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Test: Binomial Theorem - 5 - Mathematics MCQ


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20 Questions MCQ Test Topic-wise Tests & Solved Examples for Mathematics - Test: Binomial Theorem - 5

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Test: Binomial Theorem - 5 - Question 1

The coefficient of x12 in the expansion of (1 + 2x2- x3)8 is

Test: Binomial Theorem - 5 - Question 2

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Test: Binomial Theorem - 5 - Question 3

The value of 

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Test: Binomial Theorem - 5 - Question 4

Coefficient of x11 in the expansion of (1 + x2)4 (1 + x3)7 (1 + x4)12 is

Test: Binomial Theorem - 5 - Question 5

The number of irrational terms in the expansion of (21/5 + 31/10)55 is

Detailed Solution for Test: Binomial Theorem - 5 - Question 5

(21/5 + 31/10)55 Total terms = 55 + 1 = 56 

Here  r = 0, 10, 20, 30, 40, 50
Number of  rational terms = 6;  
Number of irrational terms = 56 - 6 = 50

Test: Binomial Theorem - 5 - Question 6

In the expansion of the coefficient of x-10 will be 

Detailed Solution for Test: Binomial Theorem - 5 - Question 6

Given expansion is 
∴ General term 
Since, we have to find coefficient of x-10
∴ -12 + 2r = -10  ⇒ r = 1
Now, then coefficient of x -10 is 12C1(a)11(b)1 = 12a11b

Test: Binomial Theorem - 5 - Question 7

The middle term in the expansion of (1 – 2x + x2)n is 

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Here 2n is even integer, therefore,  term will be the middle term.

Test: Binomial Theorem - 5 - Question 8

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Replacing x by -x, 
Subtracting and putting 

Test: Binomial Theorem - 5 - Question 9

(103)86 - (86)103 is divisible by 

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Given expression

Test: Binomial Theorem - 5 - Question 10

The number of dissimilar terms in the expansion of (a + b + c)2n+1 – (a + b – c)2n+1 is 

Detailed Solution for Test: Binomial Theorem - 5 - Question 10

Given expansion 

Number of dissimilar term = (2n + 1) + (2n -1) + ....(2n - 3) + .... + 5 + 3 + 1

Test: Binomial Theorem - 5 - Question 11

The fourth and fifth term of a sequence {tn}n≥1 are 4 and 5 respectively and the nth term is given as tn = 2tn-1 - tn-2, n > 3 (n ∈ N). Then the sum to first 2009 terms is 

Detailed Solution for Test: Binomial Theorem - 5 - Question 11


Thus {an} is a constant sequence  
a5 = t5 − t4 = 1  
Now a4 = t4 − t3 ⇒ 1 = 4 − t3 ⇒ t3 = 3
Similarly t2 = 2 , t1 = 1
Thus {tn} is an A.P with r = 1 and common difference 1 

Test: Binomial Theorem - 5 - Question 12

 where tr denotes the rth term of a series, then 

Test: Binomial Theorem - 5 - Question 13

 where a, b, c are in AP and | a | < 1, | b | < 1, | c | < 1, then x, y, z are in 

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Test: Binomial Theorem - 5 - Question 14

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Test: Binomial Theorem - 5 - Question 15

Sum to 20 terms of the series 1.32 + 2.52 + 3.72 + ... is  

Detailed Solution for Test: Binomial Theorem - 5 - Question 15

We have, tn = [nth term of 1, 2, 3, ... ] × [nth term of 3, 5, 7, ... ]2

Test: Binomial Theorem - 5 - Question 16

Sum up to 16 terms of the series 

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Test: Binomial Theorem - 5 - Question 17

The value of n terms is equal to  

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Test: Binomial Theorem - 5 - Question 18

The sum of the series  upto n terms 

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Test: Binomial Theorem - 5 - Question 19

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Test: Binomial Theorem - 5 - Question 20

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