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JEE Exam  >  JEE Tests  >  Physics for JEE Main & Advanced  >  Test: Behavior of Progressive Waves - JEE MCQ

Test: Behavior of Progressive Waves - JEE MCQ


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10 Questions MCQ Test Physics for JEE Main & Advanced - Test: Behavior of Progressive Waves

Test: Behavior of Progressive Waves for JEE 2024 is part of Physics for JEE Main & Advanced preparation. The Test: Behavior of Progressive Waves questions and answers have been prepared according to the JEE exam syllabus.The Test: Behavior of Progressive Waves MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Behavior of Progressive Waves below.
Solutions of Test: Behavior of Progressive Waves questions in English are available as part of our Physics for JEE Main & Advanced for JEE & Test: Behavior of Progressive Waves solutions in Hindi for Physics for JEE Main & Advanced course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Behavior of Progressive Waves | 10 questions in 10 minutes | Mock test for JEE preparation | Free important questions MCQ to study Physics for JEE Main & Advanced for JEE Exam | Download free PDF with solutions
Test: Behavior of Progressive Waves - Question 1
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As a wave propagates; which of the following is not satisfied?

Detailed Solution for Test: Behavior of Progressive Waves - Question 1

Intensity is in inverse proportion to surface area of the imaginary sphere at any point. where A=4πr^2 so inverse of distance(r, radius) is incorrect.

Test: Behavior of Progressive Waves - Question 2
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The disc of a siren containing 60 holes rotates at a constant speed of 360 rpm. The emitted sound is in unison with a tuning fork of frequency. 

Detailed Solution for Test: Behavior of Progressive Waves - Question 2

Frequency of revolution of disc = 360 rpm = 360 / 60rps = 60rps 
Frequency of emitted sound = 6 × No.of holes 
= 6 ×60 = 360Hz.

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Test: Behavior of Progressive Waves - Question 3
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The speed of transverse waves in a string depends on:

Detailed Solution for Test: Behavior of Progressive Waves - Question 3

For a string v = √(T/μ)

Test: Behavior of Progressive Waves - Question 4
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Speed of the sound in a perfectly rigid rod would be
Detailed Solution for Test: Behavior of Progressive Waves - Question 4

Since particles in a rigid body do not move and hence, no time is delayed in travelling of sound waves.

Test: Behavior of Progressive Waves - Question 5
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Which instrument work on the basis of reflection of sound waves?
Detailed Solution for Test: Behavior of Progressive Waves - Question 5

Stethoscope works on the basis of reflection of sound waves.

Test: Behavior of Progressive Waves - Question 6
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Speed of a progressive wave,v is given by
Detailed Solution for Test: Behavior of Progressive Waves - Question 6

f = v/λ
v = λf

Test: Behavior of Progressive Waves - Question 7
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What causes the rolling sound of thunder?
Detailed Solution for Test: Behavior of Progressive Waves - Question 7

The air is not of uniform density as we go upwards. as we go upwards there is a gradual decrease in air density which results in refraction thereby leading to the rolling sound of thunder.

Test: Behavior of Progressive Waves - Question 8
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Properties of a kind of wave are given below. Identify the type of wave

i. Wave can not be detected by human ear
ii. Velocity of wave in free space is 3x108m/s
iii. Velocity is not effected by temperature
iv. Waves can travel through vacuum
Detailed Solution for Test: Behavior of Progressive Waves - Question 8

These are the properties of radio waves. No possible explanation.

Test: Behavior of Progressive Waves - Question 9
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y(x,t) = 0.8/[(4x+5t)2+5] represents a moving pulse, where x and y are in meter and t in second. Then
Detailed Solution for Test: Behavior of Progressive Waves - Question 9

Test: Behavior of Progressive Waves - Question 10
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The speed of transverse waves on a string depends upon
Detailed Solution for Test: Behavior of Progressive Waves - Question 10

The speed of a wave on a string depends on the square root of the tension divided by the mass per length, the linear density.

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