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RRB JE ECE (CBT II) Mock Test- 8 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test RRB JE Mock Test Series for ECE 2025 - RRB JE ECE (CBT II) Mock Test- 8

RRB JE ECE (CBT II) Mock Test- 8 for Electronics and Communication Engineering (ECE) 2024 is part of RRB JE Mock Test Series for ECE 2025 preparation. The RRB JE ECE (CBT II) Mock Test- 8 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The RRB JE ECE (CBT II) Mock Test- 8 MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE ECE (CBT II) Mock Test- 8 below.
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RRB JE ECE (CBT II) Mock Test- 8 - Question 1

The following equation is a representation of which law?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 1
  • V is, is a representation of the Combined Gas Law.
  • This law is obtained by combining Gay-Lussac's Law, Boyles's Law and Charles's Law.
  • Boyle's Law is represented as P 1V= P2V2, P is pressure and V is the volume. 
  • Charles' Law is represented as V1T= V2T1,  V is the volume whereas T is the temperature. 
  • Graham's Law states that the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. 
RRB JE ECE (CBT II) Mock Test- 8 - Question 2

The carrier to noise ratio in satellite communication depends on:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 2

All the factors such as Bandwidth, free space loss and radiated power affects the Carrier to Noise ratio:
The Carrier to noise ratio is related to the parameters by the equation:

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RRB JE ECE (CBT II) Mock Test- 8 - Question 3

Which virus infects the important files of MS word?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 3

A virus is a program that can infect other programs by modifying them to include a possibly evolved copy of itself.

Some of the common types of viruses are:

Boot Sector Virus: A boot sector virus displaces the boot record and copies itself to the boot sector i.e. where the program to boot the machine is stored. 

File Virus: A file virus generally attacks executable files. 

Macro Virus: The virus infects an important file of MS word. As soon as the application is opened the virus gets activated. It damages the formatting of documents and may not even allow the editing or saving of documents 

Trojan Horse: It is a code hidden in games or spreadsheets. Its main objective is to cause harm to the data. They can create a bad sector on the disk, destroy file allocation tables and cause the system to hang.

Worm: It is a program capable of replicating itself on a computer network. It travels from one computer to another across communication links. They generally disrupt the routine services. 

RRB JE ECE (CBT II) Mock Test- 8 - Question 4

Which one of the following places of Indus Valley Civilization was situated on the bank of Ravi River?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 4

RRB JE ECE (CBT II) Mock Test- 8 - Question 5

Which of the following networking device is used to divide a large network into smaller segments?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 5

Bridges are used to divide larger networks into smaller sections
They do this by sitting between two physical network segments and managing the flow of data between the two
By looking at the MAC address of the devices connected to each segment, bridges can elect to forward the data (if they believe that the destination address is on another interface) or block it from crossing (if they can verify that it is on the interface from which it came)

Hubs
Hubs work at the first or Physical Layer
It links all the devices connected to it and forms a single network
Each device that directly connects to the hub uses a port on the hub
When one device sends out a message to another device, the hub does not decide where the message goes; It just repeats the message to all the ports
Each device needs to decide whether this message is for itself or for others
Switch:
Switches operate at the Data Link or second layer
Switches are “intelligent” hubs
Switches can remember which ports are connected to which devices
When a switch receives a packet (data), it resends that packet directly to the correct port
Router:
Routers are on the third layer, the Network layer
They are used to connect networks together
The Internet consists of many interconnected routers
Using a network protocol, like TCP/IP, a router can intelligently move data from one network to another

RRB JE ECE (CBT II) Mock Test- 8 - Question 6

Which operator has right to left associativity?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 6

RRB JE ECE (CBT II) Mock Test- 8 - Question 7

A resistor in a circuit becomes very hot and starts to burn. This is because the resistor is dissipating too much:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 7

When electric current flows through a resistor some of the energy is transferred to heat energy. This results in the resistor heating up.

A resistor in a circuit becomes very hot and starts to burn. This is because the resistor is dissipating too much power

Power = I2R

RRB JE ECE (CBT II) Mock Test- 8 - Question 8

A completely filled valence band in a semiconductor results in

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 8
  • In a semiconductor, the charged carriers are both electrons and holes
  • In Intrinsic Semiconductors, at room Temperature, the valence band is completely filled and conduction band is completely empty
  • Intrinsic Semiconductor is Insulators at room Temperature
  • In an n-type Semiconductor, thermal energy is not sufficient to excite electrons from valence Band to Conduction Band
  • But Energy is sufficient to excite electrons from donor to conduction Band
  • Hence in n-type semiconductor valence Band is filled But conductivity is not Zero due to thermally excited carriers from donor level

