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Practice Test: Electronics Engineering (ECE)- 12 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test GATE ECE (Electronics) Mock Test Series 2025 - Practice Test: Electronics Engineering (ECE)- 12

Practice Test: Electronics Engineering (ECE)- 12 for Electronics and Communication Engineering (ECE) 2024 is part of GATE ECE (Electronics) Mock Test Series 2025 preparation. The Practice Test: Electronics Engineering (ECE)- 12 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Practice Test: Electronics Engineering (ECE)- 12 MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test: Electronics Engineering (ECE)- 12 below.
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Practice Test: Electronics Engineering (ECE)- 12 - Question 1

Which of the following states the meaning of the idiom ‘Into the bargain’?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 1
‘Into the bargain’ has the meaning‘ in addition to what has already been mentioned or was expected’
Practice Test: Electronics Engineering (ECE)- 12 - Question 2

Direction: Find the correct relationship between the given quantities-

Quantity I: Let E be the set of all integers with 6 in their unit place. The probability that a number chosen from the set {10, 11, 12, ........59} is a member of E is?

Quantity II: A boy speaks truth in 70% of cases while another boy speaks truth in 65% cases. The probability that they will contradict each other on stating the same fact is?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 2
Quantity I: The sample space is n(s) = 50

The favourable outcomes are {16, 26, 36, 46, 56} i.e. 5

Probability = 5/50 = 0.1

Quantity II: Boy 1 speaks truth in 70% cases so 70/100 =7/10 and

Boy 2: 65/100 = 13/20

Boy 2 does not speak truth in 35/100 cases i.e. 7/20

Probability= p (A')*p (B) +p (A)*p (B’)

[7*7/ (10*20)]+ [3*13/ (10*20)]

= 0.44

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Practice Test: Electronics Engineering (ECE)- 12 - Question 3

A square metallic sheet of an area of 1296 square cm is used for making the toys. For taking the metallic sheet from that square – four equal sized of the circular plates have been cut –off. If a fencing with the Silver thread is required to make the base of toys, how many rolls of the thread is required, if a roll contains 30 cm of the thread only?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 3
Side * Side = 1296

⇒ Side= 36

Radius of each circular plate = ¼ of 36 = 9 cm

Circumference of each plate = 2 π 9 = 56.57 cm

Total Circumference = 4 *56.57 = 226.29 cm

No. of rolls = 226.29/30= 7.54 = 8 rolls

Practice Test: Electronics Engineering (ECE)- 12 - Question 4

The wrong (misfit) number of the sequence 36, 81, 144, 225, 256, 441 is

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 4
The pattern in the above sequence is the squares of consecutive multiples of 3;

62 = 36

92 = 81

122 = 144

152 = 225

182 = 324 ≠ 256

212 = 441

Thus the wrong number is 256

Hence Option D is correct

Practice Test: Electronics Engineering (ECE)- 12 - Question 5

Direction: Read the pie chart given below and answer the following questions-

The pie chart given shows the population of India in the 7 states considering there is no other states apart from these.

How much percent more is the population of UP than that of Odisha?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 5
Population of UP more than Odisha = 63⁰ - 36⁰ = 27⁰,

Now for percentage we have to calculate how much more population is in UP with respect to Odisha. So,

% more= (27⁰×100)/ 36⁰

= 75%

Practice Test: Electronics Engineering (ECE)- 12 - Question 6

Direction: In the following question, choose the word opposite in meaning to the given word as your answer.

Drought

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 6

Drought (noun) means a prolonged period of abnormally low rainfall, leading to a shortage of water. Its opposite is ‘flood’, which means an overflow of a large amount of water beyond its normal limits.

Practice Test: Electronics Engineering (ECE)- 12 - Question 7

Direction: Study the information carefully and answer the questions given below.

P is standing north of Q at a distance of 6m. R is standing toward east of P at a distance of 6m. R is to the north of S and distance between them is 6m. P is facing north direction, R is facing east, S is facing North and Q is facing towards west direction. All of them walk straight for 3m.

What is the distance between the final position of P and Q?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 7

3√10m

Let T be the final position of P and L be the final position of Q.

Now LT = √(32 + 92) = √(9 + 81) = √ 90 = 3√10m

Practice Test: Electronics Engineering (ECE)- 12 - Question 8

In the following question, a statement has been given followed by two arguments numbered I and II. Based on the argument, you have to decide which of the following argument is strong and which is a weak argument.

Statement: Shiva trilogy written by Amish Tripathi is the best fiction book.

Arguments

I. Yes, None other fiction books have three parts.

II. No, the best fiction book is subjective and it always differs from person to person.

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 8

Best fiction book or novel is a subjective thing and differs from person to person. Hence, the second argument is strong.

