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Test: CSIR-NET Chemical Sciences Mock Test - 7 - CSIR NET Chemical Science MCQ


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30 Questions MCQ Test CSIR-UGC (NET) Chemical Science Mock Test Series 2024 - Test: CSIR-NET Chemical Sciences Mock Test - 7

Test: CSIR-NET Chemical Sciences Mock Test - 7 for CSIR NET Chemical Science 2024 is part of CSIR-UGC (NET) Chemical Science Mock Test Series 2024 preparation. The Test: CSIR-NET Chemical Sciences Mock Test - 7 questions and answers have been prepared according to the CSIR NET Chemical Science exam syllabus.The Test: CSIR-NET Chemical Sciences Mock Test - 7 MCQs are made for CSIR NET Chemical Science 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: CSIR-NET Chemical Sciences Mock Test - 7 below.
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Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 1

Pancreatic juice require which medium for their action?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 1
  • Pancreatic juice require basic medium for their action.
  • Pancreatic juice is a liquid secreted by the pancreas which contains a variety of enzymes, including trypsinogen, chymotrypsinogen, elastase, carboxypeptidase, pancreatic lipase, nucleases and amylase.
  • Pancreatic juice is alkaline in nature due to the high concentration of bicarbonate ions. Bicarbonate is useful in neutralizing the acidic gastric acid, allowing for effective enzymic changes.
Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 2

What is the LCM of 10,15,20,25 ?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 2

LCM denotes least common multiple hence the LCM of 10 & 15 simply means the least number which is a multiples 10,15,20,25.
LCM of fractions =Factorize of the above numbers :
10 = 2 * 5
15 = 3 * 5
20 = 5 *2 * 2
25= 5 * 5
5*5*3*2*2= 300
300 is least common multiple for four numbers 10, 15 and 20, 25.

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Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 3

What is the insects which can transmit disease from one to another person are known as?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 3
  • A Vector is any agent which carries the infectious pathogen from one person to another person.
  • Arthropods form a major group of pathogen vectors with mosquitoes, flies, sand flies, lice etc. & the most common example is Anopheles mosquito which carries malaria parasite from one place to other.
  • Some plants and fungi act as vectors for various pathogens.
Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 4

Directions: Answer the following questions by selecting the most appropriate option.
Cost price of 20 articles is equal to selling price of x articles. If the profit is 25%, then the value of x is

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 4

Let C.P. of 1 article = A
C. P. of 20 articles = 20A
Profit = 25% = 25A/100 =A/4
Hence S.P. = C.P.+ profit = A+(A/4) = 5A/4
Let S. P. of x articles = 5Ax/4
As C. P. of 20 articles = S.P. of x articles
Hence
20A = 5Ax/4
5x = 80
⇒ x= 16

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 5

Select the correct mirror image of the given figure when the mirror is placed to the right of the figure.

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 5

In a plane mirror, a mirror image is a reflected duplication of an object that appears almost identical, but it is reversed in the direction perpendicular to the mirror surface. As an optical effect, it results from the reflection of substances such as a mirror or water.

Hence, option B is the correct answer.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 6

Which number will replace the question mark (?) in the following series
6, 7, 11, 20,?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 6

6 + 1² = 7
7 + 4 (2²) = 11
11 + 9 (3²) = 20
20 + 16 (4²) = 36
Hence, option D is the correct answer.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 7

In the following question, some statements followed by some conclusions are given. Taking the given statements to be true even if they seem to be at variance from commonly known facts, read all the conclusions and then decide which of the given conclusions logically follows the given statements.
Statements:
Some clips are pins.
Some pins are pens.
Conclusions:
I. Some clips are pens.
II. No clips are pens.
III. Some pens are not pins.