Hence, the correct option is (D)

RRB JE ECE (CBT II) Mock Test- 8 - Question 9

30 men can complete a job in 40 days. However, after 24 days some men out of the assigned 30 left the job. The remaining people took another 40 days to complete the job. The number of men who left the job is

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 9

If M1 can do the work in D1 days and M2 man can do the job in M2
days (where all man can
work at the same rate),
Then 
According to the question,
M1 = 30, D1 = 40 W1 = 1, M2 = x, D2 = 40 W2 = 16/40
Thus 

Thus, the number of man who left the job = (30-12) = 18
Hence, the correct option is (B)

RRB JE ECE (CBT II) Mock Test- 8 - Question 10

How many years a person of Indian origin has to spend to become citizen of India under the Citizenship Act, 1955 ?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 10

A person of Indian origin has to spend 7 years to become citizen of India under the Citizenship Act, 1955.
Hence, the correct option is (C)

RRB JE ECE (CBT II) Mock Test- 8 - Question 11

What is the LCM of x³ + 8, x² + 5x + 6 and x² + 4x² + 4x?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 11

As, x³ + 8
= x³ + 2³
= (x + 2)(x² - 2x + 2²)
= (x + 2)(x² - 2x + 4) .......... (i)
x² + 5x + 6
= x² + 2x + 3x + 6
= (x + 2)(x + 3) ........ (ii)
x³ + 4x² + 4x
= x(x² + 4x + 4)
= x(x + 2)² .......... (iii)
From (i), (ii) and (iii)
LCM = x(x + 2)² (x + 3)(x² - 2x + 4)
Hence, the correct option is (A)

RRB JE ECE (CBT II) Mock Test- 8 - Question 12
Food chain in which micro-organisms breakdown the food formed by primary producers is
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 12

The dead organic matter of plant or animal is called as detritus. While a part of it remains on the soil surface as litter, the other part enters the soil. Many animals such as protozoan ‘s, nematodes, insects etc. depend on detritus and hence they are called as detrivores.

From detritus, the chain proceeds to detrivores, then to carnivores and finally to top carnivores.

RRB JE ECE (CBT II) Mock Test- 8 - Question 13

Which of the following is false about flip flops?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 13

The excitation table of SR flip flop is shown

When S = 1 and R = 0 a RS flip-flop presently in a SET state and must remain in SET state.
Thus statement 4 is false

RRB JE ECE (CBT II) Mock Test- 8 - Question 14

Hall effect can be used to measure

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 14

From Hall Effect we have V H = BI/pW
Where hall coefficient is given as RH = 1/p = 1/ne
Hall Effect can be used to measure the carrier concentration and type of semiconductor

RRB JE ECE (CBT II) Mock Test- 8 - Question 15
Which type of battery is generally used in emergency lights?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 15

There are two types of rechargeable batteries used in emergency lights:

1) Lead-Acid batteries

2) Nickel-Cadmium batteries

RRB JE ECE (CBT II) Mock Test- 8 - Question 16
Methane an air pollutant is produced ________.
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 16

Animals produce methane during the digestion process. Currently, around 20 percent of the world's methane emissions comes from ruminants. Studies revealed that ruminants, which include cows and sheep, release more methane into the environment than kangaroos.

RRB JE ECE (CBT II) Mock Test- 8 - Question 17

What is the value of current I in the below circuit?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 17


Applying Nodal
V - 6/3 + V + 24/12 + V/6 = 0
4V - 24 + V + 24 + 4V/12 = 0
9 V = 0
V = 0
I = 6 - V/3 = 6 - 0/3 = 2 A

RRB JE ECE (CBT II) Mock Test- 8 - Question 18

In a circuit voltage and current are given by:

V = (10 + j5) volts and I = (6 + j4) Amps

The circuit is _____
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 18

We know that

Impedance = Z = V/I = (10 + j5)/(6 + j4) = 1.538 – 0.192j    ----(1)

Impedance = Z = R - jXC       ----(2)

By comparing equation 1 and 2 we can say the circuit is capacitive

RRB JE ECE (CBT II) Mock Test- 8 - Question 19
Feedback used in a RC oscillator is of _______
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 19

Positive Feedback is preferred in oscillators as it provides positive gain to the system. It will improve the overall system gain. For oscillator the gain should be at maximum to have sustained oscillations.

RRB JE ECE (CBT II) Mock Test- 8 - Question 20
What kind of a device is a diode?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 20

Diode is a nonlinear device because these device does not have a linear relationship between current and voltage.

Example: gas diode, tunnel diode electric arc, inductor etc.

