Practice Test: Arithmetic Progressions - Class 10 MCQ

The fourth term of an A.P. is 4. Then the sum of the first 7 terms is :

In an A.P., s₁ = 6, s₇ = 105, then s_n : s_n-3 is same as :

In an A.P. s₃ = 6, s₆ = 3, then it's common difference is equal to :

The number of terms common to the two A.P. s 2 + 5 + 8 + 11 + ...+ 98 and 3 + 8 + 13 + 18 +...+198

(p + q)th and (p – q)th terms of an A.P. are respectively m and n. The p^th term is :

The first, second and last terms of an A.P. are a,b and 2a. The number of terms in the A.P. is :

Let s₁, s₂, s₃ be the sums of n terms of three series in A.P., the first term of each being 1 and the common differences 1, 2, 3 respectively. If s₁ + s₃ = λs₂, then the value of λ is :

Sum of first 5 terms of an A.P. is one fourth of the sum of next five terms. If the first term = 2, then the common difference of the A.P. is :

If x,y,z are in A.P., then the value of (x + y – z) (y + z – x) is equal to :

The number of numbers between 105 and 1000 which are divisible by 7 is :

If the numbers a,b,c,d,e form an A.P. then the value of a – 4b + 6c – 4d + e is equal to :

If s_n denotes the sum of first n terms of an A.P., whose common difference is d, then s_n – 2s_n-1 + s_n-2 (n >2) is equal to :

The sum of all 2-digited numbers which leave remainder 1 when divided by 3 is :

The first term of an A.P. of consecutive integers is p² + 1. The sum of 2p + 1 terms of this series can be expressed as :

If the sum of n terms of an AP is 2n² + 5n, then its nth term is –

If the last term of an AP is 119 and the 8th term from the end is 91 then the common difference of the AP is –

If {a_n} = {2.5, 2.51, 2.52,...} and {b_n} = {3.72, 3.73, 3.74,...} be two AP's, then a₁₀₀₀₀₅ – b₁₀₀₀₀₅ =

If A₁ and A₂ be the two A.M.s between two numbers a and b, then (2A₁ – A₂) (2A₂ – A₁) is equal to :

 are in A.P., then n is equal to 

 where Sn denotes the sum of the first n terms of an A.P., then the common difference of the A.P. is

 In an Arithmetic Progression, if a = 28, d = -4, n = 7, then a_n is:

The sum of the first four terms of an A.P. is 56. The sum of the last four terms is 112. If its first term is 11, then find the number of terms.