OSSSC TGT Science PCM Mock Test - 9 - OTET MCQ

If a student does a mistake in language comprehensive-type questions, the teacher would provide appropriate questions with solutions and discuss the mistakes in detail.

The psychologist Robert Sternberg propounded the 'successful intelligence' theory. Intrapersonal intelligence is associated with the ability to understand one's feelings and thoughts.

Group projects must be given to the students as these projects help the students to understand the importance of working in a team and solve different problems effectively.

Active Participation means when children initiate to speak something when they try to participate in group discussions. The teachers force children so that they will try to be good speakers and gain confidence.
Hence, the correct answer is "Active participation".

A lesson can be introduced in the class by using examples related to the lesson so that it is easily understandable by children. Telling stories easily attracts students and students find it easy to understand such lessons by story-telling the children like to listen to the stories. That's why teachers introduce lessons with stories.
Hence, the correct answer is "All of these".

1. Current: This is a general term for the flow of electric charge. It can refer to any type of charge flow, not specifically electrons.

2. Electronic current: This specifically refers to the flow of electrons through a conductor.

3. Conventional current: This is the flow of positive charge and is considered to flow from the positive side to the negative side of a power source. Historically, this was defined before the discovery of electrons, so it is opposite to the direction of electron flow.

4. Photonic current: This is not a standard term in electrical engineering or physics. It might refer to currents related to photons in some contexts, but it is not related to the flow of electrons.

So, if you are referring to the flow of electrons specifically, electronic current is the accurate term.

Drift velocity is directly proportional to potential difference.
Drift velocity is defined as the average velocity with which free electrons get drifted towards the positive end of the conductor under the influence of an external electric field.
Drift velocity is given by
v_d​= eEτ​/ m
But, E=V/l​
(if l is length of the conductor and V is constant potential difference applied across the ends of the conductor)
∴v_d​= eVτ​/ml
⇒v_d​∝V
So, when the potential difference is doubled the drift velocity will be doubled.
Note - Current flowing through a conductor is directly proportional to the drift velocity.

As the magnetic field is parallel to the charge, no magnetic Lorentz force will act on it and it will move undeviated with constant velocity.

'u' should be the least distance of distinct vision.
U=-25cm
V=-50
(1/f)=(1/v)-(1/u)
=(-1/50) + (1/25)
=1/50
F=50cm
Hence a convex lens of focal length 50cm should be used.
 

Here, μ = 1.5, R₁ = 40 cm = 0.4 cm, R₂ = −0.4m

= 2.5D

P=P1​+P2​=+2−1=+1 dioptre, lens behaves as convergent
F=1​/P=1/1​=1m=100cm

Using the equation for the critical angle
θ=arcsin(n₂/n₁)
45^o= arcsin(1/n₁) à n₁=1/sin45o= √2

From the figure,
γ= α,
so,
sin β/sin γ à sin β=n₁sin γ/n₂ à
β=arcsin(n₁.sin γ/n₂)=arcsin(√2sin30^o/1)=arcsin(√2/2)à β=45^o

Representative elements in modern periodic table
The first two groups on the extreme left and last six groups on the extreme right involve the filling of s- and p- orbitals, respectively, These groups represent the main groups of the periodic table and are numbered as 1, 2, 13, 14, 15, 16, 17 and 18. The elements present in these groups are known as normal elements or representative elements.

When a transition metal ion is in highest oxidation state it tends to lower its oxidation state by gaining electrons. thus it itself reduces and oxidizes the substance from which it accepts electron. So, it acts as oxidising agent. 

 Used as a cleansing agent in industries and households. It finds its application in paper, textile, soap, and detergent industries.

1. Starch solution

Explanation: A colloidal solution consists of tiny particles suspended in a continuous medium. The particle size in a colloid is between that of a true solution and a suspension, meaning the particles do not settle out upon standing.

• Starch solution is a colloid because the starch particles are small enough to remain suspended in water without settling.
• Copper sulphate solution is a true solution, not a colloid.
• Chalk powder in water is a suspension, as the chalk particles settle down when left undisturbed.
• Kerosene oil and water form an immiscible liquid mixture, not a colloid.

Thus, starch solution is the correct example of a colloidal solution.

Carat is a unit of mass and is used for measuring gemstones and pearls.  1 ct. = 200 mg

In this Cl^– will oxidise to give Cl₂ Na⁺ water reduction potential has higher potential than that of water reduction potential, so water will reduce to give H₂.

The smallest alkane which can form a ring structure is a cyclopropane.

- Acids and Bases: Blue litmus turns red in the presence of an acid.
- Identifying the Acid:
- Mg(OH)₂: Magnesium hydroxide is a base.
- NaOH: Sodium hydroxide is a strong base.
- NH₄OH: Ammonium hydroxide is a weak base.
- CH₃COOH: Acetic acid is a weak acid.
- Correct Answer: Acetic acid (CH₃COOH) can turn blue litmus red because it is an acid.

Protoplasm is a colour less material that has a living part of a cell which includes the cytoplasm, nucleus, and other organelles.
Cytoplasm is a substance which is similar to jelly and is surrounded by the nucleus within the cell membrane.

Since if a circle inscribed a square. then the radius of the circle is half of to side of square.
∴  Radius = 10/2 = 5 cm
∴ Area of the circle = πr² = π(5)² = 25π sq. cm 

Equation of line perpendicular to x−y=0 is given by
y=−x+c
Also this line is tangent to the hyperbola x²−2y²=18
So we have m=−1, a²=18, b²=9
Thus Using condition of tangency c² = a²m²−b²
= 18−9=9
⇒ c = ±3
Hence required equation of tangent is x+y = ±3

If set A is equal to set B then every element of set A is in set B i.e. A ⊂ B and every element of set B is in set A i.e. B ⊂ A. Hence A ⊂ B and B ⊂ A.