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 7

The possible Venn – diagram is -

Conclusions:
I. Some clips are pens – False, as it is not a definite case.
II. No clips are pens – False, as it is not a definite case.
III. Some pens are not pins – False, as it is not a definite case.
Here, all conclusions are false, but conclusion I and II both are complementary pairs therefore, either I or II follows.
Hence, the correct answer is option C.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 8

Consider a dataset A with 55 distinct observations. A new dataset C is created by adding 2023 to all observations in dataset A. Which of the following is NOT true?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 8

When any constant a is added to all elements of a dataset, the mean and median are increased by the same constant.
⇒ Mean of C = 2023 + Mean of A
Also, Median of C = 2023 + Median of A
On adding a constant to all elements of dataset, there is no change in the variance and the range(maximum - minimum).
⇒ Variance of C = Variance of A
And, Range of C = Range of A
⇒ (Maximum – Minimum) of C = (Maximum – Minimum) of A
∴ The incorrect statement is (Maximum – Minimum) of C = 2023 + (Maximum – Minimum) of A.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 9

The squares in the following grid are filled with numbers 1 to 9 without any repetition, such that they add to 11 and 23 in the two horizontal rows and to 24 in the vertical column. What number appears in the square marked A?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 9

Given: Need to fill 1 to 9 numbers in the square without repetition. 

In the given figure, the places of all the numbers can be changed except 5 & 8. 
So comparing from given figure in question, A = 8
Hence, Option 3 is correct.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 10

Suppose a, b, c, d and e are five positive integers such that the values of a + b, b + c, c + d, d + e and e + 7 are same. Which of the following values is always same as a?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 10

Given the conditions that a + b, b + c, c + d, d + e, and e + 7 have the same value
⇒ a + b = b + c = c + d = d + e = e + 7
From a + b = b + c, we can infer that a = c.
From b + c = c + d, we can infer that b = d.
From c + d = d + e, we can infer that c = e.
From d + e = e + 7, we can infer that d = 7
Substituting these values into the equation a + b = b + c, we have:
a + b = b + c
⇒ a + b = b + e (since c = e)
⇒ a = e
⇒ a = 7 + e - 7
⇒ a = d + e - 7
∴ The value of d + e - 7 is always the same as the value of a.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 11

Two varieties of sugar A and B, costing Rs.40 per kg and Rs. 50 per kg, respectively were mixed before selling. The mixture containing 500 kg of A, was sold with a gain of 10% for Rs.88,000. How many kilograms of B did the sold mixture contain?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 11

Let the quantity of sugar B in the mixture be x kg.
Given, the mixture contains 500 kg of A
The cost of sugar A per kg is Rs. 40,
⇒ Total cost of sugar A in the mixture = 500 × 40 = Rs. 20,000.
Similarly, the cost of sugar B per kg is Rs. 50,
⇒ The total cost of sugar B in the mixture = x × 50 = Rs. 50x.
∴ The total cost of the mixture = Rs. (20,000 + 50x).
The mixture was sold for Rs. 88,000 with a 10% gain,
⇒ The selling price was 110% of the total cost.
⇒ 110% of (20,000 + 50x) = 88,000.
⇒1.1 ×  (20,000 + 50x) = 88,000.
⇒ 22,000 + 55x = 88,000.
⇒ 55x = 66,000.
⇒ x = 1,200.
∴ The mixture contained 1,200 kg of sugar B.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 12

Dividing sixty by half and adding half of forty yields

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 12

Dividing sixty by half means dividing sixty by 0.5, which is equivalent to multiplying sixty by 2.
⇒ Dividing sixty by half can be written as 60 / (1/2)
= 60 × 2 = 120.
Adding half of forty means adding 0.5 × 40 = 20 to the result. 
∴ Dividing sixty by half and adding half of forty yields 120 + 20 = 140.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 13

Given graph depicts the data of people drinking alcohol and deaths per year in nine villages. Which of the following can be definitely concluded from this graph?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 13

From the graph, we can see that as the percentage of people drinking alcohol increases, the number of deaths per year increases as well.
⇒ Percentage of people drinking alcohol is directly proportional to deaths per year
∴ We can definitely conclude that drinking alcohol kills people.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 14

Starting from the same point at the same time, A and B run on a 3600 m circular track with speeds of 4 m/s and 6 m/s, clockwise. After A completes the first round on the track, she reverses direction and runs anticlockwise. After how many seconds of starting the run would they cross for the first time?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 14

Given, speed of A = 4 m/s and Speed of B = 6 m/s
Length of track = 3600m
To complete 1 lap on the track, time taken by A = 3600/4 = 900 s
Similarly, time taken by B to complete 1 lap on track = 600 s
Now, by the time A completes 1 lap, B will have completed = 900/600 = 1.5 lap
Hence, after 900 seconds their position will be like the following:

Distance between A and B = 1800 m
Let A and B meet at a distance of x from B.

