Olympiad Test: Computation Operations - 3 - Class 5 MCQ

As per the BODMAS rule:
30 – (5×2³ – 15)
=30 – (5×8 – 15)
=30 – (40 – 15)
=30 – 25
=5

As per the BODMAS rule:
Start with: (3 + 2)² – 5 × 3 + 2³
Do the Bracket first: (3 + 2) = 5
⇒ 5² – 5 × 3 + 2³
Next we do the orders:
5² = 25 and  2³ = 8
⇒ 25 – 5 × 3 + 8
Next we do the Multiplication:
⇒ 25 – 15 + 8
finally we do the Addition and Subtraction, in left-to-right order:
⇒ 10 + 8 
= 18

Using BODMAS rule
First Bracket:
15 ÷ 3 + 4
Do Division first:
15 ÷ 3 + 4 = 5 + 4
Then do Addition:
5 + 4 = 9
Second Bracket:
3² – 7 × 2
Do Orders first : [Remember that 32 means 3 × 3 = 9, not 3 × 2 = 6] Next do Multiplication:
32 – 7 × 2 = 9 – 7 × 2
9 – 7 × 2 = 9 – 14
Next Subtraction:
9 – 14 = – 5
Now complete the final Subtraction:
(15 ÷ 3 + 4) – (32 – 7 × 2) = 9 – (–5)
Lastly, subtracting a negative becomes a simple addition:
9 – (– 5) = 9 + 5 = 14

There are two sets of Brackets, so do one at a time.
First Bracket:
4² – 6 + 5
Do Order first:
4² – 6 + 5 = 16 – 6 + 5
Then do Subtraction and finally Addition:
16 – 6 + 5 = 10 + 5 = 15
Second Bracket:
3² + 8 – 7 × 2
Do Orders first:
3² + 8 – 7 × 2 = 9 + 8 – 7 × 2
Next do Multiplication:
9 + 8 – 7 × 2 = 9 + 8 – 14
Next do Addition and finally Subtraction:
9 + 8 – 14 = 17 – 14 = 3
Now complete the final Division:
(4² – 6 + 5) / (3² + 8 – 7 × 2) = 15 / 3 = 5

There are two sets of Brackets, so do one at a time.
First Bracket:
3³ – 2 × 7 Do Order (the exponent “3”) first:
3³ – 2 × 7 = 27 – 2 × 7
Then do Multiplication:
27 – 2 × 7 = 27 – 14
and finally Subtraction:
27 – 14 = 13
Second Bracket:
5 × 3 – 2²
Do Orders first:
5 × 3 – 2² = 5 × 3 – 4
Next do Multiplication:
5 × 3 – 4 = 15 – 4
Next do Subtraction:
15 – 4 = 11
Now complete the final Addition:
(33 – 2 × 7) + (5 × 3 – 2²)
= 13 + 11 = 24

We have 5 + 6 × 2 – 8 ÷ 4
= 5 + 6 × 2 – 2
= 5 + 12 – 2 
= 17 – 2 = 15 

Required value
= 2 + 4 × 6 – 8 ÷ 4 
= 2 + 4 × 6 – 2 
= 2 + 24 – 2
= 26 – 2 = 24 

Here – 24 – 45 ÷ 5 + 3
= – 24 – 9 + 3 
= – 33 + 3 = -30

Here – 4³ + (8 × 11) ÷ 4
= – 64 + (8 × 11) ÷ 4 
= – 64 + 88 ÷ 4 
= – 64 + 22 = – 42 

We have 9 + 2(7×3) – 9²
= 9 + 2(7×3) – 81 
= 9 + 2(21) – 81 
= 9 + 42 – 81 
= 51 – 81 = – 30

Given (6³ ÷ 4) – 4 × 5 + 3(7 – 2)
= (216 ÷ 4) – 4 × 5 + 3(7 – 2) 
= (54) – 4 × 5 + 3(7 – 2) 
= 54 – 4 × 5 + 3(5) 
= 54 – 20 + 3(5) 
= 54 – 20 + 15
= 34 + 15 = 49

We have (3 + 9)2 – 8(6 – 3)
= (12) × 2 – 8(3) 
= 24 – 24 = 0

Here 43 + 9 × 2 – 8
= 64 + 9 × 2 – 8 
= 64 + 18 – 8 
= 82 – 8 = 74 

Here 10 – 3³ + 5 – 2(4 – 8)
= 10 – 27 + 5 – 2(4 – 8) 
= 10 – 27 + 5 – 2 (– 4) 
= 10 – 27 + 5 – (– 8) 
= 10 – 27 + 5 – (– 8) 
= – 17 + 5 – (– 8) 
= – 17 + 5 + 8 
= – 12 + 8 = – 4

Here 6 × 2 + 3 – 35 ÷ 7
= 12 + 3 – 35 ÷ 7 
= 12 + 3 – 5
= 12 + 3 – 5 
= 15 – 5 = 10 

The order of operations states that multiplication and division must be performed before addition and subtraction. So for this expression, the correct verbal phrase would be: “the product of 8 and 2, subtracted from 9.”

The correct answer is 5 + 4 x 6 – 6. The order of operations states that multiplication is to be performed before addition and subtraction.
= 5 + 4 × 6 – 6 = 5 + 24 – 6
= 5 + 24 – 6 = 29 – 6
= 29 – 6 = 23