Practice Test: Electronics Engineering (ECE)- 12 - Question 9

A year after the deadliest Ebola outbreak ever in Africa, the virus has resurfaced in Congo this time around. It is not clear yet how the first victim—a man who has since died—caught the virus. But this outbreak is not the first in Congo; the country has suffered seven prior epidemics of the virus since 1976.

Which of the following is a conclusion that can be drawn from the above paragraph?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 9

It has been said that the biggest ever Ebola epidemic in Africa struck last year. Hence, (A) is false.

The paragraph says that the first victim of the most recent Ebola outbreak in Congo is dead. Hence, (B) can be concluded from the paragraph.

It has nowhere been mentioned that Congo was not affected by last year’s epidemic. Hence (C) cannot be concluded.

Scientists have not yet figured out how the epidemic resurfaced this time, since the first victim is dead. Hence (D) cannot be concluded.

Practice Test: Electronics Engineering (ECE)- 12 - Question 10

Direction: Following bar graphs shows time taken by different pipes to fill that particular percentage of tank which is described in tabular data. For Ex- Pipe 1 fills the 10 % of tank in 6 mins.

Now, read the following data and answer the question carefully:

A Tank has three pipes; two of them are used to fil the tank while another one used to empty the tank namely: pipe 3, pipe 5 to fill the tank and a new third pipe for making the tank empty. When all three pipes are open, 7/18th part of the tank is filled in 1 hours. What is the ratio of the efficiency of Pipe-3: Pipe 5: all three pipes working together.

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 10

part of work in one hour =

(P3+P5+Third pipE. X 1 = 7/18th part of work

⇒ 7/18th part of work = 1 hr

⇒ Total work done = 18/7 hr by all three pipes

Pipe 3 does 50% of work in 90 mins

100 % of work = 90/50 * 100 = 180 mins = 3 hr

Pipe 5 does 50% of work in 60 mins

100 % of work = 60/50 * 100 = 120 mins = 2 hr

Time Tw Efficiency

Pipe -3 = 3 hr Total work

Pipe-5 = 2 hr Total work

All three = 18/7 hr Total work

hence efficiency ratio: 6: 9: 7

Practice Test: Electronics Engineering (ECE)- 12 - Question 11

Find the unit normal vector of the cone of revolution z2 = 9x2 + 15y2 at a point (1,0,3)

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 11
The unit normal vector is the grad of f = 9x2 + 15y2 - z2

Practice Test: Electronics Engineering (ECE)- 12 - Question 12

Minimum of real value function f(x) = (x−1)2/5 occurs at x equal to


Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 12

as f(x) is square of hence its min, value be 0 where at (x=1)

Practice Test: Electronics Engineering (ECE)- 12 - Question 13

The transfer function of a system is 10/(s2 + 2s + 10). Find the nature of the given system.

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 13
On comparing the given characteristic equation with the standard second-order transfer function,

ωn2/(s2+2ζωns+ωn2).

Hence, ωn2 = 10 ; 2 ζωn = 2 ⇒ ζ = 0.316

For 0 < ζ < 1, the system is said to be Under-damped.

*Answer can only contain numeric values
Practice Test: Electronics Engineering (ECE)- 12 - Question 14

In a transistor circuit , ICO = ICBO = 2μA , also it is given that α = 0.98

Then the value of ICEO is _______(μA).


Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 14

Practice Test: Electronics Engineering (ECE)- 12 - Question 15

There are two energy levels E1 and E2. E1 is E eV above the fermi level and E2 is E eV below the fermi level.

P1 = the probability of E1 being occupied by an electron.

P2 = the probability of E2 being empty.

Then, which of the following is correct?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 15
The Fermi- Dirac probability function also called Fermi function, provides the probability of occupancy of energy levels. It is given by

where EF is Fermi level or Characteristics energy, for the crystal in eV. The fermi level represents the energy state with 50 percent probability of being filled if no forbidden band exists.

Therefore, P1 And P2 can be calculated by using Fermi- Dirac probability function.

For P1

Practice Test: Electronics Engineering (ECE)- 12 - Question 16

Match List I (Regions of Bipolar Transistor in a Monolithic IC) with list II (Physical Properties)

List I

a) Emitter

b) Base

c) Collector

d) Substrate

List II

(1) Moderate resistivity

(2) Very high resistivity

(3) Large size

(4) Very high Conductivity

Select the correct answers from the following.

