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Test: Analysis of Growth & Analysis of Decay - Electrical Engineering (EE) MCQ


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20 Questions MCQ Test Basic Electrical Technology - Test: Analysis of Growth & Analysis of Decay

Test: Analysis of Growth & Analysis of Decay for Electrical Engineering (EE) 2024 is part of Basic Electrical Technology preparation. The Test: Analysis of Growth & Analysis of Decay questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Analysis of Growth & Analysis of Decay MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Analysis of Growth & Analysis of Decay below.
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Test: Analysis of Growth & Analysis of Decay - Question 1

What is the total applied voltage in an inductive circuit?

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 1

The total voltage in an inductive circuit is the sum of the voltage due to the resistor which is Ri and the voltage due to the inductor which is Ldi/dt. Hence V=Ri+Ldi/dt.

Test: Analysis of Growth & Analysis of Decay - Question 2

What is Helmholtz equation?

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 2

Helmholtz equation is an equation which gives the formula for the growth in an inductive circuit. Hence the Helmholtz formula is: i=I(1-e-Rt/L).

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Test: Analysis of Growth & Analysis of Decay - Question 3

Among the following, which is the right formula for growth in an inductive circuit?

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 3

The correct formula for growth in an inductive circuit is VL=V(1-e-t /time constant). As the time increases, the current in the inductor increases hence the voltage also increases.

Test: Analysis of Growth & Analysis of Decay - Question 4

The charging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________% of the initial voltage.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 4

We know that: V=V0(1-e-t /time constant).
When time constant=t, we have: V=V0(1-e-1)= 0.63*V0.
Hence the time constant is the time taken for the charge in an inductive circuit to become 0.63 times its initial charge.

Test: Analysis of Growth & Analysis of Decay - Question 5

What is the time constant of an inductive circuit?

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 5

The time constant in an inductive circuit is the time taken for the voltage across the inductor to become 63 percent of its initial value. It is given by: Time constant= L/R.

Test: Analysis of Growth & Analysis of Decay - Question 6

A coil has a resistance of 4 ohm and an inductance of 2H. Calculate its time constant.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 6

The expression for time constant in an inductive circuit is:
Time constant= L/R
Substituting the values from the question given, we get time constant= 0.5s.

Test: Analysis of Growth & Analysis of Decay - Question 7

A coil has a resistance of 4 ohm and an inductance of 2H. It is connected to a 20V dc supply. Calculate the final value of current in the circuit.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 7

The final value of current in the circuit is:
I=V/R= 5A.

Test: Analysis of Growth & Analysis of Decay - Question 8

A coil has a resistance of 4 ohm and an inductance of 2H. It is connected to a 20V dc supply. Calculate the value of current 1s after the switch is closed.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 8

We know that:
i=I(1-eRt/L)
I=V/R=5A
Substituting the remaining values from the given question, we get i=4.32A.

Test: Analysis of Growth & Analysis of Decay - Question 9

What happens to the inductance when the current in the coil becomes double its original value?

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 9

The formula for magnetic field strength in a coil is:
H=iN/l
The inductance is: directly proportional to magnetic field strength, hence as the current value doubles, the inductance also doubles.

Test: Analysis of Growth & Analysis of Decay - Question 10

Calculate the inductance in an inductive circuit whose time constant is 2s and the resistance is 5 ohm.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 10

We know that: Time constant= L/R
Substituting the values from the given question, we get L=10H.

Test: Analysis of Growth & Analysis of Decay - Question 11

What is the time constant of an inductive circuit?

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 11

The time constant in an inductive circuit is the time taken for the voltage across the inductor to become 63 percent of its initial value. It is given by: Time constant= L/R.

Test: Analysis of Growth & Analysis of Decay - Question 12

Among the following, which is the right formula for decay in an inductive circuit?

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 12

The correct formula for decay in an inductive circuit is i=I(e-t /time constant). As the time increases, the current in the inductor decreases, the voltage also increases.

Test: Analysis of Growth & Analysis of Decay - Question 13

The discharging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________% of the initial voltage.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 13

We know that: V=V0(e-t/time constant).
When time constant=t, we have: V=V0(e-1)= 0.36*V0.
Hence the time constant is the time taken for the charge in an inductive circuit to become 0.36 times its initial charge.

Test: Analysis of Growth & Analysis of Decay - Question 14

The discharging time constant of a circuit consisting of an inductor is the time taken for the voltage in the inductor to become __________% of the initial voltage.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 14

We know that: V=V0(e-t/time constant).
When time constant=t, we have: V=V0(e-1)= 0.36*V0.
Hence the time constant is the time taken for the charge in an inductive circuit to become 0.36 times its initial charge.

Test: Analysis of Growth & Analysis of Decay - Question 15

In case of Inductive circuit, Frequency is ______________ to the current.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 15

Inductance is inversely proportional to current since, as the inductance increases, current decreases.

Test: Analysis of Growth & Analysis of Decay - Question 16

Calculate the time constant of an inductive circuit having resistance 5 ohm and inductance 10H.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 16

We know that: Time constant= L/R
Substituting the values from the given question, we get time constant= 2s.

Test: Analysis of Growth & Analysis of Decay - Question 17

Calculate the inductance in an inductive circuit whose time constant is 2 and the resistance is 5 ohm.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 17

We know that: Time constant= L/R
Substituting the values from the given question, we get L=10H.

Test: Analysis of Growth & Analysis of Decay - Question 18

A coil has a resistance of 4 ohm and an inductance of 2H. It is connected to a 20V dc supply. Calculate the final value of current in the circuit.

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 18

The final value of current in the circuit is:
I=V/R= 5A.

Test: Analysis of Growth & Analysis of Decay - Question 19

What happens to the inductance when the current in the coil becomes double its original value?

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 19

The formula for magnetic field strength in a coil is:
H=iN/l
The inductance is: directly proportional to magnetic field strength, hence as the current value doubles, the inductance also doubles.

Test: Analysis of Growth & Analysis of Decay - Question 20

What is the total applied voltage in an inductive circuit?

Detailed Solution for Test: Analysis of Growth & Analysis of Decay - Question 20

The total voltage in an inductive circuit is the sum of the voltage due to the resistor which is Ri and the voltage due to the inductor which is Ldi/dt. Hence V=Ri+Ldi/dt.

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