SRMJEE Mock Test - 10 (Engineering) - JEE MCQ

⇒ The SI unit of power is watt (W).
⇒ Ohm's law is valid only at a constant temperature.
⇒ Conventional current flows from positive terminal to negative terminal.
⇒ Electric current is the rate of flow of electric charges.

If Q is the initial charge on capacitor C₁, then the initial energy is given by U_i = Q²/2C₁.
As the two capacitors are connected together and the charge is distributed equally, the charge on each capacitor is Q/2. Since the potential difference (in a parallel connection) across the two capacitors is also the same, it follows that their capacitance are equal (since C = Q/V).
Thus, C₁ = C₂ = C (say)
Also, Q₁ = Q₂ = Q/2
Therefore, the final energy stored in the two capacitors is

But U_i = Q²/2C
∴ U_f/U_i = 1/2, which is option (2).

The tangential acceleration is along the tangent and a_c acts radially inwards. The resultant acceleration

 (from figure)

∴tan30° = a_c / at

Consider a cube of length l which is heated, and the temperature is increased by ΔT. It has the coefficient of linear expansion α and the coefficient of volume expansion γ.

The volume of the cube is given by:
V = l³

Due to heating, the length of the cube increases and is given by:
Δl = αlΔT ...(1)

Now, the volume of the cube also increases and is given by:
ΔV = γVΔT ...(2)

The volume of the cube after expansion can also be given by:
V + ΔV = (l + Δl)³

From equation (1) and (2),
V + γVΔT = (l + αlΔT)³
= l³ + (αlΔT)³ + 3l²(αlΔT) + 3(αlΔT)²l

Ignoring α³l³ and α²l² terms, and using l³ = V, we get:
γ = 3α

Frequency range of the speech signal is of 300 Hz to 3100 Hz frequency.

FBD of 1kg Block

Consider FBD of blocks as shown in fig
for 1 kg block and 2 kg block

Using Newtons 2nd law, acceleration of 2 kg block

acceleration of 1 kg block

Relative acceleration of 1 kg block with respect to 2 kg block is

Time taken for 1 kg block to fall off the planck

We know that 
Stress = Y × (strain)
where, Y is Young's modulus 
and stress = F/A and strain =Δl/l
and for linear expansion 
Δl = l× ΔT

We are given with, stress is same for both rods and ΔT is also same and α₁ / α₂ = 2 : 6
∴ for rod 1

For rod 2

taking ratio of (3) and (4) 

No unpaired electron is present in split 'd' obirtal.
∴ It is diamagnetic (μ_B = 0).

SBR (styrene-butadiene rubber) is a polymer of two different monomers, so it is a copolymer.

Primary aromatic amines react with nitrous acid to yield arene diazonium salts.

The diazonium group can be replaced by fluorine by treating the diazonium salt with fluoroboric acid (HBF4)(HBF4) . The precipitated diazonium fluoroborate is isolated, dried and heated until decomposition occurs to yield the aryl fluoride. This reaction is known as Blaz-Schiemann reaction.

Let (h, k) be the coordinates of P,
Then, by using section formula
h = x/4 and k = y/4
⇒ x = 4 h and y = 4 k
Since (x, y) lies on y² = 4 x
∴ 16 k ² = 4 × 4 h
⇒ k² = h
Hence, the locus of (h, k) is y² = x

0 =
29 + 2 = 0

It is given that cos^-1 (1/x) = θ.
Hence, cos θ =
Now, in triangle ABC,

tan θ =

We have,

Now

(1 + α + α²)(1 + β + β²)

Given 

For g(x) to be differentiable at x = c, f'(c) must be 0. Else, it is non-differentiable.

Given differential equation: x sec(y/x) (y dx + x dy) = y cosec(y/x) (x dy − y dx)

On integrating both the sides,

We have,

Applying componendo and dividendo, we get

⇒ tan²B = tanAtanC

tan A, tan B & tan C are in G.P.

The centre 

The angle of intersection between two circles is given by (Using the Cosine rule)

In ΔABC,
tan 60° = tan ∠ACB = AB/BC

BC = 10 cm
In ΔCDE,
tan 30° = tan ∠ECD =
_{CD =}
BD = BC + CD = 10 cm + 15 cm = 25 cm

A man is facing South. He turns 135 degrees in the anticlockwise direction and then 180 degrees in the clockwise direction.

According to the question, the man turns in the anticlockwise direction, which means he is turning towards the northeast.
He turns 135°, which is  90° + 45.
On turning 90°90°, he would face east and on further turning 45°, he would face the exact centre line between north- east.
And Finally, he turns 180° in the clockwise direction, he would face the exact centre line in the South-west direction.
So, he is facing in the South-west direction at the final position.
Hence, this is the correct answer.

Prepare the eight directions diagram:

According to the question, prepare this diagram by taking the help of the directions:

We have to find out AB (Hypotenuse) using Pythagorean’s theorem. We need to first find BC (Base) and AC (perpendicular) as follows:

BC = BE + EC
= 2 + (FG − DH)
= 2 + (16 – 14)
= 4 km

AC = AD – CD
= 12 – (EF – HG)
= 12 – (16 – 14)
= 10 km

Now, in ΔACB, by Pythagoras' theorem:

AB² = AC² + BC²
= 10² + 4²
= 100 + 16
= 116

AB = √116
= √(2 × 2 × 29)
= 2√29 km

Determinant (of coefficient matrix) should be zero 

⇒ (λ − 1)(λ − 2)(λ − 3) = 0

∑λ = 1 + 2 + 3 = 6

Therefore option c will be correct option.

Let the ten's digit be x and units digit be y.
Then, (10x + y) – (10y + x) = 63 ⇔ 9 (x – y) = 63 ⇔ x – y =7|
We can only find the difference of x and y, not about number.
Thus, none of the numbers can be determined.

The passage says, "During this period, Bengal witnessed an intellectual awakening that is in some way similar to the European Renaissance during the 16th century, although Europeans of that age were not confronted with the challenge and influence of alien colonialism." Thus, it can be concluded that “Unlike the Bengalis, Europeans were not under foreign rule.” 
Hence, option (b) is the correct answer choice.

The meaning of the idiom/phrase 'Knit the brow' is 'To frown or look worried, angry or puzzled'.
Example-She knitted her brows as she listened to the strange story.
Thus, option A, that is, 'to frown' is the correct answer.