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Test: Binomial Theorem - 6 - Mathematics MCQ


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20 Questions MCQ Test Topic-wise Tests & Solved Examples for Mathematics - Test: Binomial Theorem - 6

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Test: Binomial Theorem - 6 - Question 1

{an} and {bn} be two sequences given by  for all n∈N, then a1 a2 a3 … an is equal to     

Detailed Solution for Test: Binomial Theorem - 6 - Question 1

Test: Binomial Theorem - 6 - Question 2

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Test: Binomial Theorem - 6 - Question 3

If a, b, c ∈R+ form a A.P., then 

Detailed Solution for Test: Binomial Theorem - 6 - Question 3

Since a, b, c are in A.P., therefore  

Test: Binomial Theorem - 6 - Question 4

If Zr, r = 1, 2, ...,100 are the roots of  then the value of 

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zr are the roots of z101 − 1 =0 , except 1 

Test: Binomial Theorem - 6 - Question 5

Detailed Solution for Test: Binomial Theorem - 6 - Question 5

Test: Binomial Theorem - 6 - Question 6

The sum of coefficients of (1 + x − 3x2)2134 is  

Detailed Solution for Test: Binomial Theorem - 6 - Question 6

For the sum of coefficient, put x = 1, to obtain the sum is (1 + 1 ‐ 3)2134 = 1

Test: Binomial Theorem - 6 - Question 7

The sum rCr + r+1Cr + r+2Cr + .... + nCr (n > r) equals  

Detailed Solution for Test: Binomial Theorem - 6 - Question 7

C(n, r) + c(n ‐1, r) + C(n ‐ 2, r) + . . . + C(r, r)

= n+1Cr+1 (applying same rule again and again)
(∵ nCr + nCr‐1 = n+1Cr)

Test: Binomial Theorem - 6 - Question 8

The expansion [x2 + (x6 - 1)1/2]5 + [x2 - (x6 - 1)1/2]5 is a polynomial of degree 

Detailed Solution for Test: Binomial Theorem - 6 - Question 8


Here last term is of 14 degree.

Test: Binomial Theorem - 6 - Question 9

The term independent of x in 

Detailed Solution for Test: Binomial Theorem - 6 - Question 9

The general term 
The term independent of x, (or the constant term) corresponds to x18−3r being xor 18 − 3r= 0 ⇒ r = 6 .

Test: Binomial Theorem - 6 - Question 10

The value of the greatest term in the expansion of 

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Hence, t8 is the greatest term and its value is

Test: Binomial Theorem - 6 - Question 11

9n +1 − 8n − 9 is divisible by

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Test: Binomial Theorem - 6 - Question 12

The first integral term in the expansion of is its

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∴ 
For first integral term for r = 3;

Test: Binomial Theorem - 6 - Question 13

The number of irrational terms in the expansion of (21/5 + 31/10)55 is

Detailed Solution for Test: Binomial Theorem - 6 - Question 13

(21/5 + 31/10)55
Total terms = 55 + 1 = 56

Here r = 0, 10, 20, 30, 40, 50
Number of rational terms = 6;
Number of irrational terms = 56 ‐ 6 = 50

Test: Binomial Theorem - 6 - Question 14

The number of terms in the expansion of (2x + 3y− 4z)n is 

Detailed Solution for Test: Binomial Theorem - 6 - Question 14

We have, (2x + 3y − 4z)n = {2x + (3y − 4z)}n


Clearly, the first term in the above expansion gives one term, second term gives two terms, third term gives three terms and so on.
So, Total number of term = 1 +2+3+...+n+(n+1)

Test: Binomial Theorem - 6 - Question 15

In the expansion of  the coefficient of x−10 will be  

Detailed Solution for Test: Binomial Theorem - 6 - Question 15

Given expansion is 

Since, we have to find coefficient of x−10
∴ −12 + 2r = −10 ⇒ r = 1
Now, then coefficient of x−10 is 12C1(a)11(b)1 = 12a b

Test: Binomial Theorem - 6 - Question 16

If (1 + ax)n = 1 + 8x + 24x2 + ….., then the values of a and n are equal to  

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Test: Binomial Theorem - 6 - Question 17

The product of middle terms in the expansion of  is equal to

Detailed Solution for Test: Binomial Theorem - 6 - Question 17

 it has 12 terms in it’s expansion ,
so there are two middle terms (6th and 7th);

Test: Binomial Theorem - 6 - Question 18

The middle term in the expansion of (1 – 2x + x2)n is  

Detailed Solution for Test: Binomial Theorem - 6 - Question 18


Here 2n is even integer, therefore, term will be the middle term.

Test: Binomial Theorem - 6 - Question 19

The sum of the  binomial coefficients in the expansion of (x−3/4 + ax5/4)n lies between 200 and 400 and the term independent of x equals 448. The value of a is

Detailed Solution for Test: Binomial Theorem - 6 - Question 19

Test: Binomial Theorem - 6 - Question 20

23C0 + 23C2+ 23C4 + .. + 23C22 equals 

Detailed Solution for Test: Binomial Theorem - 6 - Question 20

Given sum = sum of odd terms 

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