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Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - NEET MCQ


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30 Questions MCQ Test Physics Class 12 - Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22)

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) for NEET 2024 is part of Physics Class 12 preparation. The Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) questions and answers have been prepared according to the NEET exam syllabus.The Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) below.
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Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 1

Which of the following is NOT the property of equipotential surface?

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 1

As all other statements are correct. In uniform electric field, equipotential surfaces are never concentric spheres but are planes ⊥ to electric field lines.

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 2

Two point charges + 8q and –2q are located at x = 0 and x = L respectively. The point on x axis at which net electric field is zero due to these charges is

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 2

Let P be the observation point at a distance r from –2q and at (L + r) from + 8q.
Given Now, Net EFI at P = 0
= EFI (Electric Field Intensity) at P due to + 8q
 = EFI (Electric Field Intensity) at P due to – 2q

∴ 
∴ 
4r2 = (L + r)2
2r = L + r
r = L
∴ P is at x = L + L = 2L from origin
∴ Correct option is (C) 2L.

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Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 3

An electric dipole of moment p is placed parallel to the uniform electric field. The amount of work done in rotating the dipole by 90° is

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 3

W = pE (cos θ1 – cos θ2)
θ1 = 0°
θ2 = 90°
W = pE (cos 0° – cos 90°)
= pE (1 – 0)
= PE

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 4

hree capacitors 2 µF, 3 µF and 6 µF are joined in series with each other.
The equivalent capacitance is:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 4




Cseries = 1 µF

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 5

Two point charges placed in a medium of dielectric constant 5 are at a distance r between them, experience an electrostatic force ‘F’. The electrostatic force between them in vacuum at the same distance r will be:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 5




Q1 _______Q2
Force in the charges in the air is

= K F
= 5 F

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 6

Which statement is true for Gauss law?

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 6

All other statements except (iv) are incorrect.
The electric field over the Gaussian surface remains continuous and uniform at every point. 

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 7

A capacitor plates are charged by a battery with ‘V’ volts. After charging, battery is disconnected and a dielectric slab with dielectric constant ‘K’ is inserted between its plates, the potential across the plates of a capacitor will become:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 7


Battery is disconnected.

 
Q = Charge remains context C′ = KC
Q′ = C′V′
Q = C′V′
Q = KCV′

V′ = 

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 8

The best instrument for accurate measurement of EMF of a cell is

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 8

Potentiometer

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 9

An electric current is passed through a circuit containing two wires of same material, connected in parallel. If the lengths and radii of the wires are in the ratio of 3 : 2 and 2 : 3, then the ratio of the current passing through the wire will be

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 9


I1 : I2 = 3 : 2
r1 : r2 = 2 : 3
I1 : I2 = ?




∴ 

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 10

By increasing the temperature, the specific resistance of a conductor and a semiconductor:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 10

Specific resistance of a conductor increases and for a semiconductor decreases with increase in temperature because for a conductor, a temperature:
coefficient of resistivity, a = + ve
and for a semiconductor, a = – ve

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 11

We use alloys for making standard resistors because they have:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 11

Alloys have low temperature coefficient of resistivity and high specific resistance. If a = low, the value of ‘R’ with temperature will not change much and specific resistance is high, then required length of the wire will be less.

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 12

A constant voltage is applied between the two ends of a uniform metallic wire, heat ‘H’ is developed in it. If another wire of the same material, double the radius and twice the length as compared to original wire is used, then the heat developed in it will be:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 12





∵ V = constant


H′ /H = 2/1
H′ = 2H

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 13

If the potential difference V applied across a conductor is increased to 2V with its temperature kept constant, the drift velocity of the free electrons in a conductor will:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 13

We know


If temperature is kept constant, relaxation time τ - will remain constant and e, m are also constants.
Vd ∝ V
Vd ∝ 2V

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 14

The SI unit of magnetic field intensity is:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 14

We know


SI Unit of B = N/Am = NA1m–1

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 15

The equivalent resistance between A and B is ?

