SSC CGL (Tier II) Practice Test - 2 - SSC CGL MCQ

On squaring both sides, x² = 7x

⇒ x² – 7x = 0

⇒ x(x – 7) = 0

⇒ x = 7

⇒ 7 = (7³)^{y – 1} = 7^{3y – 3}

⇒ 3y – 3 = 1

⇒ 3y = 4

⇒ y = 4/3

RT = 3 cm, OR = 5 cm

Area of trapezium PQRS

= x²y² (x – y)

= (11)² (5)

= 121 × 5

= 605

Then, x + y = 1/30 and 16x + 44y = 1

Solving these two equations, we get

x = 1/60 and y = 1/60

Farhan's 1 day's work = 1/60

Hence, Farhan alone will finish the whole work in 60 days.

Area = 36² = 1296 cm²

Thus, we have

80% of N + 80 = N

0.8N + 80 = N

80 = 0.2N

N = 400

From the figure, we find that,

tanθ = 50/x (From triangle OMP) ... (1)

Also, tan 2θ = 300/x (From triangle OBM) ... (2)

⇒ 3(x² - 2500) = x²

⇒ x² = 3x² - 7500

⇒ 2x² = 7500

⇒ x² = 3750 = 625 × 6

⇒ x = 25√6

Hence, distance of the observer from the top of the pole is 25.

Dividing by 2,

Then, we get,

(2/3)X + (3/4)X + (4/5)X = 665

⇒ X = $300

A's share = (2/3) × 300 = $200

Or, 10x + 8x + 7x + 60° = 360°

Or, 25x = 300 or x = 12°

Difference between the largest and smallest angles = 120° - 60° = 60°

Therefore, the 4th option is the answer.

Runs scored by Rahul = x/9

Runs scored by Sachin

Total runs scored by them

Part of total runs scored by them collectively

Suppose,

p ÷ 4 = q, remainder = 2

q ÷ 5 = r, remainder = 3

r ÷ 6 = s, remainder = 4

Then,

r = 6s + 4

q = 5r + 3 = 5(6s + 4) + 3 = 30s + 23

p = 4q + 2 = 4(30s + 23) + 2 = 120s + 94

Suppose the final quotient = 1

Then, p = 120 x 1 + 94 = 214.

When the two trains are crossing each other (in opposite directions), the effective speed would be the sum of the individual speeds of the trains.

Speed of the other train = 198 - 90 = 108 km/hr

So, P = 2⁴ x A = 16A

Q = 2² x A = 4A

R = 2 x 3 x A = 6A

S = 3 x 5 x A = 15A

Clearly, as A > 0, P > S > R > Q.

Hence, answer option (1) is correct.

Statements:

1) All cars are equipment.

2) Some bikes are cars.

3) Some cars are begs.

4) All begs are books.

The least possible diagram for the given statements is as follows

Conclusions:

1) Some bikes are begs → False (It is possible but not definite)

2) Some books are bikes → False (It is possible but not definite)

3) All begs are equipment → False (It is possible but not definite)

4) Some books are equipment → True (because some cars are begs and all begs are books so some books are also equipment)

Hence, “Only conclusions 4 follows”.

The four letter meaningful words that can be made from the letters E, T, F, and L are FELT and LEFT.

There are two four letter meaningful words possible using the given letters.

Therefore, two is the correct answer.

The logic is:

(Column 1 - Column 2) = (Column 3 - Column 4)

Row 1: 14 - 12 = 2 and 10 - 8 = 2

Row 2: 10 - 8 = 2 and 6 - 4 = 2

Row 3: 8 - 6 = 2 and 4 - 2 = 2

Similarly,

Row 4:

Let the missing number be 'x'

So, x - 14 = 2

⇒ x = 2 + 14

⇒ x = 16

and 12 - 10 = 2

Hence, ‘16’ is the correct answer.

Number of hours from 5 AM of a particular day to 10 PM on 4^th day = (19 + 24 + 24 + 22) = 89 hours

Clock loses 16 minutes in 24 hours

So, in 1 hour the clock loses 16/24 minutes

So, in 89 hours, the clock loses (16/24) × 89 minutes = 59.34 minutes which is nearly equal to 1 hour.

So, the original time on the 4^th day is 11 PM when the clock shows 10 PM.

Hence, ’11 PM’ is the correct answer.

Given:

1) Raghav is standing at the 14th position from the extreme left end and Naresh is at the 16th position from the extreme right end.

2) After interchange their respective positions, Raghav now becomes 23rd from the extreme left end.

⇒ The total number of persons = Raghav position from left + Raghav position from right - 1

⇒ The total number of persons = 23 + 16 - 1 = 38

Naresh position from the right:

⇒ The total number of persons = Naresh position from left + Naresh position from right - 1

⇒ 38 = 14 + Naresh position from right - 1

⇒ Naresh position from right = 38 - 14 + 1 = 39 - 14 = 25

Hence, Naresh position from right is “25”.

The logic is:

1) 7851 – 180 → (7 + 8) × (5 + 1) × 2 = 180

2) 3712 – 60 → (3 + 7) × (1 + 2) × 2 = 60

3) 2134 – 40 → (2 + 1) × (3 + 4) × 2 ≠ 40

4) 6932 – 150 → (6 + 9) × (3 + 2) × 2 = 150

Hence, ‘2134 – 40’ is the odd one out.

The number of triangles in the figure is shown below:

Hence, ‘27’ is the correct answer.

The logic follows here is :

Middle term changes to the reverse alphabet.

Similarly,

Hence, the correct answer is "UFMHCKR".

