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Test: Binomial Theorem - 3 - Mathematics MCQ


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20 Questions MCQ Test Topic-wise Tests & Solved Examples for Mathematics - Test: Binomial Theorem - 3

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Test: Binomial Theorem - 3 - Question 1

Detailed Solution for Test: Binomial Theorem - 3 - Question 1

Test: Binomial Theorem - 3 - Question 2

Co + 3.C1 + 5.C2 + .... + (2n + 1).Cn =

Detailed Solution for Test: Binomial Theorem - 3 - Question 2

Substitute ‘n’ and verify the options.

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Test: Binomial Theorem - 3 - Question 3

Detailed Solution for Test: Binomial Theorem - 3 - Question 3

Substitute a positive integer for n and verify.

Test: Binomial Theorem - 3 - Question 4

Detailed Solution for Test: Binomial Theorem - 3 - Question 4

Test: Binomial Theorem - 3 - Question 5

If Co + C1 + C2 + ….. + Cn = 128 then  

Detailed Solution for Test: Binomial Theorem - 3 - Question 5

2n = 128 ⇒ n = 7

Test: Binomial Theorem - 3 - Question 6

If 9P5 + 5. 9P4 = 10Pr, then r = 

Detailed Solution for Test: Binomial Theorem - 3 - Question 6

nPr + r. nPr-1 = (n + 1)Pr

Test: Binomial Theorem - 3 - Question 7

The value of 1 + 1.1! + 2. 2! + 3.3! + …… + n. n! is 

Detailed Solution for Test: Binomial Theorem - 3 - Question 7

n. n! = [(n + 1) – 1]n! = (n + 1)! – n!
∴ 1 + 2! – 1! + … + (n + 1)! – n! = (n + 1)!

Test: Binomial Theorem - 3 - Question 8

15 buses fly between Hyderabad and Tirupati. The number of ways can a man go to Tirupati from Hyderabad by a bus and return by a different bus is

Detailed Solution for Test: Binomial Theorem - 3 - Question 8

15 x14 = 210

Test: Binomial Theorem - 3 - Question 9

In a class of 10 students there are 3 girls. The number of ways they can be arranged in a row, so that no two girls are consecutive is k. 8!, where k =

Detailed Solution for Test: Binomial Theorem - 3 - Question 9

7! x (8P3) = k x 8!

Test: Binomial Theorem - 3 - Question 10

S1, S2, …., S10 are the speakers in a conference. If S1 addresses only after S2, then the number of ways the speakers address is

Detailed Solution for Test: Binomial Theorem - 3 - Question 10

10!/2!

Test: Binomial Theorem - 3 - Question 11

The total number of 9 digit numbers which have all different digits is

Detailed Solution for Test: Binomial Theorem - 3 - Question 11

9 x 9!

Test: Binomial Theorem - 3 - Question 12

The number of 6 digit numbers in which all the odd digits and only odd digits appear, is 

Detailed Solution for Test: Binomial Theorem - 3 - Question 12

Clearly, one of the odd digits 1, 3, 5, 7, 9 will repeated. The number of selections of the sixth digit = 5C1 = 5.
Required, number of numbers = 5 x (6!/2!)

Test: Binomial Theorem - 3 - Question 13

The letters of the word ‘ZENITH’ are permuted in all possible ways and the words thus formed are arranged as in a dictionary. The rank of the word ‘ZENITH’ is

Detailed Solution for Test: Binomial Theorem - 3 - Question 13

Rank is 5(5!) + 0.4! + 2(3!) + 1 x 2! + 1 x 1! + 1 = 616

Test: Binomial Theorem - 3 - Question 14

The sum of all the numbers that can be formed by taking all the digits from 2, 3, 4, 5 is

Detailed Solution for Test: Binomial Theorem - 3 - Question 14

(2 + 3 + 4 + 5)(1111)3! = 93,324

Test: Binomial Theorem - 3 - Question 15

The number of ways in which 6 gentlemen and 3 ladies be seated round a table so that every gentleman may have a lady by his side is

Detailed Solution for Test: Binomial Theorem - 3 - Question 15

5!. 3!.  2! = 1440

Test: Binomial Theorem - 3 - Question 16

The number of ways in which 7 men be seated at a round table so that two particular men are not side by side is 

Detailed Solution for Test: Binomial Theorem - 3 - Question 16

6! – 5! x 2 = 480

Test: Binomial Theorem - 3 - Question 17

The letters of the word ‘MADHURI’ are arranged in all possible ways. The number of arrangements in which there are 2 letters between R and H is

Detailed Solution for Test: Binomial Theorem - 3 - Question 17

2 x 5P2 x 4!

Test: Binomial Theorem - 3 - Question 18

The number of ways to arrange the letters of the word ‘GARDEN’ with vowels in alphabetical order is

Detailed Solution for Test: Binomial Theorem - 3 - Question 18

6P6-2 = 6P4

Test: Binomial Theorem - 3 - Question 19

The number of ways in which 7 Indians and 6 Pakistanis sit around a round table so that no two Indians are together is

Detailed Solution for Test: Binomial Theorem - 3 - Question 19

In between 6 Pakistanis we have 6 gaps on a circular table, so 7 Indians cannot be arranged in 6 gaps.

Test: Binomial Theorem - 3 - Question 20

Number of ways in which 7 seats around a table can be occupied by 15 persons is

Detailed Solution for Test: Binomial Theorem - 3 - Question 20

nPr/r

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