⇒ 4x = 6 × 1800 - 6x
⇒ 10x = 10800
⇒ x = 1080
∴ Time taken to travel x distance = x/6 = 1080/6 = 180 s
∴ Total time before A and B cross each other = 900 + 180 = 1080 s.
∴ After 1080 seconds of starting the run would they cross for the first time.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 15

Hypothetically, if the rotation rate of Earth about its axis is doubled, what would be the time difference (in standard seconds) between 30°E and 60°E longitudes in the equatorial region?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 15

We know that Earth is divided into 24 time zones, each spanning 15 degrees of longitude. This means that each time zone represents a one-hour difference in local time.
Assuming the Earth's rotation rate is doubled, it means the Earth completes one full rotation in half the time it currently takes. As a result, the longitudes and time zones would still remain the same, but the time difference between them would be halved.
The distance between 30°E and 60°E longitudes is 30°.
In the equatorial region, this corresponds to a time difference of 2 hours (since each time zone spans 15 degrees).
However, with the rotation rate doubled, the time difference between 30°E and 60°E longitudes would be halved, resulting in a time difference of 1 hour = 60 × 60 = 3600 seconds.
∴ The time difference (in standard seconds) between 30°E and 60°E longitudes in the equatorial region will be 3600.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 16

Which of the following is not done using column chromatography?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 16

Separation of inorganic cations or complexes is done using paper chromatography. Column chromatography is a method used to purify individual chemical compounds from mixtures of compounds.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 17

Antoine equation is a relation between

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 17

Antoine equation is a relation between Vapour pressure and Temperature.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 18

Which among the following is not a property of aromatic hydrocarbon:

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 18

Aromatic hydrocarbons undergo both electrophilic and nucleophilic aromatic substitutions.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 19

Which of the following term describe saponification?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 19

Cleaving of ester molecules into carboxylic acid and alcohol that is triglyceride is treated with a strong base, which cleaves the ester bond, releasing fatty acid salts (soaps) and glycerol.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 20

Select the incorrect option:

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 20

All the aromatic hydrocarbon are ring shaped as all of them are sp2 hybridized with a geometry of trigonal planar.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 21

According to Newton’s law of viscosity, the maximum velocity of flow is at

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 21

According to Newton’s law of viscosity, the maximum velocity of flow is at the middle of the tube. It states that for a given shear stress acting on a fluid element, the rate at which the fluid deforms is inversely proportional to the viscosity.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 22

The rate law for a reaction between the substances A and B is given by rate = K[A]n [B]m. On doubling the concentration of A and halving the concentration of B. What will be the ratio of the new rate of the earlier rate of the reaction?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 22

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 23

Which type of chromatography is used for the structural analysis?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 23

Paper chromatography is used for the structural analysis. Paper chromatography is an analytical method that is used to separate colored chemicals or substances.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 24

Melting is process which can be stated by the below statements except,

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 24

Melting is a process which proceeds by changing from a highly ordered state to a disordered state.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 25

Which of the following is considered a useful alkali in saponification reactions?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 25

Depending on the nature of the alkali used in their production, soaps have distinct properties. Sodium hydroxide (NaOH) gives “hard soap”; hard soaps can also be used in water containing Mg, Cl, and Ca salts.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 26

The viscosity of a fluid is inversely proportional to the

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 26

The viscosity of a fluid is inversely proportional to the distance between two adjacent layers.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 27

For reaction system given below, volume is suddenly reduced to half of its value by increasing the pressure on it. If the reaction is of first order with respect to O2 and second order with respect to NO, what will be the change in the rate of reaction?
2NO(g) + O2(g) + 2NO2(g)

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 27

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 28

The energy required to rotate n-butane molecule about the carbon-carbon bond is called

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 28

The energy required to rotate n-butane molecule about the carbon-carbon bond is called torsional energy. Torsion energy can be used to solve problems of general relativity especially the singularity problem.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 29

Lye is used in soap-making. Lye is a concentrated solution of which ionic compound?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 29

Lye is another name for a strongly basic solution. Mostly it is a solution of sodium hydroxide.

Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 30

Which of the following is an example of bottom-up approach for the preparation of nanomaterials?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 7 - Question 30

Dip pen nanolithography is an example of "bottom-UP" approach for the preparation of nanomaterials. All the other options are the example of top-down approach.

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