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RRB JE ECE (CBT II) Mock Test- 1 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test RRB JE Mock Test Series for ECE 2025 - RRB JE ECE (CBT II) Mock Test- 1

RRB JE ECE (CBT II) Mock Test- 1 for Electronics and Communication Engineering (ECE) 2024 is part of RRB JE Mock Test Series for ECE 2025 preparation. The RRB JE ECE (CBT II) Mock Test- 1 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The RRB JE ECE (CBT II) Mock Test- 1 MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE ECE (CBT II) Mock Test- 1 below.
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RRB JE ECE (CBT II) Mock Test- 1 - Question 1

The internet allows to ___.

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 1

The internet connects to different systems on the network and allows the users to send Emails, browse websites and share information on the server.

RRB JE ECE (CBT II) Mock Test- 1 - Question 2

Which of the following memories requires periodic refreshing to store data?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 2

D in DRAM stands for Dynamic, which means there is leakage of charge where periodic refreshing is required.

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RRB JE ECE (CBT II) Mock Test- 1 - Question 3

In Linux and Unix CTRL+D is used to _______.

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 3

​CTRL + D closes the command line shell. This sends an EOF (End of file) marker to shell, and shell exits when it receives this marker. This is similar to running the exit command.

RRB JE ECE (CBT II) Mock Test- 1 - Question 4

If the refractive index of glass is 1.732, find the Brewster’s angle–

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 4

We know, μ = tan ip

Where ip = Polarization or Brewster’s angl

∴ ip = tan-1 μ = tan-1(1.732) = 60°

RRB JE ECE (CBT II) Mock Test- 1 - Question 5

Which of these poets were awarded 'Saraswati Samman 2017' on 22 January 2019?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 5
  • Gujarati poet Sitanshu Yashashchandra was awarded 'Saraswati Samman 2017' on 22 January 2019.
  • He was awarded for his poetry collection in Gujarati named 'Vakhar'.
  • The award was instituted by K.K.Birla foundation.
  • The award is given every year to an outstanding work of an Indian citizen published during the last 10 years in any of the languages mentioned in Schedule 8 of the constitution.
RRB JE ECE (CBT II) Mock Test- 1 - Question 6

What does WLAN stand for?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 6

A local area network (LAN) is a computer network tht interconnects computers within a limited area such as a residence, school, laboratory, university campus etc.

LANs can span over a limited range i.e. of 1 km in radius.

WLAN, which stands for 'Wireless Local Area Network', is when a mobile user connects to a local area network via a wireless connection.

RRB JE ECE (CBT II) Mock Test- 1 - Question 7

Control bus in a microprocessor are:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 7

Control Bus is a group of conducting wires, which is used to generate timing and control signals to control the associated peripherals, the microprocessor uses control bus to process data.

Some control signals are:

Memory read

Memory write

I/O read

I/O Write

Opcode fetch

RRB JE ECE (CBT II) Mock Test- 1 - Question 8

Which of the following pointer is used to delete data in queue?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 8

A queue is an ordered list in which insertions are done at one end (rear) and deletions are done at other ends (front). The first element to be inserted is the first one to be deleted. Hence, it is called First in First out (FIFO) or Last in Last out (LILO) list.

RRB JE ECE (CBT II) Mock Test- 1 - Question 9

In a certain representation, 0 is written as 1111. The representation is:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 9

The table shows a 4-bit representation of numbers in all forms

RRB JE ECE (CBT II) Mock Test- 1 - Question 10

The Default Parameter Passing Mechanism is called as

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 10

Program:
#include<stdio.h>
void print(int a)
{
printf("%d",a);
}
int main()
{
                int num = 7;
                print(num);
                return 0;
}
Output: 7
Concept:
User defined function is print. In print parameter passed is num. Value of num is passed to the defined function print. In print function, integer a received the value of num and print it.
From this it can be said that default parameter passing is call by value

RRB JE ECE (CBT II) Mock Test- 1 - Question 11

An op-amp has a common mode gain of 0.001 and a differential mode gain of 107. Its CMRR would be

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 11

CMRR is the ratio of differential mode gain to common mode gain
CMRR = Ad/Acm
CMRR = 107/10-3 = 1010
CMRR value is usually expressed in Decibels and can be converted using 20 Log (CMRR)

RRB JE ECE (CBT II) Mock Test- 1 - Question 12

Calculate equivalent resistance between A and B

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 12

Let us reduce the circuit step by step
Step 1:
2 resistors R are connected in series at the end, replace the equivalent with 2R.
Step 2:

Step 3 :

