears to be at variance with commonly known facts, decide which of the given conclusions logically follow(s) from the statements.
Statements:
I. No shirt is trousers.
II. All shorts are trousers.
Conclusion:
I. Some shorts are not shirts.
II. No trouser is a shirt.

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 22


So from the venn diagram, both conclusions, i.e., I and II follow.
Hence, the correct answer is option C.

Maths & Logical Reasoning Test - 9 - Question 23

If the age of Q is 34 and L is 43, what could be the age of O?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 23

Using the above information we get,

 
Now, since we do not have the exact position of O and Q. We cannot determine the required answer.
Hence, option D is correct.

Maths & Logical Reasoning Test - 9 - Question 24

Which interchange of signs will make the following equation correct?

161 – 99 ÷ 11 + 5 × (25 + 5) – 20 = 90

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 24

On interchanging + and –, we get

161 + 99 ÷ 11 – 5 × (25 – 5) + 20 = 90

161 + 9 – 100 + 20 = 90

90 = 90

LHS = RHS
Hence, option C is correct.

Maths & Logical Reasoning Test - 9 - Question 25

Which of the following represents 'L is niece of N'?

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 25

(a) N – K + L ⇒  
Using option (A) we get N is the brother of K and K is the father of L
Here gender of L is not clear so L can either be Nephew or Niece of N.
(b) N + K – L ⇒
Using option (B) we get N is the father of K and K is the brother of L.
Here L is either son or daughter of N.
(c) N + K × L ⇒
Using option (C) we get N is the father of K and L is the daughter of K.
Here L is the granddaughter of N.
Hence, option D is correct.

Maths & Logical Reasoning Test - 9 - Question 26

Directions: To each of the following questions, four probable answers have been given as alternatives. Select the most appropriate alternative as the answer.

You are the owner of an advertisement company. One of your clients wants to advertise which stigmatizes a particular section of the society.

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 26

Any media message which promotes social disintegration would be detrimental with the future business of the company and therefore it is of utmost importance to shun the advertisement and modify it.

Hence, Option C is the correct answer.

Maths & Logical Reasoning Test - 9 - Question 27

Four number-pairs have been given, out of which three are alike in some manner and one is different. Select the number-pair that is different.

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 27

Except for option D, in rest all the difference between the numbers gives a perfect square number.
(324, 405) → 405 – 324 = 81 = 92
(426, 490) → 490 – 426 = 64 = 82
(633, 754) → 754 – 633 = 121 = 112
(522, 581) → 581 – 522 = 59
Hence, Option D is correct.

Maths & Logical Reasoning Test - 9 - Question 28

You decide to start a new business of yours, but feel demotivated when you come to know that only 9 out of 10 start-ups are successful and rest fail.

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 28

Business are bound to be risky and therefore demotivation will not help in such scenario. Thereby, strategizing and taking calculated risk is the best possible way out.
Hence, option  D is correct.

Maths & Logical Reasoning Test - 9 - Question 29

Directions: The figure given in the question is folded to form a box. Choose from four alternatives, the box that is similar to the box formed.

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 29

Hence, option D is correct.

Maths & Logical Reasoning Test - 9 - Question 30

Choose the alternative which is closely resembles the mirror image of the given combination.

R P 9 S 1 L

Detailed Solution for Maths & Logical Reasoning Test - 9 - Question 30

By close observation, we get the mirror image of  " R P 9 S 1 L" is "".
Hence, option D is correct.

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