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Electronics and Communication Engineering (ECE) Exam  >  Electronics and Communication Engineering (ECE) Tests  >  GATE ECE (Electronics) Mock Test Series 2025  >  Practice Test: Electronics Engineering (ECE)- 3 - Electronics and Communication Engineering (ECE) MCQ

Practice Test: Electronics Engineering (ECE)- 3 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test GATE ECE (Electronics) Mock Test Series 2025 - Practice Test: Electronics Engineering (ECE)- 3

Practice Test: Electronics Engineering (ECE)- 3 for Electronics and Communication Engineering (ECE) 2024 is part of GATE ECE (Electronics) Mock Test Series 2025 preparation. The Practice Test: Electronics Engineering (ECE)- 3 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Practice Test: Electronics Engineering (ECE)- 3 MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test: Electronics Engineering (ECE)- 3 below.
Solutions of Practice Test: Electronics Engineering (ECE)- 3 questions in English are available as part of our GATE ECE (Electronics) Mock Test Series 2025 for Electronics and Communication Engineering (ECE) & Practice Test: Electronics Engineering (ECE)- 3 solutions in Hindi for GATE ECE (Electronics) Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free. Attempt Practice Test: Electronics Engineering (ECE)- 3 | 65 questions in 180 minutes | Mock test for Electronics and Communication Engineering (ECE) preparation | Free important questions MCQ to study GATE ECE (Electronics) Mock Test Series 2025 for Electronics and Communication Engineering (ECE) Exam | Download free PDF with solutions
Practice Test: Electronics Engineering (ECE)- 3 - Question 1
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“Wanted a two bedroom flat in the court area for immediate possession” - An Advertisement.
Assumptions:
I. Flats are available in the court area
II. Some people will respond to the advertisement
III. It is a practice to give such an advertisement

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 1

The advertisement depicts only the requirement, not the availability of flats in court area. So, I is not implicit. Such advertisements are given with the expectation of a response which can make such a flat available. So, II is implicit. Assumption III does not follow from the statement and so is not implicit.

Practice Test: Electronics Engineering (ECE)- 3 - Question 2
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Which of the following is most similar in meaning to the given word
DIRE

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 2

DIRE means very serious 

Alarming means something very serious. 

So the correct answer is ALARMING

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Practice Test: Electronics Engineering (ECE)- 3 - Question 3
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In the question given below, the sentence has a part printed in bold. That part may contain a grammatical error. Replace that part with four choices given below:

The famous playwright has been in the sick bed from the last one week.

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 3

We use the present perfect continuous tense to talk about an action that started in the past and is continuing now. This is often used with 'for' (showing period of time) or since (showing point of time).

As the given sentence is one, the prepositional phrase 'from the last' must be replaced with 'for the past' to make it a grammatically correct sentence. 
 

Practice Test: Electronics Engineering (ECE)- 3 - Question 4
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He always _________ you in his letters
Practice Test: Electronics Engineering (ECE)- 3 - Question 5
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His health ____________ under the pressure of work.
Practice Test: Electronics Engineering (ECE)- 3 - Question 6
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A, B and C shoots to hit a target. If A hits the target 4 times in 5 trials, B hits in 3 times in 4 trials and C hits it 2 times in 3 trials. What is the probability that the target is hit by at least 2 persons?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 6
Probability that A hits the target = 4/5
Probability that B hits the target = 3/4
Probability that C hits the target = 2/3
P (at least 2) = P(2) + P(3)
Practice Test: Electronics Engineering (ECE)- 3 - Question 7
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Two liquids are mixed in the ratio 4:3 and the mixture is sold at Rs 20 with a profit of   %. If the first liquid is costlier than the second by Rs 7. Find the sum of costs of both the liquids.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 7
Profit = %

Cost of 1 unit of liquid 1 = x+7
Cost of 1 unit of liquid 2 = x
(x+7)×4+3x = 15(4+3)
x = 11
x+7 = 18
Total value of the prices = 11+18 = 29
Practice Test: Electronics Engineering (ECE)- 3 - Question 8
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Henry and Ford worked together to complete a task in 10 days. Had Henry worked with half of his efficiency and Ford at 5 times of his efficiency it would have taken them to finish the job in 50% of the scheduled time. In how many days can Ford complete the job working alone?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 8
Let henry’s one day work be x
Let ford’s one day work be y

Solving 2 equations we get, y = 1/30
Hence, Ford can complete the job working alone in 30 days
Practice Test: Electronics Engineering (ECE)- 3 - Question 9
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A new flag is to be designed with six vertical stripes using some or all of the colours- yellow, green, blue and red. Then the number of ways this can be done such that no two adjacent stripes have the same colour out is:
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 9
There are 6 stripes. The stripe can be coloured in 4ways, in 3, in 3 and so on.
Thus, total number of ways = 4×3×3×3×3×3=12×81
Practice Test: Electronics Engineering (ECE)- 3 - Question 10
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Find the value of
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 10

y(y-3) = 0
y = 3
Practice Test: Electronics Engineering (ECE)- 3 - Question 11
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In the given circuit determine the value of current source
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 11
V = 4i

