CBSE Class 10  >  Class 10 Test  >  Online MCQ Tests  >  RD Sharma Test: Coordinate Geometry - Class 10 MCQ

RD Sharma Test: Coordinate Geometry - Class 10 Free MCQs with solutions


MCQ Practice Test & Solutions: RD Sharma Test: Coordinate Geometry (25 Questions)

You can prepare effectively for Class 10 Online MCQ Tests for Class 10 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "RD Sharma Test: Coordinate Geometry". These 25 questions have been designed by the experts with the latest curriculum of Class 10 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 25 minutes
  • - Number of Questions: 25

Sign up on EduRev for free to attempt this test and track your preparation progress.

RD Sharma Test: Coordinate Geometry - Question 1

The distance of the point (– 3, 4) from the origin is

Detailed Solution: Question 1

Let the given point be (x1, y1) = (-3, 4) and the orgin is (x2, y2) = (0, 0)
∴ Distance of the given point from the orgin = 

RD Sharma Test: Coordinate Geometry - Question 2

If A and B are the points (– 6, 7) and (– 1, – 5) respectively, then the distance 2AB is equal to 26 units 13 units 15 units 20 units 2AB 

Detailed Solution: Question 2

RD Sharma Test: Coordinate Geometry - Question 3

The distance between the points (a, a) and (−√3a,√3a) is

Detailed Solution: Question 3

RD Sharma Test: Coordinate Geometry - Question 4

Three consecutive vertices of a parallelogram ABCD are A(1, 2), B(1, 0) and C(4, 0). The co – ordinates of the fourth vertex D are

Detailed Solution: Question 4

Let coordinates of D be (x, y).
Since diagonals of a parallelogram bisect each other.

Therefore, coordinates of O will be 

Therefore, the required coordinates are (4, 2).

RD Sharma Test: Coordinate Geometry - Question 5

If (a, 0) , (0, b) and (x, y) are collinear, then

Detailed Solution: Question 5

If given points are collinear, the triangle formed by these three points is 0.

RD Sharma Test: Coordinate Geometry - Question 6

The distance between the points (– 1, – 5) and (– 6, 7) is

Detailed Solution: Question 6

Let point A be (x1, y1) = (-1, -5) and point B (x2, y2) = (-6, 7)
∴Distance between A and B

RD Sharma Test: Coordinate Geometry - Question 7

If P(x, y) is any point on the line joining the points A(a, 0) and B(0, b), then

Detailed Solution: Question 7


RD Sharma Test: Coordinate Geometry - Question 8

The distance between the points A(p sin 25, 0) and B(0, p sin 65) is

Detailed Solution: Question 8

p units p2 units 1 units 0 units Distance between 

RD Sharma Test: Coordinate Geometry - Question 9

The length of the median through A of  ΔABC with vertices A(7, – 3), B(5, 3) and C(3, – 1) is

Detailed Solution: Question 9

RD Sharma Test: Coordinate Geometry - Question 10

If the co – ordinates of a point are (3, – 7), then its ordinate is

Detailed Solution: Question 10

Since y−coordinate is called ordinate. 
Therefore, ordinate is −7.

RD Sharma Test: Coordinate Geometry - Question 11

The distance between the points (a, b) and (– a, b) is

Detailed Solution: Question 11

Let point A be (a, b) and point B is (-a, b)

∴ distance between A and B
 

RD Sharma Test: Coordinate Geometry - Question 12

The vertices of a quadrilateral are (1, 7), (4, 2), (– 1, – 1) and (– 4, 4). The quadrilateral is a

Detailed Solution: Question 12

Let A (1, 7), B (4, 2), C (-1, -1) and D(-4, 4) are the vertices of a quardinate


 


 

Since, all sides are equal and both diagonals are also equal.
Therefore, the given quadrilateral is a square.

RD Sharma Test: Coordinate Geometry - Question 13

The distance between 

Detailed Solution: Question 13

The distance between 


 

RD Sharma Test: Coordinate Geometry - Question 14

If the line segment joining the points A(x1,y1) and B(x2,y2) is divided by a point P in the ratio 1 : k internally, then the co – ordinates of the point P are

Detailed Solution: Question 14


RD Sharma Test: Coordinate Geometry - Question 15

If the co – ordinates of a point are (– 5, 11), then its abscissa is

Detailed Solution: Question 15

Since x−coordinate is called abscissa. 
Therefore, abscissa is −5.

RD Sharma Test: Coordinate Geometry - Question 16

If the distance between the points (p, – 5) and (2, 7) is 13 units, then the value of ‘p’ is

Detailed Solution: Question 16

Let point A be (p,−5)(p,−5) and point B (2, 7) and distance between A and B = 13 units

RD Sharma Test: Coordinate Geometry - Question 17

If A is point on the x – axis whose abscissa is 5 and B is the point (1, – 3), then the distance AB is

Detailed Solution: Question 17

RD Sharma Test: Coordinate Geometry - Question 18

The point where the medians of a triangle meet is called the ________ of the triangle

Detailed Solution: Question 18

The point where the medians of a triangle meet is called thecentroidof the triangle.

RD Sharma Test: Coordinate Geometry - Question 19

The base of an equilateral triangle ABC lies on the y – axis. The co – ordinates of the point C is (0, – 3). If origin is the midpoint of BC, then the co – ordinates of B are

Detailed Solution: Question 19


RD Sharma Test: Coordinate Geometry - Question 20

The abscissa of any point on the y – axis is

Detailed Solution: Question 20

Since coordinates of any point on y−axis is (0,y).
Therefore, abscissa is 0.

RD Sharma Test: Coordinate Geometry - Question 21

The values of ‘y’ for which the distance between the points (2, – 3) and (10, y) is 10 units is

Detailed Solution: Question 21

Let  one point be A (2,−3) and 2nd point is B (10,y) and

distance between point A and point B = AB = 10 units

RD Sharma Test: Coordinate Geometry - Question 22

The distance of the point (– 5, 12) from the y – axis is

Detailed Solution: Question 22

The distance of any point from y−axis is its abscissa. Therefore, the required distance is 5 units.

RD Sharma Test: Coordinate Geometry - Question 23

The co – ordinates of the mid – point of the line segment joining the points (– 2, 3) and (4, – 5) are

Detailed Solution: Question 23

Let the coordinates of midpoint C(x,y) of the line segment joining the points A(−2,3) and B(4,−5).

RD Sharma Test: Coordinate Geometry - Question 24

The point where the perpendicular bisector of the line segment joining the points A(2, 5) and B(4, 7) cuts is:

Detailed Solution: Question 24

Since, the point, where the perpendicular bisector of a line segment cuts, is the mid-point of that line segment. 
∴ Coordinates of Mid-point of line segment AB = 

RD Sharma Test: Coordinate Geometry - Question 25

The distance of a point from the y – axis is called

Detailed Solution: Question 25

The distance of a point from the y – axis is called abscissa.

459 tests
Information about RD Sharma Test: Coordinate Geometry Page
In this test you can find the Exam questions for RD Sharma Test: Coordinate Geometry solved & explained in the simplest way possible. Besides giving Questions and answers for RD Sharma Test: Coordinate Geometry, EduRev gives you an ample number of Online tests for practice
Download as PDF