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 16

Emitter – High Doping and very high conductivity

Collector – Large Size

Substrate- Very high resistivity

Base- Moderate resistivity

Practice Test: Electronics Engineering (ECE)- 12 - Question 17

Consider the circuit shown in the figure below

v(t) = 80e−1000tV ;t>0

i(t) = 5e−1000tmA ;t>0

the energy dissipated (in μ) by the resistor for 0 < t="" />< 0.6="" ms="" will="" be="" />


Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 17
The energy dissipated in the resistance is

Practice Test: Electronics Engineering (ECE)- 12 - Question 18

A practical voltage source consists of:

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 18
An ideal current source is expected to have zero losses, but practically this is not possible. The internal loss of the current source is represented as an internal resistance ‘r’ placed in series with the current source. It is placed in parallel because current remains equal in series components and divides in parallel components.
Practice Test: Electronics Engineering (ECE)- 12 - Question 19

While analysing a two-port network, which of the following parameters are obtained when one-port variables are expressed in terms of the other port variables?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 19
Expressing one port variables in terms of the other port variables,

(V1,I1) = f(V2, - I2)

The parameters so obtained are the T-parameters or the ABCD-parameters.

These are used for the analysis of the power transmission line. The input and output ports are the sending and the receiving ends respectively.

Practice Test: Electronics Engineering (ECE)- 12 - Question 20

Consider the following sentences regarding a periodic signal

a) A periodic signal always repeats itself after minimum fundamental time period T.

b) A periodic signal is exist from -∞ to +∞ and converse is also true.

c) A periodic signal exist from -∞ to +∞.

Which of the following is/are correct option?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 20
A- Is the definition of any periodic signal.

B- A periodic signal is only exist from -∞ to +∞ and converse is not true because any signal or anything practically always take birth from origin means from it increases. If it comes from positive to negative then it is a decaying signal not a periodic signal. Thus, option A is the correct answer.

Practice Test: Electronics Engineering (ECE)- 12 - Question 21

The impulse response of a second order under damped system starting from rest is given by

C(t) = 12.5e-8tcos 6t

What are the responsive value of natural frequency and damping ratio of the system?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 21

Practice Test: Electronics Engineering (ECE)- 12 - Question 22

If x(t) = δ(2t/3), what will be its amplitude at t = 0?

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 22
According to the property of Unit Impulse function

δ(t) = 0, t ≠ 0

≠ 0, t = 0 (Very Large Infinite)

Since delta function represents an infinite amplitude spike at t = 0 having area = 1.

Hence, value of x(t) at t = 0 would be infinite

*Answer can only contain numeric values
Practice Test: Electronics Engineering (ECE)- 12 - Question 23

For the CE amplifier shown, calculate value of lower cutoff frequency FL (in Hz) due to C2


Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 23

Practice Test: Electronics Engineering (ECE)- 12 - Question 24

In the given figure, β = 100, the magnitude of voltage gain (V0/Vin) will be ___ (thermal voltage is 25mV)


Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 24

First we draw the AC equivalent of circuit

Voltage gain (Av) = -gmRc

Practice Test: Electronics Engineering (ECE)- 12 - Question 25

Calculate the hysteresis width (in Volts) for an inverting Schmitt trigger with feedback fraction 0.5. Assume the supply voltage to be 10


Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 25

For a inverting Schmitt trigger.

Given: β = 0.5, Vcc = 10V

Hysteresis Voltage VH = VUT - VLT

VUT = +β x Vcc

VLT = -β x Vcc

VH = 2 x β x Vcc

VH = 2 x 0.5 x 10

VH = 10V

Practice Test: Electronics Engineering (ECE)- 12 - Question 26

For a given sample-and-hold circuit, if the value of the hold capacitor is increased, then

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 26
Capacitar drap rate = dv/dt

For a capacitar,

Drap rate decreases as capacitar value is increased

For a capacitar,

Q = cv = i × t

⇒ t ∝ c

∴ Acquisition time increases as capacitar value increased

Practice Test: Electronics Engineering (ECE)- 12 - Question 27

The amplitude of a random signal is uniformly distributed between -5 V and 5 V.

If the signal to quantization noise ratio required in uniformly quantizing the signal is 43.5 dB, the step size (in V) of the quantization is approximately

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 27

Which is close to 0.0667 Volts

Practice Test: Electronics Engineering (ECE)- 12 - Question 28

The Potential (scalar) distribution in free space is given as V = 10y4 + 20x3. if ε0 is permittivity of free space then the charge density ρ at the point (2,0) is

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 28
Here, we have to use Passion’s Equation,

At paint (2,0)

ρ = -240ε0

Practice Test: Electronics Engineering (ECE)- 12 - Question 29

For a telephone line, β = 0.02rad/km. If frequency is 1 kHz. Calculate time taken to travel 3.14 km by the wave in


Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 29

Practice Test: Electronics Engineering (ECE)- 12 - Question 30

Consider an air-filled rectangular waveguide with inside dimensions 5 cm x 2cm. If the wave impedance is 222.24 Ω for TM11 mode of propagation. Then the operating frequency (in GHz)is given by


Detailed Solution for Practice Test: Electronics Engineering (ECE)- 12 - Question 30
Given a = 5cm, b 2cm, ηTM11 = 222.24Ω

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