Req = 2R/3 + R/3
= R
Step 4:
Now, has two resistors are in parallel:
RAB= R||R = R/2

RRB JE ECE (CBT II) Mock Test- 1 - Question 13

Degree to which a material can be magnetized is given by

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 13

Permeability is the measure of the degree to which a material can be magnetized

B = μ H

μ = B/H
Hence, the correct option is (C)

RRB JE ECE (CBT II) Mock Test- 1 - Question 14
Polyurethane based casting is used to provide ________ to cable Joint
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 14

In the cast resin-based cable joints, the polyurethane based casting resins provide:

  1. Mechanical protection
  2. Electrical insulation
  3. Moisture imperviousness to the joint

Cast resin-based joints are used to make straight joints.

Straight joints can be used for indoor, outdoor, submerged and underground cable jointing.

RRB JE ECE (CBT II) Mock Test- 1 - Question 15

The Norton current for the circuit shown below is

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 15

Norton current is nothing but the short circuit current across the load terminal AB.
By applying superposition theorem
When only voltage source active and another source are inactive

I 1 = 30/15 = 2 A
Now consider 10 A current source

I2 = 10 A
Now consider 5 A current source

I3 = 5 A
Norton current IN = I1 + I2 + I3 = 2 + 10 + 5 = 17 A

RRB JE ECE (CBT II) Mock Test- 1 - Question 16
In serial interface __________
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 16

In a parallel interface, there are multiple lines connecting the I/O module and the peripheral, and multiple bits are transferred simultaneously, just as all of the bits of a word are transferred simultaneously over the data bus.

In a serial interface, there is only one line used to transmit data, and bits must be transmitted one at a time.

RRB JE ECE (CBT II) Mock Test- 1 - Question 17
An intrinsic semiconductor at 0 K behaves as:
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 17

Concept:

The conductivity of a semiconductor depends on two factors 

1. Carrier concentration (electrons in Conduction band and Holes in Valence band)

2. Mobility

Application:

At zero kelvin the thermal energy is zero.

The energy is not sufficient to excite electrons from conduction band to valence band, hence there are no free charge carriers at 0K

Thus an instrinsic semicondcutor behaves as insulator at OK.

RRB JE ECE (CBT II) Mock Test- 1 - Question 18
Which of the following is the only Union Territory to have its own High Court?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 18

  • Delhi is the only union territory of India which has its own High court.
  • It was established on 31 October 1966.
  • The High Court of Delhi was established with Chief Justice KS Hegde, Justice ID Dua, Justice HR Khanna and Justice SK Kapur as the 4 judges.
  • Chandigarh comes under the jurisdiction of Punjab and Haryana High Court.
  • Puducherry comes under the jurisdiction of Madras High Court.
  • Daman and Diu come under the jurisdiction of Bombay High Court.

RRB JE ECE (CBT II) Mock Test- 1 - Question 19
A good insulating material should have _________ dielectric strength and _________ dielectric loss?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 19

Concept:

Dielectric Strength:

The maximum electric field that the material can withstand under ideal conditions without breaking down (i.e. without failure of its insulating properties).

Dielectric Loss:

Dielectric loss, loss of energy that goes into heating a dielectric material in a varying electric field.

For example, a capacitor incorporated in an alternating-current circuit is alternately charged and discharged each half cycle.

During the alternation of polarity of the plates, the charges must be displaced through the dielectric first in one direction and then in the other and overcoming the opposition that they encounter leads to a production of heat through dielectric loss.

Application:

To withstand high electric field the dielectric strength of an insulator should be high.

To minimize losses, the dielectric losses should be low.

All the insulator behaves like dielectric, but all the dielectrics are not like insulators.

RRB JE ECE (CBT II) Mock Test- 1 - Question 20

Which of the following is the best technique for extraction of metals of high reactivity from their ores?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 20

Concept:

The metals at the top of the activity series (K, Na, Ca, Mg and Al) are so reactive that they are never found in nature as free elements.

The metals in the middle of the activity series (Zn, Fe, Pb, etc.) are moderately reactive. They are found in the earth’s crust mainly as oxides, sulphides or carbonates.

Basis of reactivity, we can group the metals into the following three categories

  1. Metals of low reactivity

(ii)Metals of medium reactivity

(iii)Metals of high reactivity.

 Different techniques are to be used for obtaining the metals falling in each category

Application:

The diagram shows the different techniques of extraction of metal from their ore.

