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Test: APP & MRP Level - 2 - Mechanical Engineering MCQ


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10 Questions MCQ Test Industrial Engineering - Test: APP & MRP Level - 2

Test: APP & MRP Level - 2 for Mechanical Engineering 2024 is part of Industrial Engineering preparation. The Test: APP & MRP Level - 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: APP & MRP Level - 2 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: APP & MRP Level - 2 below.
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Test: APP & MRP Level - 2 - Question 1

The master production schedule to manufacture a product is given below:

If the company follows Wilson’s model to place an order. The EOQ is given as 300, the stock-on-hand is 100, lead time is 1 month. Find the minimum number of orders required to fulfill the demand arise up to month-8

Detailed Solution for Test: APP & MRP Level - 2 - Question 1

Minimum number of orders required is 4

*Answer can only contain numeric values
Test: APP & MRP Level - 2 - Question 2

The product structure of product ‘P’ is shown in the figure below. The assembly of 2 units of ‘B’ and 4 units of ‘C’ to produce 1 unit of ‘A’ takes a week.

The ordering time of B, C and D are 2, 1 and 2 weeks. The master production schedule for product ‘P’ is as follows:-

The net requirement of ‘C’ if initial inventories of A, B, C and D are 10, 20, 15 and 40 is _____________


Detailed Solution for Test: APP & MRP Level - 2 - Question 2

Total demand = 80 units

For producing 1 unit of P, 80 units of ‘A’ is required but in inventory 10 units of ‘A’ is there so a total of 70 units of ‘A’ is required.

It means 4 × 70 = 280 units of C is required. But in inventory 15 units of C is there.

Therefore 280 − 15 = 265 units of ‘C’ are required.

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Test: APP & MRP Level - 2 - Question 3

Item P is made from components Q and R. Item Q, in turn is made from S and T. The lead times for items P, Q, R, S and T are 3, 4, 11, 6 and 7 weeks respectively. The lead time(in weeks) needed to respond to a customer order for item P is

Detailed Solution for Test: APP & MRP Level - 2 - Question 3

P−Q−S = 6+4+3 = 13

P−R−T = 7+4+3 = 14

P−R = 11+3 = 14

Longest lead time is 14

Test: APP & MRP Level - 2 - Question 4

The MRP table is shown below, the POR is

Detailed Solution for Test: APP & MRP Level - 2 - Question 4

Test: APP & MRP Level - 2 - Question 5

Consider the following MRP sheet

The inventory at the end of 5th week

Detailed Solution for Test: APP & MRP Level - 2 - Question 5

Inventory at the end of 5th week = 100 units

Test: APP & MRP Level - 2 - Question 6

The material requirement planning for an item is shown in the table below: The ordering quantity is 80 units. The 2nd planned order release happens in the week of _______________

(Assume LT = 3 weeks)

Detailed Solution for Test: APP & MRP Level - 2 - Question 6

Test: APP & MRP Level - 2 - Question 7

A company contains two alternative methods for manufacturing a product. The estimated time and cost for both are given below

The number of units up to which milling is justified economically is

Detailed Solution for Test: APP & MRP Level - 2 - Question 7

Milling operation is justified as long as the total cost is less than the lathe.

TC)Milling ≤ TC)Lathe

10 Q ≤ 187.5

Q ≤ 18.75

Q ≤ 19

Test: APP & MRP Level - 2 - Question 8

The plant has a capacity of producing 50,000 units per year. The annual fixed cost is Rs. 80,000. The variable cost per unit is Rs.18. The price of the product is Rs. 20 per unit. Then the breakeven point in terms of the capacity of the plant is

Detailed Solution for Test: APP & MRP Level - 2 - Question 8

Given,

Fixed cost = 80,000

Variable cost = Rs. 18/unit = V

price (P) = Rs. 20/unit

Capacity of the plant = 50,000 units/year

% of BEP = 40,000/50,000 = 0.8

= 80%

Test: APP & MRP Level - 2 - Question 9

Find the total cost using Lot for Lot technique LT = 0, CO = Rs. 100/order, CC = Rs. 1/unit/week

Detailed Solution for Test: APP & MRP Level - 2 - Question 9

Ordering quantity = demand in a particular period

TC = Stock × CC + N × CO = 0 + 4 × 100 = 400

Test: APP & MRP Level - 2 - Question 10

Find the total cost using minimum cost period technique.

LT = 0, CO = Rs. 100/order, CC = Rs. 1/unit/week

Detailed Solution for Test: APP & MRP Level - 2 - Question 10

In this method cost period is used to decide the optimum combination

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