Named, Rearrangement & Reagent - GATE Chemistry MCQ

First step is Freidel Craft alkylation and second step is wolf-Kishner reduction. Therefore, opteion (c) iscorrect.

Step - 1: Hoffman bromode degradation(amide is converted into 1⁰ amine)
Step - 2: Diazotization; followed by decarboxylation and removal of N₂ gas by heat.

This is asymmetric induction, followed by metal reduction by LiA1H₄.

The Favorski rearrangement is a chemical reaction involving:

• Conversion of α-haloketones into carboxylic acids.
• Occurs through intramolecular nucleophilic substitution.
• Forms cyclic or acyclic products based on the starting material.
• Commonly uses a base to facilitate the reaction process.

This rearrangement is significant in organic synthesis for creating complex molecules.

Oxalic acid is a mild acid, it will not isomerize.

The chelation effect in OH group is not given by the hydroxylation process because of steric effect.

It is the Swern-Oxidation with in absence of base. So, substitution product will be formed

This is acyl ion reaction mechanism is shown below :
 
 
 

DIBAL-H changes α - β unsaturated ester into alchol.

L-selective role is a Bulky reagent. So, will attack from equatorial side of the carbonyl group.

• Claisen Rearrangement:
  • Involves the rearrangement of allyl vinyl ethers to form γ,δ-unsaturated carbonyl compounds.
• Wolff Rearrangement:
  • Involves the conversion of α-diazoketones to ketenes, not isocyanates.
• Beckmann Rearrangement:
  • Transforms oximes into amides, not isocyanates.
• Schmidt Rearrangement:
  • Involves the transformation of azides, often leading to the formation of isocyanates.

The Schmidt rearrangement is the correct process for forming isocyanates.

Total number of five functional groups reduced by LiAlH₄.

In the above structure, RCOCl and R-NO₂ are not reduce by Borane.