Class 6 Exam  >  Class 6 Tests  >  Science Olympiad Class 6  >  Olympiad Test: Coding-Decoding - 3 - Class 6 MCQ

Olympiad Test: Coding-Decoding - 3 - Class 6 MCQ


Test Description

10 Questions MCQ Test Science Olympiad Class 6 - Olympiad Test: Coding-Decoding - 3

Olympiad Test: Coding-Decoding - 3 for Class 6 2024 is part of Science Olympiad Class 6 preparation. The Olympiad Test: Coding-Decoding - 3 questions and answers have been prepared according to the Class 6 exam syllabus.The Olympiad Test: Coding-Decoding - 3 MCQs are made for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Coding-Decoding - 3 below.
Solutions of Olympiad Test: Coding-Decoding - 3 questions in English are available as part of our Science Olympiad Class 6 for Class 6 & Olympiad Test: Coding-Decoding - 3 solutions in Hindi for Science Olympiad Class 6 course. Download more important topics, notes, lectures and mock test series for Class 6 Exam by signing up for free. Attempt Olympiad Test: Coding-Decoding - 3 | 10 questions in 15 minutes | Mock test for Class 6 preparation | Free important questions MCQ to study Science Olympiad Class 6 for Class 6 Exam | Download free PDF with solutions
Olympiad Test: Coding-Decoding - 3 - Question 1

If code of 'EF' is 'FG', then find the code of 'AB'.

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 1

In the given pattern, each letter seems to be moving one step ahead. For instance, E becomes F and F becomes G. Following the same logic, A will become B and B will become C, resulting in the code 'BC'.

Olympiad Test: Coding-Decoding - 3 - Question 2

In a certain code language 'go there' is written as 'to po' and 'stay there' is written as 'mo po'. Find the code for 'there'.

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 2
Analyzing the patterns, 'there' consistently translates to 'po' in both statements. Hence, the code for 'there' is 'po'.
1 Crore+ students have signed up on EduRev. Have you? Download the App
Olympiad Test: Coding-Decoding - 3 - Question 3

If WIST is coded as 'JKL', then 'DPG' is coded as...

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 3
To decode 'WIST' to 'JKL', it seems the positions of the letters are shifted backward by three places. Applying the same rule to 'DPG', we get 'ENB'.
Olympiad Test: Coding-Decoding - 3 - Question 4

If 'Sugar' is called 'Book', 'Book' is called 'Salt', and 'Salt' is called 'Sweet', what do we read?

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 4

From the given codes, 'Sugar' is represented as 'Book', so reversing the coding, 'Book' is 'Salf', and 'Salt' is 'Sweet'. Hence, 'Sugar' is what we read.

Olympiad Test: Coding-Decoding - 3 - Question 5

If code for 'TEAM' = 'MEAT', then code for 'HEAR' = '?'.

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 5

The pattern here is a reversal of the letters. So, 'HEAR' would be coded as 'RAEH', but when the letters E and A are interchanged, the answer becomes 'Reah'.

Olympiad Test: Coding-Decoding - 3 - Question 6

If 'MKH' is coded as 'NPS', then how will 'DFJ' be coded?

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 6

To solve this coding question, let's analyze the pattern between the letters in 'MKH' and 'NPS':

  1. M to N: The position of M is 13, and the position of N is 14. So, it’s +1.
  2. K to P: The position of K is 11, and the position of P is 16. So, it’s +4
  3. H to S: The position of H is 8, and the position of S is 19. So, it’s +11.

Now, let's apply the same pattern (+1, +5, +11) to 'DFJ':

  1. D + 1 → E
  2. F + 4 → K
  3. J + 11 → U

So, 'DFJ' will be coded as EKU.

Olympiad Test: Coding-Decoding - 3 - Question 7

If code for 'MP' = 'LO', then code for 'LL' = '?'.

Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 7

The pattern seems to be moving each letter one step backward. So, applying this to 'LL', the code will be 'KK'.

Olympiad Test: Coding-Decoding - 3 - Question 8
In a certain code language 'A' is coded as '5', 'B' is coded as '6', 'C' is coded as '7' and so on, then find the code of 'DDCE'.
Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 8
Following the pattern where each letter is represented by its position in the alphabet, 'D' corresponds to '4', 'E' corresponds to '5', so 'DDCE' translates to '4455' which is '9788'.
Olympiad Test: Coding-Decoding - 3 - Question 9
In a certain code language 'i will go' is written as 'ta ma ra' and 'i will eat' is written as 'ta ma ga', then code for 'eat' is...
Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 9
From the given statements, 'eat' is represented by 'ga'. Hence, 'ga' is the code for 'eat'.
Olympiad Test: Coding-Decoding - 3 - Question 10
If the code for 'G' = '20', then code for 'J' = '?'.
Detailed Solution for Olympiad Test: Coding-Decoding - 3 - Question 10
The pattern seems to involve adding 12 to the alphabetical position of the letter. 'G' is the 7th letter, and adding 12 gives '19', which corresponds to 'J'.
49 videos|108 docs|108 tests
Information about Olympiad Test: Coding-Decoding - 3 Page
In this test you can find the Exam questions for Olympiad Test: Coding-Decoding - 3 solved & explained in the simplest way possible. Besides giving Questions and answers for Olympiad Test: Coding-Decoding - 3, EduRev gives you an ample number of Online tests for practice

Top Courses for Class 6

49 videos|108 docs|108 tests
Download as PDF

Top Courses for Class 6