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O.P Tandon Test: Some Basic Principles - NEET MCQ


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O.P Tandon Test: Some Basic Principles - Question 1

The compounds C2H5OC2H5 and CH3OCH2CH2CH3 are:

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 1
  • Chain isomerism occurs due to the possibility of branching in carbon chains.
  • Geometrical isomerism or configurational isomerism or cis-trans isomerism arises when the functional group are present on same side of carbon or are on opposite side of the carbon chain.
  • Metamerism arises when organic compounds have the same molecular formula but different alkyl groups on either side of the functional group.
  • In C2H5OC2H5 and CH3OCH2CH2CH3  , we can see that in diethyl ether we have 2 carbon atoms on the left side of oxygen but in methyl propyl ether we have one carbon atom on the left of oxygen. On the right hand side of oxygen, we have 2 carbon atoms but in methyl propyl ether, we have 3 carbon atoms.

So, we can say that above molecules are metamers. Therefore, option C is correct.

O.P Tandon Test: Some Basic Principles - Question 2

C7H7Cl shows how many benzenoid aromatic isomers?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 2

4 aromatic isomers are possible.

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O.P Tandon Test: Some Basic Principles - Question 3

How many minimum no. of C-atoms are required for position & geometrical isomerism in alkene?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 3

For positional isomerism in alkene 4C-atom required →

For geometrical isomerism in alkene also 4c–atom required →

O.P Tandon Test: Some Basic Principles - Question 4

How many structural formula are possible when one of the hydrogen is replaced by a chlorine atom in anthracene?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 4

There are 3 different positions of hydrogen. Hence, 3 structural isomers are possible.

O.P Tandon Test: Some Basic Principles - Question 5

The principle involved in paper chromatography is:

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 5
  • Partition chromatography because the substances are partitioned or distributed between liquid phases. 
  • The two phases are water held in pores of the filter paper and the other phase is a mobile phase that passes through the paper.
O.P Tandon Test: Some Basic Principles - Question 6

The number of cis-trans isomer possible for the following compound:

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 6

Cis-trans Isomers:- It is under the class of geometric isomer,

  • It exists in alkenes (organic molecules which have double bonds). 
  • When two similar or higher priority groups are attached to the carbon on the same side, it is termed as cis isomer and when it is attached to the opposite side it is called a trans isomer.

O.P Tandon Test: Some Basic Principles - Question 7

The number of isomers of dibromoderivative of an alkene (molear mass 186 g mol-1) is

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 7


O.P Tandon Test: Some Basic Principles - Question 8

Increasing order of stability among the three main conformation (i.e. eclipse, anti, gauche) of ethylene glycol is:

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 8



Stability order ⇒ Gauche > Anti > Eclipse

O.P Tandon Test: Some Basic Principles - Question 9

How many primary amines are possible for the formula C4H11N?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 9

Four primary amines are possible with the molecular formula C4H11N.

O.P Tandon Test: Some Basic Principles - Question 10

In which of the following compounds the carbon marked with asterisk is expected to have greatest positive charge?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 10

In CH3 - CH- Cl, the carbon marked with asterisk has the greatest positive charge due to high electronegativity of Cl.

O.P Tandon Test: Some Basic Principles - Question 11

How many planes (pos) are presents in Anthracene?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 11


(1) Vertical plane (2) Horizontal plane (3) Molecular Plane

O.P Tandon Test: Some Basic Principles - Question 12

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 12


O.P Tandon Test: Some Basic Principles - Question 13

Geometrical isomers can be:

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 13

Geometrical Isomers can be Diastereomers or Enantiomers.


Because geometrical isomers are around restricted rotation which can not be rotate or interconvertable.

O.P Tandon Test: Some Basic Principles - Question 14

Phenol and benzyl alcohol are:

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 14
  • Phenol is C6​H5​(OH) while benzyl alcohol is C6H5​(CH2​OH). 
  • Here there is a difference of −HC2​ between their molecular formula.
  • According to the definition of homologous series, the adjacent members of the series differ by −CH2​ group.
  • Thus Phenol and benzyl alcohol are homologous of each other.
O.P Tandon Test: Some Basic Principles - Question 15

Number of chiral centers are:

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 15


Number of chiral centers = 2

O.P Tandon Test: Some Basic Principles - Question 16

Which of the follownig compounds is (S)-4-chloro-1-methylcyclohexene ?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 16

(B) & (C) compounds are R-configuration.

O.P Tandon Test: Some Basic Principles - Question 17

Which of the following compounds has two stereogenic centers (asymmetric carbons) ?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 17

O.P Tandon Test: Some Basic Principles - Question 18

Which of the following structures represents a chiral compound ?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 18


All four substituent are different so it is chiral compound.

O.P Tandon Test: Some Basic Principles - Question 19

Examine the compound on the right. How many stereoisomers having this constitution are possible ?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 19


Asymmetric = 23 = 8

O.P Tandon Test: Some Basic Principles - Question 20

Which of the following heptanols are chiral 1-heptanol, 2-heptanol, 3-heptanol, 4-heptanol.

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 20





1-Heptanol & 4-Heptanol are not chiral
2-Heptanol & 3-Heptanol are chiral compound.

O.P Tandon Test: Some Basic Principles - Question 21

Which of the following will exhibit geometrical isomerism ?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 21





O.P Tandon Test: Some Basic Principles - Question 22

 (A)  

(B) 

Relation between given pair is

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 22

O.P Tandon Test: Some Basic Principles - Question 23

Following eclipsed form of propane is repeated after rotation of  

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 23

O.P Tandon Test: Some Basic Principles - Question 24

Stereoisomers differ from each other in what respect ?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 24

Stereoisomer differ from each other in configuration.

O.P Tandon Test: Some Basic Principles - Question 25

The number of isomers of C5H10 is

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 25










O.P Tandon Test: Some Basic Principles - Question 26


 The compound with the above configuration is called.

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 26


(2s, 3s) -2-chloro-3-Hydroxy Pentane

O.P Tandon Test: Some Basic Principles - Question 27

          

The above compounds differ in

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 27


The above compounds are different in structure.

O.P Tandon Test: Some Basic Principles - Question 28

Which conformer of cyclohexane is chiral?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 28

Twisted Boat form is chiral & optically active.

O.P Tandon Test: Some Basic Principles - Question 29

Minimum C atoms required for a compound to show geometrical isomerism:

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 29

The correct answer is 3.

Geometrical isomerism arises in compounds that have restricted rotation around a double bond or a cyclic structure. This leads to the formation of isomers that differ in the spatial orientation of the substituents around the double bond or within the ring.

For example, consider a compound with the formula C3H6. This could refer to either propene or cyclopropane. Propene has a double bond and can exhibit geometrical isomerism, while cyclopropane has no double bonds and cannot exhibit geometrical isomerism.

Therefore, to exhibit geometrical isomerism, a compound must have a double bond or a cyclic structure with at least three carbon atoms. So, the minimum number of carbon atoms required for a compound to show geometrical isomerism is 3.

O.P Tandon Test: Some Basic Principles - Question 30

Which among the following does not exhibit geometric isomerism?

Detailed Solution for O.P Tandon Test: Some Basic Principles - Question 30

Alkenes like 1-hexene when flipped from top to bottom they have identical structures and also they have C=CH2 unit which does not exist as cis-trans isomers.

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