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Sequences And Series Of Real Numbers -1 - Mathematics MCQ


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20 Questions MCQ Test Topic-wise Tests & Solved Examples for Mathematics - Sequences And Series Of Real Numbers -1

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Sequences And Series Of Real Numbers -1 - Question 1

The sequence <sn> =  is 

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 1

Here lower bound = l = − 1/2 , & upper bounded u = 1. But the given sequence is neither increasing nor decreasing. Thus, <sn> is bounded but not monotonic.

Sequences And Series Of Real Numbers -1 - Question 2

The series 2 + 4 + 6 + 8 + ...is

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 2


The sequence of n th partial sum of given series is unbounded and goes to infinity.
since sequence of n th partial sum is unbounded, it is not convergent therefore the given series
is not convergent i.e. divergent.

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Sequences And Series Of Real Numbers -1 - Question 3

The series x  is convergent, if

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 3

If ∑μn be the given series, then we have


∴ From ratio test, the given series ∑μis convergent or divergent according as 

Sequences And Series Of Real Numbers -1 - Question 4

Find the sum of the series 

 

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 4

Hence, the answer is option C

Sequences And Series Of Real Numbers -1 - Question 5

For the sequence 1, 7, 25, 79, 241, 727 … simple formula for {an} is ____________ 

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 5

The ratio of consecutive numbers is close to 3. Comparing these terms with the sequence of {3n} which is 3, 9, 27 …. Comparing these terms with the corresponding terms of sequence {3n} and the nth term is 2 less than the corresponding power of 3.

Sequences And Series Of Real Numbers -1 - Question 6

The interval of convergence of is

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 6


R = 1 / P = 1 = radius of convergence
When x = 1 & x = –1, Then is converges at both 

x = 1 & x = – 1.
so, its interval of convergence is exactly [–1, 1].

Sequences And Series Of Real Numbers -1 - Question 7

The sequence 

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 7

We have 

Sequences And Series Of Real Numbers -1 - Question 8

The sequence is

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 8

Sequences And Series Of Real Numbers -1 - Question 9

Match list I with list II and select the correct answer

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 9



is also convergent series.
∴ un is also convergent series.

Hence, by d’Alembert test 

implies un is divergent series.

By Cauchy condensation test, ∑μn is convergent series.
(D) 
By Leibnitz’s test, the series is convergent.
Also,  is divergent series. 
So, the given series is converges conditionally.

Sequences And Series Of Real Numbers -1 - Question 10

The series whose nth term is 

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 10

Here it is given that

Now, taking auxiliary series 

Which is finite and non-zero. Since, vn is divergent.
Hence, tn is also divergent.

Sequences And Series Of Real Numbers -1 - Question 11

The series  convergent, if

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 11

Here given series is  is convergent

∴ The given series will be convergent, if



Hence, vn is convergent series, so un is also convergent.
∴ The given series is convergent, if | x | ≤ 1.

Sequences And Series Of Real Numbers -1 - Question 12

Determine the limits of the following sequences (xn) whose nth term xn is given below. 

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 12

In the above we have used the result that 1/n → 0 as n → ∞ and a result about combining convergent sequences and noting that the denominator converges to a non-zero value.

Sequences And Series Of Real Numbers -1 - Question 13

The series

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 13




which is finite and non-zero.
Since, ∑vn is divergent, therefore, ∑un is also divergent.

Sequences And Series Of Real Numbers -1 - Question 14

The series  is

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 14


Hence, by Cauchy’s root test, the series convergent.

Sequences And Series Of Real Numbers -1 - Question 15

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 15

Here, it is given that 




Sequences And Series Of Real Numbers -1 - Question 16

The sequence {Sn} of real numbers given by Sn = is

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 16


So <Sn> is monotonically increasing Next, we will show that it is bounded.

⇒ <Sn> is bounded. By the theorem's Every monotonic bounded sequence is convergent, Then <Sn> is convergent.
By the Lemma, if <Sn> is a convergent sequence of real numbers, Then <Sn> is a Cauchy-sequence.
 

Sequences And Series Of Real Numbers -1 - Question 17

Test the convergence of the series 

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 17

Sequences And Series Of Real Numbers -1 - Question 18

The sequence 1, 1, 1, 1, 1…. is?

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 18

For limit n tending to infinity the sum also tends to infinity and thus it is not summable.

Sequences And Series Of Real Numbers -1 - Question 19

The series 

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 19

The nth term of the given series is

Hence, ∑un is convergent.

Sequences And Series Of Real Numbers -1 - Question 20

Detailed Solution for Sequences And Series Of Real Numbers -1 - Question 20

The series is conditionally convergent.

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