The logic followed here is:

By using BODMAS and going by the options

Given equation :- 25 * 7 * 56 * 8 * 88 * 14

Interchanging * with signs given in the options

Option. 1 +, -, =, ×, -

25 * 7 * 56 * 8 * 88 * 14

25 + 7 - 56 = 8 × 88 - 14

25 + 7- 56 = 704 -14

32 - 56 = 704 -14

-24 = 690

LHS ≠ RHS

Option. 2 -, +, ×, =, ÷

25 * 7 * 56 * 8 * 88 * 14

25 - 7 + 56 × 8 = 88 ÷ 14

25 - 7 + 56 × 8 = 6.285

25 - 7 + 448 = 6.285

473 - 7 = 6.285

466 = 6.285

LHS ≠ RHS

Option. 3 -, ×, ×, =, +

25 * 7 * 56 * 8 * 88 * 14

25 - 7 × 56 × 8 = 88 + 14

25 - 3136 = 88 + 14

25 - 3136 = 102

3111 = 102

LHS ≠ RHS

Option. 4 +, ×, ÷, =, -

25 * 7 * 56 * 8 * 88 * 14

25 + 7 × 56 ÷ 8 = 88 - 14

25 + 7 × 7 = 88 - 14

25 + 49 = 88 - 14

74 = 88 - 14

74 = 74

LHS = RHS

Therefore, option "+, ×, ÷, =, -" satisfies the above equation.

Hence, the correct answer is "+, ×, ÷, =, -"

Given:

4, 3, 2 = 21

5, 6, 3 = 52

5, 8, 4 = ?

The logic followed here is:

(1st number)² + (2nd number)² – (3^rd number)² = RHS

Now follow the steps:

4, 3, 2 = 21

= 4² + 3² - 2²

= 16 + 9 – 4

= 25 - 4

= 21 = RHS

And,

5, 6, 3 = 52

= 5² + 6² - 3²

= 25 + 36 – 9

= 61 - 9

= 52 = RHS

Similarly,

5, 8, 4 = ?

= 5² + 8² - 4²

= 25 + 64 – 16

= 89 - 16

= 73 = RHS

Hence, "73" is correct answer.

It is true that selecting the right man for the right job at the right pay is the correct approach. This will ensure smooth and efficient functioning

Reason (R): A wrongly selected man is a liability.

It is true because a wrongly selected man is a liability. A wrong selection can put a company into a risk of inefficiency.

But Reason is not sufficient to support the assertion.

Hence, Both 'A' and 'R' are true but 'R' is not correct explanation of 'A' is the correct answer.

Seven people – G, H, J, K, L, M and N

1) K is sitting fourth to the left of N.

2) G is sitting immediate left of K.

3) Two people are sitting between M and G.

4) The number of people sitting between H and J is the same as the number of people sitting between J and L.

5) H is not sitting at any of the extreme ends.

Condition (4) is not satisfying in case I, so it gets eliminated and we have the final arrangement as follows:

Hence, "J, L, N" is the correct answer.

From statement I,

Only a few book are pen. Some bag are book. No pen is bag. Some pen is copy

Minimum possible diagram,

I. No bag is book is a possibility → False (because Some bag are book)

II. Some book can never be copy → False

III. All book can be pen → False (because Only a few book are pen which means some book are pen and some book are not pen)

Therefore, Statement I will not be the result of the given conclusions.

From Statement II:

No bag are book. No pen is bag. Only pen is copy. Only a few book are pen.

I. No bag is book is a possibility → False (it is already true)

II. Some book can never be copy → True (because Only pen is copy)

III. All book can be pen → False (because Only a few book are pen which means some book are pen and some book are not pen)

Therefore, Statement II will not be the result of the given conclusions.

From Statement III:

Some bag are not book. No pen is bag. Only pen is copy. Some book are pen.

I. No bag is book is a possibility → True

II. Some book can never be copy → True (because Only pen is copy)

III. All book can be pen → True

Therefore, Statement III will be the result of the given conclusions.

From Statement IV:

Only a few book are pen. Some bag are book. No pen is bag. Only pen is copy.

I. No bag is book is a possibility → False

II. Some book can never be copy → True (because Only pen is copy)

III. All book can be pen → False (because Only a few book are pen which means some book are pen and some book are not pen)

Therefore, Statement IV will not be the result of the given conclusions.

Hence, only statement III follows.

Here, the pattern being followed is, the absolute difference between digits of positional values of letters has been taken.

P → 16 → I1 - 6I = 5

U → 21 → I2 - 1I = 1

R → 18 → I1 - 8I = 7

P → 16 → I1 - 6 I = 5

L → 12 → I1 - 2I = 1

E → 05 → I0 - 5I = 5

Similarly,

O → 15 → I1 - 5I = 4

R → 18 → I1 - 8I = 7

A → 01 → I0 - 1I = 1

N → 14 → I1 - 4 I = 3

G → 07 → I0 - 7I = 7

E → 05 → I0 - 5I = 5

Hence, 471375 is the code for ORANGE.

The number of ₹5 coins = y

The number of ₹1 coins = z

Then, the number of ₹2 coins = x + 10 = y + 20 = z - 20

So, x + 10 = y + 20

⇒ y = x - 10

and x + 10 = z - 20

⇒ z = x + 30

Then,

⇒ (x + 30) × 1 + (x + 10) × 2 + (x - 10) × 5 + x × 10 = 2160

⇒ x + 30 + 2x + 20 + 5x - 50 + 10x = 2160

⇒ 18x = 2160

⇒ x = 120

So, the number of ₹10 coins = x = 120 coins

Hence, the correct answer is Option A.