Mock Test: Reasoning And Military Aptitude - 9 - AFCAT MCQ

Answer : The word that is different from the rest is: B: Swan
Reasons:
- Size: Swans are significantly larger than sparrows, parrots, and koels.
- Habitat: While the other birds (sparrow, parrot, and koel) are primarily found in various terrestrial environments, swans are mainly found in aquatic habitats such as lakes, ponds, and rivers.
- Behavior: Swans are known for their elegance and unique mating rituals (such as the famous "swan dance"), which are not seen in the other mentioned birds.
- Body Structure: Swans have long, curved necks, and their bodies are streamlined for swimming, whereas the other birds have shorter necks and are primarily adapted for perching or flying.Swan is the only water bird in the group.

The given conditions are as follows.
P, Q, R are three girls.
A, B, C are three boys.
Q is taller than R i.e. Q > R.
C is taller than Q i.e. C > Q.
C is taller than A i.e. C > A.
P is taller than B i.e. P > B.
B is taller than C i.e. B > C.
Now, the arrangement can be as follows.
C > Q > R and P > B > C and C > R.
Now, after considering all the above given conditions, the
The arrangement is as follows.


R is the shortest among the three girls. P > Q > R.

As 'Architect' makes 'Building' similarly 'Sculptor' makes 'Statue'.

15 past 5 means quarter past 5 = (5:15)
⇒ (11*15 - 60*5)/2 = 67.5

Y occurs at: 04 ;11 ;12 ;33 ;44 ;
A occurs at: 00 ;03 ;22 ;24 ;43 ;
G occurs at: 57 ;59 ;76 ;78 ;87 ;
I occurs at: 55 ;56 ;66 ;95 ;97 ;

Explanation:
In the given expression, A*B/C-D+E, we can break it down as follows:
- A*B: A is the sister of B
- B/C: B is the father of C
- C-D: C is the brother of D
- D+E: D is the mother of E
Now, let's analyze the relationships:
1. A is the sister of B
2. B is the father of C, so A is the aunt of C (since A is the sister of C's father)
3. C is the brother of D, so A is also the aunt of D (since A is the aunt of C and D is C's sibling)
4. D is the mother of E, so A is the grand-aunt of E (since A is the aunt of E's mother)
Hence, the correct answer is:
A: Grand-aunt

Mother: 17 18 19 20 21 22 23 24 25 26 Father: 19 20 21 22 23 24 22 coming common and also divisible by 11.Hence Ram joined the school on June 22.

(16)² = 256

Therefore, (2)² = 4.

At 4 o' clock, the hands are 20 minute spaces apart.

To get the first 4 min spaces between the hands ,the minute hand has to gain 20 - 4 = 16 minute spaces over the hour hand.

To get the second 4 min spaces between the hands ,the minute hand has to gain 20 + 4 = 24 minute spaces over the hour hand.

In 60 minutes, minute hand gains 55 minute spaces over the hour hand.

Time taken for gaining 16 minute spaces by minute hand

In each row, the third figure comprises of a black circle and only those line segments which are not common to the first and the second figures.

From the first row we see that the third picture is a composition of the first two.
For the second row, the same pattern follows on, but we remove the line that is common to both the pictures, which is the bottom one.
For the third row, there are no common pictures, so it's just a simple composition picture of the first two. 

From figures (i), (ii) and (iii), we conclude that 1, 3, 5 and 6 dots appear adjacent to the face with 2 dots. Therefore, 4 dots will appear opposite to 2 dots. Now, from figures (i) and (ii), we conclude that 2, 3 and 5 dots appear adjacent to 1 dot Therefore, either 4 or 6 dots will appear opposite to 1 dot. But since, 4 dots appear opposite to 2 dots it follows that 6 dots will appear opposite 1 dots.

No rule is implied here. So all codes written as it is

Given sequence:
645     172     843     241     463     571
Second highest number: 645
Its 2nd digit = 4
Highest number: 843
Its 3rd digit = 3
Clearly, the resultant = 4 × 3 = 12
Hence, Option B is correct.

According to Mohit: Apr 18 or earlier ...(i)
According to his sister: April 18 or 19 ...(ii)
From (i) and (ii), we get Apr 18.

Using direct formula,
where m - minutes and h - hours
Time, between 3 o'clock and 4 o'clock, at which the hands will be together = 
minutes past 3 o'clock

The given numbers:
428    548    943    297    567    459
Arranging all the numbers in ascending order, we get:
297    428    459    548    567    943
The smallest and the second highest numbers are 297 and 567.
Now, required sum = 297 + 567 = 864
Multiplication of all the digits of 864 = 8 X 6 X 4 = 192
Hence, the correct answer is option B.

In the Following common explanation it is clear that Bravo joined IIMA.
Option A is hence the correct answer.

Common Explanation:
References:
Delta joined SP JAIN and did not take up Marketing or Logistics and is not a B. Tech.
Inference:

References:
Foxtrot is a C.A and has taken Finance management.
Inference:

References:
Alex joined IIMB, Charlie is B.A graduate and Bravo took up HR.
The person who joined IIMA opted for HR and is not a C.A or B.Sc.
Inference:

References:
The person, who is a B.A graduate, joined JBIMS and took Logistics
Inference:

References:
The person, who is a B. Tech graduate, has taken Operations Management and did not join UBS or DAVIET.
Inference:
Thus Alex is a B. Tech graduate.
Now as Delta has not opted for Marketing, Marketing must be opted by Echo, thus Delta opts General Management.

References:
The person, who is a  B . Com  graduate, took up General Management.
Inference:
Thus Delta is  B . Com  graduate.
Now is Bravo has not done B.Sc. he must have done BBM and thus Echo has done B.Sc.

Total number of students who got selected = (Vikas's rank from the top + Vikas's rank from the bottom) - 1 = 18 + 36 - 1 = 53
Hence, total number of students who were in class 12th = 53 + 12 + 7 = 72
Hence, the correct answer is option B.