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Test: Determination of Rate of a Reaction - NEET MCQ


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24 Questions MCQ Test Chemistry Class 12 - Test: Determination of Rate of a Reaction

Test: Determination of Rate of a Reaction for NEET 2024 is part of Chemistry Class 12 preparation. The Test: Determination of Rate of a Reaction questions and answers have been prepared according to the NEET exam syllabus.The Test: Determination of Rate of a Reaction MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Determination of Rate of a Reaction below.
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Test: Determination of Rate of a Reaction - Question 1
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Direction (Q. Nos. 1-13) This section contains 13 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

For a given reaction,

A → Product,

rate = 1 x 10-4 Ms-1        at [A] = 0.01 M
rate = 1.41 x 10-4   Ms-1  at [A] = 0.02 M

Hence, rate law is 

Detailed Solution for Test: Determination of Rate of a Reaction - Question 1

Let rate law be 

1 x 10-4 = K(0.01)n

1.41 x 10-4 = K(0.02)n

∴ 1.41 = (2)n 

(2)1/2 = (2)n   (Since, √2 = 1.41)

∴ n= 1/2

Thus rate law is 

Test: Determination of Rate of a Reaction - Question 2
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The rate law for a reaction between the substances A and 8 is given by

rate = k[A]n [B]m

If concentration of A is doubled and that of B is halved, the new rate as compared to the earlier rate would be 

Detailed Solution for Test: Determination of Rate of a Reaction - Question 2



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Test: Determination of Rate of a Reaction - Question 3
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The rate equation for the reaction,

2A + B → C

is found to be, rate = k[A] [B]

Q. The correct statement in relation to this reaction is that the

Detailed Solution for Test: Determination of Rate of a Reaction - Question 3

Rate = k (A)[B]

The given reaction is first order in A and first order is B.
Thus, total order = 2

(a) Unit of k = cone 1 - n time -1 = conc-1 time-1 Thus, (a) is false.
(b)  of second-order reaction, thus (b) is false. 

Thus, (c) is correct.

Thus, value of k is dependent on the concentration of A and B. Thus, (d) is false.

Test: Determination of Rate of a Reaction - Question 4
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For the reaction,

2 A+B → Product

The half-life period was independent of concentration of B. On doubling the concentration A, rate increases two times. Thus, unit of rate constant for this reaction is
Detailed Solution for Test: Determination of Rate of a Reaction - Question 4


t50 is independent of concentration of B then w.r.t. B, (n - 1) = 0. Thus, n = 1
Thus, order w.r.t. B = 1
Also, if concentration is made m-times, rate becomes, mn-times. 

Hence, w.r.t.A 

m = 2, mn = 2

∴ 2n = 2 = 21

Thus  n = 1
Thus, order w.r.t. A = 1
Thus, total order = 2 = n
Unit of n th order reaction = conc(1-n) time-1
conc in mol L-1 and time in seconds.

Then, 

Test: Determination of Rate of a Reaction - Question 5
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Which of the following statements appears to the first order reaction?

2N2O5(CCl4) → 4NO2(CCl4) + O2(g)
Detailed Solution for Test: Determination of Rate of a Reaction - Question 5

(a)

I, II, V - represent first order equation

III, VI - zeroth order equation

IV - second order equation

Test: Determination of Rate of a Reaction - Question 6
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For a reaction, time of 75% reaction is thrice of time of 50% reaction. Thus, order of the reaction is
Detailed Solution for Test: Determination of Rate of a Reaction - Question 6

For nth order reaction (n > 1)




This equation is true, if n = 2

Test: Determination of Rate of a Reaction - Question 7
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For nth order reaction,

Graphs between log (rate) and log[A0] are of the type ([A0] is the initial concentration)

Lines P, Q, R and S are for the order 
Detailed Solution for Test: Determination of Rate of a Reaction - Question 7


n = order of the reaction =slope of the line
Larger the value of the slope of the line, larger the order.
Thus, P = 3, Q = 2, R = 1, S = 0.

Test: Determination of Rate of a Reaction - Question 8
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nA → Product

For the reaction, rate constant and rate of the reaction are equal, then on doubling the concentration of A, rate becomes,
Detailed Solution for Test: Determination of Rate of a Reaction - Question 8


Thus, order = zero Rate is independent of concentration of A.
Thus, rate remains constant.