2i = 4–v
2i = 4 – 4i
6i = 4
i = 2/3
So, v = 8/3
Practice Test: Electronics Engineering (ECE)- 3 - Question 12
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If power of a signal x (t) is 6 units, then determine the power of g(t), where g (t) is given as,
g(t) = 4x (t)
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 12
Power of g(t),

= 48 + 108
= 156 units
Practice Test: Electronics Engineering (ECE)- 3 - Question 13
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Which one of the following is non-periodic?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 13
For a signal to be periodic, the signal must be define from
Practice Test: Electronics Engineering (ECE)- 3 - Question 14
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The ROC of z-transform of the discrete time sequence, x(n) so that x(n) is absolutely summable

Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 14


Practice Test: Electronics Engineering (ECE)- 3 - Question 15
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Consider two signals and in which is band limited to 3 kHZ and is band limited to 2KHz, determine the minimum sampling frequency of g(t) where
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 15
Convolution in time domain results multiplication in frequency domain,
So resultant signal in frequency domain is limited upto 2 KHz, i.e. = 2kHz
so,             = 2 × 2
                        = 4 KHz
Practice Test: Electronics Engineering (ECE)- 3 - Question 16
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A TDM link has 30 signal channels and each channel is sampled 9000 times/sec. Each sample is represented by seven binary bits and contains an additional bit for synchronization. The total bit rate for the TDM link is:
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 16
Bit rate = 30 × 9000 (7 + 1) bits/second
= 2160 kbps
Practice Test: Electronics Engineering (ECE)- 3 - Question 17
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The signal flow graph of a closed loop system is shown in the figure, where represents the disturbance in the forward path. The effect of the disturbance can be reduced by
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 17
With feedback, the output due to disturbance

Without feedback output due to disturbance is

By comparing above two equations, feedback decreases the effect of noise
If Increases, disturbance decreases, But gain also decreases. This is not desirable.
If increases, disturbance increases, since noise links with
If increases, disturbance decreases, and gain also decreases. This is desirable.
Practice Test: Electronics Engineering (ECE)- 3 - Question 18
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The energy of constant-amplitude complex valued exponential sequence is __________ (where A is the constant amplitude)
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 18

Practice Test: Electronics Engineering (ECE)- 3 - Question 19
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In the given circuit input voltage Vin is 3V and VB is 1.5V. The resistance R is 1.5K. Cut-in voltage of diode is 0.5V. Forward bias resistance is 10Ω. The Voltage V will be ____________
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 19

Answer: b
Explanation: In piecewise linear model, we can consider diode as a voltage source of 0.5V along with an ideal diode. VIN being applied is 3V, which is greater than 1.5-0.5 V, and hence the diode is reverse biased and input appears at output.

Practice Test: Electronics Engineering (ECE)- 3 - Question 20
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Which of the following is a microwave power amplifier?
Practice Test: Electronics Engineering (ECE)- 3 - Question 21
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A carrier signal is amplitude modulated by a message signal m (t) = .If the modulation index is 0.5, then the power in USB is given by 
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 21

Practice Test: Electronics Engineering (ECE)- 3 - Question 22
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For the circuit shown in the figure assume ideal diodes with forward resistance and forward voltage drop are zero. The current through diode
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 22
In the given circuit both the diodes cannot be ON simultaneously.
In the above circuit only is ON.
So current through diode is Zero.
Practice Test: Electronics Engineering (ECE)- 3 - Question 23
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Determine the value of in the given circuit given = 100
 
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 23

Since is negative, so Transistor is in cut-off mode, therefore, = 0
and = 10V and =0
Therefore
= 10 volt
Practice Test: Electronics Engineering (ECE)- 3 - Question 24
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Determine the value of in the circuit, assume op-amp is ideal.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 24

= 11–10
= 1 volt
Practice Test: Electronics Engineering (ECE)- 3 - Question 25
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Assume the op-amp is ideal the transfer characteristics of the circuit is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 25
In the given circuit for positive half cycle of input voltage is at  i.e. –10V and diode is off,and during negative half cycle is at  i.e. +10V, so diode is ON and,virtual short-cirucit exist.
Therefore, 
So transfer characteristic
Practice Test: Electronics Engineering (ECE)- 3 - Question 26
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If cross-sectional area of base-emitter junction of transistor is 2 times of transistor then determine the value of Assume of both the transistors are very large
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 26

= 4.65 mA
As the area of base-emitter junction of transistor is two times of So
Practice Test: Electronics Engineering (ECE)- 3 - Question 27
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7 EH and 5 FH are XORed. The output is multiplied by 10 H. The result is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 27
7EH - 01111110
5FH -  01011111
XORed 0010 0001 21H
Practice Test: Electronics Engineering (ECE)- 3 - Question 28
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The minimal some of products form of is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 28

The K-map of the above function

So, the required minimal SoP of f is
f =
Practice Test: Electronics Engineering (ECE)- 3 - Question 29
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In a twin-wire transmission line in air, the adjacent voltage maxima are at 12 cm and 18 cm. The operating frequency is.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 29
Adjacent maxima appear with a distance of

f = 2.5 GHZ
Practice Test: Electronics Engineering (ECE)- 3 - Question 30
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A system has receiver noise resistance of 50W. It is connected to an antenna with an input resistance of 50W The noise figure of the system is.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 3 - Question 30
The overall noise figure of the receiver is,


= 2
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