RRB JE ECE (CBT II) Mock Test- 8 - Question 21

The correct Boolean expression for the output is:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 21

Y = C(XOR) R

C = A(AND)B = AB

B = P OR Q = (P + Q)

C = A.B = (P + Q) (P' + Q')

= PQ' + QP'

C = (P EXOR Q)

Y = C XOR R

= P EXOR Q EXOR R

RRB JE ECE (CBT II) Mock Test- 8 - Question 22

The part of the eyes refracts light entering the eye from external objects?

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 22

Most of the refraction occurs at the cornea. Lens provides only the finer adjustment
Different parts of the eyes and their functions are shown in the table:

RRB JE ECE (CBT II) Mock Test- 8 - Question 23

The value of V0 is given by:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 23

Concept:

When circuit is excited by multiple sources, use superposition theorem

Therefore to determine output voltage.

Case 1: only v1 is acting:

Case 2: only v2 is acting

Total Output Voltage

V0 = V01 + V02

= 2V2 - 3V1

RRB JE ECE (CBT II) Mock Test- 8 - Question 24
Who won the Gold Medal at the World Cadet Wrestling competition in Sofia, Bulgaria?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 24

  • In the ongoing World Cadet Wrestling competition in Sofia, Bulgaria, Indian wrestler Sonam Malik won Gold in 65kg category.
  • She beat Binbin Xiang 7-1 in the final.
  • Wrestlers in under 18 categories are competing for a total of 30 gold medals -- 20 out of them for men’s events in Greco-Roman, and freestyle wrestling and 10 others in the women’s categories.

RRB JE ECE (CBT II) Mock Test- 8 - Question 25
In order to increase the Ah capacity of a lead-acid battery
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 25

The Ah capacity of a lead-acid battery depends on following factor:

  • The number and size of plates used.
  • The rate of discharging of a cell, if discharging rate is kept high, then its capacity is reduced.
  • The quantity and density of electrolyte present in the cell
  • Temperature of the cell
  • In order to increase the Ah capacity of a lead-acid battery a greater number of plates are to be used

RRB JE ECE (CBT II) Mock Test- 8 - Question 26
Which one is the correct food chain?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 26

Food Chain is a diagram that shows how food energy moves from one organism to another in a given environment. In other words, it is the chronological order of who eats whom in a biological community.

Aquatic food chain:

Phytoplankton Zooplankton Small Fish Large Fish  Whale

Phytoplankton: A mix of algae, the primary producer

Zooplankton: Small floating elements consuming the phytoplankton, the primary consumer

RRB JE ECE (CBT II) Mock Test- 8 - Question 27
The use of ________ instruments is merely confined within laboratories as standardizing instruments.
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 27

We can classify the instruments into two types

Absolute Instruments:

  • These instruments give the magnitude of the quantity under measurements in terms of physical constants of the instrument
  • There is no necessity of calibrating or comparing with other instruments
  • Tangent Galvanometer and Rayleigh’s current balance are example of this class

Secondary Instruments:

  • These instruments are so constructed that the quantity being measured can only be measured by observing the output indicated by the instrument
  • These instruments are calibrated by comparison with an absolute instrument or any other secondary instrument which has already been calibrated against an absolute instrument
  • A voltmeter, a glass thermometer and a pressure gauge are typical examples of secondary instruments

Working with absolute instruments for routine work is time consuming. Therefore, secondary instruments are most commonly used. Absolute instruments are seldom used except in standard institutions and laboratories while secondary instruments find usage almost in every sphere of measurement.

RRB JE ECE (CBT II) Mock Test- 8 - Question 28
Which of the following is used as a string termination character?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 28

Null character is used to terminate the string in C.

The null character in c is ‘\0’

RRB JE ECE (CBT II) Mock Test- 8 - Question 29
How many 16-bit registers are there in 8051?
Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 29

  • 8051 microcontroller consists of four register banks, such as Bank 0, Bank 1, Bank 2, Bank 3 which are selected by the PSW (Program Status Word) register.
  • 8051 has 32 general-purpose registers and the size of each register is 8-bit.
  • It has two 16-bit registers and they are data pointer (DTPR) and the program counter (PC).

Important:

In an 8051 microcontroller,

  • Internal RAM (data memory) - 128 bytes
  • Internal memory (code memory) - 4 kB
  • Timer/counter - 2
  • No. of interrupt - 5
  • I/O pins - 32
  • Serial port - 1

RRB JE ECE (CBT II) Mock Test- 8 - Question 30

The Input to the circuit shown below is Vi = 2 sin ωt mV. The current I0 is:

Detailed Solution for RRB JE ECE (CBT II) Mock Test- 8 - Question 30

V = -20 sin ωt

Apply KCL at node B

I0 = -7sin ωt

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