Test: Determination of Rate of a Reaction - Question 9
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For the simple reaction,

A → B

When [A] was changed from 0.502 mol dm-3 to 1.004 mol dm-3 half-life dropped from 52 s to 26 s at 300 K. Thus, order of the reaction is 
Detailed Solution for Test: Determination of Rate of a Reaction - Question 9

For nth order reaction,

(T50 ) is t1 ,at  [A] = a1 and is t2 at [A] = a2

∴ 

(2) = (2)n-1

∴ n - 1 = 1, n = 2
 

Test: Determination of Rate of a Reaction - Question 10
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For the following reaction,

Variation of T50 with [A] is shown

Q.

After 10 min volume of N2 (g) is 10 L and after complete reaction, volume of N2 (g) is 50 L. Thus, T50 is
Detailed Solution for Test: Determination of Rate of a Reaction - Question 10

T50 is independent of concentration of [A], Thus, it follows first order kinetics.






Test: Determination of Rate of a Reaction - Question 11
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Kinetics of the following reaction,

can be studied by
Detailed Solution for Test: Determination of Rate of a Reaction - Question 11

Cl-atom attached to N-atom, is an oxidising agent and can oxidise Kl to l2.


l2 can be titrated using hypo in iodometric titration.

Cl-atom attached to benzene nucleus is not an oxidising agent.

Test: Determination of Rate of a Reaction - Question 12
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Graph between [B] and time t of the reaction of the type I for the reaction, A → B

Hence, graph between   and time t will be of the type
Detailed Solution for Test: Determination of Rate of a Reaction - Question 12

A → B


[B] increases uniformly with time t. Order is zero. Thus, at every point,  = constant

Test: Determination of Rate of a Reaction - Question 13
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If in the fermentation of sugar in an enzymatic solution that is 0.12 M, the concentration of sugar is reduced to 0.06 M in 10 h and to 0.03 M in 20 h. Thus, order of the reaction is 
Detailed Solution for Test: Determination of Rate of a Reaction - Question 13

We find that,    t75 = 2 x t50

Thus, given reaction is of first-order.

Test: Determination of Rate of a Reaction - Question 14
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Direction (Q. No. 14) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.
Detailed Solution for Test: Determination of Rate of a Reaction - Question 14

(i) Rate remains constant

(dx/dt) = k(A)n = [A]0 = k

Thus   order = 0

Thus,(i)→(s)
(ii) Half-life period is independent of concentration

∴  (n-1) = 0

∴  n = 1

Thus, (ii) →(r)



Thus, graph is for second-order reactions

Thus, (iii) → (q)

Test: Determination of Rate of a Reaction - Question 15
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Direction (Q. Nos. 15-20) This section contains 3 paragraphs, each describing theory, experiments, data, etc. Six questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage I 

Peroxy acetyl nitrite  is an air pollutant, as it decomposes into radicals :

A sample of polluted air is analysed for its PAN content which is reported as molecules per litre of air at 298 K.

Q.

Determine the order of the PAN decomposition
Detailed Solution for Test: Determination of Rate of a Reaction - Question 15

0 min 5.0 x 1014  molecules L-1
30 min 2.5 x 1014 molecules L-1
60 min 1.25  x 1014 molecules L-1
At 30 min, 50% reaction takes place.
At 60 min, 75% reaction takes place.
Thus,   T75 = 2 x T50
it is valid for first order reaction. Thus, order = 1

Test: Determination of Rate of a Reaction - Question 16
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Passage I 

Peroxy acetyl nitrite  is an air pollutant, as it decomposes into radicals :

A sample of polluted air is analysed for its PAN content which is reported as molecules per litre of air at 298 K.

Q.

Rate constant of the reaction is
Detailed Solution for Test: Determination of Rate of a Reaction - Question 16

Time : [PAN]

0 min 5.0 x 1014 molecules L-1

30 min 2.5  x 1014 molecules L-1

60 min  2.5 x 1014 molecules L-1
At 30 min, 50% reaction takes place.
At 60 min, 75% reaction takes place.

Thus,   T75 = 2 x t50

It is valid for first order reaction. Thus, order = 1

For first order reactions, T50 = 0.693/k

Test: Determination of Rate of a Reaction - Question 17
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Passage II

H The reaction between nitric oxide (NO) and hydrogen (H2)has been investigated by measuring the initial rate of decrease of pressure in known mixture of gases. The following results were obtained at 1000 K.

Q.