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 15

Redrawing the circuit, we get

3 Ω & 6 Ω are in parallel.
∴ R1 =  3 x 6 / 3 + 6 = 18/9 = 2

Now R1 and 8Ω in series
∴ R2 = R1 + 8 = 2 + 8 = 10 Ω
Now R2 and 30Ωin parallel

= 300/40 = 30/4 = 15 /2
= 7.5 Ω

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 16

Two wires of the same length are shaped into a square of side 'a' and a circle with radius 'r'. If they carry same current, the ratio of their magnetic moment is:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 16

l = length of wire

Area of a Square = a2
Also here l = 4a
a = l /4
∴ Area = l2 /16
A1 = l2/16
Area of a circle = πr2
Also here, 2πr = l
r = l/2π
Now area = 

A2 = l2/4π
Now Magnetic moment = IA
∴ M1 = IA, & M2 = I A2
Since I (current) is same in both
∴  
 M1M2 = π : 4

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 17

The coil of a moving coil galvanometer is wound over a metal frame in order to:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 17

The coil of a moving coil galvanometer is wound over metallic frame to provide electromagnetic damping so it becomes dead beat galvanometer.

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 18

The small angle between magnetic axis and geographic axis at a place is:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 18

Correct option is Magnetic declination or Angle of declination. It is the small angle between geographic axis and magnetic axis.

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 19

The horizontal component of earth’s magnetic field at a place is 3 times the vertical component. The angle of dip at that place is:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 19

Target law, BV = BH tanδ
tanδ = BV / BH
Given BH = √3BV
tanδ = BV / √3BV = 1/√3
δ = 30° or π / 6 radians.

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 20

A conducting square loop of side 'L' and resistance 'R' moves in its plane with the uniform velocity 'v' perpendicular to one of its sides. A magnetic induction 'B' constant in time and space pointing perpendicular and into the plane of the loop exists everywhere as shown in the figure. The current induced in the loop is:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 20

Current induced is I = |e/R|

Now |e| = dφ/dt
But there is no change of flux with time, as B',A' and θ all remain constant with time.
∴ No current is induced.

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 21

Two coils are placed close to each other. The mutual inductance of the pair of coils depends upon the:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 21

Mutual inductance of a pair of two coils depends on the relative position and orientation of two coils.

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 22

Which of the following graphs represent the variation of current(I) with frequency (f) in an AC circuit containing a pure capacitor?

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 22

I = V / X in pure capacitor

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 23

The magnetic flux linked with the coil (in Weber) is given by the equation:
φ = 5t2 + 3t + 16 The induced EMF in the coil at time, t = 4 will be:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 23

φ = 5t2 + 3t + 16
 |e| = dφ/dt
= d/dt(5t2 + 3t + 16)
= 10t + 3
|e|t=4 = 10(4) + 3 = 43 V
e = - 43 Volts

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 24

The instantaneous values of emf and the current in a series ac circuit are: E = Eo sin ωt and I = Io sin (ωt + π/3) respectively, then it is

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 24

E = Eo sin ωt
I = 
as I can lead the voltage in RC and LCR circuit, so it can be RC or LCR circuit.

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 25

A 20 volt AC is applied to a circuit consisting of a resistance and a coil with negligible resistance. If the voltage across the resistance is 12 volt, the voltage across the coil is:

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 25


VR = Effective voltage across R
∴ VR = Ieff R
VL = Effective voltage across L
VL = Ieff × L
Net V = 

20 = 
(20)= (12)2 + VL2
400 = 144 + VL2
VL = √400 - 144 = √266 = 16 volts

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 26

Electrostatic force between two charged particles in air is F. If charges are placed at the same distance in brass, what will be the force?

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 26

Since, dielectric constant of metal is ∞. The electric force between the charges in any medium is given by 

⇒ Fm = F/∞
⇒ Fm = 0

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 27

If the electric field is . Electric flux through a surface area 10 units lying in X-Y plane is

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 27

Direction of area element is normal to X-Y plane, i.e., z axis. Therefore, . Now, using the relationship between electric flux f and electric field

= 40 units

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 28

Work done in moving an electron from one point to another on an equipotential surface of 10 Volt potential

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 28

The potential difference between two points of equipotential surface i.e.
V2 - V1 = 0 = W/q ⇒ W = 0
Therefore, no work done is done in moving a charge from one point to another on an equipotential surface.

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 29

Electric potential at a point (x, y, z) in vacuum is V = 3x2 volt. Find the electric field intensity at the point (1m, 2m, 3m) . 

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 29

We know that

Here x = 1 m
Hence, E = 6 V/m. 

Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 30

Two copper wires of same length, having different cross-sectional area in the ratio 1:3, are connected in series. The ratio of their drift velocities vd will be 

Detailed Solution for Test: Class 12 Physics: CBSE Sample Question Paper- Term I (2021-22) - Question 30

Since, two copper wires are connected in series, current i flow through them is same. Both wires are made of same material, so n1 = n2
As, i = neAvd
⇒ 
⇒ 
⇒ 

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