RRB JE ECE (CBT II) Mock Test- 1 - Question 21
Fuse is inserted series in the circuit and protect the equipment from
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 21

A fuse is connected in series at the beginning of the circuit. The purpose of a fuse is to prevent overcurrent from damaging the load or other parts of the circuit. A series connection ensures that any current that enters the circuit passes through the fuse before reaching the load.

RRB JE ECE (CBT II) Mock Test- 1 - Question 22
An AM broadcast receiver has an intermediate frequency of 465 KHz and is tuned to 1000 KHz. Radio frequency has one tuned circuit with Q of 50. Calculate image frequency.
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 22

The image signal frequency is given by

fsi = fLo + fIF

Where

fLO = fs + fIF

Hence

fsi = fs + 2.fIF

fsi = 1000 + 2 (465)

fsi = 1930 kHz

RRB JE ECE (CBT II) Mock Test- 1 - Question 23
Which mobile network operator has overtaken Bharti Airtel to become the second-largest operator in terms of mobile subscriber base?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 23

  • Reliance Jio Infocomm Ltd has overtaken Bharti Airtel to become the second-largest operator in terms of mobile subscriber base.
  • The data was given by the Telecom Regulatory Authority of India.
  • As of May end, Jio had 322.98 million users as against Airtel’s 320.38 million users.
  • Vodafone Idea continues in the top position with 387.55 million users.

RRB JE ECE (CBT II) Mock Test- 1 - Question 24
Who is the author of the book named "A Suitable Boy"?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 24

  • Vikram Seth is the author of the book named ‘A Suitable Boy’.
  • The novel revolves around the story of four families over a period of 18 months.

RRB JE ECE (CBT II) Mock Test- 1 - Question 25

Work sheets are part of

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 25
  • Microsoft Excel is the electronic spreadsheet program within the Microsoft Office suite
  • An electronic spreadsheet is an application used to perform numeric calculations and to analyse and present numeric data
  • In Excel, the electronic spreadsheet is called a worksheet and it is contained in a file called workbook, which has the file extension .xlsx
  • Cells are the basic unit for storing data
  • In any spreadsheet program such as Excel, each rectangular box is referred to as cell
  • A cell is the intersection point of a column and a row
  • Data entered into an Excel spreadsheet is entered into a cell
  • Each cell can hold only one piece of data at a time


RRB JE ECE (CBT II) Mock Test- 1 - Question 26
Following law is applicable in the working of lead acid cell
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 26

Faraday’s Law of Electrolysis is applicable in the working of lead acid cell.

Faraday’s First Law of Electrolysis states that the chemical deposition due to the flow of current through an electrolyte is directly proportional to the quantity of electricity (coulombs) passed through it.

Faraday’s Second Law of Electrolysis states that, when the same quantity of electricity is passed through several electrolytes, the mass of the substances deposited are proportional to their respective chemical equivalent or equivalent weight.

RRB JE ECE (CBT II) Mock Test- 1 - Question 27

Find the values of VO, VD2 and ID for the circuit given below:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 27

The two diodes are connected in reverse order to each other.

Here D1 is forward biased and D2 is reversed biased

D1 is replaced by short circuit and D2 is replaced by open circuit.

Current ID becomes zero.

Current IR is 0, and hence voltage drop across 5.6 kΩ resistor is 0, correspondingly V0 = 0

When D2 is reversed biased, all the applied voltage +12 V appears across the diode.

VD2 = 12 V.

RRB JE ECE (CBT II) Mock Test- 1 - Question 28
In temporal multipoint connection
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 28

A multipoint connection is also called as multidrop connection in which more than two specific devices share a single link.

In a multipoint environment, the capacity of the channel is shared, either spatially or temporally.

If several devices can use the link simultaneously, it is a spatially shared connection.

If users must take turns, it is a timeshared connection.

RRB JE ECE (CBT II) Mock Test- 1 - Question 29
If the bit rate for an ASK signal is 800 bps, the baud rate is:
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 29

In ASK modulation each symbol is transmitted using a single bit

Hence, the bit rate = baud rate

Baud rate = 800 baud

If the question would have asked QPSK in case of ASK

Then QPSK transfers 2 bit for 1 symbol

Baud rate = 800/2 = 400 baud

RRB JE ECE (CBT II) Mock Test- 1 - Question 30
Assuming that conductivity does not vary with frequency, the ratio of the of the group and phase velocities of an electromagnetic wave in a non-dispersive medium
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 1 - Question 30

Group velocity is the speed at which energy of wave travels in a medium while a phase velocity is the speed at which phase of any one frequency content of wave travels.

In a non-dispersive medium like vacuum the group velocity and phase velocity are constant and equal hence the ratio is 1.

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