 Overall order of the reaction is
Detailed Solution for Test: Determination of Rate of a Reaction - Question 17

-dp/dt = k(PNO)a (PH2)b

0.0012 = k(0.25)a(0.2)b

0.0024 = k(0.50)a(0.1)b

0.0048 = k(0.50)a(0.2)b

From Eqs. (i) and (iii), we get 

4 = (2)a

∴   (2)2 = (2)a

∴   a = 2

Thus w.r.t. No, order = 2

From Eqs.)ii) and (iii), we get 

2 = (2)b

(2)1 = (2)b

∴   b = 1
Thus, w.r.t. H2, order = 1

Total order = 3

From Eq. (i),

0.0012 =  k(0.25)2(0.2)1 = k (0.25)2(0.2)

∴  k = 0.0012/(0.25)2(0.02) = 0.096 atm-2 min-1

Test: Determination of Rate of a Reaction - Question 18
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Passage II

H The reaction between nitric oxide (NO) and hydrogen (H2)has been investigated by measuring the initial rate of decrease of pressure in known mixture of gases. The following results were obtained at 1000 K.

Q.

Rate constant of the overall reaction is
Detailed Solution for Test: Determination of Rate of a Reaction - Question 18




0.0012 = k(0.25)2(0.2)1 = k(0.25)2(0.2)

∴   k = 0.0012/(0.25)2 (0.2) = 0.096 atm-2 min-1

Test: Determination of Rate of a Reaction - Question 19
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Passage III

A reaction between substances A and B is represented as:

A+B → C

Observations on the rate of this reaction are obtained as :

Q. 
Order of the reaction w.r.t. A and B respectively are
Detailed Solution for Test: Determination of Rate of a Reaction - Question 19


where, a == order w.r.t. A, 6 = order w.r.t. B

(i) 5.0 x 10-3 = k[0.1]a[1.0]b

(ii) 2.0 x 1-2 = k [0.1]a[2.0]b

(iii) 2.5 x 10-3 = k [0.05]a[1.0]b

From Eqs. (i) and (ii), we get

Order w.r.t.A = 1

From Eq. (ii), 5.0x10-3 = K(0.1)(1.0)2

∴  k = 5.0 x 10-2M-2h-1

Test: Determination of Rate of a Reaction - Question 20
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Passage III

A reaction between substances A and B is represented as:

A+B → C

Observations on the rate of this reaction are obtained as :

Q.

Rate constant of the overall reaction is
Detailed Solution for Test: Determination of Rate of a Reaction - Question 20


where, a == order w.r.t. A, 6 = order w.r.t. B

(i) 5.0 x 10-3 = K [0.1]a [1.0]b

(ii) 2.0 x 10-2 = k [ 0.1]a[2.0]b

(iii) 2.5 x 10-3 = k [0.05]a[1.0]b

From Eqs. (i) and (ii), we get

(2)2 = (2)b

∴ b = 2

Order w.r.t.B = 2

From Eqs. (i) and (iii), we get

(2) = (2)a

a = 1

Order w.r.t.A 

From Eq. (ii), 

5.0 x 10-3 = k (0.1) (1.0)2

∴ k = 5.0 x 10-2m-2h-1

*Answer can only contain numeric values
Test: Determination of Rate of a Reaction - Question 21
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Direction (Q. Nos. 21-24) This section contains 4 questions. When worked out will result in one integer from 0 to 9 (both inclusive).

Graph between logT50 (T50 is half-life period) and  (a = initial concentration) for n th order reaction is of the type.

What is the value of n?

Detailed Solution for Test: Determination of Rate of a Reaction - Question 21

For nth order reactions,



*Answer can only contain numeric values
Test: Determination of Rate of a Reaction - Question 22
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The acid catalysed hydrolysis of an organic compound A at 30°C has a time for half change of 100 min when carried out in a buffer solution at pH 5 and 10 min when carried out at pH 4. Half-life in both cases are independent of initial concentration of A If rate law is , then what is the value of (a + b)?

Detailed Solution for Test: Determination of Rate of a Reaction - Question 22

Half-life

T50 is independent of [A], then

(a-1) = 0

a = 1

T1 = 100 min, [H+]1 = 10-ph = 10-5M

T2 = 100 min, [H+]2 = 10-ph = 10-4M

b - 1 = 1

b = 2

∴ a + b = 3

*Answer can only contain numeric values
Test: Determination of Rate of a Reaction - Question 23
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For a reaction, A → B, half-life time for a reaction at [A] = 0.1M is 200 s and at [A] = 0.4M it is 50 s. Thus, order of the reaction i s ......

Detailed Solution for Test: Determination of Rate of a Reaction - Question 23

        

       

 

*Answer can only contain numeric values
Test: Determination of Rate of a Reaction - Question 24
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For the reaction,

A + B → Product 

Following four experiments were carried out:

Derive the value of y.

Detailed Solution for Test: Determination of Rate of a Reaction - Question 24





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